I have a page view(1) that filters a content type by diferent field results, one of them is a referenced entity and I'd like to display it's whole content whenever a filter by this referenced field is used.
I've created a block view(2) that displays the referenced entity and tried to use contextual filters to display it only in the results view page when it is used aa a filter but I haven't find the correct way to do this
I've tried to provide a default value for the content id from the url but I the field value responds to target_id, I've also tried to use php with something like: echo ($_GET['field_nameofthefield_target_id']) but it didn't work out
Could anyone help me with this please?
thanks a lot in advance
Related
Iam new to drupal 7 views.
I have a content type contains title, description fields. I want the content title's to scroll at the top of the page, so that i created a view and it works fine.What is my question is, i want to link a content (eg: 1st content (title) in a scroll) to another website instead of content page, the remaining contents linked to the content page. Is it possible?.If it is possible how it can be done?..
Thanks in advance,
A.John Melchior.
Yes, it's possible.
One way to do it, would be to use the Link module to create a link field in your node.
Use the link field to input the external link value.
In views add the link field, before the title ( order is important ) and exclude it from display
Add the node title field in the views and in the rewrite field output option, use one the link field token as your path.
I'm not looking at the Views UI right now , but you should find at least a couple of ways to redirect content when the node title is clicked. You should have the Rewrite field output and the Output this field as a link.
You could make use of Display Suite coupled with the description above.
Create a link field for your nodes.
Create 2 view modes for your content type via Display Suite. View Mode 1 will show the link field as the first data element, View Mode 2 will show the title as the first element.
Configure your view to show output using Display Suite, configured to show the first record using View Mode 1, all others using View Mode 2.
I use taxonomy terms to address my menus(these taxonomy terms show the structure of my site) so when I create a view I should use the taxonomy path (instead of alias) for the page setting (the only way that I can link the view to my taxonomy address path as far as I know :P ). whenever I see the page URL I can see the alias. now I'm trying to set up a page that has 2 tabs. I have set it up but the problem is when I click in the tab I see the taxonomy path instead of alias ? (for example taxonomy/term/6/digital instead of CCTV/digital However default menu tab still work correctly and show the alias CCTV)
Is there any way to show the alias instead of taxonomy term address ?
I assume that you have a view that is filtering your taxonomy terms. If you render the results as fields, each field can have it's formatter. If you need a custom form of the output, you can define your own formatter or generate one via GUI with help of: custom formatters.
In case that you render your output as rendered entity, you need to find the right template file and use the drupal_get_path_alias() function within it.
As last I would hint you a great module that also might help you: taxonomy menu
CASE:
I've created a content type 'Attorney', and have set a url alias pattern for all attorneys to be 'attorneys/[node:title]'. I'd like to create a view that uses the aliased path to display the information about the attorney. This view should have a 'page' display.
EXAMPLE:
When a user visits 'http://mydomain.com/attorneys/aaron-silber' the view returns data for the Attorney with the name Aaron Silber.
BACKGROUND:
I've searched high and low for a solution to this but can't seem to find one that works for me. Typically I'm asked to create a page view with a url of 'attorneys/%' and add a contextual filter with 'Content: Nid', choosing to provide a default value (type: Raw value from URL, path component 2).
The resources on the web for this case are aweful at best. Lets try to fix it here once and for all.
Thanks!
Use a Views block instead with the visibility set to "Only the listed pages" and supply "attorneys/*" in the textarea. Set the block to display in the main content region. Use the Content: Nid filter with a default value of path component 2, as you were previously attempting.
You can't have an attorney node page and a Views page occupying the same URL.
In the page I have a list of fields where I can make a filter.
Typically it reflects the caption field. The list Is subject to the field property 'captionclass' (e.g. Dimension)
I modified codeunit 42 to manage (with my function) the caption dependent on a value in a record in a table. It works fine on OpenPage however if I change records in the Page List it will not be reinitialized.
Any idea?
Does using the following code to refresh the form when necessary, resolve the issue?
Form
CurrForm.UPDATE(FALSE);
Page
CurrPage.UPDATE(FALSE);
I am trying to load/show completely different set of values in a combobox(this one resides as a editor within an EditorGridPanel) based on the valueField of another combobox(this one resides outside the grid in top bar). I have already seen a tutorial(http://www.extjs.com/learn/Tutorial%3ALinked%5FCombos%5FTutorial%5Ffor%5FExt%5F2) wherein ALL the values for the secondary object are stored locally and then filtered however, I have already created a link which will supply me with json data based on the valuefield, so I would like to use this url to keep the code efficient.
I have also tried to refresh the datastore but its simply not being reflected on the combobox.
Please advise
Thanks
Found the solution, loading values from a url is straightforward.. if you want to manipulate the query(like I wanted), you would have to strip url off the dynamic parameters and assign them to baseParams of the store and then call store.load()
It worked for me!!