C for loop iteration - c

I have a problem writing code which does the following: declare a struct{char c; int x; } array and load it with scanf via a loop. After it's loaded, a call to function f will be made which will replace every occurrence of digits in the struct's component c with 0, and will return the sum of the digits replaced by zero.
Code and output are below and I have problem that the loop in the function f seems to iterate one time, and it gives out some really weird values.
This is an exam question so I have to use printf, scanf etc. Also I have that exam in an hour so any quick help is appreciated :)
CODE:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#define MAX 2
struct par {
char c;
int x;
};
int f(struct par *niz) {
int i;
int n=0;
for(i=0; i<MAX; i++) {
if(isdigit(niz[i].c)) {
niz[i].c = niz[i].c-'0';
printf("niz[i].c = %d\n i = %d", niz[i].c, i);
n=n+niz[i].c;
niz[i].c='0';
}
}
return n;
}
void main() {
int n;
int i;
struct par niz[MAX];
printf("enter\n");
for(i=0; i<MAX; i++) {
scanf("%c", &niz[i].c);
scanf("%d", &niz[i].x);
}
n=f(niz);
for(int i=0; i<MAX; i++) {
printf("%d\n", niz[i].c);
printf("%d\n", niz[i].x);
}
printf("n = %d\n", n);
}
OUTPUT:
enter
2
2
2
niz[i].c = 2
i = 048
2
10
2
n = 2

When you press enter after the first input, the newline is not scanned by scanf and is left in the input buffer. When you then try to read the number scanf sees the newline and not a number so doesn't scan anything.
The simple solution to that is to add a leading space in front of the formats:
scanf(" %c", &niz[i].c);
scanf(" %d", &niz[i].x);
/* ^ */
This tells scanf to skip whitespace.

Use
niz[i].c = getchar();
instead of
scanf("%c", &niz[i].c);
or, you can use other better methods for getting char input discussed at SO,
Now,
You see second time you provided input only once, that is because the Enter you pressed after giving 2 as input to first char remained in input buffer, and was read on second iteration.
You are getting 10 as output, because, it is ASCII for \r, the Enter. It is not a digit, so not replaced to be '0'.

I am looking at your code (i am not using console for a decade, but ) here are some insights:
try to rename MAX with something else
do not know your IDE but sometimes MAX is reserved
and using it as macro can cause problems on some compilers
change scanf("%c", &niz[i].c) to scanf("%c", &(niz[i].c))
just to be shore that correct adsress is send to scanf
change scanf("%d", &niz[i].x) to scanf("%i", &(niz[i].x))
change "%d" to the correct value (this is main your problem)
"%c" for char
"%i" for int
Try to trace line by line and watch for improper variables change if above points does not help

weird values?
because you forgot "\n" after the line, so next print is behind the line "i = %d".
And, check return value of every function except ones that return void.

Related

Encountering undefined behavior on a function to add up numbers below 10

I am encountering UB in the terminal with my current code when the input contains comma, dot or non-only-numeric character. I am confused why that is happening.
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
float tizAlatti(int inputCount);
int main(){
int inputNumber;
printf("Number of input elements: ");
scanf("%d", &inputNumber);
if(inputNumber % 1 != 0 && (isdigit(inputNumber) == 0)){
printf("Error encountered.");
exit(1);
}
printf("\n%.2f", tizAlatti(inputNumber));
}
float tizAlatti(int inputCount){
float arr[inputCount], input = 0;
printf("\n");
for(int i = 0; i<inputCount; i++){
printf("Element %d: ", i+1);
scanf("%f", &arr[i]);
if(arr[i] < 10){
input+= arr[i];
}
}
return input;
}
Here I got this output for "h" input. It's not its ASCII code value, which was a false assumption by me.
I also got this output for "5.6" input.
I worked out that the issue lays somewhere in the if() part in the main() function, as the tizAlatti function gets invoked in the main for an input, but I don't know what this problem exactly is. Any help is highly appreciated!
I am encountering UB in the terminal with my current code when the input contains comma, dot or non-only-numeric character.
Neither scanf("%d", &inputNumber) nor scanf("%f", &arr[i]); ever read these characters*1, so they remain in stdin until something does read them. This also blocks following input.
As scanf("%d", &inputNumber) and scanf("%f", &arr[i]) then do not assign inputNumber or arr[i], that value is indeterminant leading to subsequent trouble.
Check the return value of scanf() and if not 1, exit or use other code to read/consume the non-numeric input and try again.
Even better, use fgets() to read a line of user input and stop using scanf() until you know why it is bad.
*1 '.' as a decimal point is read by scanf("%f", &arr[i]).

How to de-allocate an array of characters in c?

I'm writing a program that asks the number of strings which i'll then count how many spaces it has.
My problem is when I start a new cycle I can't allocate the array of characters I use to count the spaces.
Thanks in advance.
#include <stdio.h>
#include <string.h>
int main(){
char a[20];
int x, z, esp=0, num;
scanf("%d\n", &num);
int array[num];
for (int i=0;i<num;i++){
scanf("%[^\n]", &a);
z =strlen(a);
for (x=0; x<=z; x++){
if (a[x] == ' '){
esp++;
}
}
array[i] = esp;
esp =0;
}
for (int i=0;i<num;i++){
printf ("%d\n", array[i]);
}
return 0;
}
Problems:
Not having all warnings enabled. Save time, enable them all.
'\n' blocks for more input in scanf("%d\n", &num);
Not checking scanf() return value.
Not limiting input with a width in scanf("%[^\n]", &a);
Wrong type passed in scanf("%[^\n]", &a);
Big one: not consuming the end-of-line with repeated scanf("%[^\n]", &a); calls.
Perhaps more.
Repaired code:
// scanf("%d\n", &num);
if (scanf("%d", &num) != 1) { // '\n' removed
puts("Error1");
return -1;
}
// scanf("%[^\n]", &a);
if (scanf(" %19[^\n]", a) != 1) { // ' ' consumes white-space like \n
puts("Error2");
return -1;
}
On the first scanf, remove \n character, after the first scanf, add getchar() to consume new line character.
Replace second scanf with gets;
Then it will work correctly.
By the way, since gets is unsafe, you can use fgets with stdin parameter and max character count parameter instead of gets.
Thanks to everyone who commented and answered my question, I think I wasn't able to explain myself properly. It's a code which reads a number, the number of the lines of characters which then it'll count the spaces of; my problem started when the code executes a new cycle in which this scanf didn't let me enter the string of characters again: scanf("%[^\n]", &a), but did everything else in the cycle while using the same string.
I'm really new to this, coding and the page itself so thanks for the advices. I was able to find a solution: scanf("%[^\n]%*c, &a)
%*[^\n] scans everything until a \n, but doesn't scan in the \n. The asterisk(*) tells it to discard whatever was scanned.
%*c scans a single character, which will be the \n left over by %*[^\n] in this case. The asterisk instructs scanf to discard the scanned character.
And here is the updated code:
#include <stdio.h>
#include <string.h>
int main(){
char a[20];
int x, z, esp=0, num;
scanf("%d\n", &num);
int array[num];
for (int i=0;i<num;i++){
scanf("%[^\n]%*c", &a);
z =strlen(a);
for (x=0; x<=z; x++){
if (a[x] == ' '){
esp++;
}
}
array[i] = esp;
esp =0;
}
for (int i=0;i<num;i++){
printf ("%d\n", array[i]);
}
return 0;
}

Getting undesired result by using while loop to find the sum of n natural numbers

I am attaching the code for the same.Its working fine.But once i enter a number less than the previous one it stops giving desired output.Any help/suggestion shall be greatly appreciated.
int i=1;
int j=0;
int n;
char ch;
while(ch!='n')
{
printf("Enter the number upto which you want the sum of \n \n");
scanf("%d",&n);
while(i<=n)
{
j=j+i;
i++;
}
printf("%d \n",j);
printf("Do it with another number? Y/N \n \n");
scanf("%s",&ch);
}
return 0;
In your outer while loop, you're never resetting the value of the variable i back to 1, or j back to 0. That is why subsequent loops will produce an incorrect sum.
There are a smattering of bugs in this code, including:
Comparison to uninitialized value of of ch in the initial while expression.
Failing to reset i and j for each outer-loop iteration
Failing to test for data-read success in either scanf call to ensure proper input.
The continuation scanf("%s", &ch) is simply wrong for a single character with skipped whitespace (which you must do to avoid reading the newline after your list integer input). Unless EOF or an error state is reached, what you have now is guaranteed to invoke undefined behavior, as a string-read of at least one character requires at least two for storage (the character, and a subsequent terminator).
Addressing all of those:
#include <stdio.h>
int main()
{
char ch;
do
{
int n;
printf("Enter the number upto which you want the sum of \n \n");
if (scanf("%d", &n) != 1) // See (3)
break;
int j = 0; // See (2)
for (int i = 1; i <= n; ++i) // See (2)
j += i;
printf("%d \n", j);
printf("Do it with another number? Y/N \n \n");
if (scanf(" %c", &ch) != 1) // See (3) and (4)
break;
} while (ch != 'n' && ch != 'N'); // See (1)
return 0;
}
Everything here is self-explanatory when referred to the previous bug punch list, save for maybe the format string for reading the single character. You mentioned in comments that you tried %c but it skipped to another loop iteration. That's because you didn't have the leading whitespace " %c" that tells scanf to skip white space before extracting the next argument. With that, it should work as desired.
You need to reset i and j for every n.
i = 1;j=0;
while(i<=n)
{
Also your format specifer is wrong. For char, it should be %c and not %s
scanf("%c",&ch);
The simplest solution is to set i to 0 at the outer while:
int i=1;
int j=0;
int n;
char ch;
while(ch!='n')
{
i = 0;
printf("Enter the number upto which you want the sum of \n \n");
scanf("%d",&n);
while(i<n)
{
j=j+i;
i++;
}
printf("%d \n",j);
printf("Do it with another number? Y/N \n \n");
scanf("%s",&ch);
}
return 0;
Note that I have changed <= to < for your inner while, since you do not want to increment the value if the same n is inputted one after the other.
#include<stdio.h>
int main(){
int n;
char ch;
while(ch!='n')
{
printf("Enter the number upto which you want the sum of \n \n");
scanf("%d",&n);
int i=1;//it should be 1 in every loop of the number
int j=0;//the sum should also be initialized to zero to erase the previous value
while(i<=n)
{
j=j+i;
i++;
}
printf("%d \n",j);
printf("Do it with another number? Y/N \n \n");
scanf("%c",&ch);//this is a char not a string
}
return 0;
}
Due to the i is not initializing to 1 when the loop is coming for the second time there it is not going inside the loop and printing the previous value .

Inputting array in C

Basically I have a C program where the user inputs a number (eg. 4). What that is defining is the number of integers that will go into an array (maximum of 10). However I want the user to be able to input them as "1 5 2 6" (for example). I.e. as a white space delimited list.
So far:
#include<stdio.h>;
int main()
{
int no, *noArray[10];
printf("Enter no. of variables for array");
scanf("%d", &no);
printf("Enter the %d values of the array", no);
//this is where I want the scanf to be generated automatically. eg:
scanf("%d %d %d %d", noArray[0], noArray[1], noArray[2], noArray[3]);
return 0;
}
Not sure how I might do this?
Thanks
scanf automatically consumes any whitespace that comes before the format specifier/percentage sign (except in the case of %c, which consumes one character at a time, including whitespace). This means that a line like:
scanf("%d", &no);
actually reads and ignores all the whitespace before the integer you want to read. So you can easily read an arbitrary number of integers separated by whitespace using a for loop:
for(int i = 0; i < no; i++) {
scanf("%d", &noArray[i]);
}
Note that noArray should be an array of ints and you need to pass the address of each element to scanf, as mentioned above. Also you shouldn't have a semicolon after your #include statement. The compiler should give you a warning if not an error for that.
#include <stdio.h>
int main(int argc,char *argv[])
{
int no,noArray[10];
int i = 0;
scanf("%d",&no);
while(no > 10)
{
printf("The no must be smaller than 10,please input again\n");
scanf("%d",&no);
}
for(i = 0;i < no;i++)
{
scanf("%d",&noArray[i]);
}
return 0;
}
You can try it like this.

Using an array to decode numbers to letters

For my task I have to print numbers to the screen and decode them into their specific letters. I'm using only the letters a-l in this code just to keep it simple so I can understand it.
The problem I'm having is that when I, for example, put in the number 0 which corresponds to the first entry to the array which is a, it will take out a and print b-l.
How do I make it so if I put in the number 0, the code will print only a to the screen?
#include <stdio.h>
int main()
{
char code[] = "abcdefghijkl";
int i, j, k;
printf("how many letters does your code contain?: ");
scanf("%d", &j);
for(i=0; i<j; ++i){
printf("enter a number between 0 and 11\n");
scanf("%d", &k);
printf("%s\n", &code[k]);
}
}
You print only the character at that location, so change
printf("%s\n", &code[k]);
to
printf("%c\n", code[k]);
You should also check that the value you read into k is >= 0 && < 11 , otherwise you'll access the array outside its bounds.
%s format specifier is used for printing strings, you need to use %c specifier which prints a character to the screen.
printf("%c\n", code[k]); instead of printf("%s\n", &code[k]);

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