In my class today we were assigned a project that involves reading in a file using the ./a.out"<"filename command. The contents of the file look like this
16915 46.25 32 32
10492 34.05 56 52
10027 98.53 94 44
13926 32.94 19 65
15736 87.67 5 1
16429 31.00 58 25
15123 49.93 65 38
19802 37.89 10 20
-1
but larger
My issue is that any scanf used afterwards is completely ignored and just scans in what looks like garbage when printed out, rather than taking in user input. In my actual program this is causing an issue with a menu that requires input.
How do I get the program to stop reading the file provided by the ./a.out"<"filename command?
also I stop searching at -1 rather than EOF for the sake of not having an extra set of array data starting with -1
ex
-1 0 0 0
in my real program the class size is a constant that is adjustable and is used to calculate class averages, I'd rather not have a set of 0's skewing that data.
#include <stdio.h>
int main(void)
{
int i = 0,j = 1,d,euid[200],num;
int tester = 0;
float hw[200],ex1[200],ex2[200];
while(j)
{
scanf("%d",&tester);
if( tester == -1)
{
j = 0;
}
else
{
euid[i] = tester;
}
scanf("%f",hw+i);
scanf("%f",ex1+i);
scanf("%f",ex2+i);
i++;
}
for(d = 0;d < 50;d++) /*50 because the actual file size contains much more than example*/
{
printf("euid = %d\n",euid[d]);
printf("hw = %f\n",hw[d]);
printf("ex1 = %f\n",ex1[d]);
printf("ex2 = %f\n",ex2[d]);
}
printf("input something user\n");
scanf("%d",&num);
printf("This is what is being printed out -> %d\n",num);
return 0;
}
I'm having the exact same problem. Tried every method I could find to eat the remaining input in the buffer, but it never ends.
Got it to work using fopen and fscanf, but the prof. said he prefers the code using a.out < filename
Turns out this is in fact not possible.
Related
This program takes as an input the following lines:
23 12 33 19 10 8
5
23 19 8 12 60 18
14 60 12 44 54 10
8 3 12 19 33 10
33 15 7 60 12 10
22 12 19 23 33 11
23 12 33 19 10 8 ( The first line ) are the lottery results.
n ( in this specific case, 5 ) informs how many lines will follow below.
Each line has 6 numbers. The number order doesn't matter.
The rules are: numbers range from 1 to 60 ( including 1 and 60 ) and they never repeat themselves in the same line.
The variable "quadra" stores how many lines have got 4 numbers right.
The variable "quina" stores how many lines have got 5 numbers right.
The variable "sena" stores how many lines have got 6 numbers right.
So, a computer program is running some tests over my code below and it's claiming that it goes wrong for most of them, but I can't see what's the problem here. Does anybody have a clue? Is this code wrong, or is there something wrong with the software that's testing this code?
#include <stdio.h>
int main(){
int mega[6];
int v[50500][6];
int n,swap;
int i,j,k; //counters
int quadra,quina,sena;
quadra = 0;
quina = 0;
sena = 0;
for(i=0;i<6;++i) scanf("%i",&mega[i]); //first line, lottery results
scanf("%i",&n);
for(i=0;i<n;++i){
for(j=0;j<6;++j){
scanf("%i",&v[i][j]);
}
}
for(i=0;i<n;++i){
for(j=0;j<6;++j){
for(k=0;k<6;++k){
if(v[i][j] == mega[k]){
v[i][j] = 61;
}
}
}
}
//reverse bubble sort
for(i=0;i<n;++i){
for(j=0;j<6;++j){
for(k=j+1;k<6;++k){
if(v[i][j] < v[i][k]){
swap = v[i][k];
v[i][k] = v[i][j];
v[i][j] = swap;
}
}
}
}
for(i=0;i<n;++i){
for(j=0;v[i][j] == 61 && j<6;++j);
if(j == 4) ++quadra;
else if(j == 5) ++quina;
else if(j == 6) ++sena;
}
return 0;
}
Your code is true, I understood and tried the flow of it. Looks fine but if you dont need to sort everyline (and use j as a counter in this loop for(j=0;v[i][j] == 61 && j<6;++j); ), you can use simpler ifstatements to compare real lottery results with the ones that entered. What I mean is that your algorithm is a little complex. Try a simple one and see how it works.
Yes, there are a couple of noteworthy issues with your code:
Compile time indicates possibility of uninitialized variable:
But, run-time results in fatal run-time at unknown source location. Stack overflow. It is likely due to this line:
int v[50500][6];
Increase your stack size. It needs to be about 2.5Mbytes for v alone.
Also, this line may not be what you intended:
for(i=0;i<6;++i) scanf("%i",&mega[i]); //first line, lottery results
^
If you meant to loop around the remainder of the code, remove the ; after the for() statement, and use curly braces:
for(i=0;i<6;++i) scanf("%i",&mega[i]) //first line, lottery results
{
scanf("%i",&n);
....
I need to receive and put into variables text file.
For example:
/*
system_1
6
challenge_2 22 2
challenge_3 33 3
challenge_4 44 1
challenge_5 55 3
challenge_6 66 3
challenge_1 11 1
4
room_2 1 22
room_1 3 11 44 66
room_3 3 55 33 11
room_4 4 22 44 55 66
*/
I know that every one of the words (not line) is not more than 50 characters.
What will be the easy way to put each word in the appropriate (int,string...).
Also I need to know where the line is ending because the number of words in line is not constant.
I think fscanf is the most efficient, but I dont know how to use it for line ending and such...
I would love to see an example of using fscanf as I wanted.
Thanks in advance.
It's more efficient, because you do not know the format string to use fgets to return a line from the file, then to parse it yourself rather than using scanf.
An example would be like this:
FILE* file = fopen("somefile.txt", "r");
char buffer[51];
while (fgets(buffer, 50, file)) {
// Buffer now stores the line, lets see if it can be an integer.
int possible_num = 0;
// sscanf will return 1 if it read a possible integer from the buffer.
if (sscanf(buffer, "%d", &possible_num) == 1) {
// We read a number, so possible_num is now the number.
}
else {
// We read a string, buffer stores the string.
}
}
NOTE: The code will return a false positive if your string is something like "10hello", as sscanf will still read the 10. There are multiple ways of checking if a string is a valid integer out there in C, which I'm sure you will be able to find on StackOverflow, but this code should give you a place to get started.
I have to read text in from a file, then prompt for a value and search the file for this number. Once the file is read all the way through, I have to print the initial position and the number of times it appears. Obviously I do not just want the answer, but rather where my program went wrong because I am blind to it as of now.
My source code looks like this:
int count, number, value;
printf("What number are you looking for? ");
scanf("%d",&value);
FILE *fp = fopen("data.in","r");
count = 0;
while (!feof(fp)) {
fscanf(fp,"%d",&number);
if (number == value) {
++count;
}
}
fclose(fp);
printf("The number %d appears first at position %d in the file",value,number);
printf("The number %d appears %d time(s)",value,count);
return 0;
}
The data file I am reading from is:
3 8 33 75 25 10 41 8
10
55 10 1 0 10
10 18
However, when I run the program it returns:
What number are you looking for? 10
The number 10 appears first at position 18 in the file
The number 10 appears 5 time(s)
What number are you looking for? -5
The number -5 appears first at position 18 in the file
The number -5 appears 0 time(s)
Any ideas? Again, I am not looking for the straight answer, rather a way for me to look for these issues both now and in the future.
After coming out from while loop number is always the last number i.e. 18
irrespective of number you are looking for.
The line fscanf(fp,"%d",&number); reads the number of each line and when loop terminates the number is assigned as 18.
Also read : “while( !feof( file ) )” is always wrong ?
Do something like following:
int pos = -1, curr_lno = 0 ; // Keep track of position
while (fscanf(fp,"%d",&number) == 1)
{
++curr_lno ;
if (number == value)
{
pos = ( pos == -1 ) ? curr_lno : pos ;
++count;
}
}
fclose(fp);
if ( count > 0 )
{
printf("The number %d appears first at position %d in the file",value, pos );
}
I want to ask something that I write in C.
I use the fopen() command to open and read a text file that contains only two lines. in
first line is an integer N number, and in the second line is the N integer numbers that the first line says.
Eg.
-------------- nubmers.txt --------------
8 <-- we want 8 numbers for the 2nd line
16 8 96 46 8 213 5 16 <-- and we have 8 numbers! :)
but I want to take restrictions when the file openend.
the number N should be between 1 ≤ Ν ≤ 1.000.000. If not then show an error message. If the file is ok then the programm continue to run with another code.
Here is what I done until now:
int num;
....
fscanf(fp,"%d",&num); // here goes the fscanf() command
if(num<1 || num>1000000) // set restrictions to integer
{
printf("The number must be 1<= N <= 1.000.000",strerror(errno)); // error with the integer number
getchar(); // wait the user press a key
return 0; // returning an int of 0, exit the program
}
else // if everything works.....
{
printf("work until now"); // Everything works until now! :)
getchar(); // wait the user press a key
return 0; // returning an int of 0, exit the program
}
But the problem is that the restriction checks only for the first line number , it's correct though, but don't read the numbers in the second line.
What I mean is that :
Lets say that I have the number 10 in the first line.
The code will analyze the number, will check for restrictions and will proceed to the 'else' part
else // if everything works.....
{
printf("work until now"); // Everything works until now! :)
getchar(); // wait the user press a key
return 0; // returning an int of 0, exit the program
}
..and it will said that everything is working.
But what if I have 20 numbers in the second line? -when I need only 10
Eg.
-------------- nubmers.txt --------------
10
16 8 96 46 8 213 5 16 8 9 21 5 69 64 58 10 1 7 3 6
So I hoped be as cleared as I could. My question is that I need a code in the program, besides the 1st restriction, that have also another one restriction under the first that will read the second line of the txt file with the numbers and check if there are as many numbers as the first line says!
How do I do that?
If you guys want any other declarations feel free to ask!
Hope I was clear with my problem :)
This will check the number of integers and report too many or not enough. The integers are not saved except for each one being read into the value. Do you want to store each integer?
fscanf(fp,"%d",&num); // here goes the fscanf() command
if(num<1 || num>1000000) // set restrictions to integer
{
printf("The number must be 1<= N <= 1.000.000",strerror(errno)); // error with the integer number
getchar(); // wait the user press a key
return 0; // returning an int of 0, exit the program
}
else // if everything works.....
{
int i = 0;
int value = 0;
while ( fscanf ( fp, "%d", &value) == 1) { // read one integer
i++; // this loop will continue until EOF or non-integer input
}
if ( i > num) {
printf ( "too many integers\n");
}
if ( i < num) {
printf ( "not enough integers\n");
}
getchar(); // wait the user press a key
return 0; // returning an int of 0, exit the program
}
use a loop that takes the first num and checks is is the number of integers in next line:
int z = num;
while(z--){
if (getchar() == EOF)
printf("err")
}
Do it like this:
fscanf(fp,"%d",&num);
// next lines of code (restrictions). Then place the below code before getchar in the else
int temp[num+1];// space to store num integers to temp and 1 space to check for extra number
for(i=0;i<num;i++)
{
if(fscanf(fp,"%d",&temp[i]) != 1)// fscanf will automatically read 2nd line and store them in temp array
//error ! Less numbers in file !
}
if(fscanf(fp,"%d",&temp[num]==1) //if still numbers can be scanned
//Extra numbers found in line 2
Hello I have file with text:
14
5 4
45 854
14
4
47 5
I need to write a text to a specific line. For example to the line number 4 (Doesn't matter whether I will append the text or rewrite the whole line):
14
5 4
45 854
14 new_text
4
47 5
I have found function fseek(). But in the documentation is written
fseek(file pointer,offset, position);
"Offset specifies the number of positions (bytes) to be moved from the location specified bt the position."
But I do not know the number of bites. I only know the number of lines. How to do that? Thank you
You can't do that, (text) files are not line-addressable.
Also, you can't insert data in the middle of a file.
The best way is to "spool" to a new file, i.e. read the input line by line, and write that to a new file which is the output. You can then easily keep track of which line you're on, and do whatever you want.
I will assume that you are going to be doing this many times for a single file, as such you would be better indexing the position of each newline char, for example you could use a function like this:
long *LinePosFind(int FileDes)
{
long * LinePosArr = malloc(500 * sizeof(long));
char TmpChar;
long LinesRead = 0;
long CharsRead = 0;
while(1 == read(FileDes, &TmpChar, 1))
{
if (!(LinesRead % 500)
{
LinePosArr = realloc(LinePosArr, (LinesRead + 500) * sizeof(long));
}
if (TmpChar == '\n')
{
LinePosArr[LinesRead++] = CharsRead;
}
CharsRead++;
}
return LinePosArr;
}
Then you can save the index of all the newlines for repeated use.
After this you can use it like so:
long *LineIndex = LinePosFind(FileDes);
long FourthLine = LineIndex[3];
Note I have not checked this code, just written from my head so it may need fixes, also, you should add some error checking for the malloc and read and realloc if you are using the code in production.