Iam facing some logical issues.Hope that someone can find me a solution to it
Iam having a query
select FirstName||'|'||LastName||to_char(salary)
from (select FirstName,LastName,salary from subs_tbl where salary=24000)
union all select FirstName||'|'||''||to_char(salary)
from (select FirstName,LastName,salary from subs_tbl where salary=30000)
so my result will be
Satish|Kumar|24000
Vimal|Kumar|24000
Dinesh||30000
Let say am having 3 rows as my result but i need to add another condition to the whole query that i need only 2 rows out of the combination of these queries.
Please help me with this
select FirstName||'|'||LastName||to_char(salary)
from (select FirstName,LastName from subs_tbl where salary=24000)
union all select FirstName||'|'||''||to_char(salary)
from (select FirstName,LastName from subs_tbl where salary=30000) limit 0,2
Try this avoid union's that you have used
SELECT FirstName||'|'||LastName||to_char(salary)
FROM subs_tbl
WHERE salary=24000 or salary=30000)
LIMIT 2
EDIT
SELECT fullname
FROM (SELECT firstname
|| '|'
|| lastname
|| To_char(salary) AS 'FullName'
FROM (SELECT firstname,
lastname,
salary
FROM subs_tbl
WHERE salary = 24000)
UNION ALL
SELECT firstname
|| '|'
|| ''
|| To_char(salary) AS 'FullName'
FROM (SELECT firstname,
lastname,
salary
FROM subs_tbl
WHERE salary = 30000))
WHERE rownum <= 5;
Hope this helps
Related
We have companies' data stored in a table. In an effort to de-duplicate the rows, we need to identify duplicate data sets of companies by using following criterion: If First five letters of the CompanyName, City and postal code match with other records' same fields then it is a duplicate. We will later remove the duplicates. The problem I am running in to is that I can't retrieve IDs of these records since I am not grouping the records on ID.
I am using following SQL:
Select count(ID) as DupCount
, SUBSTRING(Name,1,5) as Name
, City
, PostalCode
from tblCompany
group by SUBSTRING(Name,1,5)
, City
, PostalCode
Having count(ID) > 1
order by count(ID) desc
How do I retrieve the ID of these records?
You can use window functions:
Select c.*
from (select c.*,
count(*) over (partition by left(Name, 5), City, PostalCode) as cnt
from tblCompany c
) c
where cnt >= 2;
This will return the individual rows with dups. You can then summarize this or do what you want with the result set.
Use group_concat() to get the ids as a comma separated list:
select
SUBSTRING(Name,1,5) as Name,
City,
PostalCode,
count(ID) as counter,
group_concat(id order by id) as ids
from tblCompany
group by SUBSTRING(Name,1,5), City, PostalCode
having count(ID) > 1
order by count(ID) desc
I would like to insert to Clients table data from two different tables (Surname and name). Moreover I would like to have a third column (email) that is a concatination from the first two. when i try the code hereunder it gives me the following error: "Subquery returned more than 1 value".
insert into CLIENTS (LastName,Firstname, EMAIL)
select (select top 150 Surname from Surname order by NEWID()),
(select top 150 Name from Name order by Newid()),
(select concat(concat(FisrtName, LastName),'#novaims.com') from clients);
Could you please help me understand where is the problem?
The error message is obvious your sub-query can result more than one record. Try this
;WITH cte
AS (SELECT 1 AS val
UNION ALL
SELECT val + 1
FROM cte
WHERE val < 150)
SELECT FisrtName,
LastName,
Concat(FisrtName, LastName, '#novaims.com')
FROM cte
OUTER apply (SELECT TOP 1 Surname FROM Surname ORDER BY Newid()) s (FisrtName)
OUTER apply (SELECT TOP 1 NAME FROM NAME ORDER BY Newid()) n (LastName)
Option (Maxrecursion 0)
You need to move the table references to the from clause. I think this does what you want:
insert into CLIENTS (LastName, Firstname, EMAIL)
select surname, name, concat(name, surname, '#novaims.com')
from (select Surname, row_number() over (order by newid()) as seqnum
from Surname
) s join
(select Name, row_number() over (order by newid()) as seqnum
from Name
)
on n.seqnum = s.seqnum;
Another method uses apply:
insert into CLIENTS (LastName, Firstname, EMAIL)
select top 150 s.surname, n.name, concat(n.name, s.surname, '#novaims.com')
from surname s cross apply
(select top 1 n.*
from names n
order by newid()
) n
order by newid();
This is more similar to your original idea. Do note, though, that the same name can appear more than once. And the performance should be better for the first version (because the sort is only happening once on each table).
I want to find the recent duplicate records from SQL Server 2012. Here is the table structure I have.
I have table name called UserRegistration which contains the duplicate of UserID(GUID) and in same table, I have CreatedDate Column as well (Date). Now I want to find the recent duplicate records from this table.
Here is the same data.
id FirstName LastName CreatedDate UserID
109 FirstNameA LastNameA 28-04-2015 GUID1
110 FirstNameC LastNameD 19-05-2015 GUID2
111 FirstNameE LastNameF 22-05-2015 GUID1
If you notice on above tables, GUID 1 are having the duplicate, Now I want to find the recent one means it should return me only those rows with duplication but recent data. So in above table structure, it should return me 111 because record has been created recently compared to the 109. I believe you understand.
Do let me know if you have any question. I am happy to answer. Thanks. Awaiting for the reply.
Harshal
Try the below query this should do the work based on your i/p data -
create table #UserRegistration (id int,FirstName varchar(20),LastName varchar(20),CreatedDate date,UserID varchar(20))
insert into #UserRegistration
select 109, 'FirstNameA', 'LastNameA', '2015-04-28', 'GUID1' union
select 110, 'FirstNameC', 'LastNameD', '2015-05-19', 'GUID2' union
select 111, 'FirstNameE', 'LastNameF', '2015-05-22', 'GUID1'
select id, FirstName, LastName, CreatedDate, UserID from
(SELECT ur.*,row_number() over(partition by UserID order by CreatedDate) rn
FROM #UserRegistration ur) A
where rn > 1
You could use CTE. Group your records by UserID and give your particular row a rank ordered by CreatedDate.
insert into tab(id, FirstName, LastName, CreatedDate, UserID)
values(109, 'FirstNameA', 'LastNameA', '2015-04-28', 'guid1'),
(110, 'FirstNameC', 'LastNameD', '2015-05-19', 'guid2'),
(111, 'FirstNameE', 'LastNameF', '2015-05-22', 'guid1');
with cte as
(
select id, ROW_NUMBER() over (partition by UserID order by CreatedDate asc) as [Rank],
FirstName, LastName, CreatedDate, UserID
from tab
)
select id, FirstName, LastName, CreatedDate, UserID from cte where Rank > 1
Rank > 1 condition is responsible for retrieving duplicated items.
sqlfiddle link:
http://sqlfiddle.com/#!6/4d1f2/6
Solved this by using tmp-tables:
SELECT a.UserID,
MAX(a.CreatedDate) As CreatedDate
INTO #latest
FROM <your table> a
GROUP BY a.UserID
HAVING COUNT(a.UserID) > 1
SELECT b.id
FROM #latest a
INNER JOIN <your table> b ON a.UserID = b.UserID AND a.CreatedDate = b.CreatedDate
try this,
SELECT * FROM TableName tt WHERE
exists(select MAX(createdDate)
from TableName
where tt.UserID = UserID
group by UserID
having MAX(createdDate)= tt.createdDate)
I think your createddate field is not a date field, then try Format
WITH TempAns (id,UserID,duplicateRecordCount)
AS
(
SELECT id,
UserID,
ROW_NUMBER()OVER(partition by UserID ORDER BY id)
AS duplicateRecordCount
FROM #t
)
select * from #t where id in (
select max(id )
from TempAns
where duplicateRecordCount > 1
group by name )
You'd rank your records with ROW_NUMBER() to give all last records per userid #1. With COUNT() you make sure only to get the userids having more than one record.
select
id, firstname, lastname, createddate, userid
from
(
select
id, firstname, lastname, createddate, userid,
row_number() over (partition by userid oder by createddate desc) as rn,
count(*) over (partition by userid) as cnt
from userregistration
) ranked
where rn = 1 -- only last one
and cnt > 1; -- but only if there is more than one record for the userid
This gets the latest record for every userid that has duplicates.
I have a situation where I need to be able to see if a given person is within a user/manager hierarchy.
I have the next structure of table:
UserId
UserName
ManagerId
I have 2 IDs: some UserId (say 5) and ManagerId (say 2). As a result I need to know if manager with given Id (2) is chief for user with given id (5)? For example, if
User 1 reports to user 2.
User 3 reports to user 1.
User 4 reports to user 3
the result SQL-query have to show that for UserId = 4 and ManagerId = 1 answer is true.
I've just created query for getting all hierarchy:
WITH temp (level, UserName, UserId, ManagerId) AS
(
SELECT 1 AS level, EmployeeName, EmployeeId, BossId
FROM Employees
WHERE BossId IS NULL
UNION ALL
SELECT level+1 AS level, EmployeeName, EmployeeId, BossId
FROM Employees, temp
WHERE BossId = UserId
)
SELECT t.* from temp AS t
But now I don't know how to get result query with above mentioned conditions :(
Thanks in advance for any help!
Find the user in the anchor and walk your way back up the hierarchy. Check the rows you have got in the recursive query against the manager.
This will return the manager row if there exist one.
WITH temp AS
(
SELECT EmployeeName, EmployeeId, BossId
FROM Employees
WHERE EmployeeId = #UserID
UNION ALL
SELECT E.EmployeeName, E.EmployeeId, E.BossId
FROM Employees AS E
inner join temp AS T
ON E.EmployeeId = T.BossId
)
SELECT *
FROM temp
WHERE EmployeeId = #ManagerID
This will return the BossID if he or she exist:
WITH BOSSES AS
(
SELECT BossID
FROM Employees
WHERE EmployeeID = #uID
UNION ALL
SELECT E.BossID
FROM Employees E
JOIN BOSSES B ON E.EmployeeID = B.BossID
)
SELECT *
FROM BOSSES
WHEN BossID = #bID
I've included the hierarchy of all levels with the CTE that you can then use to query. Using this hierarchy, you can see all the managers of a given employee in a delimited column (might be useful for other calculations).
Give this a try:
WITH cte (UserId, ManagerId, Level, Hierarchy) as (
SELECT EmployeeId, BossId, 0, CAST(EmployeeId as nvarchar)
FROM Employee
WHERE BossId IS NULL
UNION ALL
SELECT EmployeeId, BossId, Level+1,
CAST(cte.Hierarchy + '-' + CAST(EmployeeId as nvarchar) as nvarchar)
FROM Employee INNER JOIN cte ON Employee.BossId=cte.UserId
)
SELECT *
FROM cte
WHERE UserId = 4
AND '-' + Hierarchy LIKE '%-1-%'
And here is the Fiddle. I've used UserId = 4 and ManagerId = 1.
Good luck.
I have a CustomerData table with the following attributes:
FirstName, LastName, DateofBirth, ID, Location
I am trying to write a query that pulls the first name, last name, date of birth, and IDNumber of users who belong to more than one location.
I tried the following code but I am getting an error about aggregates needing a group by clause.
SELECT *
FROM CustomerData
WHERE Count(Location) > 2
Any assistance would be greatly appreciated
Use HAVING:
SELECT FirstName, LastName, DateofBirth, ID, Count(Location)
FROM CustomerData
GROUP BY FirstName, LastName, DateofBirth, ID
HAVING Count(Location) > 2
HAVING is basically a WHERE that allows you to use aggregate functions.
You can also use a sub-query:
select c1.FirstName, c1.LastName, c1.DateofBirth, c1.ID, c2.CntLocation
from CustomerData c1
left join
(
SELECT Count(Location) CntLocation, location
FROM CustomerData
group by location
) c2
on c1.location = c2.location
WHERE CntLocation > 2