How to reuse Loop ? get_template_part() or? - loops

I want to use the same Loop and Pagination for
index.php , search.php , and archive.php
However, for search.php I want a title "Search Results" to appear before the Loop
and for archive.php I want a title "Archive Page" to appear before the Loop.
Method A
Keep index.php, search.php, and archive.php
And use get_template_part() for navigation and Loop ?
Method B
Just use index.php
but how?
Or is there a simpler method since all I want is to add a title before the Loop?
Simple code for the sake of this example:
index.php
<?php
if ( have_posts() ) : while ( have_posts() ) : the_post();
the_excerpt();
endwhile; endif;
?>
code for Pagination
search.php
<h2>Search Results</h2>
code for The Loop
code for Pagination
archive.php
<h2>Archive Page</h2>
code for The Loop
code for Pagination

I don't know the exact structure of your pages, but I would place the code in header.php. Here is my thought on this
The header is common to all of these templates, and I would suspect that you are going to need these titles between your header stuff and the content area
Target pages with conditional tags . Open your header, and right down at the bottom, add something like this
if(is_search()) {
//your title for search page etc
} elseif(is_archive()) {
//your title for archive page
} else {
//display nothing if you don't need to display any custom title
}
Just add the necessary mark up and style accordingly
EDIT
It seems that you are still very new to php. From your comment
Weird. I put <?php if(is_search()) { <h2>Search Results</h2> } ?> at very bottom of header.php but got White Screen. So instead, I put it in index.php and deleted search.php but still White Screen. I tested it in my theme and Twentytwelve. ---------- Can you help me understand... Does less php files equal to a faster website? Is reducing the amount of php files considered best practice? So if index.php , search.php , archive.php uses the same code except for a title "Search Results" and "Archive Page" - is it best practice to simply have one php file and do conditional statements for titles?
Your problem is switching between php and html elements. Whenever you switch from php to html, you need to close your php tag (?>)before your html element. On the otherhand, you need to open a new php tag (<?php) right after your last html element and before your first php element.
Not doing this correctly will lead to a synatx error, which causes a white screen of death.
So in short, your code will need to look like this for it to work properly. Note the php tags
<?php
if(is_search()) { // this part is php
?> <!-- Close php because whe're switching to html -->
<h2>Search Results</h2> <!-- this part is html -->
<?php // open new php tag as we're switching to php again
} elseif(is_archive()) { //same sequence above applied
?>
<h2>Archive Page</h2>
<?php
} else {
//display nothing if you don't need to display any custom title
}
?>
Less php files does not mean a faster website, speed is determined by content, content type, database queries, amount of queries, etc etc. A one page website can be slower than a 10 page website.
What I've done with this code and why I placed it in the header is just to keep the code together. You can split it up as you wish. There is no best practice. What really counts is readability, accesibility, not repeating code over and over, and keeping a proper file system

You could output the title before you start the loop. The contents of the loop would be called using get_template_part(). For example:
if ( have_posts() ) {
// Output the title.
the_title();
// Begin loop.
while ( have_posts() ) {
the_post();
get_template_part( 'loop', 'index' );
}
}
Update: Using just index.php to display a title conditionally, you would do this:
if ( is_search() ) {
// Display the search page title here.
} else if ( is_category() ) {
// Display the category title here.
}
Ref: http://codex.wordpress.org/Function_Reference/get_template_part

Related

how can I load a joomla module as a link?

this is my problem...
I have some of images and links that I want to load different joomla modules when user click on them.
mean each hyperlink can load another module|position
thanks all
In case that you just want to call a module's content from a url the following answer will help you.
If you just want to show / hide a module in the same page you could use something similar to my previous answer: Joomla 3 Show different modules on same position depending on toggler
Joomla provides the functionality to call a specific file of the active template by adding the tmpl=FILENAME key/value to the url's query string.
All built-in templates have a component.php file if user wants to load the template with the component only. You could check the following link for more details: Adding print pop-up functionality to a component.
You could do something similar to only show the modules that you want to load.
You could copy the component.php to a new file (I have used custom.php) and added the following php code in the <body> ... </body> part.
<?php
$jinput = JFactory::getApplication()->input;
$selectedPosition = $jinput->getString("position", "");
$selectedModule = $jinput->getString("module", "");
$selectedModuleTitle = $jinput->getString("title");
if($selectedPosition !== "") {
$modules = JModuleHelper::getModules($selectedPosition);
foreach ($modules as $module) {
echo JModuleHelper::renderModule($module);
}
} elseif ($selectedModule !== "") {
$module = JModuleHelper::getModule($selectedModule, $selectedModuleTitle);
echo JModuleHelper::renderModule($module);
}
?>
So with a similar way as loadposition / loadmodule works you could call the new template file using:
index.php?tmpl=custom&position=MODULE_POSITION
or
index.php?tmpl=custom&module=MODULE_TYPE
or
index.php?tmpl=custom&module=MODULE_TYPE&title=MODULE_TITLE
Optionally if you want to load the module with a specific style, you could pass it to the second paramter of the renderModule method like:
echo JModuleHelper::renderModule($module, array("style" => "xhtml"));
Hope this helps

virtuemart3 shows 2 images with mouse hover

I need to show 2 images per products in categories menu. Please refer
this link for more clarification.
To do this ,I have used below code in sublayouts folder and products.php files:
<div class="img-wrapper">
<?php
$image = $product->images[0]->displayMediaThumb('class="browseProductImage featuredProductImageFirst" id="Img_to_Js_'.$product->virtuemart_product_id.'" border="0"',false) ;
if(!empty($product->images[1])){
$image2 = $product->images[1]->displayMediaThumb('class="browseProductImage featuredProductImageSecond" border="0"',false) ;
} else {$image2= $product->images[0]->displayMediaThumb('class="browseProductImage featuredProductImageSecond" border="0"',false) ;}
echo JHTML::_('link', JRoute::_('index.php?option=com_virtuemart&view=productdetails&virtuemart_product_id='.$product->virtuemart_product_id.'&virtuemart_category_id='.$product->virtuemart_category_id),'<div class="front">'.$image.'</div><div class="back">'.$image2.'</div>');
?>
</div>
but didn't work out.It shows only one image
live demo: http://new.decoricor.com/decoricor-jewelery/hair-style
There is a hidden configuration to show more than one picture in the category view.
You can set values here:
/administrator/components/com_virtuemart/virtuemart.cfg
prodimg_browse needs to be set to 2. prodimg_browse=2
This is called in the view.html.php of the category view.
After that, two pictures will be in your array.
Documentation for the hidden configuration:
http://docs.virtuemart.net/manual/general-concepts/206-hidden-configurations.html

Styling/Theming Drupal 7 Content Type Record

I developed a Content type of "Car Sales" with following fields:
Manufacturer
Model
Make
Fuel Type
Transmission (Manual/Automatic)
Color
Registered? (Yes/No)
Mileage
Engine Power
Condition (New/Reconditioned/Used)
Price
Pictures (Multiple uploads)
I have developed View of this Content Type to display list of cars. Now I want to develop a screen/view for individual Car Sale Record like this:
Apart from arranging fields, please note that I want to embed a Picture Gallery in between. Can this be achieved through Drupal 7 Admin UI or do I need to create custom CSS and template files? If I need to edit certain template files/css, what are those? I'm using Zen Sub Theme.
I would accomplish this by creating a page, and then creating a node template to accompany it. Start by creating a new node, and then record the NID for the name of the template.
Then, in your template, create a new file, and name it in the following manner: node--[node id].tpl.php
Then, in that file, paste in the following helper function (or you can put it in template.php if you're going to use it elsewhere in your site):
/**
* Gets the resulting output of a view as an array of rows,
* each containing the rendered fields of the view
*/
function views_get_rendered_fields($name, $display_id = NULL) {
$args = func_get_args();
array_shift($args); // remove $name
if (count($args)) {
array_shift($args); // remove $display_id
}
$view = views_get_view($name);
if (is_object($view)) {
if (is_array($args)) {
$view->set_arguments($args);
}
if (is_string($display_id)) {
$view->set_display($display_id);
}
else {
$view->init_display();
}
$view->pre_execute();
$view->execute();
$view->render();
//dd($view->style_plugin);
return $view->style_plugin->rendered_fields;
} else {
return array();
}
}
Then add the following code to your template:
<?php
$cars = views_get_rendered_fields('view name', 'default', [...any arguments to be passed to the view]);
foreach ($cars as $car): ?>
<div>Put your mockup in here. It might be helpful to run <?php die('<pre>'.print_r($car, 1).'</pre>'); ?> to see what the $car array looks like.</div>
<?php endforeach;
?>
Just change the placeholders in the code to whatever you want the markup to be, and you should be set!
As I mentioned above, it's always helpful to do <?php die('<pre>'.print_r($car,1).'</pre>'); ?> to have a visual representation of what the array looks like printed.
I use views_get_rendered_fields all the time in my code because it allows me to completely customize the output of the view.
As a Reminder: Always clear your caches every time you create a new template.
Best of luck!

Including JS in default View in Cake PHP

I can do this in any of my View file in Cake PHP:
<?php echo $this->Html->script('myjs.js', false); ?>
but if I do the same thing in my default view (default.ctp) then the JS files don't load i.e. they don't get echoed. I have tried moving includes above and below <?php echo $scripts_for_layout ?> in the default view but they still don't get printed:
<?php echo $scripts_for_layout ?>
<?php echo $this->Html->script('myjs.js'); ?>
<?php echo $this->Html->script('myjs.js'); ?>
<?php echo $scripts_for_layout ?>
Any ideas?
Thank you :).
with or without an extension - this is not the reason why the script do not get echoed,
as mensch mentioned before it makes no difference because of:
source of html helper cakephp 2
if (strpos($url, '?') === false && substr($url, -3) !== '.js') {
$url .= '.js';
}
the reason is:
you have already inserted this script inside your view,
cake checks if the script is already inserted on the page
options - 'once' - Whether or not the script should be checked for uniqueness. If true scripts will only be included once, use false to allow
the same script to be included more than once per request.
by default the value of once is set to TRUE
remove the script from your view first and then try it with or without '.js'
P.S.: why the petervaz answer has worked for you:
because this check:
if ($options['once'] && isset($this->__includedScripts[$url])) {
return null;
}
made before check for file extension
so isset(__includedScripts['myjs']) == false // because first key was __includedScripts['myjs.js']
and you've got your script included
I have a project with scripts added just before $scripts_for_layout and they are displayed fine. The only difference is that I'm not adding the extension .js to the call, like this:
default.ctp:
<head>
<?php echo $this->Html->charset(); ?>
<title>
<?php echo "Site > $title_for_layout"; ?>
</title>
<?php
echo $this->Html->script('jquery-1.6.4');
echo $this->Html->script('jquery-ui-1.8.16.custom.min');
echo $this->Html->script('mercado');
echo $scripts_for_layout;
?>
</head>
Another thing I'd DEFINITELY recommend is to check that loading your JS in a view is 100% OK with everything.
Do NOT use $this->Html->script if you are unsure about:
--- the dependency of scripts on each other
--- the dependency of some plugins on other scripts
--- how many different layouts and/or views you want to use in the future.
For example, some plugins use jQuery but they require jQuery to be loaded BEFORE the plugin itself.
So if you put jQuery in a view or layout, the plugin's JS loads before jQuery and plugin may not work. If you want to make sure some script loads first, you can try this:
in your app/View/Helper/AppHelper.php:
class AppHelper extends Helper {
public $helpers = array('Html', 'Session');
public function beforeRender($viewFile){
echo $this->Html->script('jquery', array('inline'=>false));
}
}
Therefore you don't have to include jQuery in multiple views and it loads first.
$scripts_for_layout in a layout is a placeholder for all the scripts included in views, so if you include it or don't won't have any effect if you load scripts directly in the default.ctp.
That being said, adding the extension or leaving it out of the $this->Html->script() call shouldn't make a difference. What could be the case is that the HtmlHelper isn't called correctly (it's called by default in Cake 2.0), but you should be receiving error messages. Is debug set to 2 in /app/Config/core.php?

How to reduce form code duplication in CakePHP

I have a form in CakePHP with a few dozen fields in it. From all the examples I have seen, there is duplicate form code for an add view and an edit view.
Is there any tricks to keep the duplication out? What is best method in CakePHP for this?
What I do, is to put all form fields in an element, and then insert the element in the add.ctp and edit.ctp
Don't forget to add the hidden field with the id in the edit.ctp
This way all visible elements are in one file, easier to maintain.
View/MyModel/add.ctp
echo $this->Form->create('MyModel');
echo $this->element('my_form');
echo $this->Form->end();
View/MyModel/edit.ctp
echo $this->Form->create('MyModel');
echo $this->Form->input('id');
echo $this->element('my_form');
echo $this->Form->end();
View/Elements/my_form.ctp
// your form inputs
// whatever they are
You should NOT merge those views, because add/edit are different actions and deserve separate view files. As your application grows you will realize that its good to have separate views to reduce complexity of if else conditions.
If you still want to avoid the separate files, Use
function add() {
.....
$this->render('edit')
}
I've done this before, but reverted back to having separate views, mainly for my own sanity.
It's easy enough to do. The edit requires an input for the record id. This is usually hidden. Any default form values for the add form will have to be contained in conditionals so that the stored values are not overwritten with defaults when you are editing a record
On the controller side of things, you'll need a conditional statement to decide whether to act as an add or edit depending on whether the $this->data['MyModel']['id'] is set.
I think that covers it - if I think of anything else I'll add it in.
My work pattern tends to be to build the edit view, then copy and paste to create the basis for the add view.
this code will check if you have admin_form.ctp or form.ctp which will make it use the same code for add / edit
https://github.com/infinitas/infinitas/blob/dev/app_controller.php#L389
1.3 submits the forms automatically to where the are from so when you go to /edit/1 it will post to there, and /add will post to add.
that is all you need to do. if you have a edit that is vastly different to the add, then you just create the 2 files. when you want them the same, just make the one.
in your app controller
public function render($view = null, $layout = null) {
$viewPaths = App::path('View', $this->plugin);
$rootPath = $viewPaths[0] . DS . $this->viewPath . DS;
$requested = $rootPath . $view . '.ctp';
if (in_array($this->request->action, array('admin_edit', 'admin_add', 'edit', 'add'))) {
$viewPath = $rootPath . $this->request->action . '.ctp';
if (!file_exists($requested) && !file_exists($viewPath)) {
if (strpos($this->request->action, 'admin_') === false) {
$view = 'form';
} else {
$view = 'admin_form';
}
}
}
return parent::render($view, $layout);
}
and in your view you can always check whether its edit or add
if ($this->request->params['action'] == 'admin_edit') {
//do something
}
if ($this->request->params['action'] == 'admin_add') {
//do something
}
in edit.ctp
if($this->data[ModelName]['id']) {
$this->Form->input('id');
}
// create rest of the fields
in Controller::add()
$this->autoRender=false; // at the start of function
$this->render('edit.ctp'); // at the point where you actually want to render
no need to create add.ctp

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