I am currently using an interrupt to reset an ATTiny20. Here is the relevant code:
int main(void)
{
...
// Set up interrupt for reset button (PCINT5)
SREG |= 1<<7; // Enable global interrupts
GIMSK |= 1<<PCIE0; // Enable Pin Change Interrupt 0 (enables interrupts on PCINT[7:0]
PCMSK0 |= 1<<PCINT5; // Enable PCINT5 (physical pin 8) interrupt
...
}
The interrupt-handling function:
ISR(PCINT0_vect)
{
if (!(BUTTON_1_PORT & 1<<BUTTON_1_PIN)) // Only reset if button is pushed
{
wdt_enable(WDTO_2S);
while(1){};
}
}
This works quite well - when the button is pushed the system freezes for 2 seconds and then resets... and promptly gets stuck in a reset loop. A bit of googling uncovered the culprit: on newer chips the watchdog timer is left enabled (at its shortest delay setting) after a watchdog reset. The following code is meant to remedy this issue:
// Disable watchdog on reset
void wdt_init(void) __attribute__((naked)) __attribute__((section(".init3")));
void wdt_init(void)
{
// MCUSR = 0; // See below for reason for commenting this line
wdt_disable();
return;
}
*N.B. MCUSR = 0 is commented out because MCUSR does not exist on the ATTiny20. I have tried replacing it with SREG = 0 but to no avail.
Even with this code in place, which should disable the watchdog timer, the issue persists. Flashing LEDs on the device indicate that the program is running through part of the main() function before it resets, but putting wdt_disable(); at the top of main() has not helped either.
Is there something critical that I'm missing re: the ATTiny20? Something I've missed in the datasheet? The problem - and solution - seem so obvious, but I'm stumped. I'm using Atmel Studio 6.1.
// Disable watchdog on reset
void wdt_init(void) __attribute__((naked)) __attribute__((section(".init3")));
void wdt_init(void)
{
// This is the flag that must be cleared on an ATTiny20 before the WDT can be disabled
/***************/
/* RSTFLR = 0; */
/***************?
wdt_disable();
return;
}
Related
Every time I enable the timer it instantly activates the Interrupt. No matter how I try to prescale it. only ARR seems to work but 16 bit with 0,5MHz clock gives me ~160ms maneuver.
#define SYSCLK_FREQ 524288
void timer_init(uint16_t detonation_delay_ms);
int main(void){
RCC->APB2ENR = RCC_APB2ENR_TIM22EN;
TIM22->PSC = (SYSCLK_FREQ/1000)-1;
NVIC_EnableIRQ(TIM22_IRQn);
NVIC_SetPriority(TIM22_IRQn,4);
}
/* calling function */
timer_init(65535);
/* calling function */
void timer_init(uint16_t detonation_delay_ms){
TIM22->CR1 &= ~TIM_CR1_CEN;
TIM22->SR=0;
TIM22->ARR = detonation_delay_ms;
TIM22->CR1 |= TIM_CR1_CEN;
TIM22->SR = 0;
}
void TIM22_IRQHandler(void){
TIM22->CR1 &= ~TIM_CR1_CEN;
TIM22->SR=0;
GPIOB->BSRR = GPIO_BSRR_BS_7;
}
I wish that calling function makes the timer tick till the called value in milisec. But no matter how I set it up it ends up with no scaled timer and instant interrupt after calling it.
Correct way to do it?
TIM22->DIER = TIM_DIER_UIE;
TIM22->ARR = 65535-detonation_delay_ms;
TIM22->EGR = TIM_EGR_UG;
TIM22->CR1 |= TIM_CR1_OPM | TIM_CR1_CEN;
TIM22->SR=0;
Do not delay in interrupts
you enable the timer then set the ARR which is wrong - first set ARR and prescaller, then generate the UG event using the EGR register, then enable the timer.
Works like a charm. Just because I got help here will describe for future interested people.
The way to get the interrupt working for the timers is to generate interrupt 'by hand' once. It's okay to do it because you can control what's happening during the interrupt by a single 'if'.
/* TIMER Enable */
RCC->APB2ENR = RCC_APB2ENR_TIM22EN;
I had a problem with the above declaration, dunno why but it wasn't working after declaring some more modules before it. Had to put it on higher on the list. Manual does not say why it happened.
/* Configure TIM22 interrupt */
TIM22->PSC = (SYSCLK_FREQ/1000)-1; /* Prescaler TIMERA 22 */
TIM22->DIER = TIM_DIER_UIE;
TIM22->CNT = 0;
TIM22->EGR = TIM_EGR_UG;
NVIC_EnableIRQ(TIM22_IRQn); /* Zalaczenie przerwania od TIMER'a */
NVIC_SetPriority(TIM22_IRQn,4); /* Ustawienie priorytetu przerwania od TIMER'a */
The prescaler meant to be 1ms so I divided 524288 of my core speed. Then enabling the interrupt, resetting the counter to make sure it starts from 0 and then manually generating the interrupt. And it does the interrupt 'loop' once but with a single 'if' and variable, I can control what it does.
So what I do, I am calling a function that set the clock and enables the count inside another function enable = 1; timer_init(ms);
Then comes the function call
void timer_init(uint16_t ms)
{
TIM22->CNT = 65535-ms;
TIM22->CR1 |= TIM_CR1_CEN;
}
void TIM22_IRQHandler(void)
/* Up-Counter milisec */
{
if(TIM22->CR1 & TIM_CR1_CEN) {TIM22->CR1 &= ~TIM_CR1_CEN;}
if(TIM22->SR & TIM_SR_UIF) {
if(enable == 1){
GPIOB->BSRR = GPIO_BSRR_BS_7;
}
}
TIM22->SR=0;
}
And the interrupt.
Thanks a lot!Have fun with registers!
I have set up a project using a 16-bit Microcontroller called Thunderbird12, similar to the 9s12/Freescale 68HC12 family. It does a few things but mainly turn on an external water pump. Everything works fine except I need to implement an interrupt. I want to be able to stop the motor using an interrupt through a push button.
I have set up the button which sets pin 0 of port P to high when pressed. Using C, I have initialized the hardware and written the code but the flag is not called. Please see code below.
// Interrupt function
int interruptFlag;
void interrupt 56 WaterPumpRoutine() {
if ((PIFP & 0x01) == 0x01) { // check if pin 0 of port p is high (when button is pressed)
interruptFlag = 1; // set the flag to 1
}
// Main
void main() {
DDRP = 0x00; // set port P as input
PIEP = PIEP | 0x01; // enable interrupts on port P, pin 0
PERP = PERP | 0x01; // enable pull-up/down on port P, pin 0
if ( interruptFlag == 1)
PORTB = (PORTB & 0x00) // Here I'm turning off all the pins in Port B, which includes the pump.
}
If I put this code PORTB = (PORTB & 0x00) inside the WaterPumpRoutine() function, it works fine, but I need to be able to call the flag anywhere. I'm not sure what I'm missing. Any help would be appreciated!
Assuming that the interrupt call works fine..
Change the variable int interruptFlag; to volatile int interruptFlag;. This is to avoid optimizing away the if condition in main by the compiler.
In main you need to reset the interruptFlag on some condition. This is program dependent. Maybe you can do it like this.
if ( interruptFlag == 1)
{
PORTB = (PORTB & 0x00) // Here I'm turning off all the pins in Port B, which includes the pump.
interruptFlag = 0;
}
If you are using a push button, you should introduce a debounce mechanism to avoid detecting multiple inputs.
You need to add the if condition in main inside a while(1) loop as the interrupt can come at any time.
while(1)
{
if(interruptFlag == 1)
{
...
}
}
If u still can't get interrupt to fire , after things that other suggested, you should check if you got global interrupts or interrupt for specific part (GPIO) enabled since in most uc setting GPIO to generate interrupts doesn't enable interrupts
I'm new to PIC programming and I'm using MPLAb. I have a question regarding interrupt..
so What I want to do, when I push a button then I want to turn on LED 0, and if I release the button then turn on LED 1. I thought the code I wrote making sense but it didn't work.
Here is what happens. Let say the initial state of interrupt pin is low (0), when a button is pushed. Then the LED 0 is on, and when I release the button then LED 1 is on. When I push the button again, I expect LED 0 is on, but LED 1 stays on, and never change the state.
I added last line to see the state of interrupt pin, and once the interrupt is high, it never change it to low.. Can you please advise me what is my misunderstanding?
Thanks in advance!
Here is my code:
void interrupt ISR(void)
{
if(INTCONbits.INTF)
{
nextLED = 1;
LATC = Output_Code_Buffer[nextLED];
__delay_ms(250);
}
else
{
nextLED = 0;
LATC = Output_Code_Buffer[nextLED];
__delay_ms(250);
}
nextLED = INTCONbits.INTF + 2;
LATC = Output_Code_Buffer[nextLED];
__delay_ms(250);
}
// Interrupt Enable settings
INTCONbits.INTE = 1;
INTCONbits.TMR0IE = 1; // Enable TMR0 interrupts
INTCONbits.TMR0IF = 0; // Clear TMR0 interrupt flag
INTCONbits.GIE = 1; // Enable global interrupts
You need to reset the interrupt flag in the ISR function or it will just keep triggering. Please read the datasheet, it should mention if this is necessary. So just add INTCONbits.INTF = 0; to the ISR and it should work as expected.
When setting up any peripheral or function of the mcu, you should go through the datasheet and use the description of the registers and what to set them. You'll also need to be careful with analogue ports, which often default to analogue instead of digital, causing interrupt not to fire as expected or causing unexpected interrupts. It's best to first setup the MCU config bits, set the TRIS and analogue selection registers (ANSELx or ANSELAx etc), then the registers for any peripheral you want to use. Then setup the interrupts, always reset all the interrupt flags you're going to use to start with a known state.
You also set TMR0IE = 1, which will do the same thing, trigger an interrupt. If you don't reset the TMR0 flag it will keep triggering, locking up your mcu or slow it down.
I have been looking all of for an answer to this problem and have not been able to find anything. When my ISR is triggered, it goes through and does everything that it is supposed to perfectly fine, then before exiting and returning back to the main loop the ISR executes again. Once it has gone though the second time it then returns back to the main loop. This only happens when I use a 115V relay to operate the interrupt.
I am trying to detect when there is a power outage or when the power comes back on. I am using a Pin change interrupt to sense if the relay is closed or open. When the power goes out the relay will open and will trigger the ISR. If I connect this setup to a normal push button or switch everything works as needed and there is no problem, it is only when it is connected to the relay that there is a problem.
Here is the code that I have:(I know I don't need cli I have just been trying everything)
ISR(PCINT2_vect){
cli();
sbi(PORTC,5);
_delay_ms(6000);
cbi(PORTC,5);
for(delay_counter=0;delay_counter<2;delay_counter++)
{
_delay_ms(6000);
}
sbi(PORTC,5);
_delay_ms(6000);
if(bit_is_set(PIND,2))
{
lcd_clrscr();
lcd_puts("Sending SMS");
usart_print("at");
USART_Transmit('\r');
_delay_ms(6000);
for(i=0;i<=1;i++)
{
usart_print("at*smsm2m=");
USART_Transmit('"');
for(j=0;j<11;j++)
{
USART_Transmit(Alert_Numbers[i][j]);
}
usart_print(" Power has been lost");
USART_Transmit('"');
USART_Transmit('\r');
_delay_ms(6000);
}
lcd_clrscr();
lcd_puts("SMS Sent");
_delay_ms(6000);
lcd_clrscr();
lcd_puts("Status:NO POWER");
cbi(PORTC,5);
}
else if(bit_is_clear(PIND,2))
{
lcd_clrscr();
lcd_puts("System Reset");
_delay_ms(6000);
_delay_ms(6000);
usart_print("at");
USART_Transmit('\r');
_delay_ms(6000);
for(i=0;i<=1;i++)
{
usart_print("at*smsm2m=");
USART_Transmit('"');
for(j=0;j<11;j++)
{
USART_Transmit(Alert_Numbers[i][j]);
}
usart_print(" Pump regained power");
USART_Transmit('"');
USART_Transmit('\r');
_delay_ms(6000);
}
lcd_clrscr();
lcd_puts("POWER ON");
_delay_ms(6000);
lcd_clrscr();
lcd_puts("Status: Good");
}
else
{
}
}
int main(void)
{ /*Initializations*/
DDRC = 0x20; // PORTC,5 is now output
sbi(PORTC,5);
USART_Init(51);
lcd_init(LCD_DISP_ON);
lcd_clrscr();
/*Set interrupts*/
DDRD = 0b11111011; // set PD2 to input
PORTD = 0b00000100; // set PD2 to high
PCICR |= (1 << PCIE0);
PCMSK0 |= (1 << PCINT0);
PCICR |= (1<<PCIE2);
PCMSK2 |= (1<<PCINT18);
sei();
lcd_clrscr();
lcd_puts("Status: Good");
/*Main Program Loop: NOP*/
while(1)
{
lcd_clrscr();
lcd_puts("MAIN LOOP");
for(delay_counter=0;delay_counter<3;delay_counter++)
{
_delay_ms(6000);
}
}
}
I am using a Pin change interrupt to sense if the relay is closed or
open.
Don't do that. Seriously. Do not try to hook mechanical switches to an interrupt pin to trigger ISRs.
If you insist on doing so, at least make sure the switch's signal is decently debounced in hardware before it hits the µC's input pin.
Besides, waiting of any kind (_delay_ms(6000);) is not something one wants to have in an ISR.
The reason your code fails: When the signal is bouncing, even if you wait 6 seconds in your interrupt, the flag is set again (while you are still in your ISR). The quick and dirty solution would be to reset the flag just before you exit the ISR.
Two (in my opinion) better solutions:
If you want to do this in software, just set a variable in the ISR routine which indicates a event. Then, in your main loop (or in a function), do the debouncing of the relais (10 to 100ms should be enough).
if you want to do this in hardware, just add a R C combination as a filter to the pin (the c to ground and the r to the relais. Just try some combinations like 100k and 10µF.
My personal recommendation:
do both ;)
Annotations:
- using a 6 second delay in an interrupt routine is really a bad practice. Better: Use a Timer which is called every say 10 ms and increase a counter if the flag is set and the relais indicate power loss. If the relais has power, reset the flag and counter to 0. If the counter reaches 600, this means the power outage is longer than 6 seconds.
Have fun!
I had the problem myself, so I decided to answer it even though it is an old entry:
The reason why the interrupt fires twice is that the interrupt flag is not reset. This is a problem of some atmega types. You can solve the problem by one simple line:
Post this at the very end of you ISR interrupt function:
PCIFR |= (1<<PCIF2);
This will write a "1" into the interrupt-flag bit for the PCINT2 interrupt. If you are using other Interrupts, you have to set other flags to 1. Notice that the interrupt flag is inverted. So a 1 disables the interrupt, whereas a 0 triggers the interrupt.
Have a look into the datasheet:
http://www.atmel.com/images/doc2545.pdf
See Point 13.2.5:
Bit 2 - PCIF2: Pin change interrupt flag 2 -
When a logic change on any PCINT23..16 pin triggers an interrupt request, PCIF2 becomes set
(one). If the I-bit in
SREG and the PCIE2 bit in PCICR are
set (one), the MCU will jump to the
corresponding Interrupt Vector. The flag is cleared
when the interrupt routine is executed. Alternatively, the flag can be cleared by writing a logical one to it.
I hope this helped you and maybe some other people who have the same problem. Just search the datasheet for the name of the register and the bit corresponding to the interrupt flag and set it to 1.
Bye
I am programming a AVR MCU.
It has a POT that reads off an analogue pin. It seems that the interrupt is constantly called, and it must be called during a LCD_display method as it is messing with my LCD.
Is there a way to STOP the inturrupts until after the block is run?
int main(void)
{
/*Turn on ADC Interrupt */
ADCSRA |= (1 << ADIE);
/*Turn On GLobal Interrupts*/
sei();
/* Intalise LCD */
lcd_init(LCD_DISP_ON); /* initialize display, cursor off */
lcd_clrscr();
lcd_puts("READY");
DDRB &= ~(1 << PINB5); //set input direction
ADC_Init(128, 0); //initalize ADC
while (1)
{
if (!bit_is_clear(PINB, 5))
{
_delay_ms(500);
if (!pressed)
{
lcd_gotoxy(0,0);
lcd_clrscr();
lcd_puts("test"); //Doesnt work unless I dont comment out the last line of interrupt
pressed = 1;
}
}
/* INTERRUPTS */
//ADC INTERRUPT
ISR(ADC_vect)
{
char adcResult[4];
uint8_t theLowADC = ADCL;
uint16_t theTenBitResults = ADCH<<8 | theLowADC;
itoa(theTenBitResults, adcResult, 10);
ADCSRA |= (1 << ADSC); //next conversion *if i comment out this line it works*
}
If the interrupt handler behaves bad with your code, the reason could be you spend too much time in the interrupt handler. You should only do critical work in the interrupt handler and defer the less critical work in the application code; use a volatile flag shared between the handler and the application code to let the application code know if it has work to do. In your example, you should defer the itoa call in the application code.
Use cli(); to disable interrupts and sei(); to enable them again after you finished the display routine.
Which MCU are you using? You should propably use a timer instead of a delay of 500ms.
I believe, I am little late but still I had the same issue I solved it using the following method,
Interrupts are enabled using two flags
1.A global interrupt flag
2.A module related interrupt flag (in your case ADC)
You can have control over module related flag, in your case in the ADCSRA control register there is a flag named ADIE- ADC Interrupt Enable flag you can use that to control the Interrupts.
For example,
In main function you can enable the flag and in ISR disable the flag.
main()
{
//enable global flag and ADC flag
while(1)
{
//your logic
// enable ADC flag
}
}
ISR()
{
//disable the ADC flag
}
I hope this solves the issue you are having.