Please consider the following documentation:
http://livedocs.adobe.com/coldfusion/8/htmldocs/help.html?content=CFScript_11.html#1161053
I'm studying the description of following code:
<cfscript>
//Set the variables
acceptedApplicants[1] = "Cora Cardozo";
acceptedApplicants[2] = "Betty Bethone";
acceptedApplicants[3] = "Albert Albertson";
rejectedApplicants[1] = "Erma Erp";
rejectedApplicants[2] = "David Dalhousie";
rejectedApplicants[3] = "Franny Farkle";
applicants.accepted=acceptedApplicants;
applicants.rejected=rejectedApplicants;
rejectCode=StructNew();
rejectCode["David Dalhousie"] = "score";
rejectCode["Franny Farkle"] = "too late";
The description says that, "Creates two one-dimensional arrays, one with the accepted applicants and another with the rejected applicants. "
I'm new to ColdFusion and I don't see any array declaration using the array keyword in the above code just like the following doc:
http://livedocs.adobe.com/coldfusion/8/htmldocs/help.html?content=arrayStruct_03.html#1121128
Please explain.
You need to initialize your acceptedApplicants and rejectedApplicants arrays
There should be
acceptedApplicants = [];
rejectedApplicants= [];
somewhere above in the code. Like Peter said, if this is in a function make sure you var those variables.
Related
I have to arrays and I have to find difference values from it.
Here is my Laravel Controller code
$product_list = Operation::where('kvit_id', $kvit->id)->pluck('product_id')->toArray();
$hamkor_products = ListProduct::where('user_id', $newkvit->user_id)->pluck('product_id')->toArray();
$operProductList = array_diff($product_list, $hamkor_products);
dd($product_list, $hamkor_products, $operProductList);
Here is result which I'm getting
What kind of mistake I made? $operProductList is returns []
You must just change the order of parameters in array_diff(), it must be like :
$product_list = Operation::where('kvit_id', $kvit->id)->pluck('product_id')->toArray();
$hamkor_products = ListProduct::where('user_id', $newkvit->user_id)->pluck('product_id')->toArray();
$operProductList = array_diff($hamkor_products, $product_list);
dd($product_list, $hamkor_products, $operProductList);
1.I have this array and i want to extract only the "rate" values.
I want y Array to look like this
array = [6,355.1675 , 4,826.3112 , 5,429.8488]
[{
code = USD;
description = "United States Dollar";
rate = "6,355.1675";
"rate_float" = "6355.1675";
symbol = "$";
}, {
code = GBP;
description = "British Pound Sterling";
rate = "4,826.3112";
"rate_float" = "4826.3112";
symbol = "£";
}, {
code = EUR;
description = Euro;
rate = "5,429.8488";
"rate_float" = "5429.8488";
symbol = "€";
}]
It looks like you have JSON that contains an array of dictionaries.
Write some code that:
Decodes the JSON into native objects. At the simplest it would be converted to an array of dictionaries.
You could then write code that loops through the array, extracts the rate value for each array entry, and prints it.
As others have said, you could do this with a map statement, but if you're new to programming then the for loop approach is easier to understand.
If you array is called array, then you can do it this way:
array.map { print ($0["rate"] }
Up until now I have been creating var inside the classes I made. e.g.
var backpack:Array = new Array("food", "water");
I want to create objects dynamically now like:
player = {};
player.backpack = ("food", "water"); // not the right syntax
OR
player = {backpack:Array = new Array("food", "water")} // not right either.
Any help? Thanks in advance. I can do this with simple vars like int, but can't find the answer to arrays.
ActionScript's generic object properties don't have any variable type associated with them. You assign them one of the following ways.
Example 1
player = {backpack: new Array("food", "water")};
Example 2
player.backpack = new Array("food", "water");
Example 3
player["backpack"] = new Array("food", "water");
You can use square brackets to define literal arrays. Not only is it shorter, but it's also faster (see this post).
The correct syntax for your two examples are
player = {};
player.backpack = ["food", "water"];
and
player = {backpack: ["food", "water"]};
Also, if you find it easier, you can use it in the first line of code you wrote.
var backpack:Array = ["food", "water"];
I’m new to Swift and have been having some troubles figuring out some aspects of Arrays and Dictionaries.
I have an array of dictionaries, for which I have used Type Aliases - e.g.
typealias myDicts = Dictionary<String, Double>
var myArray : [myDicts] = [
["id":0,
"lat”:55.555555,
"lng”:-55.555555,
"distance":0],
["id":1,
"lat": 44.444444,
"lng”:-44.444444,
"distance":0]
]
I then want to iterate through the dictionaries in the array and change the “distance” key value. I did it like this:
for dict:myDicts in myArray {
dict["distance"] = 5
}
Or even specifically making sure 5 is a double with many different approaches including e.g.
for dict:myDicts in myArray {
let numberFive : Double = 5
dict["distance"] = numberFive
}
All my attempts cause an error:
#lvalue $T5' is not identical to '(String, Double)
It seems to be acting as if the Dictionaries inside were immutable “let” rather than “var”. So I randomly tried this:
for (var dict:myDicts) in myArray {
dict["distance"] = 5
}
This removes the error and the key is indeed assigned 5 within the for loop, but this doesn't seem to actually modify the array itself in the long run. What am I doing wrong?
The implicitly declared variable in a for-in loop in Swift is constant by default (let), that's why you can't modify it directly in the loop.
The for-in documentation has this:
for index in 1...5 {
println("\(index) times 5 is \(index * 5)")
}
In the example above, index is a constant whose value is automatically
set at the start of each iteration of the loop. As such, it does not
have to be declared before it is used. It is implicitly declared
simply by its inclusion in the loop declaration, without the need for
a let declaration keyword.
As you've discovered, you can make it a variable by explicitly declaring it with var. However, in this case, you're trying to modify a dictionary which is a struct and, therefore, a value type and it is copied on assignment. When you do dict["distance"] = 5 you're actually modifying a copy of the dictionary and not the original stored in the array.
You can still modify the dictionary in the array, you just have to do it directly by looping over the array by index:
for index in 0..<myArray.count {
myArray[index]["distance"] = 5
}
This way, you're sure to by modifying the original dictionary instead of a copy of it.
That being said, #matt's suggestion to use a custom class is usually the best route to take.
You're not doing anything wrong. That's how Swift works. You have two options:
Use NSMutableDictionary rather than a Swift dictionary.
Use a custom class instead of a dictionary. In a way this is a better solution anyway because it's what you should have been doing all along in a situation where all the dictionaries have the same structure.
The "custom class" I'm talking about would be a mere "value class", a bundle of properties. This was kind of a pain to make in Objective-C, but in Swift it's trivial, so I now do this a lot. The thing is that you can stick the class definition for your custom class anywhere; it doesn't need a file of its own, and of course in Swift you don't have the interface/implementation foo to grapple with, let alone memory management and other stuff. So this is just a few lines of code that you can stick right in with the code you've already got.
Here's an example from my own code:
class Model {
var task : NSURLSessionTask!
var im : UIImage!
var text : String!
var picurl : String!
}
We then have an array of Model and away we go.
So, in your example:
class MyDict : NSObject {
var id = 0.0
var lat = 0.0
var lng = 0.0
var distance = 0.0
}
var myArray = [MyDict]()
let d1 = MyDict()
d1.id = 0
d1.lat = 55.55
d1.lng = -55.55
d1.distance = 0
let d2 = MyDict()
d2.id = 0
d2.lat = 44.44
d2.lng = -44.44
d2.distance = 0
myArray = [d1,d2]
// now we come to the actual heart of the matter
for d in myArray {
d.distance = 5
}
println(myArray[0].distance) // it worked
println(myArray[1].distance) // it worked
Yes, the dictionary retrieved in the loop is immutable, hence you cannot change.
I'm afraid your last attempt just creates a mutable copy of it.
One possible workaround is to use NSMutableDictionary:
typealias myDicts = NSMutableDictionary
Have a class wrapper for the Swift dictionary or array.
class MyDictionary: NSObject {
var data : Dictionary<String,Any>!
init(_ data: Dictionary<String,Any>) {
self.data = data
}}
MyDictionary.data
I'm curious, is there another way to convert a struct into an array in Coldfusion without looping over it? I know it can be done this way if we use a for in loop:
local.array = [];
for (local.value in local.struct)
{
arrayAppend(local.array, local.value);
}
Does StructKeyArray suit your requirements?
Description
Finds the keys in a ColdFusion
structure.
If you are trying to maintain order in your structure you could always use a Java LinkedHashMap like so:
cfmlLinkedMap = createObject("Java", "java.util.LinkedHashMap").init();
cfmlLinkedMap["a"] = "Apple";
cfmlLinkedMap["b"] = "Banana";
cfmlLinkedMap["c"] = "Carrot";
for(key in cfmlLinkedMap){
writedump(cfmlLinkedMap[key]);
}
You could also do the same thing in a more "java" way not sure why you'd want to but its always an option:
//no need to init
linkedMap = createObject("Java", "java.util.LinkedHashMap");
//java way
linkedMap.put("d","Dragonfruit");
linkedMap.put("e","Eggplant");
linkedMap.put("f","Fig");
//loop through values
iterator = linkedMap.entrySet().iterator();
while(iterator.hasNext()){
writedump(iterator.next().value);
}
//or
//loop through keys
iterator = linkedMap.keySet().iterator();
while(iterator.hasNext()){
writedump(linkedMap.get(iterator.next()));
}
Just remember that the keys are case SeNsItIvE!
In Coldfusion 10 or Railo 4, if you want an array of values (instead of keys), you can use the Underscore.cfc library like so:
_ = new Underscore();// instantiate the library
valueArray = _.toArray({first: 'one', second: 'two'});// returns: ['one','two']
Note: Coldfusion structures are unordered, so you are not guaranteed to have any specific order for the values in the resulting array.
(Disclaimer: I wrote Underscore.cfc)