Hi i have a code which select the particular select attribute value of a product
<?php $attribute_value = $_product->getAttributeText('highligted_features');
print_r($attribute_value);
?>
when i am using this in view file it works properly
but when i place this code in a different file and call that file in
static block
and
than when i call that block in file it gives 500 internal server error
.
when i
Check attribute is not available in used in Product list attribute setting .Thus you cannot getting in other pages,If you using catalog product flat then flat table is not include highligted_features attribute in it columns
Related
What is the syntax to reference a staged zip file from UDF? Specifically, I created UDF in Snowpark and it needs to load s-bert sentence_transformers pre-trained model (I downloaded the model, zipped it, and uploaded it to internal stage).
The "SentenceTransformer" method (see the code line below) takes a parameter that can either be the name of the model -- in which case, the pre-trained model will be downloaded form the web; or it can take a directory path to a folder that contains already downloaded pre-trained model files.
Downloading the files from the Web with UDF is not an option in Snowflake.
So, what is the directory path to the internally staged file that I can use as a parameter to the SentenceTransformer method so it can access already downloaded zip model? "#stagename/filename.zip" is not working.
#udf(....)
def create_embedding()..:
....
model = SentenceTransformer('all-MiniLM-L6-v2') #THIS IS THE LINE IN THE QUESTION
....
....
UDFs need to specify specific files when creating them (for now):
https://docs.snowflake.com/en/developer-guide/udf/python/udf-python-creating.html#loading-a-file-from-a-stage-into-a-python-udf
Check the example from the docs, which uses imports, snowflake_import_directory to open(import_dir + 'file.txt'):
create or replace function my_udf()
returns string
language python
runtime_version=3.8
imports=('#my_stage/file.txt')
handler='compute'
as
$$
import sys
IMPORT_DIRECTORY_NAME = "snowflake_import_directory"
import_dir = sys._xoptions[IMPORT_DIRECTORY_NAME]
def compute():
with open(import_dir + 'file.txt', 'r') as file:
return file.read()
$$;
code:
query = Order.update(is_review=1, review_time=review_time).where(Order.order_sn == order_sn)
query.execute()
exception:
cursor = database.execute(self)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python37\lib\site-packages\peewee.py", line 2952, in execute
sql, params = ctx.sql(query).query()
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python37\lib\site-packages\peewee.py", line 601, in sql
return obj.__sql__(self)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python37\lib\site-packages\peewee.py", line 2363, in __sql__
for k, v in sorted(self._update.items(), key=ctx.column_sort_key):
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python37\lib\site-packages\peewee.py", line 555, in column_sort_key
return item[0].get_sort_key(self)
AttributeError: 'UnknownField' object has no attribute 'get_sort_key'
environment：
peewee version:3.9.5
python:3.7
I notice that you have posted this as a GitHub issue on the Peewee issue tracker as well. I've responded to your ticket and will paste my response here for anyone else:
You are clearly using models generated using the pwiz tool. If pwiz cannot determine the right field type to use for a column, it uses a placeholder "UnknownField". You will need to edit your model definitions and replace the UnknownField with an appropriate field type (e.g. TextField, IntegerField, whatever) if you wish to be able to use it in queries.
Can any one suggest me how to write SQL query in .tpl file?
I tried to write db_query("select * from table_name "); But it is not working.
Please give me a solution to write sql query in tpl file
.tpl files are for the template layout and should not have much more logic than if a region has content. For anything requiring more logic I'd recommend either adding an applicable hook in your template.php or look into creating your own module.
What is the goal you are trying to achieve it may be solvable in another way instead of using a custom query. Likely you can create a view for your page?
Otherwise, try testing your query first through your database - if you have phpmyadmin or similar set up to see if it is actually returning a result.
And see https://api.drupal.org/api/drupal/includes!database!database.inc/function/db_query/7 for more information on how to use that particular function.
I have tried below code and getting the records
$result = db_query("SELECT * from node");
$records = $result->fetchAll();
print_r($records);
Can you check the tpl file is correct or not, OR can you share the code.
Better to write a function in your module and return the data from the query to the tpl file.
// function inside your module
function your_custom_function(){
$result = db_query("SELECT * from node");
$records = $result->fetchAll();
retun $records;
}
Then you can call this function from tpl file
// calling the function from tpl
$data = your_custom_function();
foreach($data as $value){
// do your template logic here
}
If in Yii 1.1.x there is some extension, to create valid file system(linux) name from object title with unique name, like a slug, but with unique name in given directory ?
I mean I want to save file on disk with name based on title of object.
Thanks!
Actually I would like a bit more :
1) In title of object all illigel chars(for Linux/windows OS) and space must be converted to '-'
2) if there is such file add valid counter for it , like "_45"
Maybe that not yii extension, but some php function.
The simplest way - you can add object id to prefix of file. Then your file names always be uniqueness. For example:
1-title-first
2-title-first
3-title-second
you can use php own uniqueid() to generate unique ids!
$title = uniqid('wp_'); // have wp_ prefixed for title
I've done a few searches here, and while some issues are similar, they don't seem to be exactly what I need.
What I'm trying to do is import an Excel file into a SQL table via SSIS, but the problem is that I will never know the exact filename. We get files at no steady interval, and the file usually has a date/month in the name. For instance, our current file is "Census Data - May 2013.xls". We will only ever load ONE file at a time, so I don't need to loop through a directory for multiple Excel files.
My concept is that I can take this file, copy it to a "Loading" directory, and load it from there. At the start of the package, I will first clear out the loading directory, then scan the original directory for an Excel file, copy it to the loading directory and then load it into SQL. I suppose I may have to store the file names somewhere so I don't copy the same file into the loading directory in subsequent months, but I'm not really sure of the best way to handle that.
I've pretty much got everything down except the part that scans the directory for the Excel file and copies it to the loading directory. I've taken the majority of my info from this page, which (again) is close to what I want to do but not quite exactly the solution I need.
Can anyone get me over the finish line? I can't seem to get the Excel Connection Manager right (this is my first time using variables), and I can't figure out how to get the file into the Loading directory.
Problem statement
How do I dynamically identify a file name?
You will require some mechanism to inspect the contents of a folder and see what exists. Specifically, you are looking for an Excel file in your "Loading" directory. You know the file extension and that is it.
Resolution A
Use a ForEach File Enumerator.
Configure the Enumerator with an Expression on FileSpec of *.xls or *.xlsx depending on which flavor of Excel you're dealing with.
Add another Expression on Directory to be your Loading directory.
I typically create SSIS Variables named FolderInput and FileMask and assign those in the Enumerator.
Now when you run your package, the Enumerator is going to look in Diretory and find all the files that match the FileSpec.
Something needs to be done with what is found. You need to use that file name that the Enumerator returns. That's done through the Variable Mappings tab. I created a third Variable called CurrentFileName and assign it the results of the enumerator.
If you put a Script Task inside the ForEach Enumerator, you should be able to see that the value in the "Locals" window for #[User::CurrentFileName] has updated from the Design time value of whatever to the "real" file name.
Resolution B
Use a Script Task.
You will still need to create a Variable to hold the current file name and it probably won't hurt to also have the FolderInput and FileMask Variables available. Set the former as ReadWrite and the latter as ReadOnly variables.
Chose the .NET language of your choice. I'm using C#. The method System.IO.Directory.EnumerateFiles
using System;
using System.Data;
using System.IO;
using Microsoft.SqlServer.Dts.Runtime;
using System.Windows.Forms;
namespace ST_fe2ea536a97842b1a760b271f190721e
{
[Microsoft.SqlServer.Dts.Tasks.ScriptTask.SSISScriptTaskEntryPointAttribute]
public partial class ScriptMain : Microsoft.SqlServer.Dts.Tasks.ScriptTask.VSTARTScriptObjectModelBase
{
public void Main()
{
string folderInput = Dts.Variables["User::FolderInput"].Value.ToString();
string fileMask = Dts.Variables["User::FileMask"].Value.ToString();
try
{
var files = Directory.EnumerateFiles(folderInput, fileMask, SearchOption.AllDirectories);
foreach (string currentFile in files)
{
Dts.Variables["User::CurrentFileName"].Value = currentFile;
break;
}
}
catch (Exception e)
{
Dts.Events.FireError(0, "Script overkill", e.ToString(), string.Empty, 0);
}
Dts.TaskResult = (int)ScriptResults.Success;
}
enum ScriptResults
{
Success = Microsoft.SqlServer.Dts.Runtime.DTSExecResult.Success,
Failure = Microsoft.SqlServer.Dts.Runtime.DTSExecResult.Failure
};
}
}
Decision tree
Given the two resolutions to the above problem, how do you chose? Normally, people say "It Depends" but there only possible time it would depend is if the process should stop/error out in the case that more than one file did exist in the Loading folder. That's a case that the ForEach enumerator would be more cumbersome than a script task. Otherwise, as I stated in my original response that adds cost to your project for Development, Testing and Maintenance for no appreciable gain.
Bits and bobs
Further addressing nuances in the question: Configuring Excel - you'll need to be more specific in what isn't working. Both Siva's SO answer and the linked blogspot article show how to use the value of the Variable I call CurrentFileName to ensure the Excel File is pointing to the "right" file.
You will need to set the DelayValidation to True for both the Connection Manager and the Data Flow as the design-time value for the Variable will not be valid when the package begins execution. See this answer for a longer explanation but again, Siva called that out in their SO answer.