cakephp find associated models of associated model - cakephp

I am calling a find on a model called Book which is associated with a model Page(book_id)
However Page is associated with a model called Asset(page_id). I would like to get the array with all three models
Book
Page1
Asset1
Asset2
Asset3
Page2
Asset1
Asset2
Asset3
The code I have at the moment only get me Book and Page
$options = array(
'conditions' => array('Book.' . $this->Book->primaryKey => $id),
'contain' => 'Page'
);
$books = $this->Book->find('first', $options);
Book hasMany Pages
Page hasMany Assets

You can contain deeper associations, like it says in the docs
Example from the docs
$this->User->find('all', array(
'contain' => array(
'Profile',
'Account' => array(
'AccountSummary'
),
'Post' => array(
'PostAttachment' => array(
'fields' => array('id', 'name'),
'PostAttachmentHistory' => array(
'HistoryNotes' => array(
'fields' => array('id', 'note')
)
)
),
'Tag' => array(
'conditions' => array('Tag.name LIKE' => '%happy%')
)
)
)
));
Same thing with your models...
$options = array(
'conditions' => array('Book.' . $this->Book->primaryKey => $id),
'contain' => array('Page' => array('Asset')))
);
$books = $this->Book->find('first', $options);
Should work if your associations are set correctly (and if all models implement containable behavior).
EDIT
(to address the confusion the OP had)
The nested contain options works for the model expanding the array. For example, if models are associated like this
Model-A -> Model-B -> Model-C & Model-D
-> Model-E -> Model-C
you could get the entire array with data like
Model-A
Model-B1
Model-C1
Model-C2
Model-D2
Model-B2
Model-C (null)
Model-D3
Model-E1
Model-C1
Model-C3
using something like
$this->ModelA->find('all'), array(
'contain' => array(
'Model-B' => array('Model-C', 'Model-D'),
'Model-E' => array('Model-C')
)
);
Also, you can add options to the containable array, including the ones used for searching, like 'conditions' (though be careful with this, it means that if the model doesn't match the condition it will return a null array, it does not mean the the whole "Model-A" will not be in the returned data since one of the nested conditions was not fulfilled).

Related

CakePHP only get results that have a related model

In my CakePHP 2 project, I have Projects that have many Articles, an Article can belong to many projects (a many-to-many relation).
Now I would like to find all Projects that have an Article.
My current code for getting the Projects is as follows
$projects = $this->Project->find('list', array(
'fields' => array('Project.slug', 'Project.name')
));
I tried adding contain to the query, without results
$projects = $this->Project->find('list', array(
'contain' => array('PressArticles' => array()),
'fields' => array('Project.slug', 'Project.name')
));
How can I modify this so I receive all projects that have an article?
Containing won't help, non-1:1 relations will be retrieved in a separate query, so that won't have any effect on your main query.
You could for example manually create INNER joins with the association's join and target table, that would automatically filter out all projects that have no associated articles, something along the lines of this (I've more or less guessed the names, it's just a quick and dirty example):
$projects = $this->Project->find('list', array(
'fields' => array('Project.slug', 'Project.name'),
'joins' => array(
array(
'table' => 'press_articles_projects',
'alias' => 'PressArticleProject',
'type' => 'INNER',
'conditions' => array(
'PressArticleProject.project_id = Project.id',
),
),
array(
'table' => 'press_articles',
'alias' => 'PressArticle',
'type' => 'INNER',
'conditions' => array(
'PressArticle.id = PressArticleProject.press_article_id',
),
)
),
'group' => 'Project.id'
));
Or if you are using a counter cache, then filtering by the counter would be an option too:
$projects = $this->Project->find('list', array(
'fields' => array('Project.slug', 'Project.name'),
'conditions' => array(
'Project.press_article_count >' => 0
)
));
See also
Cookbook > Models > Associations: Linking Models Together > Joining tables
Cookbook > Models > Associations: Linking Models Together > counterCache - Cache your count()
In your Project model, you can do
public $hasMany = array(
'PressArticle' => array(
'className' => 'PressArticle',
'foreignKey' => 'project_id'
)
);
For more info, check here

CakePHP conditions for deep associations

I have some deep associations using containable and need to filter back the results. For the sake of this question, let's say we are selling cars and want to narrow the results down by features.
Car hasmany make hasmany model HABTM features
$options = array(
'order' => array('Car.price'),
'contain' => array(
'make',
'model' => array(
'order' => 'Model.name ASC'
),
'features'
)
);
$cars = $this->Car->find('all', $options);
How would I go about excluding all cars that don't have power windows (Features.name != power_windows).
Containable is only suitable for you to specify what models you wanted to include when fetching data, but not limiting the parent model from fetching data at all. One obvious symptom is that sometimes your parent data may have some null contained data.
So to achieve it, I think we should use joins here so you can specify condition:
$options = array(
'order' => array('Car.price'),
'contain' => array(
'make',
'model' => array(
'order' => 'Model.name ASC'
),
'features'
),
'joins' => array(
array(
'table' => 'features',
'alias' => 'Feature',
'type' => 'LEFT',
'conditions' => array(
'Car.id = Feature.car_id'
)
)
),
'conditions' => array(
'Features.name !=' => 'power_windows',
)
);
But one drawback of this is that you might have duplicated Car due to joining. That's a separate issue ;)

Associate different column name to one Model + cakephp

how to get name of (UserTransactionType.name) with Transaction.who_pay_fee_1,2,3 fields.
'user_transaction_type_id' works well but how to get the rest of fields work :(
//Transaction Model
public $belongsTo = array(
'UserTransactionType' => array(
'className' => 'UserTransactionType',
'foreignKey' => 'user_transaction_type_id',
'conditions' => '',
'fields' => '',
'order' => ''
),
//UserTransactionType Model
public $hasMany = array(
'Transaction' => array(
'className' => 'Transaction',
'foreignKey' => 'user_transaction_type_id',
'dependent' => false,
))
This is the sample code for your controller:
$this->UserTransactionType->find('all',array(
'fields' => array('name'),
'contain' => array('Transaction')
)
);
If Models are associated you can specify in 'contain' which of them you want to get in the result.
If you want to have only some fields of related Model, you can determine them after 'Transaction' in 'contain' just like in the regular find() query:
'contain' => array('Transaction' => array('fields' => array('field_1',
'field_2') ))
But in your case, you don't need to specify fields, because by default you get all fields.
So no matter if you define or not fields "who_pay_fee_1,2,3" because if you use 'contain' by default you will get foreing_key - user_transaction_type_id.
I hope it's helpful
For people they like CakePhp :)
in Controller ->
get the list of 'UserTransactionType'
in View ->
after looping trough all the transactions; in Transaction Status column simply load the 'UserTransactionType'array and assign the number of array to $userTransactionTypes.
$userTransactionTypes[$transaction['Who_pay_fee_1']];
To be honest it was straight forward but needed a bit concentration :)

Containable behavior doesn't return deeper model association and selecting fields

I want to limit the fields returned by a deeper association using containable.
My associations:
Game hasMany Review
The paginate and containable code:
$this->paginate = array(
'conditions' => $conditions,
'fields' => array(
'Game.id', 'Game.name',
'Publisher.id', 'Publisher.name'
),
'contain' => array(
'Game' => array(
'Review' => array(
'fields' => array('Review.id', 'ROUND(AVG(Review.score),1)')
)
),
)
);
$games = $this->paginate('Game');
Currently, all of the fields in the Review table are returned. 'ROUND(AVG(Review.score),1)' is never returned. How can I specify what fields I want returned from the Review association?
SQL dumps for two search results using #theJetzah's answer. The first is a search with one game as a result and the second is a search returning three games.
SELECT `Review`.`id`, `Review`.`review_text`, `Review`.`score`, `Review`.`user_id`, `Review`.`game_id`, `Review`.`created`, `Review`.`platform_id`, (ROUND(AVG(`Review`.`score`),1)) AS `Review__average_score` FROM `videogamedb`.`reviews` AS `Review` WHERE `Review`.`game_id` = (55)
SELECT `Review`.`id`, `Review`.`review_text`, `Review`.`score`, `Review`.`user_id`, `Review`.`game_id`, `Review`.`created`, `Review`.`platform_id`, (ROUND(AVG(`Review`.`score`),1)) AS `Review__average_score` FROM `videogamedb`.`reviews` AS `Review` WHERE `Review`.`game_id` IN (55, 56, 57)
Not a full answer, but an attempt to get it working :)
Approach1 (UPDATE: Containable doesn't support 'group by')
First of all, try to add the 'Game' model to the $uses array of your Controller, if it is not included yet, and re-organise the pagination array (as previously suggested by Sam), so that you'll be pagination the Game model itself.
Then, It may help to create a virtual field for the calculated score, but the results of 'Review' need to be grouped, otherwise you'll not be able to calculate the average score.
I'm not able to test this, but it may worth trying
something like this;
public $uses = array(
'Game',
// other models
);
public function myfunction()
{
$this->Game->Review->virtualFields['average_score'] = 'ROUND(AVG(Review.score),1)';
$this->paginate = array(
'Game' => array(
'fields' => array(
'Game.id',
'Game.name',
'Publisher.id',
'Publisher.name'
),
'contain' => array(
'Review' => array(
'fields' => array(
'Review.game_id,
'Review.average_score',
),
'group' => array(
'Review.game_id,
),
)
)
)
);
// Conditions can be passed to paginate,
// that way you can specify 'paginate' at
// one place and don't have to modify it
// to include the conditions
$games = $this->paginate('Game', $conditions);
}
Alternative approach: Using joins and a database-view
Apparently, the Containable behavior doesn't like group-by clauses; See this ticket for more information: Containable behavior does not implement 'group' option
CakePHP allows you to manually specify a join: Joining Tables
To simplify things and to prevent having to add a 'group by' for all fields, create a simple database-view in your database;
CREATE VIEW review_scores AS
SELECT
game_id,
ROUND(AVG(score),1) AS average_score,
COUNT(id) AS total_reviews
FROM
reviews
GROUP BY
game_id;
If you're unfamiliar with this; a database 'view' is basically a 'stored query', which can be accessed as if it was a regular table. See Create View
Then, use a 'manual' join, using the newly created database-view as the source-table. In your case, this will look something like this;
$this->paginate = array(
'Game' => array(
'fields' => array(
'Game.id',
'Game.name',
'Publisher.id',
'Publisher.name',
'ReviewScore.average_score',
'ReviewScore.total_reviews',
),
'joins' => array(
array(
'table' => 'review_scores',
'alias' => 'ReviewScore',
'type' => 'LEFT',
'conditions' => array(
'ReviewScores.game_id = Game.id',
)
)
)
)
);
Hope this helps
I think your array is a configured a little wrong, try:
$this->paginate = array(
'Game' => array(
'conditions' => $conditions,
'fields' => array(
'Game.id', 'Game.name',
'Publisher.id', 'Publisher.name'
),
'contain' => array(
'Review' => array(
'fields' => array('Review.id', 'ROUND(AVG(Review.score),1)')
)
)
)
);
$games = $this->paginate('Game');
As an aside, from personal experience, specifying the fields in a query doesn't always speed it up (certainly for small number of fields), assuming this is the motive for doing so. It does reduce memory occupancy but this is only relative to original size of the record and the number of records returned.

CakePHP 2.x containable behavior conditions on deep associations

I have model relations like this:
Project hasMany SubProject hasMany Item
I want to set up a containable array so that I can find all of the Items which belong to a particular Project, and paginate the results. So, in my ItemsController I have:
public $paginate = array(
'Item' => array(
'limit' => 10,
'order' => array('
'Item.create_time' => 'desc'
),
'contain' => array(
'SubProject' => array(
'Project'
)
)
)
);
Somewhere, obviously, I need to place a condition like "SubProject.project_id = $pid", but nothing I've tried yields the correct results. The best I can manage is results that look like this:
Array
(
[0] => Array
(
[Item] => Array
(
[id] => 13
[file_name] => foo.tar.gz
.... other keys ...
[create_time] => 2013-01-23 14:59:49
[subProject_id] => 4
)
[SubProject] => Array
(
[id] => 4
[name] => foo
[project_id] => 2
..... other keys ....
[Project] => Array
(
)
)
)
[1] => Array
.....
Edit: It is quite correctly omitting the Project record that doesn't match; I want to skip any Item records with out a matching Project record.
It has crossed my mind to manually specify my joins, but I feel like that shouldn't be necessary.
It seems like this should be obvious, but alas, the solution escapes me.
I did eventually solve this problem, so I thought I'd explain what I did in the hope it might help someone else.
After reading this blog post by Mark Story (which is from the days of 1.2 but still relevant) I decided that the thing to do was create a custom find type in my Item model that binds the Project model directly. This gives a first-level association that Containable can filter correctly.
So, in the Items model, I have something like the following (see the documentation on custom find types).
public $findMethods = array('byProject' => true);
public function _findByProject($state, $query, $results=array()) {
if ($state == 'before') {
$this->bindModel(array(
'hasOne' => array(
'Project' => array(
'foreignKey' => false,
'conditions' => array('Project.id = SubProject.project_id')
)
)
));
return $query;
}
return $results;
}
Note that setting foreignKey to false is necessary to prevent CakePHP from trying to automatically use a non-existent database key. In the ItemsController, the pagination options now look like this:
public $paginate = array(
'Item' => array(
'findType' => 'byProject',
'limit' => 10,
'order' => array(
'Item.create_time' => 'desc'
),
'contain' => array(
'SubProject',
'Project'
),
'conditions' => array('Project.id' = $pid)
),
);
...where $pid is the id of the project to display. Some minor tweaks in the view code to accomodate the slightly different results array structure, and I was all set.
EDIT ===============
public $paginate = array(
'limit' => 10,
'order' => 'Item.create_time DESC', //'order' => array(''Item.create_time' => 'desc'),
'contain' => array(
'SubProject' => array(
'Project' => array(
'conditions' => array(
'id' => $project_id // Passed parameter
)
)
)
)
);
=================================================
Have you tried using conditions as in the following? Also, I did not write the 'order' section of the code the way you have it.
public $paginate = array(
'Item' => array(
'limit' => 10,
'order' => 'Item.create_time DESC', //'order' => array(''Item.create_time' => 'desc'),
'contain' => array(
'SubProject' => array(
'Project' => array(
'conditions' => array(
'id' => $project_id // Passed parameter
)
)
)
)
)
);

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