Making a delay in C with 20MHz crystal(beginner level) - c

I've recently started with C and Im trying to figure out how to make a 10ms delay for
PIC16F884. From the formulas in the datasheet I've managed to create the following:
fosc = 20MHz and Toscx4 = 200ns
If I put a preset to 100 => t=100x200ns=20us and to get a 10 ms delay
10ms/20us = 500
Will the following code in C give me what Im looking for (10ms delay)? Assume I have all the initiating code and variables.
void interrupt ISR(void){
if(TMR0IF){
TMR0IF=0;
counter++;
}
if(counter==100){
delay++;
counter=0;
}
}
int main(void){
TMR0=155;
if(delay>4){
//any code
delay=0;
}
}
Might be a bad example but hopefully you understand

No, since the code in main() never actually waits, it won't implement a delay.
Assuming the interrupt and timer logic is properly set up, you're still going to need to loop:
delay = 0;
TMR0 = 155; /* Start timer. */
while(delay < 4)
; /* Do nothing */
/* More code here, delay has expired */
Also, remember to make delay a volatile variable since you're accessing it from multiple parallel threads of execution.

If you're a really beginner and want a tool that can help you calculate timer settings I advise you to look at this link :
http://www.mikroe.com/timer-calculator/
It generate the ccode for settiing properly a lot of different microcontroller

Related

Duration for Sound on the 8051

I am trying to create a short tune using timers on the 8051. I am trying to send a square wave with a specified frequency to create the notes.
However, with my current code all I am getting is one infinite note, that never stops playing. Any help figuring out how to stop the note, and create a duration function would be greatly appreciated.
#include<reg932.h>
sbit speaker=P1^7;
void tone(unsigned char, unsigned char);
void main()
{
P1M1 = 0;
P1M2 = 0;
tone(0xC8, 0xF3);
}
void tone(unsigned char highval, unsigned char lowval)
{
TMOD=0x01;
TL0=lowval;
TH0=highval;
TR0=1;
while(TF0==0);
speaker=0;
TR0=0;
TF0=0;
}
I haven't programmed 8051's devices in a long time, but here's what I'd do:
1.a. figure out if it's tone() that never exits
1.b. if it is, I'd make sure that the while loop is indeed in there (see the disassembly of tone()), if it's not, the compiler optimizes the check out and it needs fixing (e.g. declaring TF0 as volatile)
1.c. see if the check is correct (the right bit in the right register, etc)
write an assembly routine to waste N CPU clocks, use the slowest instruction (was MUL or DIV the slowest?) in a loop or simply repeated M times so you get like a 10 ms delay or something, write a C function to call that routine as many times as necessary (e.g. 100 times for 1 second). (You could use a timer here, but this may be the simplest)

How to force interrupt to restart main loop instead of resuming? (timing issue!)

For the last two days i wrote a program that in basic terms generates a fairly accurate user adjustable pulse signal (both frequency and duty cycle adjustable). It basically uses the micros() function to keep track of time in order to pull low or high the 4 digital output channels.
These 4 channels need to have a phase difference of 90 degrees (think a 4cyl engine) always. In order for the user to change settings an ISR is implemented which returns a flag to the main loop to re-initialise the program. This flag is defined as a boolean 'set4'. When it is false a 'while' statement in the main loop will run the outputs. When it is true an 'if' statement will perform the necessary recalculations and reset the flag so that the 'while' statement will resume.
The program works perfectly with the initial values. Phase is perfect. However when the ISR is called and comes back to the main loop, from how i understand it resumes the program in the 'while' statement from where was originally interrupted, until it finishes and re-checks the flag 'set4' to see it is now true and it should stop.
Then, even though the 'if' statement afterwards resets and re-calculates all the necessary variables the phase between these 4 output channels is lost. Tested manually i see depending on which time the ISR is called it will give different results, usually having all 4 output channels synchronised together!
This happens even though i might don't change any values (thus the 'if' routine resets the variables to exactly the same ones when you first power up the arduino!). However, if i comment out this routine and just leave the line which resets the flag 'set4' the program will continue normally like nothing never happened!
I'm pretty sure that this is somehow caused because of the micros() timer because the loop will be resumed from where the ISR was called. I've tried to do it differently by checking and disabling for interrupts using cli() and sei() but i couldn't get it to work because it will just freeze when the arguments for cli() are true. The only solution that i can think of (i've tried everything, spend the whole day searching and trying out stuff) is to force the ISR to resume from the start of the loop so that the program may initialize properly. Another solution that comes to mind is to maybe reset the micros() timer somehow..but this would mess up the ISR i believe.
To help you visualise what is going on here's a snip of my code (please don't mind the 'Millis" name in the micros variables and any missing curly brackets since it is not pure copy-paste :p):
void loop()
{
while(!set4)
{
currentMillis = micros();
currentMillis2 = micros();
currentMillis3 = micros();
currentMillis4 = micros();
if(currentMillis - previousMillis >= interval) {
// save the last time you blinked the LED
previousMillis = currentMillis;
// if the LED is off turn it on and vice-versa:
if (ledState == LOW)
{
interval = ONTIME;
ledState = HIGH;
}
else
{
interval = OFFTIME;
ledState = LOW;
}
// set the LED with the ledState of the variable:
digitalWrite(ledPin, ledState);
}
.
.
//similar code for the other 3 output channels
.
.
}
if (set4){
//recalculation routine - exactly the same as when declaring the variables initially
currentMillis = 0;
currentMillis2 = 0;
currentMillis3 = 0;
currentMillis4 = 0;
//Output states of the output channels, forced low seperately when the ISR is called (without messing with the 'ledState' variables)
ledState = LOW;
ledState2 = LOW;
ledState3 = LOW;
ledState4 = LOW;
previousMillis = 0;
previousMillis2 = 0;
previousMillis3 = 0;
previousMillis4 = 0;
//ONTIME is the HIGH time interval of the pulse wave (i.e. dwell time), OFFTIME is the LOW time interval
//Note the calculated phase/timing offset at each channel
interval = ONTIME+OFFTIME;
interval2 = interval+interval/4;
interval3 = interval+interval/2;
interval4 = interval+interval*3/4;
set4=false;
}
}
Any idea what is going wrong?
Kind regards,
Ken
The problem is here:
previousMillis = 0;
previousMillis2 = 0;
previousMillis3 = 0;
previousMillis4 = 0;
All if statement will be true on the next loop.
Try with:
previousMillis = micros();
previousMillis2 = micros();
previousMillis3 = micros();
previousMillis4 = micros();

Arduino interupt a delay function

in my next project i use 4 Leds with delay(10000). I need a function for cancel this loop and start again with a new delay value e.g. 100.
I have enabled interrupts and when i pressed a button, delay changed to 100 AFTER a round. I have to wait 10 seconds.. It is possible to restart the loop function with the new values?
Wow that was rude ignacio
At least be helpful.
You can do this but not as you have implemented.
Delay is not good to be used in this circumstance. A much better way of implementing is to use a while loop like this:
int delayLED = 10000;
int beginMillis = millis();
while( millis() - beginMillis < delayLED)
{
// insert the code for your "interrupt" here
// kinda like this
if(button pressed)
{
delayLED = 100;
break;
}
}
This is just a template not a complete answer.
Let me know if you have further questions.
Happy coding!

Assign delays for 1 ms or 2 ms in C?

I'm using code to configure a simple robot. I'm using WinAVR, and the code used there is similar to C, but without stdio.h libraries and such, so code for simple stuff should be entered manually (for example, converting decimal numbers to hexadecimal numbers is a multiple-step procedure involving ASCII character manipulation).
Example of code used is (just to show you what I'm talking about :) )
.
.
.
DDRA = 0x00;
A = adc(0); // Right-hand sensor
u = A>>4;
l = A&0x0F;
TransmitByte(h[u]);
TransmitByte(h[l]);
TransmitByte(' ');
.
.
.
For some circumstances, I must use WinAVR and cannot external libraries (such as stdio.h). ANYWAY, I want to apply a signal with pulse width of 1 ms or 2 ms via a servo motor. I know what port to set and such; all I need to do is apply a delay to keep that port set before clearing it.
Now I know how to set delays, we should create empty for loops such as:
int value= **??**
for(i = 0; i<value; i++)
;
What value am I supposed to put in "value" for a 1 ms loop ?
Chances are you'll have to calculate a reasonable value, then look at the signal that's generated (e.g., with an oscilloscope) and adjust your value until you hit the right time range. Given that you apparently have a 2:1 margin, you might hit it reasonably close the first time, but I wouldn't be much on it.
For your first approximation, generate an empty loop and count the instruction cycles for one loop, and multiply that by the time for one clock cycle. That should give at least a reasonable approximation of time taken by a single execution of the loop, so dividing the time you need by that should get you into the ballpark for the right number of iterations.
Edit: I should also note, however, that (at least most) AVRs have on-board timers, so you might be able to use them instead. This can 1) let you do other processing and/or 2) reduce power consumption for the duration.
If you do use delay loops, you might want to use AVR-libc's delay loop utilities to handle the details.
If my program is simple enough there is not a need of explicit timer programming, but it should be portable. One of my choices for a defined delay would be AVR Libc's delay function:
#include <delay.h>
_delay_ms (2) // Sleeps 2 ms
Is this going to go to a real robot? All you have is a CPU, no other integrated circuits that can give a measure of time?
If both answers are 'yes', well... if you know the exact timing for the operations, you can use the loop to create precise delays. Output your code to assembly code, and see the exact sequence of instructions used. Then, check the manual of the processor, it'll have that information.
If you need a more precise time value you should employ an interrupt service routine based on an internal timer. Remember a For loop is a blocking instruction, so while it is iterating the rest of your program is blocked. You could set up a timer based ISR with a global variable that counts up by 1 every time the ISR runs. You could then use that variable in an "if statement" to set the width time. Also that core probably supports PWM for use with the RC type servos. So that may be a better route.
This is a really neat little tasker that I use sometimes. It's for an AVR.
************************Header File***********************************
// Scheduler data structure for storing task data
typedef struct
{
// Pointer to task
void (* pTask)(void);
// Initial delay in ticks
unsigned int Delay;
// Periodic interval in ticks
unsigned int Period;
// Runme flag (indicating when the task is due to run)
unsigned char RunMe;
} sTask;
// Function prototypes
//-------------------------------------------------------------------
void SCH_Init_T1(void);
void SCH_Start(void);
// Core scheduler functions
void SCH_Dispatch_Tasks(void);
unsigned char SCH_Add_Task(void (*)(void), const unsigned int, const unsigned int);
unsigned char SCH_Delete_Task(const unsigned char);
// Maximum number of tasks
// MUST BE ADJUSTED FOR EACH NEW PROJECT
#define SCH_MAX_TASKS (1)
************************Header File***********************************
************************C File***********************************
#include "SCH_AVR.h"
#include <avr/io.h>
#include <avr/interrupt.h>
// The array of tasks
sTask SCH_tasks_G[SCH_MAX_TASKS];
/*------------------------------------------------------------------*-
SCH_Dispatch_Tasks()
This is the 'dispatcher' function. When a task (function)
is due to run, SCH_Dispatch_Tasks() will run it.
This function must be called (repeatedly) from the main loop.
-*------------------------------------------------------------------*/
void SCH_Dispatch_Tasks(void)
{
unsigned char Index;
// Dispatches (runs) the next task (if one is ready)
for(Index = 0; Index < SCH_MAX_TASKS; Index++)
{
if((SCH_tasks_G[Index].RunMe > 0) && (SCH_tasks_G[Index].pTask != 0))
{
(*SCH_tasks_G[Index].pTask)(); // Run the task
SCH_tasks_G[Index].RunMe -= 1; // Reset / reduce RunMe flag
// Periodic tasks will automatically run again
// - if this is a 'one shot' task, remove it from the array
if(SCH_tasks_G[Index].Period == 0)
{
SCH_Delete_Task(Index);
}
}
}
}
/*------------------------------------------------------------------*-
SCH_Add_Task()
Causes a task (function) to be executed at regular intervals
or after a user-defined delay
pFunction - The name of the function which is to be scheduled.
NOTE: All scheduled functions must be 'void, void' -
that is, they must take no parameters, and have
a void return type.
DELAY - The interval (TICKS) before the task is first executed
PERIOD - If 'PERIOD' is 0, the function is only called once,
at the time determined by 'DELAY'. If PERIOD is non-zero,
then the function is called repeatedly at an interval
determined by the value of PERIOD (see below for examples
which should help clarify this).
RETURN VALUE:
Returns the position in the task array at which the task has been
added. If the return value is SCH_MAX_TASKS then the task could
not be added to the array (there was insufficient space). If the
return value is < SCH_MAX_TASKS, then the task was added
successfully.
Note: this return value may be required, if a task is
to be subsequently deleted - see SCH_Delete_Task().
EXAMPLES:
Task_ID = SCH_Add_Task(Do_X,1000,0);
Causes the function Do_X() to be executed once after 1000 sch ticks.
Task_ID = SCH_Add_Task(Do_X,0,1000);
Causes the function Do_X() to be executed regularly, every 1000 sch ticks.
Task_ID = SCH_Add_Task(Do_X,300,1000);
Causes the function Do_X() to be executed regularly, every 1000 ticks.
Task will be first executed at T = 300 ticks, then 1300, 2300, etc.
-*------------------------------------------------------------------*/
unsigned char SCH_Add_Task(void (*pFunction)(), const unsigned int DELAY, const unsigned int PERIOD)
{
unsigned char Index = 0;
// First find a gap in the array (if there is one)
while((SCH_tasks_G[Index].pTask != 0) && (Index < SCH_MAX_TASKS))
{
Index++;
}
// Have we reached the end of the list?
if(Index == SCH_MAX_TASKS)
{
// Task list is full, return an error code
return SCH_MAX_TASKS;
}
// If we're here, there is a space in the task array
SCH_tasks_G[Index].pTask = pFunction;
SCH_tasks_G[Index].Delay =DELAY;
SCH_tasks_G[Index].Period = PERIOD;
SCH_tasks_G[Index].RunMe = 0;
// return position of task (to allow later deletion)
return Index;
}
/*------------------------------------------------------------------*-
SCH_Delete_Task()
Removes a task from the scheduler. Note that this does
*not* delete the associated function from memory:
it simply means that it is no longer called by the scheduler.
TASK_INDEX - The task index. Provided by SCH_Add_Task().
RETURN VALUE: RETURN_ERROR or RETURN_NORMAL
-*------------------------------------------------------------------*/
unsigned char SCH_Delete_Task(const unsigned char TASK_INDEX)
{
// Return_code can be used for error reporting, NOT USED HERE THOUGH!
unsigned char Return_code = 0;
SCH_tasks_G[TASK_INDEX].pTask = 0;
SCH_tasks_G[TASK_INDEX].Delay = 0;
SCH_tasks_G[TASK_INDEX].Period = 0;
SCH_tasks_G[TASK_INDEX].RunMe = 0;
return Return_code;
}
/*------------------------------------------------------------------*-
SCH_Init_T1()
Scheduler initialisation function. Prepares scheduler
data structures and sets up timer interrupts at required rate.
You must call this function before using the scheduler.
-*------------------------------------------------------------------*/
void SCH_Init_T1(void)
{
unsigned char i;
for(i = 0; i < SCH_MAX_TASKS; i++)
{
SCH_Delete_Task(i);
}
// Set up Timer 1
// Values for 1ms and 10ms ticks are provided for various crystals
OCR1A = 15000; // 10ms tick, Crystal 12 MHz
//OCR1A = 20000; // 10ms tick, Crystal 16 MHz
//OCR1A = 12500; // 10ms tick, Crystal 10 MHz
//OCR1A = 10000; // 10ms tick, Crystal 8 MHz
//OCR1A = 2000; // 1ms tick, Crystal 16 MHz
//OCR1A = 1500; // 1ms tick, Crystal 12 MHz
//OCR1A = 1250; // 1ms tick, Crystal 10 MHz
//OCR1A = 1000; // 1ms tick, Crystal 8 MHz
TCCR1B = (1 << CS11) | (1 << WGM12); // Timer clock = system clock/8
TIMSK |= 1 << OCIE1A; //Timer 1 Output Compare A Match Interrupt Enable
}
/*------------------------------------------------------------------*-
SCH_Start()
Starts the scheduler, by enabling interrupts.
NOTE: Usually called after all regular tasks are added,
to keep the tasks synchronised.
NOTE: ONLY THE SCHEDULER INTERRUPT SHOULD BE ENABLED!!!
-*------------------------------------------------------------------*/
void SCH_Start(void)
{
sei();
}
/*------------------------------------------------------------------*-
SCH_Update
This is the scheduler ISR. It is called at a rate
determined by the timer settings in SCH_Init_T1().
-*------------------------------------------------------------------*/
ISR(TIMER1_COMPA_vect)
{
unsigned char Index;
for(Index = 0; Index < SCH_MAX_TASKS; Index++)
{
// Check if there is a task at this location
if(SCH_tasks_G[Index].pTask)
{
if(SCH_tasks_G[Index].Delay == 0)
{
// The task is due to run, Inc. the 'RunMe' flag
SCH_tasks_G[Index].RunMe += 1;
if(SCH_tasks_G[Index].Period)
{
// Schedule periodic tasks to run again
SCH_tasks_G[Index].Delay = SCH_tasks_G[Index].Period;
SCH_tasks_G[Index].Delay -= 1;
}
}
else
{
// Not yet ready to run: just decrement the delay
SCH_tasks_G[Index].Delay -= 1;
}
}
}
}
// ------------------------------------------------------------------
************************C File***********************************
Most ATmega AVR chips, which are commonly used to make simple robots, have a feature known as pulse-width modulation (PWM) that can be used to control servos. This blog post might serve as a quick introduction to controlling servos using PWM. If you were to look at the Arduino platform's servo control library, you would find that it also uses PWM.
This might be a better choice than relying on running a loop a constant number of times as changes to compiler optimization flags and the chip's clock speed could potentially break such a simple delay function.
You should almost certainly have an interrupt configured to run code at a predictable interval. If you look in the example programs supplied with your CPU, you'll probably find an example of such.
Typically, one will use a word/longword of memory to hold a timer, which will be incremented each interrupt. If your timer interrupt runs 10,000 times/second and increments "interrupt_counter" by one each time, a 'wait 1 ms' routine could look like:
extern volatile unsigned long interrupt_counter;
unsigned long temp_value = interrupt_counter;
do {} while(10 > (interrupt_counter - temp_value));
/* Would reverse operands above and use less-than if this weren't HTML. */
Note that as written the code will wait between 900 µs and 1000 µs. If one changed the comparison to greater-or-equal, it would wait between 1000 and 1100. If one needs to do something five times at 1 ms intervals, waiting some arbitrary time up to 1 ms for the first time, one could write the code as:
extern volatile unsigned long interrupt_counter;
unsigned long temp_value = interrupt_counter;
for (int i=0; 5>i; i++)
{
do {} while(!((temp_value - interrupt_counter) & 0x80000000)); /* Wait for underflow */
temp_value += 10;
do_action_thing();
}
This should run the do_something()'s at precise intervals even if they take several hundred microseconds to complete. If they sometimes take over 1 ms, the system will try to run each one at the "proper" time (so if one call takes 1.3 ms and the next one finishes instantly, the following one will happen 700 µs later).

Using hardware timer in C

Okay, so I've got some C code to perform a mathematical operation which could, pretty much, take any length of time (depending on the operands supplied to it, of course). I was wondering if there is a way to register some kind of method which will be called every n seconds which can analyse the state of the operation, i.e. what iteration it is currently at, possibly using a hardware timer interrupt or something?
The reason I ask this is because I know the common way to implement this is to be keeping track of the current iteration in a variable; say, an integer called progress and have an IF statement like this in the code:
if ((progress % 10000) == 0)
printf("Currently at iteration %d\n", progress);
but I believe that a mod operation takes a relatively long time to execute, so the idea of having it inside a loop which will be ran many, many times scares me, from an optimisation point of view.
So I get the feeling that having an external way of signalling a progress print is nice and efficient. Are there any great ways to perform this, or is the simple 'mod check' the best (in terms of optimising)?
I'd go with the mod check, but maybe with subtractions instead :-)
icount = 0;
progress = 10000;
/* ... */
if (--progress == 0) {
progress = 10000;
printf("Currently at iteration %d0000\n", ++icount);
}
/* ... */
While mod operations are usually slow, the compiler should be able to optimize and predict this really well and only mis-predict once ever 10'000 ifs, burning one mod operation and ~20 cycles (for the mis-prediction) on it, which is fine. So you are trying to optimize one mod operation every 10'000 iterations. Of course this assumes you are running it on a modern and typical CPU, and not some embedded system with unknown specs. This should even be faster than having a counter variable.
Suggestion: Test it with and without the timing code, and figure out a complex solution if there is really a problem.
Premature optimisation is the root of all evil. -Knuth
mod is about the same speed as division, on most CPU's these days that means about 5-10 cycles... in other words hardly anything, slower than multiply/add/subtract, but not enough to really worry about.
However you are right to want to avoid sting in a loop spinning if you're doing work in another thread or something like that, if you're on a unixish system there's timer_create() or on linux the much easier to use timerfd_create()
But for single threaded, just putting that if in is enough.
Use alarm setitimer to raise SIGALRM signals at regular intervals.
struct itimerval interval;
void handler( int x ) {
write( STDOUT_FILENO, ".", 1 ); /* Defined in POSIX, not in C */
}
int main() {
signal( SIGALRM, &handler );
interval.it_value.tv_sec = 5; /* display after 5 seconds */
interval.it_interval.tv_sec = 5; /* then display every 5 seconds */
setitimer( ITIMER_REAL, &interval, NULL );
/* do computations */
interval.it_interval.tv_sec = 0; /* don't display progress any more */
setitimer( ITIMER_REAL, &interval, NULL );
printf( "\n" ); /* done with the dots! */
}
Note, only a smattering of functions are OK to call inside handler. They are listed partway down this page. If you want to communicate anything for a fancier printout, do it through a sig_atomic_t variable.
you could have a global variable for the iterations, which you could monitor from an external thread.
While () {
Print(iteration);
Sleep(1000);
}
You may need to watch out for data races though.

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