Sorry im new in cakePHP. i use cakePHP 2.2. I have two table, Books and Transactions.
Table : Books
id
title
author
Table : Transactions
id
book_id
status
borrow_date
In table transaction list all transaction of the book.
My question, how to get status of max transaction id?
I try use this
options['joins'] = array(
array(
'table' => 'transactions',
'alias' => 'Transaction',
'type' => 'RIGHT OUTER',
'fields' => array('MAX(Transaction.id)', '*'),
'conditions' => array(
'Catalogue.id = Transaction.catalogue_id',
//'Transaction.user_id' => $userId
),
'order' => array('Transaction.id' => 'desc'),
)
);
$this->set('Book', $this->Book->find('all',$options));
at view:
$Book['Transaction']['status'];
But it shows an error:
Notice (8): Undefined index: Transaction [APP\View\Catalogues\user_katalog.ctp, line 32]
You are doing find(all) so you have a list of books
var_dump($Book);
you will see
array(
0 => array(
'Transaction' => ...
),
1 => array(
'Transaction' => ...
)
.....
);
not
array(
'Transaction' => ...
);
Either loop through $Book or use find('first', ...) if you want one.
dogmatic69 is right. Here's an example:
since you've used this in controller:
$this->set('Book', $this->Book->find('all',$options));
you should use this in view:
foreach( $Book as $b ) {
echo $b['Transaction']['status'];
}
Related
I am working on a cakephp 2.x .. I have two tables in my database both have the userid I am using bindModel.. my query is working fine ... I just have one problem .. I want to add the condition in where clause that
**where userid = $userid**
function getMessages($userid){
$this->bindModel(array(
'belongsTo' => array(
'Contact' => array(
'className' => 'Contact',
'foreignKey' => false,
'conditions' => array(
'Message.user_id = Contact.user_id',
'AND' =>
array(
array('OR' => array(
array('Message.mobileNo = Contact.mobileNo'),
array('Message.mobileNo = Contact.workNo'),
)),
)
),
'type' => 'LEFT',
)
)
), false);
return $this->find('all', array('conditions' => array(),
'fields' => array('Message.mobileNo'
),
'group' => 'Message.mobileNo',
'limit' => 6));
}
I am getting user id in parameter ... so I want to add the condition that get the following result where
message.userid and contact.userid = $userid ...
Just split the conditions in two lines like:
'conditions' => array(
'Contact.user_id' => $userid,
'Message.user_id = Contact.user_id',
[...]
)
But the approach that makes more sense is to leave the bind as is - after all the bind is generally between message users and contact users with the same id - and add the condition for the specific case in your find('all') with 'Message.user_id' => $userid.
In my CakePHP app I have three tables:
Businesses, Towns and Categories.
A business can belong to multiple towns and multiple categories so I have created joining tables and hasMany and belongsTo relationships. Everything works fine when finding businesses by either Town or Category by using the Town or Category model to search, but I am completely stuck when I want to search for businesses in a certain town AND a certain category, eg. Plumbers in London.
The associations just don't seem to work when searching with the Business model and I get column not found errors when trying to use the associated tables. I would think that this would be along the lines of what needs to be done, but I can't get it to work:
$this->set('listings', $this->Business->find('all', array(
'conditions' => array(
'Business.approved' => 1,
'BusinessesCategory.category_id' => $id,
'BusinessesTown.town_id' => $town_id,
'Business.sasite' => 1
)
You need to join the tables to do that.
I will put above a example how has to work with category and you can do the town yourself.
$this->Business->find("all", array(
"joins" => array(
array(
"table" => "businness_categories",
"alias" => "BusinessesCategory",
"type" => "LEFT",
"conditions" => array(
"Businesses.id = BusinessesCategory.business_id"
)
),
array(
"table" => "categories",
"alias" => "Category",
"type" => "LEFT",
"conditions" => array(
"BusinessesCategory.category_id = Category.id"
)
)
),
'conditions' => array(
'Business.approved' => 1,
'Category.id' => $id,
)
));
You also could use a behavior to do that for you:
https://github.com/Scoup/SuperJoin
Hi I had a very similar setup and the same problem. This is how I would solve your problem:
As you dont give away to much of your code I make some assumptions:
- You implemented your search method in the BusinessController
- Your search argument for the town is stored in vaiable $where and the one for Category is stored in $what
Code if you only have conditions for one table
$this->Businesses->Town->recursive = -1;
....
$options['joins'] = array(
array('table' => 'towns',
'alias' => 'Town',
'type' => 'inner',
'conditions' => array(
'Business.town_id = Town.id',
)
)
);
$options['conditions'] = array(
'Town.townName' => $where
);
$result = $this->Business->find('all', $options);
Code if you have conditions for two table
$this->Businesses->Town->recursive = -1;
$this->Businesses->Category->recursive = -1;
....
$options['joins'] = array(
array('table' => 'towns',
'alias' => 'Town',
'type' => 'inner',
'conditions' => array(
'Business.town_id = Town.id',
)
),
array('table' => 'categories',
'alias' => 'Category',
'type' => 'inner',
'conditions' => array(
'Business.category_id = category.id',
)
)
);
$options['conditions'] = array(
'Town.townName' => $where,
'Category.categoryName' => $what
);
$result = $this->Business->find('all', $options);
You can use
$this->Business->find('all', array(
'conditions' => array(
'AND' => array(
'BusinessesTown.town_id' => $town_id,
'BusinessesCategory.category_id' => $id
)
),
'recursive' => 2
));
i have a two tables namely; histories and users. i need to display data like:
id | Username | Lastest created Post | First created Post
the data of id and username is from users table and the last created and first created post data is from histories. i need to view all the users, their lastest created post and their first created post. please help me to make controller and view thanks
Try below.
<?php
$users = $this->User->find('all',array
(
'conditions' => array
(
//conditions goes here
),
'fields' => array
(
'User.id',
'User.username',
'History.Lastest created Post',
'History.First created Post'
)
));
?>
Assume that relation between 'User' and 'History' table is One-to-One and there's a 'user_id' column in History table, you may need to specify relation between them in History model, for example:
var $hasOne = array(
'User' => array(
'className' => 'User',
'foreignKey' => 'user_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
Then, you need to perform joins to do this. For example, somewhere in your User model, try something like this:
class User extends AppModel {
....
function getAllUsersHistory{
$allHistories = $this->find('all', array(
'joins' => array(
'table' => 'history',
'alias' => 'HistoryJoin'
'type' => 'INNER',
'conditions' => array(
// your conditions, for example: 'History.user_id' => 'User.id'
)
),
'fields' => array(
'User.id',
'User.username',
'History.lastest_created_post',
'History.first_created_post'
)
));
return $allHistories;
}
.....
}
I have model relations like this:
Project hasMany SubProject hasMany Item
I want to set up a containable array so that I can find all of the Items which belong to a particular Project, and paginate the results. So, in my ItemsController I have:
public $paginate = array(
'Item' => array(
'limit' => 10,
'order' => array('
'Item.create_time' => 'desc'
),
'contain' => array(
'SubProject' => array(
'Project'
)
)
)
);
Somewhere, obviously, I need to place a condition like "SubProject.project_id = $pid", but nothing I've tried yields the correct results. The best I can manage is results that look like this:
Array
(
[0] => Array
(
[Item] => Array
(
[id] => 13
[file_name] => foo.tar.gz
.... other keys ...
[create_time] => 2013-01-23 14:59:49
[subProject_id] => 4
)
[SubProject] => Array
(
[id] => 4
[name] => foo
[project_id] => 2
..... other keys ....
[Project] => Array
(
)
)
)
[1] => Array
.....
Edit: It is quite correctly omitting the Project record that doesn't match; I want to skip any Item records with out a matching Project record.
It has crossed my mind to manually specify my joins, but I feel like that shouldn't be necessary.
It seems like this should be obvious, but alas, the solution escapes me.
I did eventually solve this problem, so I thought I'd explain what I did in the hope it might help someone else.
After reading this blog post by Mark Story (which is from the days of 1.2 but still relevant) I decided that the thing to do was create a custom find type in my Item model that binds the Project model directly. This gives a first-level association that Containable can filter correctly.
So, in the Items model, I have something like the following (see the documentation on custom find types).
public $findMethods = array('byProject' => true);
public function _findByProject($state, $query, $results=array()) {
if ($state == 'before') {
$this->bindModel(array(
'hasOne' => array(
'Project' => array(
'foreignKey' => false,
'conditions' => array('Project.id = SubProject.project_id')
)
)
));
return $query;
}
return $results;
}
Note that setting foreignKey to false is necessary to prevent CakePHP from trying to automatically use a non-existent database key. In the ItemsController, the pagination options now look like this:
public $paginate = array(
'Item' => array(
'findType' => 'byProject',
'limit' => 10,
'order' => array(
'Item.create_time' => 'desc'
),
'contain' => array(
'SubProject',
'Project'
),
'conditions' => array('Project.id' = $pid)
),
);
...where $pid is the id of the project to display. Some minor tweaks in the view code to accomodate the slightly different results array structure, and I was all set.
EDIT ===============
public $paginate = array(
'limit' => 10,
'order' => 'Item.create_time DESC', //'order' => array(''Item.create_time' => 'desc'),
'contain' => array(
'SubProject' => array(
'Project' => array(
'conditions' => array(
'id' => $project_id // Passed parameter
)
)
)
)
);
=================================================
Have you tried using conditions as in the following? Also, I did not write the 'order' section of the code the way you have it.
public $paginate = array(
'Item' => array(
'limit' => 10,
'order' => 'Item.create_time DESC', //'order' => array(''Item.create_time' => 'desc'),
'contain' => array(
'SubProject' => array(
'Project' => array(
'conditions' => array(
'id' => $project_id // Passed parameter
)
)
)
)
)
);
This is one of those times when I know I'm doing something wrong, but I'm apparently deaf, dumb and blind with respect to seeing it. I'm hoping that another pair of eyes can open my own.
I have a ZipCode model and an Incentive model. There is a glorified join table (glorified because it has its own key) sitting in the middle. The join table has id, incentive_id and zip fields (legacy database). My ZipCode model HABTM Incentive as shown:
public $hasAndBelongsToMany = array(
'Incentive' => array(
'with' => 'ZipCodeIncentive',
'foreignKey' => 'zip',
'associationForeignKey' => 'incentive_id',
),
);
My Incentive model HABTM ZipCode as follows:
public $hasAndBelongsToMany = array(
'ZipCode' => array(
'with' => 'ZipCodeIncentive',
'foreignKey' => 'incentive_id',
'associationForeignKey' => 'zip',
),
I have a method, ZipCode::incentives( $zip ) that wants to pull all of the incentives relevant to the specified zip code:
$incentives = $this->Incentive->find(
'all',
array(
'contain' => array( 'ZipCode' ),
'fields' => array( 'Incentive.id', 'Incentive.name', 'Incentive.it_name', 'Incentive.amount', 'Incentive.state', 'Incentive.entire_state', 'Incentive.excluded', 'Incentive.is_active' ),
'conditions' => array(
'Incentive.excluded' => 0,
'Incentive.is_active' => 1,
'OR' => array(
'Incentive.state' => 'US', # nationwide incentives
array(
# Incentives that apply to the entire state the zip code belongs to
'Incentive.entire_state' => 1,
'Incentive.state' => $state,
),
'ZipCode.zip' => $zip # specific to the building's zip code
)
),
'order' => array( 'Incentive.amount DESC' ),
)
);
What I get for my trouble is the following error:
SQL Error: 1054: Unknown column 'ZipCode.zip' in 'where clause'
The ZipCode model's table isn't getting joined in the SQL, but I haven't grasped why yet. It's worth mentioning that the Incentive model is tied to a MySql view, not a table, via $useTable. I haven't seen anything to suggest that it should be a problem in this scenario, but it's non-standard.
If you see what I'm missing, please call 911 or at least drop an answer.
Rob
Move the condition
'ZipCode.zip' => $zip
To your contain declaration like this
array(
'contain' => array( 'ZipCode'=>
array('conditions'=>
array('ZipCode.zip' => $zip ))),
Then continue with the rest of your statement as usual