I have this error:
Notice (8): Undefined variable: informations [APP/View/Information/index.ctp, line 2]
I have this function in my controller
public function index($slug){
$this->layout = 'sbhealth';
$this->loadModel('Menu');
$informations = $this->Menu->findBySlug($slug);
if($informations){
$this->set('index', $informations);
}else{
return $informations = "not find";
}
}
I need to pass datas to my view "index.ctp" index.ctp will then find the ID in my array to pass it to an Element. but the View doesn't recognize "$informations"
This probably doesn't constitute something that should be on StackOverflow, since it's specified in great detail in the book, but...
// in your controller
$this->set('informations', $informations);
The first item is the name of the variable that will be available in the view.
The second item is the value you want to put in that variable.
Related
I want to get the value from the array I've passed from the first view to another view.
I found this works by using route (not url), but I don't know how to get it without parameter in the controller.
Please help me within the right syntax.
This is the latest code I've tried
$id = $request->id;
if($request->has('download', 'id')){
$pdf = PDF::loadView('pdfview');
return $pdf->download('pdfview.pdf',['id'=>$id])->with('id',$id);}
This is my code *used to download pdf file from a view
Controller
public function pdfview(Request $request)
{
$items = DB::table("items")->get();
view()->share('items',$items);
$id = $request->only(['id']);
if($request->has('download', 'id')){
$pdf = PDF::loadView('pdfview');
return $pdf->download('pdfview.pdf', ['id'=>$id])->with('id', $id);
}
return view('pdfview', ['id'=>$id])->with('id', $id);
}
Route
Route::get('pdfview',array('as'=>'pdfview','uses'=>'MaatwebsiteDemoController#pdfview'));
View
Download PDF
I want to get the $employee->nip value
But it is still Undefined variable: id
Don't really have time to test it. But this thread looks promising.
https://laravel.io/forum/03-14-2016-basics-passing-info-from-one-view-to-another
I have the following code in backbone view:
getAccounts: function() {
var filteredCollection = this.view.collection.reset(this.view.collection.where({ AccountStatus: 'Open' }));
return filteredCollection;
}
And I assume that this code returns me collection according to doc link http://backbonejs.org/#Collection-reset
But it returns an array. What is wrong here?
The documentation says
Returns the newly-set models
This means you get an array containing newly set models. It doesn't say it returns the collection itself. There is no reason to return the collection itself because you just performed this action on the collection and you already have access to it.
You can just do return this.view.collection instead.
I am trying to merge the contents of 2 arrays then use usort to get the posts with most views.
Trying to use usort to sort the contents of an array.
Am getting the follow error:
("Notice: Undefined property: Acme\DemoBundle\Entity\Article::$getViews in /.../PageController.php line 15")
Can someone point out what I am doing wrong?
Sort function inside of controller
private static function popularSort($articles, $posts, $articles2, $posts2)
{
return $articles->getViews() == $posts->getViews() ? 0 : ( $articles->getViews() < $posts->getViews()) ? 1: -1;
}
Sidebar action
$articles = $this->getDoctrine()->getRepository('AcmeDemoBundle:Article')
->getArticles();
$posts = $this->getDoctrine()->getRepository('AcmeDemoBundle:Post')
->getPosts();
$popular = array_merge($articles, $posts);
usort($popular, array($this, 'popularSort'));
getViews is a getter method for accessing the property views of the Entities Post and Article. So while accessing it u should access it as $articles->getViews().
But if you simply want to compare the property views of the two entities compare them using their property name instead of their getter
Assuming views as the name of the property, the call should be something like:
$posts->views and $articles->views.
You don't have a property called getViews in your Article class.
You probably have a property called views and a method getViews meaning you should call the actual method with the brackets like $article->getViews().
I've two controllers one is "Upload" which deals with images uploads and other is "Page" whid deals with the creation of pages of CMS now if in my "Upload" controller I load both the models i.e 'image_m' which deals with image upload and "page_m" which deals with the pages creation I've highlighted the relevant code my problem is if I access the variables in the view
$this->data['images'] = $this->image_m->get(); sent by this I can access in foreach loop as "$images->image_title, $images->image_path" etc
But the variable sent by this line ***$this->data['get_with_images'] = $this->page_m->get_no_parents();*** as $get_with_images->page_name, $get_with_images->page_id etc produces given error
A PHP Error was encountered
Severity: Notice
Message: Trying to get property of non-object
Filename: upload/index.php
Line Number: 20
what is the difference between these two access levels one for $image & other for $get_with_images because I can only access its values as $get_with_images
class Upload extends Admin_Controller {
public function __construct() {
parent::__construct();
***$this->load->model('image_m');
$this->load->model('page_m');***
}
public function index($id = NULL) {
//var_dump($this->data['images'] = $this->image_m->get_with_images());
//$this->data['images'] = $this->image_m->get_with_images();
***$this->data['images'] = $this->image_m->get();***
$this->data['subview'] = 'admin/upload/index';
if ($id) {
$this->data['image'] = $this->image_m->get($id);
count($this->data['image']) || $this->data['errors'][] = 'Page Could not be found';
}
$id == NULL || $this->data['image'] = $this->image_m->get($id);
/*this calls the page_m model function to load all the pages from pages table*/
***$this->data['get_with_images'] = $this->page_m->get_no_parents();***
You are not posting all your code so its hard to tell but is it because you used $this-> in the controller, but you haven't done the same thing in the view?
In this case i would recommend not using $this-> because its not necessary. Also its much better to check for errors etc when you call the model so do something like
if ( ! $data['images'] = $this->image_m->get($id) ) {
// Failure -- show an appropriate view for not getting any images
// am showing $data in case you have other values that are getting passed
$this->load->view( 'sadview', $data ); }
else {
// Success -- show a view to display images
$this->load->view( 'awesomeview', $data ); }
so we are saying if nothing came back - the ! is a negative - then show the failure view. Else $data['images'] came back, and it will be passed to the view. note i have not had to use $this-> for anything and it won't be needed in the view.
Would also suggest using separate methods - have one method to show all images and a separate method like returnimage($id) to show an image based on a specific validated $id.
====== Edit
You can access as many models as you want and pass that data to the View. You have a different issue - the problem is that you are waiting until the View to find out - and then it makes it more difficult to figure out what is wrong.
Look at this page and make sure you understand the differences between query results
http://ellislab.com/codeigniter/user-guide/database/results.html
When you have problems like this the first thing to do is make a simple view, and echo out directly from the model method that is giving you problems. Its probably something very simple but you are having to look through so much code that its difficult to discover.
The next thing is that for every method you write, you need to ask yourself 'what if it doesn't return anything?' and then deal with those conditions as part of your code. Always validate any input coming in to your methods (even links) and always have fallbacks for any method connecting to a database.
On your view do a var_dump($get_with_images) The error being given is that you are trying to use/access $get_with_images as an object but it is not an object.
or better yet on your controller do a
echo '<pre>';
var_dump($this->page_m->get_no_parents());
exit();
maybe your model is not returning anything or is returning something but the data is not an object , maybe an array of object that you still need to loop through in some cases.
If I have a person model with first_name and last_name, how do I create and display a full_name? I would like to display it at the top of my Edit and View views (i.e. "Edit Frank Luke") and other places. Simply dropping echoes to first_name and last_name isn't DRY.
I'm sorry if this is a very simple question, but nothing has yet worked.
Thank you,
Frank Luke
Edit for clarity: Okay, I have a function on the person model.
function full_name() {
return $this->Person->first_name . ' ' . $this->Person->last_name;
}
In the view, I call
echo $person['Person']['full_name']
This gives me a notice that I have an undefined index. What is the proper way to call the function from the view? Do I have to do it in the controller or elsewhere?
If what you are wanting is just to display a full name, and never need to do any database actions (comparisons, lookups), I think you should just concatenate your fields in the view.
This would be more aligned with the MVC design pattern. In your example you just want to view information in your database in a different way.
Since the action of concatenating is simple you probably don't save much code by placing it in a separate function. I think its easiest to do just in the view file.
If you want to do more fancy things ( ie Change the caps, return a link to the user ) I would recommend creating an element which you call with the Users data.
The arrays set by the save() method only return fields in the datbase, they do not call model functions. To properly use the function above (located in your model), you will need to add the following:
to the controller, in the $action method:
$this->set( 'fullname', $this->Person->full_name();
// must have $this-Person->id set, or redefine the method to include $person_id
in the view,
echo $fullname;
Basically, you need to use the controller to gather the data from the model, and assign it to the controller. It's the same process as you have before, where you assign the returned data from the find() call to the variable in the view, except youre getting the data from a different source.
There are multiple ways of doing this. One way is to use the afterFind-function in a model-class.
See: http://book.cakephp.org/view/681/afterFind.
BUT, this function does not handle nested data very well, instead, it doesn't handles it al all!
Therefore I use the afterfind-function in the app_model that walks through the resultset
function afterFind($results, $primary=false){
$name = isset($this->alias) ? $this->alias : $this->name;
// see if the model wants to attach attributes
if (method_exists($this, '_attachAttributes')){
// check if array is not multidimensional by checking the key 'id'
if (isset($results['id'])) {
$results = $this->_attachAttributes($results);
} else {
// we want each row to have an array of required attributes
for ($i = 0; $i < sizeof($results); $i++) {
// check if this is a model, or if it is an array of models
if (isset($results[$i][$name]) ){
// this is the model we want, see if it's a single or array
if (isset($results[$i][$name][0]) ){
// run on every model
for ($j = 0; $j < sizeof($results[$i][$name]); $j++) {
$results[$i][$name][$j] = $this->_attachAttributes($results[$i][$name][$j]);
}
} else {
$results[$i][$name] = $this->_attachAttributes($results[$i][$name]);
}
} else {
if (isset($results[$i]['id'])) {
$results[$i] = $this->_attachAttributes($results[$i]);
}
}
}
}
}
return $results;
}
And then I add a _attachAttributes-function in the model-class, for e.g. in your Person.php
function _attachAttributes($data) {
if (isset($data['first_name']) && isset($data['last_name'])) {
$data['full_name'] = sprintf("%s %s %s", $data['first_name'], $data['last_name']);
}
return $data;
}
This method can handle nested modelData, for e.g. Person hasMany Posts then this method can also attachAttributes inside the Post-model.
This method also keeps in mind that the linked models with other names than the className are fixed, because of the use of the alias and not only the name (which is the className).
You must use afterFind callback for it.
You would probably need to take the two fields that are returned from your database and concatenate them into one string variable that can then be displayed.
http://old.nabble.com/Problems-with-CONCAT-function-td22640199.html
http://teknoid.wordpress.com/2008/09/29/dealing-with-calculated-fields-in-cakephps-find/
Read the first one to find out how to use the 'fields' key i.e. find( 'all', array( 'fields' => array( )) to pass a CONCAT to the CakePHP query builder.
The second link shows you how to merge the numeric indexes that get returned when you use custom fields back into the appropriate location in the returned results.
This should of course be placed in a model function and called from there.