Arranging the fields of a structure into order - arrays

I am trying find away of ordering a polynomial in the form a structure so that the exponent fields are in ascending order. I don't want to use a built in sort function to do this.
for example the polynomial:
p = struct('exponent',{2,3,2,9},'coeff',{1,2,91,40})
represents the polynomial:
p = 1(x^2) + 2(x^3) + 91(x^2)+ 40(x^9)
I want to rearrange it so that it becomes (the exponents are now in ascending order)
p = 1(x^2) + 91(x^2) + 2(x^3) + 40(x^9)
my code to do this is:
function [ output ] = myMergepoly2( p )
h=1;
output(1,length(p))=struct('exponent',{},'coeff',{});
while (h<length(p))
if p(1,h+1).exponent<p(1,h).exponent
output(1,h).exponent = p(1,h+1).exponent;
output(1,h).coeff = p(1,h+1).coeff;
h=h+1;
else
output(1,h).exponent = p(1,h).exponent;
output(1,h).coeff = p(1,h).coeff;
end
end
end
However when I try to run this function MATLAB remote has 'busy' written out with no error message. I am unsure what is causing this and how to fix it, any help would be appreciated.

In the else section of the loop, you don't increment h, so it goes like this:
h=1 --> if p(1,h+1).exponent<p(1,h).exponent is false --> skip to else loop and set output(1,1).exponent --> h=1 (while loop keeps going).
Using MATLAB inbuilt sort I'd just do something along the lines of:
exponent = [p.exponent];
coeff = [p.coeff];
[exponent idx] = sort(exponent);
output.exponent = exponent;
output.coeff = coeff(idx);

Replace this line :
output(1,length(p))=struct('exponent',{},'coeff',{});
With this line :
output = struct('exponent',cell(1,length(p)),'coeff',cell(1,length(p)));
Also put this instead:
while (h<length(p))
if p(1,h+1).exponent<p(1,h).exponent
output(1,h).exponent = p(1,h+1).exponent;
output(1,h).coeff = p(1,h+1).coeff;
else
output(1,h).exponent = p(1,h).exponent;
output(1,h).coeff = p(1,h).coeff;
end
h=h+1;
end
However I'm still not getting the right output, I'm working on it.

Related

Run parallel loops in Ruby

I have two sets of arrays stored in a file and I need to extract values one by one and compare them. I am using this code but does look like I am doing correctly.
# First Dataset
File.foreach(file_set_a) do |data_a|
data_array_a = data_a.split("\t")
#file_name_a = data_array_a[0]
#file_ext_a = data_array_a[1]
# Second Dataset
File.foreach(file_set_b) do |data_b|
data_array_b = data_b.split("\t")
#file_name_b = data_array_b[0]
#file_ext_b = data_array_b[1]
#Compare
#file_name_a == #file_name_b
end
end
The problem is, I cannot go back and extract the next values in the set A when I enter the set B. Any suggestions?
First, convert those 2 files into two separated data arrays
lines_array_a = File.readlines(file_set_a)
lines_array_b = File.readlines(file_set_b)
I am assuming both of the array size will be same. Now run a loop and get the items from both array to compare them.
for i in 0..(lines_array_a.count - 1) do
data_array_a = lines_array_a[i].split("\t")
#file_name_a = data_array_a[0]
#file_ext_a = data_array_a[1]
data_array_b = lines_array_b[i].split("\t")
#file_name_b = data_array_b[0]
#file_ext_b = data_array_b[1]
#file_name_a == #file_name_b
end

Change an array to an integer percentage value

I have a function that gives me a value in the form of an array as an output when run but I need the output as an integer percentage for a results piece
def pred_datsci(file_path):
prev_precompute = learn.precompute
learn.precompute = False
try:
trn_tfms, val_tfms = tfms_from_model(arch,sz)
test_img = open_image(file_path)
im = val_tfms(test_img)
pred = learn.predict_array(im[None])
class_index = (np.exp(pred))
class_index1 = np.argmax(np.exp(pred))
print(class_index*100)
return data.classes[class_index1]
finally:
learn.precompute = prev_precompute
This is what the output looks like:
pred_datsci(f"data/dogscats1/valid/dogs/12501.jpg")
My question is how do I get these two values to display as :
Cat % = 15.81724%
Dog % = 84.18274%
You can use zip function as:
for z in zip(['Cat', 'Dog'], [15.3, 84.6]):
print('%s %% = %s%%'%(z[0], z[1]))

How to use arrays created by loop? Matlab

The code I'm using imports data from multiple files and saves them into an array of cells, the code is as follows:
[FileName,PathName,FilterIndex] = uigetfile('*.txt*','MultiSelect','on');
numfiles = size(FileName,2);
FileData= cell(1,numfiles);
for ii = 1:numfiles
FileName{ii};
A=[];
entirefile =fullfile(PathName,FileName{ii});
fid = fopen(entirefile);
tline = fgets(fid);
while ischar(tline)
parts = textscan(tline, '%f;');
if numel(parts{1}) > 0
A = [ A ; parts{:}' ];
end
tline = fgets(fid);
end
fclose(fid);
FileData{ii} = A;
A = FileData{ii};
X = A(:,1);
Y = A(:,5);
DataToUse = [X,Y];
end
Now my issue is I want to use the first DataToUse created by the loop, which will be data from the first file, seperatley to the other files but I can not issolate it. I have tried DataToUse(1), DataToUse(1,1) and DataToUse(:,[1,2]) but none are working for me. An example of the type of data would be:
DataToUse=
0.0762 0.0271
0.0763 0.2671
0.0764 0.4079
0.0765 0.0510
0.0766 0.0087
0.0767 0.0099
0.0768 0.0067
0.0769 0.0047
0.0770 0.0047
0.0771 0.0349
0.0772 0.2094
0.0773 0.2740
0.0774 0.0294
0.0775 0.0100
0.0776 0.0159
I have different numbers of this kind of data depending on how many files are selected but I would like to only use the first initially and use the others later. Anybody know how I can go about doing this? Many thanks in advance
The solution is to use cell arrays, like so:
DataToUse{ii} = [X, Y]
To get the desired output put this after your for-loop:
firstLoopXY = DataToUse{1}
Enjoy!

Lua/LOVE indexing problems

I'm getting a very irritating error whenever I do anything like this with arrays. I have code that sets up the array in the love.load() function:
function iceToolsInit()
objectArray = {} --for object handling
objectArrayLocation = 0
end
and then code that allows for the creation of an object. It basically grabs all of the info about said object and plugs it into an array.
function createObject(x, y, renderimage) --used in the load function
--objectArray is set up in the init function
objectArrayLocation = objectArrayLocation + 1
objectArray[objectArrayLocation] = {}
objectArray[objectArrayLocation]["X"] = x
objectArray[objectArrayLocation]["Y"] = y
objectArray[objectArrayLocation]["renderimage"] =
love.graphics.newImage(renderimage)
end
After this, an update function reads through the objectArray and renders the images accordingly:
function refreshObjects() --made for the update function
arrayLength = #objectArray
arraySearch = 0
while arraySearch <= arrayLength do
arraySearch = arraySearch + 1
renderX = objectArray[arraySearch]["X"]
renderY = objectArray[arraySearch]["Y"]
renderimage = objectArray[arraySearch]["renderimage"]
if movingLeft == true then --rotation for rightfacing images
renderRotation = 120
else
renderRotation = 0
end
love.graphics.draw(renderimage, renderX, renderY, renderRotation)
end
end
I of course clipped some unneeded code (just extra parameters in the array such as width and height) but you get the gist. When I set up this code to make one object and render it, I get this error:
attempt to index '?' (a nil value)
the line it points to is this line:
renderX = objectArray[arraySearch]["X"]
Does anyone know what's wrong here, and how I could prevent it in the future? I really need help with this.
It's off-by-one error:
arraySearch = 0
while arraySearch <= arrayLength do
arraySearch = arraySearch + 1
You run through the loop arrayLength+1 number of times, going through indexes 1..arrayLength+1. You want to go through the loop only arrayLength number of times with indexes 1..arrayLength. The solution is to change the condition to arraySearch < arrayLength.
Another (more Lua-ly way) is to write this as:
for arraySearch = 1, #objectArray do
Even more Lua-ly way is to use ipairs and table.field reference instead of (table["field"]):
function refreshObjects()
for _, el in ipairs(objectArray) do
love.graphics.draw(el.renderimage, el.X, el.Y, movingLeft and 120 or 0)
end
end
objectArray and movingLeft should probably be passed as parameters...

Appending Int to an Array Matlab

I am using an API to get real data times of trains and am trying to get the closest train time to a user entered time and then display that train time, and the next 4 granted the trains are running. I am reading in the information and the code goes through what its supposed to do but when I look at the array its a bunch of [] brackets in 7 cells instead of the calculated numbers. Any suggestions? Code is below with the API
TEST VALUES:
requestStationSelected = 'University%20City' and requestEndStation = 'Roslyn'
%this is the API link for the live data from Septa this will get 30
%results and see which time is closer to the user entered time
requestInfoSeptaLive = ['http://www3.septa.org/hackathon/NextToArrive/' requestStationSelected '/' requestEndStation '/30'];
%Again tries to get the information and if there is a failure it will give
%a probable cause and terminate the program
try
getInfoSeptaLive = urlread(requestInfoSeptaLive);
catch
if getInfoSeptaLive ~= '[]'
disp...
('Either the arrival/depart stations dont quite match up or theres a server error. Try again.');
return;
else
disp('Unable to fetch the information from Septa, please try again')
return;
end
end
%parses the information returned from the Live API
dataReturnedFromLiveAPI = parse_json(getInfoSeptaLive);
dataReturnedFromLiveAPI = dataReturnedFromLiveAPI{1};
%gets the size of the API in case there are no trains running
sizeOfDataNoTrains = size(dataReturnedFromLiveAPI, 1);
sizeOfData = size(dataReturnedFromLiveAPI, 2);
counter = 0;
for i = 1:sizeOfData
scanForClosestTime = dataReturnedFromLiveAPI{1,i}.orig_departure_time;
trainTimeGivenH = sscanf(scanForClosestTime, '%i');
findColonTrain = strfind(scanForClosestTime, ':');
trainTimeGivenMStr = scanForClosestTime(findColonTrain+1:4);
trainTimeGivenM = int32(str2num(trainTimeGivenMStr));
trainDepartTimeM = (trainTimeGivenH(1,1) * 60) + (trainTimeGivenM);
differenceBetweenTimes = trainDepartTimeM - userEnteredMins;
if trainDepartTimeM < userEnteredMins
differenceBetweenTimes = userEnteredMins - trainDepartTimeM;
end
stopAtEndOfData = sizeOfData;
goodTimeFrame = 60;
closestTime = cell(1, stopAtEndOfData);
storeTheDifference = cell(1, stopAtEndOfData);
if(differenceBetweenTimes < 60)
if (counter < 5)
closestTime{i} = scanForClosestTime;
storeTheDifference{i} = differenceBetweenTimes;
counter = counter + 1;
end
end
end
You assign your cell arrays inside the for loop:
for i = 1:sizeOfData
...
closestTime = cell(1, stopAtEndOfData);
storeTheDifference = cell(1, stopAtEndOfData);
...
end
This means that you turn both of them into an array of {[],[],[],[],[]...} on every iteration of the loop - so unless the last iteration has a valid "closest Time" in it, your cell array will be all empty arrays - and if it does, all but the last element will still be [].
To fix this, move the two lines to before the start of the for loop.
The second problem seems to be the indexing of the arrays where you store the results. If you only want five results, I am assuming you want to store them in elements 1 - 5 of your array, and not in "just any" locations. I would change the code to
if (counter < 5)
counter = counter + 1;
closestTime{counter} = scanForClosestTime;
storeTheDifference{counter} = differenceBetweenTimes;
end
But maybe I misinterpreted how you want to handle that?
Unrelated to your question, you might want to take a look at the line
trainTimeGivenMStr = scanForClosestTime(findColonTrain+1:4);
It is quite possible that this is not what you intended to do - looking at an example of the response, I found the string "orig_departure_time":"11:57PM". I expect that findColonTrain == 3, so that the above line becomes
trainTimeGivenMStr = scanForClosestTime(4:4);
just a single character. Perhaps you meant
trainTimeGivenMStr = scanForClosestTime(findColonTrain+(1:4));
which would turn into
trainTimeGivenMStr = scanForClosestTime(4:7);
so that
trainTimeGivenMStr = '57PM';
I hope these three things help you get it all working!
EDIT: had a chance to run your code this morning - discovered a number of other problems. I include below an annotated "working" code: the biggest problem was most likely that you were not handling AM/PM in your code. Note that I used a different json parser - this changed a couple of lines very slightly. I'm sure you can put it back together to work the way you want. This returned valid data in all cells.
dataReturnedFromLiveAPI = loadjson(getInfoSeptaLive);
% next line not needed - loadjson returns struct array, not cell array
%dataReturnedFromLiveAPI = dataReturnedFromLiveAPI{1};
%gets the size of the API in case there are no trains running
sizeOfDataNoTrains = size(dataReturnedFromLiveAPI, 1);
sizeOfData = size(dataReturnedFromLiveAPI, 2);
counter = 0;
stopAtEndOfData = sizeOfData;
closestTime = cell(1, stopAtEndOfData);
storeTheDifference = cell(1, stopAtEndOfData);
userEnteredMins = 12*60+30; % looking for a train around 12:30 pm
for ii = 1:sizeOfData
scanForClosestTime = dataReturnedFromLiveAPI(ii).orig_departure_time;
trainTimeGivenH = sscanf(scanForClosestTime, '%i');
% since we'll be considering AM/PM, have to set 12 = 0:
if (trainTimeGivenH == 12), trainTimeGivenH = 0; end
findColonTrain = strfind(scanForClosestTime, ':');
% change next line to get minutes plus AM/PM:
trainTimeGivenMStr = scanForClosestTime(findColonTrain+(1:4));
% look at just minutes:
trainTimeGivenM = int32(str2num(trainTimeGivenMStr(1:2)));
% adjust for AM/PM:
if(trainTimeGivenMStr(3:4)=='PM'), trainTimeGivenH = trainTimeGivenH+12; end;
% compute time in minutes:
trainDepartTimeM = (trainTimeGivenH * 60) + (trainTimeGivenM);
differenceBetweenTimes = trainDepartTimeM - userEnteredMins;
if trainDepartTimeM < userEnteredMins
differenceBetweenTimes = userEnteredMins - trainDepartTimeM;
end
% added a couple of lines to see what is happening:
fprintf(1, 'train %d: depart %s - in minutes this is %d vs user entered %d\n', ...
ii, scanForClosestTime, trainDepartTimeM, userEnteredMins);
goodTimeFrame = 60;
if(differenceBetweenTimes < 600)
if (counter < 10)
counter = counter + 1;
closestTime{counter} = scanForClosestTime;
storeTheDifference{counter} = differenceBetweenTimes;
end
end
end

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