Related
This works:
Suppose I want to use in an ArrayFormula() the indirect() function, which doesn't work. That is, supposed I type this in cell E1, =ArrayFormula(indirect(address(row(E:E),column(A:A)))), this will return the value of cell A1 in all the cells in column E. To circumvent this, I created the custom function below:
function retValue(cell){
if(cell.map) {
return cell.map(retValue);
} else {
var cellRang = SpreadsheetApp.getActive().getRange(cell);
return cellRang.getValue();
}
}
Now, when I enter this =ArrayFormula(retValue(address(row(E:E),column(A:A)))) in cell E1, each cell in column E will have the corresponding value of the cell in the same row of column A.
My problem:
What I need is to have a custom function that receives 2 arguments, like function retValue2(cell, anotherRange) but I only care if cell is an array, as anotherRange must be an array anyway. What happens is that when I iteratively call cell.map(retValue2) the argument anotherRange is lost and I'm not entirely sure how to go about this.
I tried to come up with this:
function retValue2(cell, anotherRange) {
if (cell.map) {
return cell.map(retValue2);
} else {
var range = SpreadsheetApp.getActive().getRange(anotherRange);
var nrRows = range.getNumRows();
var nrCols = range.getNumColumns();
return cell + ',' + nrRows + ',' + nrCols;
}
}
But it fails because anotherRange is not recognized inside the iteration I think. How do I solve this?
PS.: in the example that works, why exactly does it work at all? I understand that when I do this return cell.map(retValue); it will use my own function as the callback, which would return all the values in the array, but in the spreadsheet it shows only the one on the same row. What is the magic here?
EDIT:
My end goal is to create my own lookup function where I pass a search key and a 2-dimensional array (rows and columns) and then, it locates the coordinates of that key in the array.
Look here:
function retCoord(sKey, sIRange) {
try {
var key = SpreadsheetApp.getActive().getRange(sKey).getValue();
}
catch(e) {
var key = sKey;
}
var range = SpreadsheetApp.getActive().getRange(sIRange).getValues();
nbRow = range.length;
nbColumn = range[0].length;
for(var i = 0; i<nbRow; i++){
for(var j = 0; j<nbColumn; j++){
if(range[i][j] == key){
return i + ", " + j;
}
}
}
}
If in my spreadsheet I enter something like =retCoord("K4","A:L") it will search the content of cell K4 in my 2-dimensional array A:L and return where in the array the value is, 1, 2 for example. It also works if I use =retCoord(K4,"A:L") or =retCoord("term searched","A:L"), and in this latter case I enter directly the term searched. This works fine until I use it in an ArrayFormula().
First, instead of =retCoord("K4","A:L") I could very well use =retCoord(address(4, 11),"A:L") for instance and my .getRange() method would get the cell K4 just fine.
Now, here is the big problem. I want to use my function in an ArrayFormula(), and, positioning my cursor in O1 and hoping to search the items from column D in the columns E through L I want to pass as one of the inputs of address(), row(O:O), like this: =ArrayFormula(retCoord(address(row(O:O),4,4),"E:L")), meaning that for each row, a new address is passed. that is, in O1 cell, it should return the result of retCoord(D1,"E:L"), in O2 should be retCoord(D2,"E:L"), in O3 should be retCoord(D3,"E:L") and so on.
The issue happens because in my function, sKey is an array and if I try to use the same approach as my function retValue (here above in the This works: section) it fails because now, in retCoord, I have 2 inputs, and the introspection function calling from before fails because of the second input. Of course I'm missing something and there is always a better and more elegant way to approach a problem. But for now, can anyone help me with this one?
EDIT2:
I changed the code a little and it seems I moved forward but not quite yet. Check comment below for line indicated by (*):
function retCoord(sKey, sIRange) {
var key = '';
try {
key = SpreadsheetApp.getActive().getRange(sKey).getValue();
return key;
}
catch(e) {
if (sKey.map) {
var objKey = sKey.map(retCoord);
return objKey; // (*) <--- comments below
key = objKey;
} else {
key = sKey;
}
}
var range = SpreadsheetApp.getActive().getRange(sIRange).getValues();
nbRow = range.length;
nbColumn = range[0].length;
for(var i = 0; i<nbRow; i++){
for(var j = 0; j<nbColumn; j++){
if(range[i][j] == key){
return key + " = "+ i + ", " + j;
}
}
}
}
This (*) line I added only to see what was returning from the map. Surprisingly (in a way), it is an object with all the elements of that column and that is expected. What I didn't expect was that if I return that object to my spreadsheet cell, it brings back only the value of that specific cell (as I wanted but not really as expected). But the problem is I cannot use that object to compare against a string as it will expand and become something else and will never match. Look:
If I do return objKey in my custom function, over cell O1 it returns "a", in O2 it returns
"b", in O3 it returns "c" as expected because those are the values
of my cells D1, D2, D3 respectively.
If I do return "-> " + objKey
in in my custom function, instead of returning -> a, -> b, -> c in O1, O2, O3 respectively, it returns -> =A:A,a,b,c,d,e,f for all the cells in column O, which seems it did some type of objKey.toString() under the hood before concatenating with "-> "
Conclusion: how do I "coerce" the apparent result of objKey into string keeping the apparent result when you return the object without changing it? Simply put, I want the concatenation "some string" + to be equal to "some string" + "one string representing the value in that row instead of an object". In other words, what the hell is happening here? How does Google Sheets now that in that row, that element is the one representing the one I want? This is what I asked in the "PS." in the first part of this post.
You want to search all keys in the sKey column within the Range sIRange and note the position of each key within the range into the corresponding row in a destination column ?
This is how you can do it with Apps Script without formulas:
function retCoord(sKeyColumn, destinationColumn, sIRange) {
var key = sKeyColumn;
var range=SpreadsheetApp.getActive().getRange(sIRange);
var rangeValues = SpreadsheetApp.getActive().getRange(sIRange).getValues();
var nbRow = rangeValues.length;
var nbColumn = rangeValues[0].length;
var sKeyRange=SpreadsheetApp.getActive().getRange(sKeyColumn);
var destinationRange=SpreadsheetApp.getActive().getRange(destinationColumn);
var sKeyValues=sKeyRange.getValues();
for(var k=0;k<sKeyValues.length;k++){
for(var i = 1; i<=nbRow; i++){
for(var j = 1; j<=nbColumn; j++){
if(range.getCell(i, j).getValue() == sKeyValues[k][0]){
destinationRange.getCell(k+1, 1).setValue(range.getCell(i, j).getA1Notation());
}
}
}
}
}
Sample call:
function myFunction(){
retCoord('A1:A6','B1:B6','C1:J7');
}
retCoord('A:A','B:B','C:J'); would also work but would take very long, since the code would also loop through empty rows
This is probably easy but I just cannot get the answer. Here is a simple Array:
I want the information to be distributed from an Input textBox to different dynamic textBox after a click. I am OK with buttons.
var ERLQ1:Array = ["ERLQ1", "N09°02.61 / E100°49.11", "ErawanLq"];
InputText = "ERLQ1";
//I want to display:
Txt1 = "ERLQ1" //Being first part of the array as main reference.
Txt2 = "N09°02.61 / E100°49.11" // Should be: String(ERLQ1[1])
Txt3 = "ErawanLq" // Should be: String(ERLQ1[2])
First time I write in a forum like this. Please forgive if not perfect. Thanks in advance.
Andre
If I understand correctly, an array of objects would work well. Since you have a set number of textfields I assume that you also have a set number of details that you want to display in them. If that is the case, this solution should work fine.
arr:Array = [{_name:"ERLQ1",ans1:"N09°02.61 / E100°49.11",ans2:"ErawanLq"},
{_name:"ERLQ2",ans1:"question 2 answer 1",ans2:"ques2ans1"}];
So, I don't really "get" your application, but if it were some sort of a quiz, you'd have a new array element for each question, and that element has a name, and two answers. Easy to modify it to grab answers from an answer pool. Now to find the element in the array that has ._name == "ERLQ1" you will need to loop through all the elements and return the one that has the ._name property that matches your search. Here is an example function:
private function matchName(arr:Array, term:String):int{
for (var i:int = 0; i < arr.length; i++){
if (arr[i]._name == term){
return i;
}
}
return -1;
}
This function will return the array index number of the matching term. If no match exists, it returns -1. So you could use it like this (pseudocode):
// on submit search{
// find the index number in the array of the element that matches the search term
var ind:int = matchName(arr, searchTerm);
// assign the textfield texts to the corresponding associated values
textBox1:text = arr[ind]._name;
textBox2:text = arr[ind].ans1;
textBox3:text = arr[ind].ans2;
}
I perhaps misunderstood (because of my English), but :
import flash.text.TextField;
import flash.text.TextFieldAutoSize;
var ERLQ1:Array = ["ERLQ1", "N09°02.61 / E100°49.11", "ErawanLq"];
var Txt1 : TextField = new TextField();
Txt1.autoSize=TextFieldAutoSize.CENTER;
Txt1.type = TextFieldType.INPUT;
Txt1.border = true;
var Txt2 : TextField = new TextField();
Txt2.autoSize=TextFieldAutoSize.CENTER;
Txt2.type = TextFieldType.INPUT;
Txt2.border = true;
var Txt3 : TextField = new TextField();
Txt3.autoSize=TextFieldAutoSize.CENTER;
Txt3.type = TextFieldType.INPUT;
Txt3.border = true;
addChild(Txt1);
addChild(Txt2);
addChild(Txt3);
Txt1.x = 20, y =40;
Txt2.x = 180, y =40;
Txt1.x = 300, y =40;
Txt1.text = ERLQ1[0]; // is now : first part of the array as main reference (String(ERLQ1[0]).
Txt2.text = ERLQ1[1]; // is now : String(ERLQ1[1]);
Txt3.text = ERLQ1[2]; // is now : String(ERLQ1[2]);
This will display 3 TextFiels as input text like this :
If I misunderstood your question, please tell me more about what You expect!
Best regards.
Nicolas
first question ever here...
I am coding a simple 3-card poker hand evaluator and am having problems finding/extracting multiple "straights" (sequential series of values) from an array of values.
I need to extract and return EVERY straight the array possibly has. Here's an example:
(assume array is first sorted numerically incrementing)
myArray = [1h,2h,3c,3h,4c]
Possible three-value sequences are:
[1h,2h,3c]
[1h,2h,3h]
[2h,3c,4c]
[2h,3h,4c]
Here is my original code to find sequences of 3, where the array contains card objects with .value and .suit. For simplicity in this question I just put "2h" etc here:
private var _pokerHand = [1h,2h,3c,3h,4c];
private function getAllStraights(): Array
{
var foundStraights:Array = new Array();
for (var i: int = 0; i < (_handLength - 2); i++)
{
if ((_pokerHand[i].value - _pokerHand[i + 1].value) == 1 && (_pokerHand[i + 1].value - _pokerHand[i + 2].value) == 1)
{
trace("found a straight!");
foundStraights.push(new Array(_pokerHand[i], _pokerHand[i + 1], _pokerHand[i + 2]));
}
}
return foundStraights;
}
but it of course fails when there are value duplicates (like the 3's above). I cannot discard duplicates because they could be of different suits. I need every possible straight as in the example above. This allows me to run the straights through a "Flush" function to find "straight flush".
What array iteration technique am I missing?
This is an interesting problem. Given the popularity of poker games (and Flash) I'm sure this has been solved many times before, but I couldn't find an example online. Here's how I would approach it:
Look at it like a path finding problem.
Begin with every card in the hand as the start of a possible path (straight).
While there are possible straights:
Remove one from the list.
Find all the next valid steps, (could be none, or up to 4 following cards with the same value), and for each next valid step:
If it reaches the goal (completes a straight) add it to a list of found straights.
Otherwise add the possible straight with the next step back to the stack.
This seems to do what you want (Card object has .value as int):
private function getAllStraights(cards:Vector.<Card>, straightLength:uint = 3):Vector.<Vector.<Card>> {
var foundStraights:Vector.<Vector.<Card>> = new <Vector.<Card>>[];
var possibleStraights:Vector.<Vector.<Card>> = new <Vector.<Card>>[];
for each (var startingCard:Card in cards) {
possibleStraights.push(new <Card>[startingCard]);
}
while (possibleStraights.length) {
var possibleStraight:Vector.<Card> = possibleStraights.shift();
var lastCard:Card = possibleStraight[possibleStraight.length - 1];
var possibleNextCards:Vector.<Card> = new <Card>[];
for (var i:int = cards.indexOf(lastCard) + 1; i < cards.length; i++) {
var nextCard:Card = cards[i];
if (nextCard.value == lastCard.value)
continue;
if (nextCard.value == lastCard.value + 1)
possibleNextCards.push(nextCard);
else
break;
}
for each (var possibleNextCard:Card in possibleNextCards) {
var possibleNextStraight:Vector.<Card> = possibleStraight.slice().concat(new <Card>[possibleNextCard]);
if (possibleNextStraight.length == straightLength)
foundStraights.push(possibleNextStraight);
else
possibleStraights.push(possibleNextStraight);
}
}
return foundStraights;
}
Given [1♥,2♥,3♣,3♥,4♣] you get: [1♥,2♥,3♣], [1♥,2♥,3♥], [2♥,3♣,4♣], [2♥,3♥,4♣]
It gets really interesting when you have a lot of duplicates, like [1♥,1♣,1♦,1♠,2♥,2♣,3♦,3♠,4♣,4♦,4♥]. This gives you:
[1♥,2♥,3♦], [1♥,2♥,3♠], [1♥,2♣,3♦], [1♥,2♣,3♠], [1♣,2♥,3♦], [1♣,2♥,3♠], [1♣,2♣,3♦], [1♣,2♣,3♠], [1♦,2♥,3♦], [1♦,2♥,3♠], [1♦,2♣,3♦], [1♦,2♣,3♠], [1♠,2♥,3♦], [1♠,2♥,3♠], [1♠,2♣,3♦], [1♠,2♣,3♠], [2♥,3♦,4♣], [2♥,3♦,4♦], [2♥,3♦,4♥], [2♥,3♠,4♣], [2♥,3♠,4♦], [2♥,3♠,4♥], [2♣,3♦,4♣], [2♣,3♦,4♦], [2♣,3♦,4♥], [2♣,3♠,4♣], [2♣,3♠,4♦], [2♣,3♠,4♥]
I haven't checked this thoroughly but it looks right at a glance.
Im trying to access an individual tile inside of my 2d array of tiles
Ive created my array like so:
private var map:Array = [[25,25]];
ive tried several ways including:
map[1][1] = 1;
all that does is give me this:
ReferenceError: Error #1056: Cannot create property 1 on Number.
ive also tried:
map[[1,1]] = 1;
nothing happends that I can tell
The only way that ive tried so far that gets me a result thats not an error is:
map[1,1] = 1;
The issue here is this selects the whole row.
Any help would be apreciated..thanks!
This is not correct way to create 2D array:
private var map:Array = [[25,25]];
This array contains one array which contains two elements. You can't address to the second element like this:
map[1][1] = 1;
because the second element (array) of map doesn't exist.
You can create 2D array this way:
var map:Array = [];
for (var i:int = 0; i < rows; i++)
{
map[i] = [];// this line adds new row to the 2D array
// To fill the array by zeros add next loop
for (var j:int = 0; j < cols; j++)
{
map[i][j] = 0;
}
}
To start, I think that to get the error mentioned in your question, your array should looks like this :
var map:Array = [
[25, 25], // map[0] = [25, 25] ( array of two elements )
35 // map[1] = 35 ( just a simple number )
];
So, if you write :
trace(typeof map[1]); // gives : number
You will get : number, and that's why you can not right : map[1][1] = value; and it's normal that you got the #1056 error.
Here, I don't know if you meant assign the value 1 to your 2nd 25 of map[0] or you want really add or edit map[1][1], in the 1st case, you can simply write :
map[0][1] = 1; // gives : map[0] = [25, 1]
In the 2nd case, you can do :
map[1] = [any_other_value, 1]; // gives : map[1] = [any_other_value, 1]
Last remark, forget that you got an error and suppose that your map array was just:
var map:Array = [
[25, 25]
];
Here, you can not also write map[1][1] = value;, why ? Let's use the same method :
trace(map[1]); // gives : undefined
So sure you can not add a property to an undefined, that's why when you write :
map[1][1] = value;
You will get an #1010 error : "undefined has no properties. ".
Of course here, we should firstly create map[1] :
map[1] = []; // or directly map[1] = [any_other_value, value]
And then :
map[1][1] = value;
Hope that can help.
im basically trying to make a mini game where you have to dodge the oncoming objects by using the on-screen buttons (button left and right of the screen) it worked fine when i did it with an individual object then i decided to have more objects and make an array to hold them. thats when the error accrued.
the error is :
TypeError: Error #1010: A term is undefined and has no properties.at Untitled_fla::MainTimeline/cyclespeed()
Your cycle Array has 5 elements starting by the index 0 and ending by 4 :
... Array indices are zero-based, which means that the first element in the array is [0], the second element is [1], and so on.
That's why your for loop should be like this :
for (var i:int = 0; i < 5; i++) { }
OR
for (var i:int = 0; i <= 4; i++) { }
OR simply
for (var i:int = 0; i < cycle.length; i++) { }
In your cyclespeed function, the value of your i var will be always 5, which is the last value assigned to it in your for loop, and of course cercle[5] didn't exist that's why you got the TypeError: Error #1010: A term is undefined and has no properties : cercle[5] is undefined and has not an x property.
In your case you can use only one Event.ENTER_FRAME listener to do all the job like this :
stage.addEventListener(Event.ENTER_FRAME, onEnterThisFrame);
function onEnterThisFrame(e:Event):void {
box_MC.x -= 1;
for (var i:int = 0; i < cycle.length; i++) {
cycle[i].x += 1;
if(box_MC.hitTestObject(cycle[i])) {
trace ("true");
box_MC.x += 4;
}
}
if (movingdown == 1) {
box_MC.y -= 4.5;
} else if (movingup == 1) {
box_MC.y += 4.5;
}
}
Hope that can help.
I don't have enough rep points to comment, so I'll critique what I saw in your code.
There are quite a few things wrong with the code.
This was declared twice, once in a for loop and one outside of the functions
addEventListener(Event.ENTER_FRAME, cyclespeed);
You attached the "handleCollision" event to the stage and not a movieclip.
handleCollision refers to "cycle[i]" but i is out of scope since it is not apart of the for loop where i has been declared
function handleCollision( e:Event) : void {
if(box_MC.hitTestObject(cycle[**i**])) {
trace ("true");
box_MC.x += 4;
}
}
I would suggest building each piece one at a time because it seems like you are trying to do a lot at once, without actually getting anything to work.