pivot table for schedule by hour - pivot-table

I am have trouble figuring out how to Pivot a table. I need an out put that looks like this
8 9 10 11 12 13 14
---------------------------------------------
1 test1 test1 test1 test2 text2 test2 test2
2 test2 test2 test3 test3 text3 test3 test3
3
4 test3
i have data something like this :
name hour date
-------------------
test1 8 1
test1 9 1
test1 10 1
test2 11 1
test2 12 1
test2 13 1
test2 14 1
test2 8 2
test2 9 2
test3 10 2
test3 11 2
test3 12 2
test3 13 2
test3 14 2
test3 11 4
i also had tried with query like this
select [8],[9],[10],
[11],[12],[13],[14]
from
(select name,hour,date
from myschedule)as x
pivot
(
max(name) for hour in ([8],[9],[10],
[11],[12],[13],[14])
)as pivottable
does anyone can solve this problem, i dont know how to query this stuff :(
thanks


Try this query
select *
from
(
select NAME,HOUR,DATE
from myschedule
unpivot
(
NAME
for HOUR in ([8],[9],[10],
[11],[12],[13],[14])
) unpiv
) src
Fiddle Demo

Related

Get output of multiple Counts in one query

Could you help me how to write a query for the following issue:
There are two tables:
Table persons:
P_id Name BirthDate
1 N1 2016-08-02
2 N2 2015-05-02
3 N3 2013-06-01
4 N4 2014-01-09
Table visited:(p_id is foreign key to table persons)
Id. Visitor_id. P_id. Visit_date
1 10 1 2017-03-05
2 11 2 2017-01-01
3 10 2 2017-02-03
4 12 3 2016-05-07
5 11 4 2016-04-09
6 10 1 2017-04-09
We are going to get the count of visited by each Visitor and also count of visited distinct person on filter on for those person who their age are under 1, between 1 and 2, between 2 and 3 at date of visit_date by each visitor_id.
The results should be like :
Under_one Bet_one_two Bet_two_three
Visitor_id VisitedCount/PersonCount VisitedCount/PersonCount VisitedCount/PersonCount
10 2 1 1 1 0 0
11 0 0 1 1 1 1
12 0 0 0 0 1 1
Between 1 and 2 means the result of subtracting visited_date and birthdate (for example : the result of 2013/03/05 - 2011/06/07) is between 1 and 2 years.

I don't know if I can give you the output laid out exactly as you have specified, but this
SELECT
visited.Visitor_id,
visited.P_id,
Int(([Visit_date]-[BirthDate])/365) AS Age,
Count(persons.P_id) AS NumVisits
FROM persons INNER JOIN visited ON persons.P_id = visited.P_id
GROUP BY
visited.Visitor_id,
visited.P_id,
Int((-[BirthDate]+[Visit_date])/365);
returns
Visitor_id P_id Age NumVisits
10 1 0 2
10 2 1 1
11 2 1 1
11 4 2 1
12 3 2 1

How to pull consecutive months data in sql server even if there is null value

I'm newbie trying to create a SQL query to find how much each Theater has sold the tickets per month during previous year (i.e. for all 12 months). If the collection amount is null or blank I need to produce an output as Zero of any such given month in that year.
I have two tables as below mentioned:
TABLE 1:
Month_Number Year
1 2016
2 2016
3 2016
4 2016
5 2016
6 2016
7 2016
8 2016
9 2016
10 2016
11 2016
12 2016
TABLE 2:
Theater month Amount_In_Thousands
ABC 1 165
ABC 3 70
ABC 4 102
GHI 1 45
GHI 2 70
GHI 3 42
GHI 4 57
ABC 6 122
ABC 7 67
ABC 8 22
ABC 9 80
ABC 11 46
ABC 12 38
You might have noticed for 'ABC' Theater there is 0 or null values for month 2, month 5 and month 10. I am unable to produce these missing months with zero value. I tried with simple left outer join but still the data output row doesn't show with month/year and zero value.
I need to produce the output as below:
OUTPUT
Movie_Theators Month Amount_In_Thounds
ABC 1 165
ABC 2 0 *
ABC 3 70
ABC 4 102
ABC 5 0 *
ABC 6 122
ABC 7 67
ABC 8 22
ABC 9 80
ABC 10 0 *
ABC 11 46
ABC 12 38
GHI 1 45
GHI 2 70
GHI 3 42
GHI 4 57
Can anybody please help me how to write sql script in order to produce the output as shown above. Thank you so much in advance.

You can use a CROSS JOIN between every theater and month-year, and then perform a LEFT JOIN with Table2:
SELECT A.Theater,
B.Month_Number,
B.[Year],
ISNULL(C.Amount_In_Thousands,0) Amount_In_Thousands
FROM ( SELECT DISTINCT Theater
FROM dbo.Table2) A -- or use a dbo.Theater table if you have one
CROSS JOIN dbo.Table1 B
LEFT JOIN dbo.Table2 C
ON A.Theater = C.Theater
AND B.Month_Number = C.[month]
AND B.[Year] = C.[Year];

How to count number of months in T-SQL

I've got a problem in SQL Server.
"Whate'er is well conceived is clearly said, And the words to say it flow with ease", Nicolas Boileau-Despreaux
Well, I don't think I'll be able to make it clear but I'll try ! And I'd like to apologize for my bad english !
I've got this table :
id ind lvl result date
1 1 a 3 2017-01-31
2 1 a 3 2017-02-28
3 1 a 1 2017-03-31
4 1 a 1 2017-04-30
5 1 a 1 2017-05-31
6 1 b 1 2017-01-31
7 1 b 3 2017-02-28
8 1 b 3 2017-03-31
9 1 b 1 2017-04-30
10 1 b 1 2017-05-31
11 2 a 3 2017-01-31
12 2 a 1 2017-02-28
13 2 a 3 2017-03-31
14 2 a 1 2017-04-30
15 2 a 3 2017-05-31
I'd like to count the number of month the combo {ind, lvl} remain in the result 1 before re-initializing the number of month to 0 if the result is not 1.
Clearly, I need to get something like that :
id ind lvl result date BadResultRemainsFor%Months
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0
So that if I was looking for the number of months the result was 1 for the date 2017-05-31 with the id 1 and the lvl a, I know it's been 3 months.

Assume all the date the the end day of month:
;WITH tb(id,ind,lvl,result,date) AS(
select 1,1,'a',3,'2017-01-31' UNION
select 2,1,'a',3,'2017-02-28' UNION
select 3,1,'a',1,'2017-03-31' UNION
select 4,1,'a',1,'2017-04-30' UNION
select 5,1,'a',1,'2017-05-31' UNION
select 6,1,'b',1,'2017-01-31' UNION
select 7,1,'b',3,'2017-02-28' UNION
select 8,1,'b',3,'2017-03-31' UNION
select 9,1,'b',1,'2017-04-30' UNION
select 10,1,'b',1,'2017-05-31' UNION
select 11,2,'a',3,'2017-01-31' UNION
select 12,2,'a',1,'2017-02-28' UNION
select 13,2,'a',3,'2017-03-31' UNION
select 14,2,'a',1,'2017-04-30' UNION
select 15,2,'a',3,'2017-05-31'
)
SELECT t.id,t.ind,t.lvl,t.result,t.date
,CASE WHEN t.isMatched=1 THEN ROW_NUMBER()OVER(PARTITION BY t.ind,t.lvl,t.id-t.rn ORDER BY t.id) ELSE 0 END
FROM (
SELECT t1.*,c.MonthDiff,CASE WHEN c.MonthDiff=t1.result THEN 1 ELSE 0 END AS isMatched
,CASE WHEN c.MonthDiff=t1.result THEN ROW_NUMBER()OVER(PARTITION BY t1.ind,t1.lvl,CASE WHEN c.MonthDiff=t1.result THEN 1 ELSE 0 END ORDER BY t1.id) ELSE null END AS rn
FROM tb AS t1
LEFT JOIN tb AS t2 ON t1.ind=t2.ind AND t1.lvl=t2.lvl AND t2.id=t1.id-1
CROSS APPLY(VALUES(ISNULL(DATEDIFF(MONTH,t2.date,t1.date),1))) c(MonthDiff)
) AS t
ORDER BY t.id
id ind lvl result date
----------- ----------- ---- ----------- ---------- --------------------
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0

By slightly tweaking your input data and slightly tweaking how we define the requirement, it becomes quite simple to produce the expected results.
First, we tweak your date values so that the only thing that varies is the month and year - the days are all the same. I've chosen to do that my adding 1 day to each value1. The fact that this produces results which are one month advanced doesn't matter here, since all values are similarly transformed, and so the monthly relationships stay the same.
Then, we introduce a numbers table - here, I've assumed a small fixed table is adequate. If it doesn't fit your needs, you can easily locate examples online for creating a large fixed numbers table that you can use for this query.
And, finally, we recast the problem statement. Instead of trying to count months, we instead ask "what's the smallest number of months, greater of equal to zero, that I need to go back from the current row, to locate a row with a non-1 result?". And so, we produce this query:
declare #t table (id int not null,ind int not null,lvl varchar(13) not null,
result int not null,date date not null)
insert into #t(id,ind,lvl,result,date) values
(1 ,1,'a',3,'20170131'), (2 ,1,'a',3,'20170228'), (3 ,1,'a',1,'20170331'),
(4 ,1,'a',1,'20170430'), (5 ,1,'a',1,'20170531'), (6 ,1,'b',1,'20170131'),
(7 ,1,'b',3,'20170228'), (8 ,1,'b',3,'20170331'), (9 ,1,'b',1,'20170430'),
(10,1,'b',1,'20170531'), (11,2,'a',3,'20170131'), (12,2,'a',1,'20170228'),
(13,2,'a',3,'20170331'), (14,2,'a',1,'20170430'), (15,2,'a',3,'20170531')
;With Tweaked as (
select
*,
DATEADD(day,1,date) as dp1d
from
#t
), Numbers(n) as (
select 0 union all select 1 union all select 2 union all select 3 union all select 4
union all
select 5 union all select 6 union all select 7 union all select 8 union all select 9
)
select
id, ind, lvl, result, date,
COALESCE(
(select MIN(n) from Numbers n1
inner join Tweaked t2
on
t2.ind = t1.ind and
t2.lvl = t1.lvl and
t2.dp1d = DATEADD(month,-n,t1.dp1d)
where
t2.result != 1
),
1) as [BadResultRemainsFor%Months]
from
Tweaked t1
The COALESCE is just there to deal with the edge case, such as for your 1,b data, where there is no previous row with a non-1 result.
Results:
id ind lvl result date BadResultRemainsFor%Months
----------- ----------- ------------- ----------- ---------- --------------------------
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0
1An alternative way to perform the adjustment is to use a DATEADD/DATEDIFF pair to perform a "floor" operation against the dates:
DATEADD(month,DATEDIFF(month,0,date),0) as dp1d
Which resets all of the date values to be the first of their own month rather than the following month. This may fell more "natural" to you, or you may already have such values available in your original data.

Assuming the dates are continously increasing in month, you can use window function like so:
select
t.id, ind, lvl, result, dat,
case when result = 1 then row_number() over (partition by grp order by id) else 0 end x
from (
select t.*,
dense_rank() over (order by e, result) grp
from (
select
t.*,
row_number() over (order by id) - row_number() over (partition by ind, lvl, result order by id) e
from your_table t
order by id) t ) t;

SQL Server 2008 R2: Recursive query

This is the follow up question of : Prepare a recursive query
I have the table with the two columns namely cola and colb as shown below:
Table : Test
create table Test
(
cola int,
colb int
);
Records I have entered are:
Cola Colb
------------
1 2
1 3
1 4
2 5
2 6
2 3
3 2
3 4
3 7
3 10
10 11
11 12
11 13
11 14
12 15
13 16
14 99
15 88
16 77
Note: Now I want to show the only records who are connected with value I have pass. For example If I pass the value as 1 then it should display me the connected number to it and form connect like a tree.
For the above requirement I have got the script from Dark Knight as shown below which works fine.
;WITH CTE AS
(
SELECT COLA,COLB,','+CAST(COLA AS VARCHAR(MAX))+',' AS CHCK FROM test WHERE COLA=1
UNION ALL
SELECT C1.COLA,C1.COLB,C.CHCK+CAST(C1.cola AS VARCHAR(MAX))+','
FROM CTE C INNER JOIN test C1 ON C.colb = C1.cola
WHERE CHARINDEX(','+CAST(C.colb AS VARCHAR(MAX))+',',C.CHCK)=0
),
OUTERCTE AS
(
SELECT DISTINCT COLA,COLB,ROW_NUMBER() OVER(PARTITION BY Colb ORDER BY Cola) rn FROM CTE --ORDER BY COLA
)
SELECT Cola,Colb FROM OUTERCTE
WHERE rn<=1
ORDER BY CASE WHEN Cola = 1 THEN 1 ELSE 2 END;
Which gives me this:
----------------
Cola Colb
----------------
1 2
1 3
1 4
2 5
2 6
3 7
3 10
10 11
11 12
11 13
11 14
12 15
13 16
16 77
15 88
14 99
Requirement: Now I want to show the levels of records.
Expected Result:
------------------------------
Cola Colb Level
------------------------------
1 2 1
1 3 1
1 4 1
2 5 2
2 6 2
3 7 2
3 10 2
10 11 3
11 12 4
11 13 4
11 14 4
12 15 5
13 16 5
16 77 6
15 88 6
14 99 5

;WITH CTE AS
(
SELECT COLA,COLB
,','+CAST(COLA AS VARCHAR(MAX))+',' AS CHCK
, 1 as lvl FROM #Test WHERE COLA=1
UNION ALL
SELECT C1.COLA,C1.COLB ,C.CHCK+CAST(C1.cola AS VARCHAR(MAX))+','
, c.lvl+1
FROM CTE C INNER JOIN #Test C1 ON C.colb = C1.cola
WHERE CHARINDEX(','+CAST(C.colb AS VARCHAR(MAX))+',',C.CHCK)=0
),
cte2 as (
select * , ROW_NUMBER() over (partition by colb order by lvl)as rn From CTE
)
select cola,colb,lvl from cte2 where rn = 1

How to split rows recursively

I've following table:
Id CreationDate FromEntryNo ToEntryNo
1 2013-01-01 1 4
2 2013-01-03 5 8
3 2013-01-05 9 11
...
I want to split this into multiple rows to have a list with all consecutive EntryNo, something like this:
Id CreationDate FromEntryNo ToEntryNo EntryNo
1 2013-01-01 1 4 1
1 2013-01-01 1 4 2
1 2013-01-01 1 4 3
1 2013-01-01 1 4 4
2 2013-01-03 5 8 5
2 2013-01-03 5 8 6
2 2013-01-03 5 8 7
2 2013-01-03 5 8 8
3 2013-01-05 9 11 9
3 2013-01-05 9 11 10
3 2013-01-05 9 11 11
...
My first attempt is CTE with recursion, but it doesn't work:
with cte as
(select gr.Id, gr.CreationDate, gr.FromEntryNo, gr.ToEntryNo, gr.FromEntryNo as [EntryNo]
from dbo.[Register] gr
union all
select No, CreationDate, FromEntryNo, ToEntryNo, EntryNo + 1 from cte where EntryNo <= ToEntryNo
)
select Id, CreationDate, FromEntryNo, ToEntryNo, EntryNo from cte
<
Any idea how to do this using one SQL query?

with cte as
(select gr.Id, gr.CreationDate, gr.FromEntryNo, gr.ToEntryNo,
gr.FromEntryNo as [EntryNo]
from dbo.[Register] gr
union all
select Id, CreationDate, FromEntryNo,
ToEntryNo, EntryNo + 1
from cte where EntryNo < ToEntryNo
)
select Id, CreationDate, FromEntryNo, ToEntryNo, EntryNo
from cte
ORDER BY Id,EntryNo

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