MSSQL select substring according to this pattern - sql-server

I have to ask you for something which is connetced with MSSQL.
So, I've got one column named Command(VARCHAR) which is a part of some table named TB_Commander.
This Column include results for example like (rows):
1.Delete o:2312312, c=312321
2.Add o:342342344, c=5
BTW. The thing I'd like to do is select substring from this rows which include only 'o:2312312' and for row number 2, only 'o:342342344'.
I'm stuck over here:
select
SUBSTRING(Command,PATINDEX('%1%',Command),
CHARINDEX(',',Command,PATINDEX('%o=%',Command))-0) as OperationID
from TB_Commander
where IdRow = 921321
Sorry for my english...
Thanks for any hand...

Try this ;)
select
substring(command,
patindex('%o:%', command) - 2,
patindex('%, c%', command)) as OperationID
from TB_Commander
where IdRow = 921321

This solution returns only the data you need, taking in to account length of patterns you use to extract the needed data:
SELECT
SUBSTRING(command,
PATINDEX('%o:%', command) + LEN('o:'),
PATINDEX('%, c%', [FiscalizationRequest]) - PATINDEX('%o:%',[FiscalizationRequest]) - LEN('o:')
) as OperationID
FROM TB_Commander;

declare #i int
declare #str varchar(1000)
set #str='interesting data'
declare #pattern varchar(1000)
set #pattern='eres'
SELECT #i=PATINDEX('%ter%', #str);
select substring(#str,#i-4,len(#pattern)+4)

Related

Find and change specific number in first part out of string and replace it

I start to work on old project and there is sql server database column which stores articles numbers for example as follows:
11.1006.45
11.1006.46
11.1006.47
01.10012.11
01.10012.12
2.234.1
2.234.2
2.234.3
657.104324.32
Every number contains 3 parts. First part describe what producent it is and that's something i have to change when user choose diffrent number for specific producent. For example producent number 2 will be now 13 so according to our examples:
2.234.1
2.234.2
2.234.3
has to be done this way right now:
13.234.1
13.234.2
13.234.3
I am looking for sql query which would find all records where producent number is e.g 2.xxxxx and then replace to 13.xxxxx. I would like this query to be secure to avoid any issues with numbers replacments.Hope you understand what i ment.
You could use this for update. '2. and 13.' could be any other string
DECLARE #SampleTable AS TABLE
(
Version varchar(100)
)
INSERT INTO #SampleTable
VALUES
('11.1006.45'),
('11.1006.46'),
('11.1006.47'),
('01.10012.11'),
('01.10012.12'),
('2.234.1'),
('2.234.2'),
('2.234.3'),
('657.104324.32')
UPDATE #SampleTable
SET
Version = '13.' + substring(Version, charindex('.', Version) + 1, len(Version) - charindex('.', Version))
WHERE Version LIKE '2.%'
SELECT * FROM #SampleTable st
Demo link: Rextester
update t
set t.col= replace(yourcol,substring(yourcol,1,charindex('.',yourcol,1),2)
from table t
this finds first character before first dot
substring(yourcol,1,charindex('.',yourcol,1)
then you use replace ,to replace it with whatever you need
You can use this query for multiple updation,
DECLARE #Temp AS TABLE
(
ArtNo VARCHAR(100)
)
INSERT INTO #Temp
VALUES
('11.1006.45'),
('11.1006.46'),
('11.1006.47'),
('01.10012.11'),
('01.10012.12'),
('2.234.1'),
('2.234.2'),
('2.234.3'),
('657.104324.32')
UPDATE #Temp
SET ArtNo = CASE WHEN SUBSTRING(ArtNo,1,CHARINDEX('.',ArtNo)-1) = '2' THEN STUFF(ArtNo,1,CHARINDEX('.',ArtNo)-1,'13')
WHEN SUBSTRING(ArtNo,1,CHARINDEX('.',ArtNo)-1) = '11' THEN STUFF(ArtNo,1,CHARINDEX('.',ArtNo)-1,'15')
ELSE ArtNo
END
SELECT * FROM #Temp

SQL Server : Replace (Charindex)

I have a SQL Server table with numbers in column no:
12345670000115
14245670000116
58492010000118
I need a function that will remove one number 1 from right side of number, so result must be like:
1234567000015
1424567000016
5849201000018
I find some solutions to use charindex() with substring(), but my SQL skills are poor so I really need help.
Thanks
Assuming this is varchar data here is an easy way to accomplish this. BTW, I would suggest you not use column names like 'no'. It is a reserved word and it is horribly ambiguous. Does that mean number or the opposite of yes? If it is number as I assume it would be better to name the column with an indication of what the number is. PartNumber, ItemNumber, CatalogNumber whatever...
LEFT(no, len(no) - 2) + RIGHT(no, 1)
Try to use this query:
declare #charToReplace char = '1'
select REVERSE(stuff(REVERSE(no), charindex(#charToReplace, REVERSE(no)), 1, ''))
from table
or
declare #charToReplace char = '1'
declare #tmp_table TABLE (NO varchar(16))
insert into #tmp_table
select REVERSE(NO)
from yourtable
select REVERSE(stuff(NO, charindex(#charToReplace, NO), 1, ''))
For your particular data, if the numbers fit a BIGINT, one easy way is to treat them like numbers:
Setup
create table #tmp (
number VARCHAR(16)
)
insert into #tmp values ('12345670000115'), ('14245670000116'), ('58492010000118')
GO
Script:
select number, cast( (cast(number AS bigint) - 100) / 100 * 10 + cast(number AS bigint) % 100 as VARCHAR(16))
from #tmp
GO
I resolve problem. There is answer in which I remove one character 1 and update whole table. Thanks all for help!
Update myTableName
set barcode=substring(barcode,1,11)+substring(barcode,13,1)
where len(barcode)>= 14

Converting nvarchar to numeric

I have variable called #prmclientcode which is nvarchar. The input to this variable can be a single client code or multiple client codes separated by comma. For e.g.
#prmclientcode='1'
or
#prmclientcode='1,2,3'.
I am comparing this variable to a client code column in of the tables. The data type of this column is numeric(6,0). I tried converting the variable data type like below
SNCA_CLIENT_CODE IN ('''+convert(numeric(6,0),#prmclientcode+''')) (The query is inside a dynamic sql).
But when I try executing this I get the error
Arithmetic overflow error converting nvarchar to data type numeric.
Can anyone please help me here!
Thanks!
You need to convert the numeric(6,0) column to nvarchar data type. You can use below scrip to convert it to nvarchar, before processing:
SNCA_CLIENT_CODE IN ('''+convert(cast( numeric(6,0) as nvarchar(max) ),#prmclientcode+'''))
Please try with the below code snippet.
DECLARE #ProductTotals TABLE
(
ProductID int
)
INSERT INTO #ProductTotals VALUES(1)
INSERT INTO #ProductTotals VALUES(11)
INSERT INTO #ProductTotals VALUES(3)
DECLARE #prmclientcode VARCHAR(MAX)='1'
SELECT * FROM #ProductTotals
SELECT * FROM #ProductTotals WHERE CHARINDEX(',' + CAST(ProductID AS VARCHAR(MAX)) + ',' , ',' + ISNULL(#prmclientcode,ProductID) + ',') > 0
Let me know if any concern.
use following code in order to separate your variable:
DECLARE
#T VARCHAR(100) = '1,2,3,23,342',
#I int = 1
;WITH x(I, num) AS (
SELECT 1, CHARINDEX(',',#T,#I)
UNION ALL
SELECT num+1,CHARINDEX(',',#T,num+1)
FROM x
WHERE num+1<LEN(#T)
AND num<>0
)
SELECT SUBSTRING(#T,I,CASE WHEN num=0 THEN LEN(#T)+1 ELSE num END -I)
FROM x
Use can use either table function or dynamic sql query, both options will work.
Let me know if you need more help

how to check particular ID is present in string

I want to check if a ID is present or not in a set of multiple ID.
Example
if id 5 is present in multiple id list like '1,2,3,4,5'
use CHARINDEX to return the index of the searched value.
Declare #MyString varchar(50)
Set #MyString = '1,2,3,4,5'
IF CHARINDEX('5',ContactName) > 0
Begin
Print '5 Exists'
End
Else
Begin
Print '5 Does not exists'
End
select count(*) FROM table where id = '5';
If it returns more than 0 means it's present.
If you are talking about sql this query will work for you, if you get nothing it means searching id is not there in the list else there.
SELECT * FROM journal_pulses WHERE mood_credentials in (2,27)
SELECT column FROM table WHERE CHARINDEX(',5,',(',' + column + ',')) > 0
Fiddle
One good solution in this context could be to store the values with leading and trailing comma, as:
',1,2,3,4,5,'
So, even if you store one value, store it as:
',5,'
This will help you look for required value as:
SELECT column FROM table WHERE column like '%,5,%';
Or
SELECT column FROM table WHERE CHARINDEX(',5,',(',' + column + ',')) > 0
Also, using this solution you can uniquely identify different values, given that the string does not contain duplicate values.
So, it is easy to identify 5, 50 and 350 from:
',5,50,150,250,350,450,500,'
I am not sure if you can change how the values can be stored. Please read this answer in light of the context of the question - as a starting point and not as a copy-paste solution.
I have tried something like this
DECLARE #item VARCHAR(50)
SET #ExpressionToSearch = '23,12'
SET #item = '23'
SELECT COUNT(*) from dbo.Split(#ExpressionToSearch,',')
WHERE ',' + (#ExpressionToSearch) + ','
LIKE '%'+#item +'%'
This scenario will return output greater than 0

How to get MAX value of numeric values in varchar column

I have a table with a nvarchar column. This column has values for example:
983
294
a343
a3546f
and so on.
I would like to take MAX of this values, but not as text but like from numerics. So in this example numerics are:
983
294
343
3546
And the MAX value is the last one - 3546. How to do this in TSQL on Microsoft SQL?
First install a regular expression function. This article has code you can cut/paste.
Then with RegexReplace (from that article) you can extract digits from a string:
dbo.RegexReplace( '.*?(\d+).*', myField, '$1' )
Then convert this string to a number:
CAST( dbo.RegexReplace( '.*?(\d+).*', myField, '$1' ) AS INT )
Then use this expression inside a MAX() function in a SELECT.
You can try to keep it simple without using Regular Expression
Here is the source
create table #t ( val varchar(100) )
insert #t select 983
insert #t select 294
insert #t select 'a343'
insert #t select 'a3546f';
GO
;with ValueRange as (
select val,
[from] = patindex('%[0-9]%', val),
[to] = case patindex('%[a-z]', val)
when 0 then len(val)
else patindex('%[a-z]', val) - patindex('%[0-9]%', val)
end
from #t
)
select substring(val, [from], [to]) as val
from ValueRange VR
order by cast(substring(val, [from], [to]) as int) desc
CAST() would do the trick, probably.
SELECT MAX(CAST(yourColumn AS int)) AS maxColumns FROM yourTable
Edit.
I didn't read the whole question, as it seems...
– Function to strip out non-numeric chars
ALTER FUNCTION dbo.UDF_ParseNumericChars
(
#string VARCHAR(8000)
)
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE #IncorrectCharLoc SMALLINT
–SET #IncorrectCharLoc = PATINDEX(’%[^0-9A-Za-z]%’, #string)
SET #IncorrectCharLoc = PATINDEX(’%[^0-9.]%’, #string)
WHILE #IncorrectCharLoc > 0
BEGIN
SET #string = STUFF(#string, #IncorrectCharLoc, 1, ”)
SET #IncorrectCharLoc = PATINDEX(’%[^0-9.]%’, #string)
END
SET #string = #string
RETURN #string
END
GO
I picked it from here. (I voted up the reg exp answer though)
you can write a function something like
create FUNCTION [dbo].[getFirstNumeric](
#s VARCHAR(50)
)
RETURNS int AS
BEGIN
set #s = substring(#s,patindex('%[0-9]%',#s),len(#s)-patindex('%[0-9]%',#s) + 1)
if patindex('%[^0-9]%',#s) = 0
return #s
set #s = substring(#s,1,patindex('%[^0-9]%',#s)-1)
return cast(#s as int)
end
and then call
select max(dbo.getFirstNumeric(yourColumn)) from yourTable
if you are using SQL Server 2005 or never you can also use the solution posted by Sung Meister
As far as I know you would need to create a process (or user defined function) to scrub the column, so that you can actually convert it to an INT or other appropriate datatype, then you can take the max of that.
By using user defined function parse the value to an int and then run the select.
SELECT MAX(dbo.parseVarcharToInt(column)) FROM table
SELECT dbo.RegexReplace('[^0-9]', '','a5453b',1, 1)
and RegexReplace installation like Jason Cohen said
This is an old question, I know - but to add to the knowledge base for others...
Assuming all your values have at least 1 number in them:
Select max(convert(int, SubString(VarName, PATINDEX('%[0-9]%',VarName), Len(VarName))))
from ATable
This is my simple answer. You can try it. But it works for fixed removable string value.
select max(cast(SUBSTRING(T.column,3,len(T.column)) as int)) from tablename T

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