I have a table Product with the following columns
ProductId Name RegistrationDate UnregistrationDate
1 AB 2013-01-01 2013-03-01
2 CD 2013-01-10 2013-03-13
etc
I would like to get a list of Registered Products per every month of a year.
Example : Year , Month and the number of dealers which are registered and not unregistered.
Year Month RegisteredProucts
2013 2 35
2013 3 45(includes products even registered before March 2013)
I wrote the follwing stored procedure to find the Registered products for one month:
& it works :
#Begin Time = First Day of the Month
#End Time = Last Day of the Month
select COUNT(DISTINCT P.ProductId) as RegisteredProducts from Product P
where ((P.RegisteredDate < #EndTime)
AND (P.UnregisteredDate > #EndTime))
I then wrote the query below but it seems to group the results by the RegisteredDate.
I would like to know how I can group registered products (which are not unregistered) by the end of each month
for a duration of one year ?
select YEAR(P.RegisteredDate) AS [YEAR],MONTH(P.RegisteredDate) AS [MONTH], COUNT(DISTINCT P.ProductId) as RegisteredProducts from Product P
where ((P.RegisteredDate < #EndTime)
AND (P.UnregisteredDate > #EndTime))
group by YEAR(D.RegisteredDate), MONTH(D.RegisteredDate)
WITH months (mon) AS
(
SELECT CAST('2013-01-01' AS DATE) AS mon
UNION ALL
SELECT DATEADD(month, 1, mon)
FROM months
WHERE mon < DATEADD(month, -1, GETDATE())
)
SELECT mon, COUNT(productId)
FROM months
LEFT JOIN
registeredProducts
ON registrationDate < DATEADD(month, 1, mon)
AND (unregistrationDate >= mon OR unregistrationDate IS NULL)
GROUP BY
mon
; with months as
(
select cast('2013-01-01' as date) as dt
union all
select dateadd(month, 1, dt)
from months
where dt < '2014-01-01'
)
select *
from months m
cross apply
(
select count(*) as ProductCount
from Product p
where p.RegistrationDate < dateadd(month, 1, m.dt) and
(
UnregistrationDate is null
or UnregistrationDate >= m.dt
)
) p
Example at SQL Fiddle.
Related
I'm wondering how could I use the GROUP BY on month, but from the n-th of a month to the (n-1)-th of the next month. For exemple, I want to GROUP by from the 20 of january to the 19 of february, from the 20 of february to the 19 of march...
Currently I can GROUP BY Months and dates <20 with a condition. There is the demo :
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=8b55b7df44350c4ad3c595d03e421b6e
But now I don't know how can I group the 'false' of a month (ie that the value is the sum for days > 20) with the 'true' of the next month.
Does anyone as a idea how to do that ?(maybe what i'm trying os not the good way how to do that)
For each date before the 20th you can subtract 1 month and group it with the previous month:
WITH cte AS (
SELECT CASE
WHEN DAY(Date) >= 20 THEN Date
ELSE DATEADD(mm, -1, Date)
END Date,
Value
FROM tablename
)
SELECT YEAR(Date) year, MONTH(Date) month, SUM(Value) val
FROM cte
GROUP BY YEAR(Date), MONTH(Date)
ORDER BY YEAR(Date), MONTH(Date)
Or you can change the CASE expression to:
CASE
WHEN DAY(Date) < 20 THEN Date
ELSE DATEADD(mm, 1, Date)
END
so that all dates after the 19th are grouped with the next month.
Or:
SELECT FORMAT(DATEADD(dd, -20, Date), 'yyyy-MM') year_month,
SUM(Value) val
FROM tablename
GROUP BY FORMAT(DATEADD(dd, -20, Date), 'yyyy-MM')
See the demo.
I need list of those employees who are absent one day before and one day after weekend in a week......like if some is absent in Friday and present on Monday should not be included in the list
Use datepart(weekday, ) to fetch all records relative to monday and friday.
Have a look at SET DATEFIRST function too.
select *
from your_table
where datepart(weekday, Date) = 5
or datepart(weekday, Date) = 1;
This will list all employee id that are absent on a Friday and the following Monday (+1 week). I set-up a calendar week from mininum date to maximum date from the table and get only Friday and Monday. Then get all empid that has no attendance in any of those dates.
with caldte as (
SELECT dateadd(day, rn - 1, t.mindte) as dates,
datepart(weekday, dateadd(day, rn - 1, t.mindte)) as weekday,
datepart(wk, dateadd(day, rn - 1, t.mindte)) as weeknum
FROM (
select row_number() OVER ( order by c.object_id ) AS rn
FROM sys.columns c) rns,
(select min(dte) as mindte, max(dte) as maxdte
from tbl) t
WHERE rn - 1 <= datediff(day, t.mindte, t.maxdte)
and datepart(weekday, dateadd(day, rn - 1, t.mindte)) in (2, 6)
)
select distinct empid
from tbl
where empid not in (
select t.empid
from caldte c, tbl t
where c.dates = t.dte)
order by empid
Good Day! I am working on a chart where I need to display all the days of the current week to show the sales per Week. So far, I am able to display all the days of the current week, I'm just having a trouble in displaying the sales for each day of the week.Since there are no records in the database for the days of the week, it the TOTAL_SALES column should all return a Null value. Instead, it returns the total sales recorded in the database. Here is my Stored Procedure query so far.
WITH DAYSOFTHEWEEK AS
(
SELECT 0 DAY
UNION ALL
SELECT DAY + 1 FROM DAYSOFTHEWEEK WHERE DAY < 6
)
SELECT DATEADD(DAY, DAY, DATEADD(DAY, 2-DATEPART(WEEKDAY, CONVERT (date, GETDATE())), CONVERT (date, GETDATE()))) AS DAY_OF_THE_WEEK,
SUM([ORDER].NET_AMOUNT) AS TOTAL_SALES
FROM DAYSOFTHEWEEK, [ORDER]
GROUP BY DAYSOFTHEWEEK.DAY
I tried adding this condition statement,
WHERE DAYSOFTHEWEEK.DAY IN ([ORDER].ORDER_DATE)
But it returns this error
Operand type clash: date is incompatible with int
Can someone help me out on this?Is there a work around with the code that I already have? Thanks in advance!
What I think you're after is a SUM of each day's sales for the current week with NULL if there are no sales. The secret is to left join your date list onto your data:
-- Setup some fake sales data
WITH TestData(N, Order_Date, Net_Amount) AS (
SELECT 1 N, CAST(GETDATE() AS DATE) Order_Date, RAND() * 100 Net_Amount
UNION ALL
SELECT N+1 N, CAST(GETDATE()-N/5 AS DATE) Order_Date, RAND(CHECKSUM(NEWID())) * 100 Net_Amount FROM TestData
WHERE N < 20
)
SELECT TestData.Order_Date, TestData.Net_Amount INTO #Order FROM TestData
--Set the first day of the week (if required)
SET DATEFIRST 7 --Sunday
;WITH Days(N,DayOfTheWeek) AS (
SELECT 1 N, DATEADD(DAY, 1-DATEPART(WEEKDAY, GETDATE()), CONVERT(DATE,GETDATE())) DayOfTheWeek
UNION ALL
SELECT N+1 N,DATEADD(DAY, 1, DayOfTheWeek) DayOfTheWeek FROM Days
WHERE N < 7
)
SELECT d.DayOfTheWeek, SUM(Net_Amount) TotalAmount
FROM Days d
LEFT JOIN #Order ON d.DayOfTheWeek = Order_Date
GROUP BY d.DayOfTheWeek
DayOfTheWeek TotalAmount
------------ ----------------------
2016-08-07 219.036784917497
2016-08-08 273.319570812461
2016-08-09 271.148114731087
2016-08-10 194.780039228967
2016-08-11 NULL
2016-08-12 NULL
2016-08-13 NULL
Here is every day this week, starting at your datefirst date, which can be temporarily varied for the query with SET DATEFIRST if you need to have some other week start date
I think you have some sales table there that you haven't shown us, you need to join to that on date, then group by
WITH DAYSOFTHEWEEK AS
(
SELECT cast(dateadd(
day,
-datepart(weekday,getdate()) + 1 ,
GETDATE()
)
as date) [DAY], 0 as cnt
UNION ALL
SELECT dateadd(day,1,[DAY]), cnt + 1 FROM DAYSOFTHEWEEK WHERE cnt < 6
)
select DAYSOFTHEWEEK.[day], SUM([ORDER].NET_AMOUNT) AS TOTAL_SALES from daysoftheweek
JOIN
SalesTable on
CAST(SalesTable.SalesDate date) = DAYSOFTHEWEEK.[day]
GROUP BY DAYSOFTHEWEEK.[day]
A little over complicated for me:
To get name of the week use, for example
SELECT DATENAME(dw,getdate())
But you really need something like this:
SELECT ProductName,Sum(Sales) From NameOfTable GROUP BY
DATENAME(ww,salesDate)
I have an query that I'm feeling out-of-my depth with.
I need to loop through months between two dates and return a subset of data for each month with a blank row for months with no data.
For example:
TransactionID | Date | Value
1 | 01/01/2015 | £10
2 | 16/01/2015 | £15
3 | 21/01/2015 | £5
4 | 15/03/2015 | £20
5 | 12/03/2015 | £15
6 | 23/04/2015 | £10
Needs to return:
Month | Amount
January | £30
February | £0
March | £35
April | £10
My query will rely on specifying a date range so I can set the first and last date of the query.
I feel like I maybe over thinking this, but have gotten to that stage where you start to feel like you tying yourself in knots.
The key is having access to a list of integers to represent the months in the range. If you don't have a Numbers Table, then spt_values will do in a pinch.
SqlFiddle Demo
SELECT
[Year] = YEAR(DATEADD(month,[i],#range_start))
,[Month] = DATENAME(month,DATEADD(month,[i],#range_start))
,[Amount] = ISNULL(SUM([Value]),0)
FROM (
SELECT TOP (DATEDIFF(month,#range_start,#range_end)+1)
ROW_NUMBER() OVER(ORDER BY (SELECT 1))-1 [i]
FROM master.dbo.spt_values
) t1
LEFT JOIN #MyTable t2
ON (t1.[i] = DATEDIFF(month,#range_start,t2.[Date]) )
GROUP BY [i]
ORDER BY [i]
SQL is a tricky language at first. You actually do not want a loop. In fact, you pretty much never want to loop in SQL except in very few cases. Try this out:
DECLARE #StartDate DATE,
#EndDate DATE;
SET #StartDate = '01 January 2015';
SET #EndDate = '30 April 2015';
WITH CTE_Months
AS
(
SELECT #StartDate dates
UNION ALL
SELECT DATEADD(MONTH,1,dates)
FROM CTE_Months
WHERE DATEADD(MONTH,1,dates) < #EndDate
)
SELECT YEAR(B.[date]) AS yr,
DATENAME(MONTH,B.[Date]) AS month_name,
SUM(ISNULL(B.Value,0)) AS Amount
FROM CTE_Months A
LEFT JOIN yourTable B
ON YEAR(A.[date]) = YEAR(B.[date])
AND MONTH(A.[date]) = MONTH(B.[date])
GROUP BY YEAR(B.[date]),DATENAME(MONTH,B.[Date])
One way: create a table called months with a monthnum int field and 12 rows of [1..12]
declare #start date = '01 jan 2015',
#end date = '30 apr 2015'
select
datename(month, dateadd(month, monthnum, 0) - 1),
isnull(Amount, 0)
from months
left join (
select
month(date) Month,
sum(Value) Amount
from tbl
where date between #start and #end
group by month(date)
) T on (T.Month = months.monthnum)
where months.monthnum between month(#start) and month(#end)
order by monthnum
The following code will generate one output row for each month between the first and last transaction dates. Spanning a year boundary, or multiple years, is handled correctly.
-- Some sample data.
declare #Transactions as Table
( TransactionId Int Identity, TransactionDate Date, Value Int );
insert into #Transactions ( TransactionDate, Value ) values
( '20141125', 10 ), ( '20150311', 20 ), ( '20150315', 5 ), ( '20150509', 42 );
select * from #Transactions;
with
-- Determine the first and last dates involved.
Range as (
select Min( TransactionDate ) as FirstDate, Max( TransactionDate ) as LastDate
from #Transactions ),
-- Generate a set of all of the months in the range.
Months as (
select DateAdd( month, DateDiff( month, 0, FirstDate ), 0 ) as Month,
DateAdd( month, DateDiff( month, 0, LastDate ), 0 ) as LastMonth
from Range
union all
select DateAdd( month, 1, Month ), LastMonth
from Months
where Month < LastMonth )
-- Summarize the transactions.
select M.Month, Coalesce( Sum( T.Value ), 0 ) as Total
from Months as M left outer join
#Transactions as T on DateAdd( month, DateDiff( month, 0, T.TransactionDate ), 0 ) = M.Month
group by M.Month
order by M.Month
option ( MaxRecursion 1000 );
I'm trying to get all months in which no transaction is placed for the same year (If different years is not possible)
This is my query to get transactions between 2 dates, but don't know how can I select only months for which transaction in database is missing
SELECT *
FROM Installment
WHERE OrderId = 1
AND InstallmentDate
BETWEEN cast('8/02/2014' as date)
AND cast('12/25/2014' as date)
InstallmentId OrderId CustomerKey InstallmentAmount InstallmentDate
18 1 INS-1 3000 2014-09-03
92 1 INS-1 3000 2014-10-13
137 1 INS-1 3000 2014-11-05
in this case record for the 12th month and 8th month is missing, how can I get this with SQL Server Query ?
Update
select yymm.yy, yymm.mm
from (select distinct year(InstallmentDate) as yy, month(InstallmentDate) as mm
from Installment
where InstallmentDate BETWEEN '2014-09-02' and '2015-01-15'
) yymm left join
Installment i
on i.OrderId = 1 and
year(i.InstallmentDate) = yymm.yy and
month(i.InstallmentDate) = yymm.mm
where i.OrderId is not null;
Gordon's query is returning all the years and months from table between 2 dates, just by changing i.OrderId is null to i.OrderId is not null here is the out of his query
yy mm
2014 9
2014 10
2014 11
Expected Output (if possible)
yy mm
2014 12
2015 1
Using the following recursive CTE:
DECLARE #start DATE = '2014-09-02'
DECLARE #end DATE = '2015-01-15'
;WITH IntervalDates (date)
AS
(
SELECT #start
UNION ALL
SELECT DATEADD(MONTH, 1, date)
FROM IntervalDates
WHERE DATEADD(MONTH, 1, date)<=#end
)
SELECT YEAR(date) AS Year, MONTH(date) AS Month
FROM IntervalDates
you can get a list of all Years/Months between the two dates of interest:
Year Month
==============
2014 9
2014 10
2014 11
2014 12
2015 1
Using EXCEPT on the above CTE:
;WITH IntervalDates (date)
AS
(
SELECT #start
UNION ALL
SELECT DATEADD(MONTH, 1, date)
FROM IntervalDates
WHERE DATEADD(MONTH, 1, date)<=#end
)
SELECT YEAR(date) AS Year, MONTH(date) AS Month
FROM IntervalDates
EXCEPT
SELECT DISTINCT YEAR(InstallmentDate) AS yy, MONTH(InstallmentDate) AS mm
FROM Installment
WHERE OrderId = 1 AND InstallmentDate BETWEEN #start AND #end
yields the required result set:
Year Month
=============
2014 12
2015 1
To do this in SQL, you need to start with a list of months. Assuming you have at least one record for each month in the table, you can then get the missing dates easily using a subquery. The rest of the query is just a left join and checking for non-matches:
select yymm.yy, yymm.mm
from (select distinct year(InstallmentDate) as yy, month(InstallmentDate) as mm
from Installment
where InstallmentDate BETWEEN '2014-09-02' and '2015-01-15'
) yymm left join
Installment i
on i.OrderId = 1 and
year(i.InstallmentDate) = yymm.yy and
month(i.InstallmentDate) = yymm.mm
where i.OrderId is null;
Simplest way I can think of is to have a date dimension table that contains (at least) date, and 1st of month then. For creating one take a look at something like https://dba.stackexchange.com/questions/74957/best-approach-for-populating-date-dimension-table , although that one doesn't have firstOfMonthDate in it as my example show but the idea is the same.
then your query becomes
SELECT DISTINCT
firstOfMonthDate
FROM
dateRef dr
LEFT OUTER JOIN
InstallmentDate i ON dr.date = i.InstallmentDate AND i.OrderId = 1
WHERE
i.InstallmentDate IS NULL
AND
dr.date BETWEEN #startDate and #endDate
change firstOfMonthDate for fiscal month etc. as required. This would work across any range of dates you have in your table so different years wouldn't be an issue.
Try the below script. I retrieve all dates between the specified dates and use a LEFT JOIN to get those which are not present in your table:
DECLARE #startDate AS DATETIME, #endDate AS DATETIME
DECLARE #dates AS TABLE (CurrentDate DATETIME)
SET #startDate = '2014-01-01'
SET #endDate = '2014-01-31';
with GetDates AS
(
SELECT #startDate AS TheDate
UNION ALL
SELECT DATEADD("DD", 1, TheDate) FROM GetDates
WHERE TheDate < #endDate
) INSERT INTO #dates SELECT TheDate FROM GetDates
OPTION (MAXRECURSION 0)
SELECT DISTINCT YEAR(d.CurrentDate), MONTH(d.CurrentDate) FROM #dates d
LEFT JOIN InstallmentDate i ON i.InstallmentDate BETWEEN #startDate AND #endDate AND OrderId = 1
WHERE i.InstallmentDate IS NULL
Hope this helps...