Using the make command without makefiles? - c

I was compiling some C code for an assignment and I ran "make codeFile", where "codeFile" was the name of my C program, and even though I didn't have a makefile, an executable was created, and it ran and worked correctly.
Does anyone know why this worked? Why does make compile something even if I don't have a makefile? The only reference I could find was this:
http://daly.axiom-developer.org/TimothyDaly_files/class5/node5.html

Make has an internal database with implicit rules. You can use make -p to list them. Also make -d will tell you which rules are being applied, so that would help you discover which implicit rules are being used in this case.

Make has several pre-defined implicit rules. In particular, in your case, it uses two such rules when trying to determine what to do for the target codeFile:
%: %.o # Link object file
$(CC) $(LDFLAGS) n.o $(LOADLIBES) $(LDLIBS)
%.o: %.c # Compile C source code
$(CC) $(CPPFLAGS) $(CFLAGS) -c

Using the make command without makefiles?
make has implicit rules that work as defaults unless you override them.
According to the make man page:
make -p -f/dev/null
will list all of the implicit rules (and relevant environment variables) without attempting to actually remake files.
To demonstrate the usage, I ran make in Cygwin, which gave me an exe file. Note no .c on the name passed to make:
$ ls
hello.c
$ make hello
cc hello.c -o hello
$ ls
hello.c hello.exe
I also ran this in Ubuntu Linux, and my result was nearly the same as above, but the .exe extension was not there, instead I had the plain hello executable:
$ ls
hello.c hello
Step by step derivation
I believe the relevant pieces of the make implicit rules are as follows:
CC = cc
cc is aliased to CC
LINK.c = $(CC) $(CFLAGS) $(CPPFLAGS) $(LDFLAGS) $(TARGET_ARCH)
a LINK format is created, where the flags will be empty, and the TARGET_ARCH variable is also empty (to allow users to set values for various target architectures.) Then we have:
%: %.c
# recipe to execute (built-in):
$(LINK.c) $^ $(LOADLIBES) $(LDLIBS) -o $#
The ^ variable is the prerequisite, hello.c. The other variables are empty. These are followed by the -o flag and the target name. The empty variables explain the extra spaces in the command make ran:
cc hello.c -o hello
And the %: %.c matched the target given to make with the filename of the same target name ending in .c, which caused the recipe to execute.

Related

Makefile: "ld: can't link with a main executable file" in C

I am trying to compile two c files, calutil.c and calutil.h into one executable. Here is my makefile:
CC = gcc
CFLAGS = -Wall -std=c11 -DNDEBUG
all: caltool
caltool: calutil.o caltool.o
$(CC) $(CFLAGS) calutil.o caltool.o
caltool.o: caltool.c
$(CC) $(CFLAGS) caltool.c -o caltool.o
calutil.o: calutil.c
$(CC) $(CFLAGS) -c calutil.c -o calutil.o
clean:
rm -rf *.o *.out
calutil.c has no main, while caltool.c has a main. I get the error
ld: can't link with a main executable file when I make. What is the cause of this?
The main problem is that some your recipe for linkage is missing the output file, and that your compilation is missing -c.
In case you're using GNU make, the following Makefile would be sufficient to do what you want to do:
CFLAGS:=-Wall -std=c11
CPPFLAGS:=-DNDEBUG
.PHONY: all
all: caltool
caltool: caltool.o calutil.o
.PHONY: clean
clean::
$(RM) *.o
Explanation:
When you're not using target-specific variables, you should use := instead of = to assign variables so that they're expanded at assignment and not at evaluation.
When your Makefile grows and you split it, you might want to have multiple targets called clean which all would be executed. In that case use clean:: instead of clean:.
There's a predefined variable to call rm, it is $(RM) and it includes the -f flag to prevent the Makefile from failing in case one or more of the files to be removed do not exist in the first place.
The pattern for clean should be *.[adios] (that's really easy to remember, adios is Spanish for goodbye) so that it removes intermediate archives (.a when you build your own static libraries), dependency files (.d), preprocessor output (.i) and assembler files (.s) in case you use -save-temps to see what the compiler is doing.
GNU make has built-in rules to compile and link, see http://git.savannah.gnu.org/cgit/make.git/tree/default.c?id=3.81
The built-in rule for compilation calls $(CC) $(CFLAGS) $(CPPFLAGS) $(TARGET_ARCH) -c -o $# $< so you don't need to write your own rule.
The built-in rule for linkage calls $(CC) $(LDFLAGS) $(TARGET_ARCH) $^ $(LOADLIBES) $(LDLIBS) -o $#
Targets which are not files themselves should be declared .PHONY to prevent confusion when a user creates a file with the same name, like all or clean.
I do not see how any of your commands would create a file matching the glob pattern *.out, so I removed that part of the clean rule.
Flags for the preprocessor should go into CPPFLAGS instead of CFLAGS. Preprocessor flags typically are all those -D and -I flags and would also be passed to other tools that use a C preprocessor in the same project, like splint or PC-Lint.
When the Makefile is run, it is looking how to make all, and it finds that for all it has to make caltool. For caltool it finds that it has to first make calutil.o and caltool.o. When it tries to make calutil.o and caltool.o, it finds that it can make them from calutil.c and caltool.c and will do so. Then it will link caltool.o and calutil.o into caltool.
From your naming I guessed that it's caltool.c that contains the main() function. It is helpful to place the object which contains main() first once you use static link libraries.
Edit: Here's some more magic for you. I assume that you have a header file calutil.h which is included by caltool.c to access extern symbols provided by calutil.c. You want to rebuild all objects that depend on these header files. In this case, add the following lines to your Makefile:
CPPFLAGS+=-MMD
-include caltool.d calutil.d
In order to not have the list of objects multiple times, you could add a variable objects like this:
objects:=caltool.o calutil.o
You would then build the application with this rule:
caltool: $(objects)
And include the dependency files like this:
-include $(objects:.o=.d)
In case you keep your working tree "clean", i.e. do not "pollute" it with "alien" code, i.e. you always want to include all .c files in your project, you can change the definition of objects as follows:
sources:=$(wildcard *.c)
objects:=$(sources:.c=.o)
In case you wonder why it is CPPFLAGS (uppercase) but objects (lowercase): it is common to use uppercase for all variables which configure the recipes of rules and control the built-in behavior of make, tools built on top of it, and classic environment variables, and lowercase variables for everything else.
I just removed the .o files from the directory, and edited my makefile to add -c to the caltool.o line.

Makefile for C Program

I am trying to use this Makefile for a C Program. Could you please share with me a way how I can understand the Make utility better? I am trying the following:
# stack/Makefile
CC := gcc
CFLAGS += -std=c99
CFLAGS += -Wall
CFLAGS += -Wextra
CFLAGS += -g
VPATH = main src
all: bin/main.exe clean run
bin/main.exe: bin/main.o bin/stack.o
$(CC) -o $# $^ $(LDFLAGS) $(LDLIBS)
bin/main.o: main.c
bin/stack.o: stack.c stack.h
bin/%.o: %.c
$(CC) $(CFLAGS) -c -o $# $<
demo:
../bin/main.exe
clean:
rm -f bin/*.o
run:
bin/main.exe
.PHONY: all clean run
And I getting this message:
gcc -std=c99 -Wall -Wextra -g -c -o bin/main.o main.c
error: unable to open output file 'bin/main.o': 'No such file or directory'
1 error generated.
make: *** [bin/main.o] Error 1
The error stems from the fact that your Makefile wants to
generate the executable and object files in subdirectory bin but it
contains no rule to ensure that bin exists when it is
needed. As #JonathanLeffler comments, you can solve that
just by manually creating bin yourself.
But it is often desired that a Makefile itself will ensure
that a subdirectory, or some other resource, exists when it
is needed, and you probably assumed that the pattern-rule
bin/%.o: %.c
would create bin as needed. It won't.
Your Makefile can ensure the existence of bin if you
amend it like this:
Somewhere below the all rule, add a new target:
bin:
mkdir -p $#
This is to make the bin subdirectory if it doesn't exist.
Then change the rule:
bin/%.o: %.c
$(CC) $(CFLAGS) -c -o $# $<
to:
bin/%.o: %.c | bin
$(CC) $(CFLAGS) -c -o $# $<
The additional | bin is an example of an order-only prequisite
It means: If any of the targets (the bin/%.o things) needs to be remade from any of preceding prequisites (the ones before |, i.e. the %.c
things), then bin must be made first. So, as soon as anything needs to be made in bin, bin will be made first.
There is another more basic flaw in your Makefile. all is dependent on clean, so every time you successfully build
your program the object files are deleted. I understand that you intend this, but it entirely
defeats the purpose of make, which is to avoid the need to rebuild everything (object files, executables) every
time by instead just rebuilding those things that have become out-of-date with respect to their prerequisites.
So all should not depend on clean, and then an object file will be recompiled only if it needs to
be recompiled, i.e. is older than the corresponding source file. If and when you want to clean out the
object files, run make clean.
Finally, your demo rule:
demo:
../bin/main.exe
is inconsistent with the others. The others assume that the bin where the executable
is put is in the current directory. The demo rule assumes it is in the parent of
the current directory. If you correct the demo rule then it will be identical to
the run rule, so it is superfluous, but if it were not superfluous then it should
be added it to the .PHONY targets.
The best way to learn the proper way to use makefiles is to read the manual. Also, you can Google for some simple tutorials.

Creating a Makefile in Raspbian

I'm trying to create a Makefile for my C program in Raspbian (Raspberry Pi).
My program consists of a bunch of .c and .h Files. I've looked at countless Makefiles, but I just don't unterstand how it works with multiple files. There are always .o files in the Makefile but as I understand object files are the result of compiling, so I dont have any o. Files as I am trying to compile my .c Files.
Please explain to me how this works.
Edit:
Thank you. So I tried this and it starts compiling but there are errors 'multiple definition'. Example:
These are my Files:
main.c main.h
calibration.c calibration.h
file.c file.h
frame.c frame.h
gamepad.c gamepad.h
gpio.c gpio.h
uart.c uart.h
types.h
this is my makefile:
all: main
main: main.o calibration.o file.o frame.o gamepad.o gpio.o uart.o
%.o: %.c
gcc -c -std=c99 -Wall $< -o $# -lncurses
Where can i put 'types.h'?
With every file I get errors 'multiple definitions'
A very simple but typical makefile could look like this
SOURCES = source1.c source2.c source3.c
OBJECTS = $(SOURCES:%.c=%.o)
TARGET = myExecutable
$(TARGET): $(OBJECTS)
gcc $^ -o $#
%.o: %.c
gcc -c $< -o $#
The complicated parts:
SOURCES = source1.c source2.c source3.c This is a variable definition, it assigns the string "source1.c source2.c source3.c to the variable SOURCES.
$(SOURCES:%.c=%.o) This is a shorthand for the patsubst text function. It takes all text from the $(SOUCES) variable, and replaces the pattern %.c with %.o, i.e. it takes e.g. the string source1.c and replace it with source1.o.
$(TARGET): $(OBJECTS) This makes myExecutable depend on all object files, meaning if one object file is modified then the command in the rule will be executed.
gcc $^ -o $# This calls the gcc command, passing all dependencies ($^) as arguments (that is, all object files), and tells gcc to output a file with the name of the target ($#).
%.o: %.c This is the rule that makes object files depend in their source file. So if you have source1.c then source1.o will depend on that source file.
gcc -c $< -o $# This is the command that compiles the source file (the first dependency, $<) to an object file (with the -c option) and name it as the target of the rule ($#).
Also note that if you invoke make without a specific target, then the first rule will be selected. In the case of the above makefile, it will be the $(TARGET): $(OBJECTS) rule which will make sure that all object files are build from the source files, and then link the object files into the resulting executable.
The basic syntax of a make rule is:
target … : prerequisites …
recipe
…
…
On the left of the semicolon are the targets. The targets are your object files(.o). On the right of the semicolon are the files that you will need to create this file. Those files are the source files(.c).
Lets give a basic example of what such a rule could look like.
%.o: %.c
gcc -c $< -o $#
The % sign is a wildcard. %.o means everything that ends with .o. So, if you want to make an object file, you can say make file.o, and make will try to find a rule with which it can make this target. This happens to be the rule I just showed as an example, because file.o matches %.o.
Then the recipe. This is what will be executed. Usually it's about invoking the compiler(gcc), and feeding it the source file to generate the object file. That's what we do with gcc -c $< -o $#. The $< and $# mean target and prerequisites respectively.
So, what happens when you 'just' want to build your program? You usually will type make, and it will build. The default rule that's used when you type make, is all. So, if you make a rule about all, then you can specify what files you want to create to build your program. Example of such a rule:
all: main
Then, when make is invoked, it will find that rule and finds out it needs main. To create main you need another rule:
main: file.o
This rule says that to build main, you need file.o. So, when you put all of the example rules together you get this:
all: main
main: file.o
%.o: %.c
gcc -c $< -o $#
Note that you can specify more than one file, so instead of file.o, you can say file.o main.o other_file.o etc. Every prerequisite that you specify will be made, if they can find a rule to make it.

Creating a generic makefile

I'm trying to create a makefile which would have as little command repetition as possible. Basic idea is to have variable name assigned at the target, like so:
CC = gcc
CFLAGS = -std=c99 -pedantic-errors -Wall
some_target:
P = some_target
some_other_target:
P = some_other_target
...
#common compilation command
$(CC) $(CFLAGS) $(P).c -o $(P).o
So there's only one compilation command which receives variable P which is unique for each target. Obviously example above doesn't work, what do i need to change to make it correct?
This is already built in. The variable $< expands to the first dependency and $^ expands to all dependencies. There is also $? which expands to only those dependencies which are newer than the target. See the documentaion for a full list.
Make already knows how to compile a .c file into an .o file, but if you want to see how it's done, the pattern looks a bit different from yours.
some_command.o: some_command.c
other.o: other.c
%.o: %.c
$(CC) $(CCFLAGS) $< -o $#

A Makefile Puzzle: Multiple Programming Languages

I have a simple test Makefile:
hello: hello.o
.SUFFIXES: .c .f90 .o
.f90.o:
pgf90 -c -o $# $<
.c.o:
cc -c -o $# $<
You don't have to tell me that it having a foo.c and a foo.f90 in the same directory will create confusion. I would never do this for real. I am simply trying to get an idea of how Make handles some precedents. So, when I simply issue the make command, make runs:
pgf90 -c -o hello.o hello.f90
cc hello.o -o hello
And of course, the "cc" link fails because "cc" can't link a FORTRAN object to make an executable. Fine. But my question is: I have tried everything I can think of to discourage make from using the pgf90 command as its first compile command, and to opt for the cc command instead. I have changed the order of the suffix rules. I have changed the order of the suffixes in the .SUFFIXES statement. The only thing that seems to work is leaving the .f90 suffix rule out altogether. Why is this and can it be changed? Thanks. (In case it doesn't go without saying, I do have simple hello.f90 and hello.c source files in my directory, and they do compile and execute just fine.)
UPDATE: Ran make with -d. The relevant output (AFAICT) looks like:
Considering target file 'hello.o'.
File 'hello.o' does not exist.
Looking for an implicit rule for 'hello.o'.
Trying pattern rule with stem 'hello'.
Trying implicit prerequisite 'hello.c'.
Not being impressed with "implicit prerequisite 'hello.c'", make tries a whole bunch of other things before it comes to
Found an implicit rule for 'hello.o'.
Considering target file 'hello.f90'.
Looking for an implicit rule with stem 'hello.f90'
.
.
.
No implicit rule found for 'hello.f90'. #???????
.
.
Must remake target 'hello.o'
pgf90 -c -o hello.o hello.f90
Curiouser and curiouser
For reasons that are a mystery to me (but are probably obscure and historical), you can change this behavior by changing the suffix rules
.f90.o:
pgf90 -c -o $# $<
.c.o:
cc -c -o $# $<
into pattern rules (and reversing the order):
%.o : %.c
cc -c -o $# $<
%.o : %.f90
pgf90 -c -o $# $<

Resources