I have created a dataset user in logical data model and publish it. Then, I wanted to connect the dataset in GD Writer, but in select box the dataset is not supported to be select. Does someone know where is the problem?
Thank you very much!
It is probably with setting the right ${GDC_PROJECT_ID} parameter in workspace.prm file.
Related
I would like to set up a dashboard to display information about a customer.
To do so, the user will need to input an ID which identifies the customer.
I know how to set up custom filters, but those don't seem to allow free text entry.
How do I set up a dashboard that allows a user to input some text which is then used in a query in the underlying worksheet.
Can't be done yet, maybe add it to Snowflake Suggestions in the community page?
Snowflake does not currently support this funtionality.
A workaround is to use a BI tool such as Power BI as a front end.
Alternatively you could roll-your-own using something like R Shiny.
I have an Azure Data Factory Pipeline with a For Each Activity. This contains a Copy Data Activity which should insert into Azure Sql. I need to make use of the Additional columns feature but it refuses to let me select any value other than $$FILEPATH. It also will not let me type anything into the VALUE combo box.
Has anyone else hit this problem?
A workaround is to add a column as you did and change its value by editing the code of the pipeline.
The problem is a display issue with the scrolling menu hidden by a layer (I have it too). It is maybe specific to some web browsers.
Goal:
Possible to use use search function instead of using dropdownlist in Reporting services.
Problem:
Today, the dropdownlist consist of 2500 rows in relation to parameter for prompt.
You might understand that it is not userfriendly to review and locate a specific information from the dropdownlist by using scroll.
Does SSRS provide a function that you can write in a textbox something similiar and it will display the result based on the data from dropdownlist?
In other words, you write something and a result will display instead of reviewing the dropdownlist.
Info:
*This is related to reporting services that is part of SQL server
Thank you!
This picture is a sample of dropdownlist.
I am Facing problem with Lov, I am having three lov fields in the page which are defined on other viewObjects than current page viewObject. iam successfully able to bind them to the page i.e getting values by clicking the icon.
but the problem is while executing i am not getting any values for these fields, i tried to override createInstanceFromResultSet() method in viewImpl class where iam getting ids and setting values, for example by using appid in current row of Vo, iam setting appName, with out success. iam very new to ADF, any solutions. my jdevelper version is oracle 11g release2
Actually my functionality is similar to POST-QUERY trigger in oracle forms, where you set the values based on id.
Anybody has any guesses please share.
The Best way i found out is From "Oracle® Fusion Middleware Fusion Developer's Guide for Oracle Application Development Framework Release1 is To have your View object based on multiple Entity Objects, joining in all the information you need in the query from the main table, as well as any auxiliary/lookup-value tables. so in one trip you can bring all the values from the database.
I believe the way that you did bind these LOVs are wrong, follow this blog post https://blogs.oracle.com/prajkumar/entry/create_lov_in_adf_application it'll give you a heads up about the proper way to make LOVs
If you can't get LOV value after execution in ADF, then please check both data types you defined on ViewObject and to those fields, apply Lov. If the data type of both the fields is different, then the submitted value is refresh and Lov field is showing blank.
I have a job to import excel file and save the data to database via cakephp, the probleme is, this application allow user to choose the table that he want to used to save the data from excel file, so i need to list all the model name, i have search through google how to get all model name but i can't find it. I just can get all the table name, but this is not enough. I must know all the model name, please help me...
I can get all the field name uses this code:
$this->loadModel('Person');
$fieldsArray=$this->Person->find('all');
$fieldsArray=Set::extract('/0/Person',$fieldsArray);
$fieldNames=array_keys($fieldsArray[0]['Person']);
debug($fieldNames);
but as you can see, i have to know the model name, i can't solve this problem, please help me..
Best regards...
$Model = App::objects('Model');
pr($Model);
Do you mean:
$allModelNames = Configure::listObjects('model');
pr($allModelNames);
Note:
This only works for CakePHP1.x
For CakePHP2.x please use App::objects() instead.