I created a full text search with a catalog and index and the contains query works fine when I run a query with one word like below.
SELECT Name
FROM dbo.Gifts
WHERE CONTAINS(Name, 'gift')
it returns 'test gift'
I have only one row in the table and the data in the Name column looks like this: 'test gift'
but when I run the conaints query with this statement:
SELECT Name
FROM dbo.Gifts
WHERE CONTAINS(Name, 'test gift')
It throws an error saying: Syntax error near 'gift' in the full-text search condition 'test gift'.
I thought contains could query phrases and multiple words that match and sound alike?
You need double quotes to manage that space, keeping in mind that you are searching for the entire string, and not the words of the string. The following query would find "test gift" but not "gift test"
SELECT Name
FROM dbo.Gifts
WHERE CONTAINS(Name, '"test gift"')
or, if you want to search words individually, it would be
SELECT Name
FROM dbo.Gifts
WHERE CONTAINS(Name, '"test" AND "gift"')
this second one should get you a field with "gift test" as well as "test gift"
Related
this is my query:-
select * from dbo.zones where freetext(name, 'test');
select * from dbo.zones where contains(name, 'formsof(INFLECTIONAL, test)');
this give me result of- test, testing, tested
Select * from dbo.zones where contains(name, 'test');
this query only give me test result.
I am trying to get record which have "test" string like, "this is a test case".
so my query needs to find "test" string in "this is a test case" values also.
suppose i have a string in db column like "this is new generation", then i write a query like-
select * from dbo.zones where contains(name, 'formsof(INFLECTIONAL, gen)');
then this query not returning result of "this is new generation",
i need that if i pass "gen" for searching then this give above result
I want to create a select query that return the outcome like this :
A table that contains MatrixCode column with such values like this: 'shampo250', 'condishioner500', and 'AMO200'.
The query will check for each word in the column whether it is contained within text
SELECT *
FROM [t_MO_MatrixCodeMapping]
WHERE 'AMO200IL351972598764' LIKE MatrixCode
I tried to use contain too but it did dot worked.
I can not cut the text from 'AMO200IL351972598764' to 'AMO200'
Are you not after this?
SELECT *
FROM [t_MO_MatrixCodeMapping]
WHERE 'AMO200IL351972598764' LIKE MatrixCode + '%';
LIKE might as well be equivilent to = in your query, as it contains no wild cards. WHERE 'AMO200IL351972598764' LIKE 'AMO200' won't resolve the true, as it is semantically equivalent to 'WHERE 'AMO200IL351972598764' = 'AMO200'.
I would like to filter the output of show tables.
The documentation has one example on how to do this using result_scan(last_query_id()), but for me the example does not work:
show tables;
select "schema_name", "name" as "table_name", "rows"
from table(result_scan(last_query_id()))
where "rows" = 0;
-- SQL compilation error: error line 1 at position 8 invalid identifier 'SCHEMA_NAME'
The column SCHEMA_NAME is actually in the output of show tables,
so I do not understand what is wrong.
Best,
Davide
Run the following on your account and see what it is set to:
show parameters like 'QUOTED_IDENTIFIERS_IGNORE_CASE';
If this is set to TRUE, then it is ignoring the quotes in your query, which will then uppercase the column names, which won't match to the lowercase names of the SHOW output.
To resolve for your own session, you can run the following:
ALTER SESSION SET QUOTED_IDENTIFIERS_IGNORE_CASE = False;
You can also change this at a user or account level, if you wish. Setting this value to TRUE isn't recommended for the reason that you are running into.
You can reference the filter column using $<col_n> syntax (#8 for rows).
Example:
show tables;
select *
from table(result_scan())
where $8 > 5
That being said, your query worked for me.
The data in my column user_likes is as follows: anime^sitcom^scifi. I am trying to get the first item in the user likes column as output.
My query is as follows:
SELECT split(user_likes,"\\^")[0] as likes from user_data_consolidated
but the output of this query is:
anime^sitcom^scifi
SELECT substr(user_likes,1,((locate('^',user_likes )-1)))
as likes from user_data_consolidated
Consider the following example
CREATE ALIAS IF NOT EXISTS FT_INIT FOR "org.h2.fulltext.FullText.init";
CALL FT_INIT();
DROP TABLE IF EXISTS TEST;
CREATE TABLE TEST(ID INT PRIMARY KEY, NAME VARCHAR);
INSERT INTO TEST VALUES(1, 'Hello World');
CALL FT_CREATE_INDEX('PUBLIC', 'TEST', NULL);
and i have executed the following query
SELECT * FROM FT_SEARCH('Hello', 0, 0);
But this query is returning "PUBLIC"."TEST" WHERE "ID"=1 .
Do i have to again execute this "PUBLIC"."TEST" WHERE "ID"=1 to get the record containing 'Hello' word ?
What is the query to search all records with 'ell' word in them from the FT_Search. such as like %ell% in H2 Native Full-Text Search
Yes, each row in a query using FT_SEARCH represents a schema-table-row where one of the key words was found. The search is case insensitive, and the text parameter to FT_SEARCH may include more than one word. For example,
DELETE FROM TEST;
INSERT INTO TEST VALUES(1, 'Hello World');
INSERT INTO TEST VALUES(2, 'Goodbye World');
INSERT INTO TEST VALUES(3, 'Hello Goodbye');
CALL FT_REINDEX();
SELECT * FROM FT_SEARCH('hello goodbye', 0, 0);
returns only row three:
QUERY SCORE
"PUBLIC"."TEST" WHERE "ID"=3 1.0
Also note that FT_SEARCH_DATA may be used to retrieve the data itself. For example,
SELECT T.* FROM FT_SEARCH_DATA('hello', 0, 0) FT, TEST T
WHERE FT.TABLE='TEST' AND T.ID=FT.KEYS[0];
returns both rows containing the keyword:
ID NAME
1 Hello World
3 Hello Goodbye
Apache Lucene supports wildcard searches, although leading wildcards (e.g. *ell) tend to be expensive.
Do i have to again execute this "PUBLIC"."TEST" WHERE "ID"=1 to get the record containing 'Hello' word ?
Yes, except if you use a join as described by trashgod. The reason is: usually rows are much larger than just two words. For example, a row contains a CLOB with a document. If the result of the fulltext search would contain the data, then fulltext search would be much slower.
What is the query to search all records with 'ell' word in them from the FT_Search. such as like %ell% in H2 Native Full-Text Search
The native fulltext search can't do that directly. The reason is: fulltext search only indexes whole words. (By the way: does Google support searches if you only know a part of a word? Apache Lucene does support it) Actually, for H2, there would be a way: first, search the words table (FT.WORDS) for matches, and then use a regular search.