virtuemart3 shows 2 images with mouse hover - joomla3.0

I need to show 2 images per products in categories menu. Please refer
this link for more clarification.
To do this ,I have used below code in sublayouts folder and products.php files:
<div class="img-wrapper">
<?php
$image = $product->images[0]->displayMediaThumb('class="browseProductImage featuredProductImageFirst" id="Img_to_Js_'.$product->virtuemart_product_id.'" border="0"',false) ;
if(!empty($product->images[1])){
$image2 = $product->images[1]->displayMediaThumb('class="browseProductImage featuredProductImageSecond" border="0"',false) ;
} else {$image2= $product->images[0]->displayMediaThumb('class="browseProductImage featuredProductImageSecond" border="0"',false) ;}
echo JHTML::_('link', JRoute::_('index.php?option=com_virtuemart&view=productdetails&virtuemart_product_id='.$product->virtuemart_product_id.'&virtuemart_category_id='.$product->virtuemart_category_id),'<div class="front">'.$image.'</div><div class="back">'.$image2.'</div>');
?>
</div>
but didn't work out.It shows only one image
live demo: http://new.decoricor.com/decoricor-jewelery/hair-style

There is a hidden configuration to show more than one picture in the category view.
You can set values here:
/administrator/components/com_virtuemart/virtuemart.cfg
prodimg_browse needs to be set to 2. prodimg_browse=2
This is called in the view.html.php of the category view.
After that, two pictures will be in your array.
Documentation for the hidden configuration:
http://docs.virtuemart.net/manual/general-concepts/206-hidden-configurations.html

Related

how can I load a joomla module as a link?

this is my problem...
I have some of images and links that I want to load different joomla modules when user click on them.
mean each hyperlink can load another module|position
thanks all
In case that you just want to call a module's content from a url the following answer will help you.
If you just want to show / hide a module in the same page you could use something similar to my previous answer: Joomla 3 Show different modules on same position depending on toggler
Joomla provides the functionality to call a specific file of the active template by adding the tmpl=FILENAME key/value to the url's query string.
All built-in templates have a component.php file if user wants to load the template with the component only. You could check the following link for more details: Adding print pop-up functionality to a component.
You could do something similar to only show the modules that you want to load.
You could copy the component.php to a new file (I have used custom.php) and added the following php code in the <body> ... </body> part.
<?php
$jinput = JFactory::getApplication()->input;
$selectedPosition = $jinput->getString("position", "");
$selectedModule = $jinput->getString("module", "");
$selectedModuleTitle = $jinput->getString("title");
if($selectedPosition !== "") {
$modules = JModuleHelper::getModules($selectedPosition);
foreach ($modules as $module) {
echo JModuleHelper::renderModule($module);
}
} elseif ($selectedModule !== "") {
$module = JModuleHelper::getModule($selectedModule, $selectedModuleTitle);
echo JModuleHelper::renderModule($module);
}
?>
So with a similar way as loadposition / loadmodule works you could call the new template file using:
index.php?tmpl=custom&position=MODULE_POSITION
or
index.php?tmpl=custom&module=MODULE_TYPE
or
index.php?tmpl=custom&module=MODULE_TYPE&title=MODULE_TITLE
Optionally if you want to load the module with a specific style, you could pass it to the second paramter of the renderModule method like:
echo JModuleHelper::renderModule($module, array("style" => "xhtml"));
Hope this helps

How to reuse Loop ? get_template_part() or?

I want to use the same Loop and Pagination for
index.php , search.php , and archive.php
However, for search.php I want a title "Search Results" to appear before the Loop
and for archive.php I want a title "Archive Page" to appear before the Loop.
Method A
Keep index.php, search.php, and archive.php
And use get_template_part() for navigation and Loop ?
Method B
Just use index.php
but how?
Or is there a simpler method since all I want is to add a title before the Loop?
Simple code for the sake of this example:
index.php
<?php
if ( have_posts() ) : while ( have_posts() ) : the_post();
the_excerpt();
endwhile; endif;
?>
code for Pagination
search.php
<h2>Search Results</h2>
code for The Loop
code for Pagination
archive.php
<h2>Archive Page</h2>
code for The Loop
code for Pagination
I don't know the exact structure of your pages, but I would place the code in header.php. Here is my thought on this
The header is common to all of these templates, and I would suspect that you are going to need these titles between your header stuff and the content area
Target pages with conditional tags . Open your header, and right down at the bottom, add something like this
if(is_search()) {
//your title for search page etc
} elseif(is_archive()) {
//your title for archive page
} else {
//display nothing if you don't need to display any custom title
}
Just add the necessary mark up and style accordingly
EDIT
It seems that you are still very new to php. From your comment
Weird. I put <?php if(is_search()) { <h2>Search Results</h2> } ?> at very bottom of header.php but got White Screen. So instead, I put it in index.php and deleted search.php but still White Screen. I tested it in my theme and Twentytwelve. ---------- Can you help me understand... Does less php files equal to a faster website? Is reducing the amount of php files considered best practice? So if index.php , search.php , archive.php uses the same code except for a title "Search Results" and "Archive Page" - is it best practice to simply have one php file and do conditional statements for titles?
Your problem is switching between php and html elements. Whenever you switch from php to html, you need to close your php tag (?>)before your html element. On the otherhand, you need to open a new php tag (<?php) right after your last html element and before your first php element.
Not doing this correctly will lead to a synatx error, which causes a white screen of death.
So in short, your code will need to look like this for it to work properly. Note the php tags
<?php
if(is_search()) { // this part is php
?> <!-- Close php because whe're switching to html -->
<h2>Search Results</h2> <!-- this part is html -->
<?php // open new php tag as we're switching to php again
} elseif(is_archive()) { //same sequence above applied
?>
<h2>Archive Page</h2>
<?php
} else {
//display nothing if you don't need to display any custom title
}
?>
Less php files does not mean a faster website, speed is determined by content, content type, database queries, amount of queries, etc etc. A one page website can be slower than a 10 page website.
What I've done with this code and why I placed it in the header is just to keep the code together. You can split it up as you wish. There is no best practice. What really counts is readability, accesibility, not repeating code over and over, and keeping a proper file system
You could output the title before you start the loop. The contents of the loop would be called using get_template_part(). For example:
if ( have_posts() ) {
// Output the title.
the_title();
// Begin loop.
while ( have_posts() ) {
the_post();
get_template_part( 'loop', 'index' );
}
}
Update: Using just index.php to display a title conditionally, you would do this:
if ( is_search() ) {
// Display the search page title here.
} else if ( is_category() ) {
// Display the category title here.
}
Ref: http://codex.wordpress.org/Function_Reference/get_template_part

can't get image name in cakephp edit.ctp file

$image_name = $this->data['ApkCollection']['apk_image']['name'];
echo $image_name; // it show result as number like 7 or 3 etc...
when am upload image in edit.ctp file means it show image name as above result, but it works fine on add.ctp file
Someone help me...
Is your code from the controller or view (edit.ctp)? If you're inspecting the posted data in the controller, what does this show?
pr($this->request->data['ApkCollection']['apk_image'])
If it's in the view, wouldn't it just be this?
$image_name = $this->data['ApkCollection']['apk_image'];
echo $image_name;
The file details array (that 'name' is part of) only exists as the result of a post, I think.
Toby

Getting current page in CakePHP pagination

On one of my webpage, I show a list of customer details with default pagination [Paginator helper]. Each customer row has a corresponding 'edit' button which when clicked shows a DIV populated with that customer information. [This DIV has textboxes etc. where I can change customer info] After re-entering/modifying customer details, when I click on "Save" button, 2 ajax calls are made..
First one to save the edited record
The second one Updates the customer Listing on the same page with modified information
My problem : If I am on page 3 and edit one customer record, the 2nd ajax call refreshes the list but does not go to the page 3. It starts from page 1.
Please help.
You can get your current page here:
<?php echo $this->Paginator->counter(array(
'format' => ('{:page}')
)); ?>
This is part of the solution. :)
You can get your current page here:
$this->request->params['named']['page']
Did you try to use the link from Paginator? It maintains the page # to the controller.
Something like
// same parameters as $this->Html->link
<?php echo $this->Paginator->link( ... ) ?>
Check also the reference documentation for the Paginator Helper
I use jquery / javascript to store the page on a cookie and then read it from the controller.
// -------------------------------------------------------------------------
// on action click remember current page
$('td.actions').click( function( event )
{
var page = $('li.active a').html();
var name = window.location.href.split('-').join('_').split('/').pop();
$.cookie.raw = true;
$.cookie( 'CakeCookie[' + name + '_page]', page, { expires: 365, path: '/' } );
});

Styling/Theming Drupal 7 Content Type Record

I developed a Content type of "Car Sales" with following fields:
Manufacturer
Model
Make
Fuel Type
Transmission (Manual/Automatic)
Color
Registered? (Yes/No)
Mileage
Engine Power
Condition (New/Reconditioned/Used)
Price
Pictures (Multiple uploads)
I have developed View of this Content Type to display list of cars. Now I want to develop a screen/view for individual Car Sale Record like this:
Apart from arranging fields, please note that I want to embed a Picture Gallery in between. Can this be achieved through Drupal 7 Admin UI or do I need to create custom CSS and template files? If I need to edit certain template files/css, what are those? I'm using Zen Sub Theme.
I would accomplish this by creating a page, and then creating a node template to accompany it. Start by creating a new node, and then record the NID for the name of the template.
Then, in your template, create a new file, and name it in the following manner: node--[node id].tpl.php
Then, in that file, paste in the following helper function (or you can put it in template.php if you're going to use it elsewhere in your site):
/**
* Gets the resulting output of a view as an array of rows,
* each containing the rendered fields of the view
*/
function views_get_rendered_fields($name, $display_id = NULL) {
$args = func_get_args();
array_shift($args); // remove $name
if (count($args)) {
array_shift($args); // remove $display_id
}
$view = views_get_view($name);
if (is_object($view)) {
if (is_array($args)) {
$view->set_arguments($args);
}
if (is_string($display_id)) {
$view->set_display($display_id);
}
else {
$view->init_display();
}
$view->pre_execute();
$view->execute();
$view->render();
//dd($view->style_plugin);
return $view->style_plugin->rendered_fields;
} else {
return array();
}
}
Then add the following code to your template:
<?php
$cars = views_get_rendered_fields('view name', 'default', [...any arguments to be passed to the view]);
foreach ($cars as $car): ?>
<div>Put your mockup in here. It might be helpful to run <?php die('<pre>'.print_r($car, 1).'</pre>'); ?> to see what the $car array looks like.</div>
<?php endforeach;
?>
Just change the placeholders in the code to whatever you want the markup to be, and you should be set!
As I mentioned above, it's always helpful to do <?php die('<pre>'.print_r($car,1).'</pre>'); ?> to have a visual representation of what the array looks like printed.
I use views_get_rendered_fields all the time in my code because it allows me to completely customize the output of the view.
As a Reminder: Always clear your caches every time you create a new template.
Best of luck!

Resources