Using strcat to append spaces. Compiles but overwrites string - c

Question

The language I am working in is C.
I am trying to use a mix of built in c string functions in order to take a list of tokens (space separated) and "convert" it into a list of tokens that is split by quotations.
A string like
echo "Hello 1 2 3 4" test test2
gets converted to
[echo] ["Hello] [1] [2] [3] [4"] [test] [test2]
I then use my code (at bottom) to attempt to convert it into something like
[echo] [Hello 1 2 3 4] [test] [test2]
For some reason the second 'token' in the quoted statement gets overridden.
Here's a snippet of the code that runs over the token list and converts it to the new one.
88 for (int i = 0; i < counter; i++) {
89 if ( (strstr(tokenized[i],"\"") != NULL) && (inQuotes == 0)) {
90 inQuotes = 1;
91 tokenizedQuoted[quoteCounter] = tokenized[i];
92 strcat(tokenizedQuoted[quoteCounter]," ");
93 } else if ( (strstr(tokenized[i],"\"") != NULL) && (inQuotes == 1)) {
94 inQuotes = 0;
95 strcat(tokenizedQuoted[quoteCounter],tokenized[i]);
96 quoteCounter++;
97 } else {
98 if (inQuotes == 0) {
99 tokenizedQuoted[quoteCounter] = tokenized[i];
100 quoteCounter++;
101 } else if (inQuotes == 1) {
102 strcat(tokenizedQuoted[quoteCounter], tokenized[i]);
103 strcat(tokenizedQuoted[quoteCounter], " ");
104 }
105 }
106
107 }

Answer 1

In short, adding an space to a char * means that the memory pointed by it needs more bytes. Since you do not provide it, you are overwritting the first byte of the following "word" with \0, so the char * to it is interpreted as the empty string. Note that writting to a location that has not been reserved is an undefined behavior, so really ANYTHING could happen (from segmentation fault to "correct" results with no errors).
Use malloc to create a new buffer for the expanded result with enough bytes for it (do not forget to free the old buffers if they were malloc'd).