Can someone help me in YiiBooster checkboxListGroup. I'm trying to preselect items in
$form->checkboxListGroup(
$modelPermissions,
'ID',
array(
'widgetOptions' => array(
'data' => array(
'a'=>'1111',
'b'=>'2222',
'c'=>'3333',
),
),
)
);
But with no success.
Can anybody help me with that ?
You have to specify in model field the values that you want to be default checked.
Try this:
$modelPermissions->id=array('a','b');
Related
i have an question regarding search filter in cakephp. Without complicating my question, below are the structure of what i want....
1) I have a projects table.
2) another one is project_funder_names table which is associated with projects table. project_id is in project_funder_names table. i have made project_funder_names table because i need multiple funder names for a single project, thats why i have made this table.
3) now the main point is i want if i search multiple funders in search filter which is coming in dropdown with checkbox, i will get project details according to these values. so how it would happen.
here is my cakephp find all query....
$project_info = $this->Project->find('all', array(
'conditions' =>
array(
'Project.status' => 1,
'OR' => array($search)),
'fields' => array('id', 'title', 'short_description', 'budget_allocation', 'currency', 'total_comments', 'published_date'),
'contain' => array(
'ProjectFunderName' => array(
'conditions' => array($search_funder)),
'Currency' => array('currency_symbol'),
'ProjectBookmark' => array('project_id', 'user_id')
)
)
);
problem is in $search_funder.
please help me for this.. thanks.
Looks like you need to search results based on associated models. One drawback of using containable behavior is if you're trying to assign a condition to an associated model, the main model will be retrieved no matter what.
In situations where you'd want to retrieve the main as well as the associated records based on a condition for the associated model, I'd suggest you to use join.
$joins = array(
array('table' => 'project_funder_names',
'alias' => 'ProjectFunderName',
'type' => 'LEFT',
'conditions' => array('ProjectFunderName.project_id = Project.id')
),
array('table' => 'currencies',
'alias' => 'Currency',
'type' => 'LEFT',
// It's unclear how currencies is associated with the other tables. Use appropriate table join condition here
),
array('table' => 'project_bookmarks',
'alias' => 'ProjectBookmark',
'type' => 'LEFT',
'conditions' => array('ProjectBookmark.project_id = Project.id')
)
)
);
$project_info = $this->Project->find('all',
array(
"joins" => $joins,
"fields" => array(.........) // Specify all your desired fields here
"conditions" => array(....) // Specify all conditions for Project, ProjectFunderName models.
)
);
Hope this helps.
Peace! xD
Hey my problem is to define a condition for a HABTM Model
(int) 0 => array(
'Article' => array(
'id' => '',
'title' => '',
'body' => '',
'created' => null,
'modified' => null
),
'Channel' => array(
'id' => '',
'channelname' => '',
'created' => null,
'modified' => null
),
'Tag' => array(
(int) 0 => array(
'id' => '1',
'value' => 'example',
),
(int) 1 => array(
[maximum depth reached]
),
(int) 2 => array(
[maximum depth reached]
)
),
),
I want to define a condition that searches the Tag values for specific values .. like that:
$this -> Article -> find('all', array('conditions' => array('Tag.0.value' => 'test'))
So does someone knows how to "foreach" that array in this condition? thanks (:
You either need to:
Run your find from the other direction (using CakePHPs awesome Containable Behavior to get the Articles):
$this->Tag->find('all', array(
'conditions' => array(
'Tag.value' => 'test'
),
'contain' => array(
'Article'
)
));
Or, use JOINs. Run your find like you're doing, but do an INNER JOIN on tags where the tag value='test'
You cannot limit the main Model's results based on an associated model's conditions. The reason is, when you rely on recursive, or use Contain, CakePHP actually creates separate queries to pull in your different models' data. Therefore, you can't have a condition in one query affect the other query.
See similar question/answers:
How do I restrict query results based on sub-results in CakePHP?
Conditions in JOINed tables shows error CakePHP
cakephp contain filtering by parent model value
cakephp contain association conditions issue
Adding conditions to Containable in CakePHP
i want to display certain field in database use scaffold , please help me
EX:
Product Model has property is ("name", "description", "price", "created_at")
and i want to display field 'name','description' and 'price' use scaffold
Thanks for any help!
I'm not sure its a good way to do this but it will work for you---
Just define a table schema on model class.
Like your-
Product.php
public $_schema = array(
'name' => array(
'type' => 'string',
'length' => 30
),
'description' => array(
'type' => 'text'
),
'price' => array(
'type' => 'float'
)
);
So this is what I am trying to do.
My table say(Courses) has multiple entries with same id.
When I get the data from paginate it shows all the records. So if I have 3 records with Id 5 it will show record number 5 three times.
Now What I want is that it should show the record only once.
I searched online but can't find anything.
If anyone has come across such problem and found a solution to it please let me know.
Thanks,
I came across your problem, as I had a similar problem. David Z's solution did not work for me, but I did find that the group variable in $paginate worked for me.
So using your code sample above, this is how I'd think it should work.
$paginate = array(
'Courses' => array(
'limit' => 20,
'fields' => array('Courses.id'),
'conditions' => $cond,
'group' => array('Courses.id'),
'order' => array('Courses.id' => 'asc')
)
);
To hopefully shed some more light on the solution that worked for me, I have Systems that belong to Companies. I wanted to get a list of the unique companies, for the systems I have. This is the exact code I used, that worked for me
$this->paginate = array ('fields' => array ('Company.*'),
'order' => array('Company.name' => 'ASC'),
'group' => array('Company.id'));
$this->set('companies', $this->paginate($this->Company->System));
Hope this has helped
Looking at the CakePHP cookbook, the documentation for pagination shows that you can override the $paginate member. Behind the scenes, this similar to passing in the parameters for your model's find('all'). Maybe try setting parameter to explicitly return the filds that you are interested with the distinct keyword to narrow down the values you need?
class RecipesController extends AppController {
var $paginate = array(
'fields' => array('Model.field1', 'DISTINCT Model.field2')
);
}
So here is how my paginate variable looks like:
var $paginate = array(
'Courses' => array(
'limit' => 20,
'page' => 1,
'order' => array(
'Courses.id' => 'asc')
),
);
The condition variable looks something like this:
$cond = array("Courses.id LIKE "=>$this->data['id_search'],
"Courses.length LIKE "=>$this->data['length_search'],
"Courses.marks LIKE "=>$this->data['marks']
);
And this is how I am calling paginate.
$data = $this->paginate('CdmaRfReport',$cond);
I tried doing
$paginate = array(
'Courses' => array(
'limit' => 20,
'fields' => array('DISTINCT Courses.id'),
'page' => 1,
'conditions' => $cond,
'group' => array('id'),
'order' => array(
'Courses.id' => 'asc')
)
);
It doesn't seem to help.
I also tried
$cond = array("DISTINCT Courses.id "=>$this->data['id_search'],
"Courses.length LIKE "=>$this->data['length_search'],
"Courses.marks LIKE "=>$this->data['marks']
);
Even this errors out
I might be something wrong. But I am not able to figure it out.
Any suggestions please let me know.
Background
I have a CGridView that contains multiple checkbox columns. I have created the checkbox columns using code like this:
$columns[] = array(
'header'=>'Health',
'value' => 'CHtml::checkBox("hsid[]", $data->healthService, array("value"=>$data->wc_client_id,"id"=>"hsid_".$data->wc_client_id))',
'type'=>'raw',
'htmlOptions'=>array('style'=>'text-align:center'),
);
$columns[] = array(
'header'=>'Education',
'value' => 'CHtml::checkBox("esid[]", $data->educationService, array("value"=>$data->wc_client_id,"id"=>"esid_".$data->wc_client_id))',
'type'=>'raw',
'htmlOptions'=>array('style'=>'text-align:center'),
);
The $data->healthService and $data->educationService are used to set the initial checked state of the checkbox, based on data from the database.
Question
How can I capture changes to each of the different checkbox in a row, and send those changes back to my controller? The controller would then update the database based on checkbox changes.
Here is how I finally got it to work:
View Code
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'service-grid',
'dataProvider'=>$clients->search(),
'columns'=>array(
'first_name',
'last_name',
array(
'header'=>'Education',
'class'=>'CDataColumn',
'type'=>'raw',
'htmlOptions'=>array('style'=>'text-align:center'),
'value' => 'CHtml::checkBox("esid[]", $data->education, array("value"=>$data->wc_client_id,"id"=>"esid_".$data->wc_client_id))',
),
array(
'header'=>'Health',
'class'=>'CDataColumn',
'type'=>'raw',
'htmlOptions'=>array('style'=>'text-align:center'),
'value' => 'CHtml::checkBox("hsid[]", $data->health, array("value"=>$data->wc_client_id,"id"=>"hsid_".$data->wc_client_id))',
)
),
));
Controller Code To Retrieve Selected IDs
$healthClientId = array();
if(isset($_POST['hsid']) && is_array($_POST['hsid']))
{
$healthClientId = $_POST['hsid'];
}
$educationClientId = array();
if(isset($_POST['esid']) && is_array($_POST['esid']))
{
$educationClientId = $_POST['esid'];
}
May be a better choice is a CCheckBoxColumn ?
See http://www.yiiframework.com/doc/api/1.1/CCheckBoxColumn