I have a search form where User can enter data to be searched and after that he has the possibility to use pagination.
For pagination I have to send again and again the searched paramters. What will be the best way to handle this situation.
You can send that searched parameter through url as named parameter. For example:
http://127.0.0.1/cakeproj/controllers/action/q:searchedItem/...
and you'll get this named parameter in controller's action like:
$this->params->named;
or
$this->params['named'];
and it will give you an array like:
[named] => Array
(
[q] => 'searchedItem',
....
)
To get the searched item directly:
$this->params->named['q'];
or
$this->params['named']['q'];
Related
If I want to display many posts in my web application but every post have its own type and I want to display each type in single page so, What's the best method to do that? Is put all all posts in one url and use query string to filter the posts upon the type and display it in the page?
For example : axios.get('/posts?type =sport')
Or I have to put every single type in separate Url
For example: axios.get('/posts/sport')
Also one more question please?
use one reducer to manage every posts or create one reducer for each post type?
you can add a dynamic route to every new type.
Ex:
'/transaction' -> component-1
'/transaction/:type' -> component-any (multiple)
welcome to Stackoverflow!
I can imagine you have a web API of some sort serving a URL /posts. You want to consume that endpoint from your web application, and you are using axios to do that. I can assume you are using JSON to return that data. Correct me if I'm wrong.
Now that the basic information is "clear", what data you serve from the endpoint, and how it is requested from the client is up to you. Do you want to ask the server what types are there first, and then do one AJAX request per type? Ok. Do you want to serve all posts independent of their type? Ok. Do you want to accept POST data in your controller so you can filter the results before returning a response? Ok.
If you are looking for a more specific answer, you must give more details, or specify more. But I hope I could be of help.
Edit: complete answer.
If you want to filter the results, you have to send some additional data in your POST request, in this case, your post type. In axios, this could be done like this:
axios.post('https://example.com/posts', {
type: 'sports'
}).then((data) => {
console.log(data);
});
You can obviously get the "type" value from a select input, other variable, even the current router page. I don't know your exact setup, but you can always come back and ask ;)
THEN, in your API controller you have to get that POST parameter type, and use it to filter the results. Again, I don't know your exact setup, but for MySQL if would be a WHERE statement in your query, or similar.
I have a searchable, sortable table in cakephp. The search and sort criteria are passed as named parameters. Now I would like to add a button which calls a method viewPdf on the very same controller to create a PDF showing the current table content. In fact, I get the correct PDF output just by replacing the action parameter in my url. But how do I get the correct link url for the button with all the current parameters?
I could implode all the values and keys of $this->params->named but I am sure there is a much better way to achieve what I want.
Regards
Alex
You are actually pretty close. You can form such a link using
$url = array('action' => 'pdf') + $this->request->params['named'];
echo $this->Html->link('Title', $url);
Assuming you are using cake2.x (which you always should mention in your question!).
I've got a Cake application with a reports query interface, where the admin user can filter the data by various inputs in a form and the results are then displayed on the screen. I am looking for the simplest way to add a button which allows the user to download the results of this same query as CSV.
I'm sure I can create one for myself if I have to, but is there already a way to regenerate any given form based on $this->data? That way, I can just add .csv to the form action and use RequestHandler to choose the right output format.
[here take a look at the following...
instead of finding the data from Db you can simply pass $this->data to it.
take a look at follo
Exporting data to CSV the CakePHP way
I guess you have to replicate the function on your controller, one for generating the results on screen and another same function intended for csv, but on the function for csv it must have parameters which are similar to the values of $this->data. Use javascript to redirect on the function for csv.
The short version of this question is:
How can I take data that only exists in an array (ie: not saved in a model yet) and relate it to a value in a $this->find('list') array from a model?
The long version of this question is:
I'm using CakePHP and the Wizard Component for a 3-step application form.
The 3 form steps are contact, course and details.
After these steps, there is a 'review' step which I want to display all of the submissions from the previous 3 form steps for the user to check one last time before pressing submit. For the most part, this works very well. I just need to do the following in the controller:
function _prepareReview() {
$contact = $this->Wizard->read('contact');
$course = $this->Wizard->read('course');
$details = $this->Wizard->read('details');
$this->set(compact('contact','course','details'));
}
Then, in review.ctp I can reference things like $contact['Contact']['firstname']; to get the person's firstname etc.
However, the problem is getting data from 'related' models. For example, there's a "Nationality" field which is just an ID. In the 'details' step, I use find('list') to get a list of all nationalities from the Nationality model as a dropdown menu which displays properly and then Cake saves the corresponding ID as it should do.
But, when I come to the 'review' step in the Wizard Component, I only get the actual ID from the Wizard Component's array. I couldn't really expect to get anything else.
I can't see any obvious way to access $details[Detail][Nationality][name] (or something like this) from the context of the Wizard Component because setting recursive doesn't work because the data isn't actually in the model at this stage, it's just an array of form data.
So, in other words, I have data in an array (NOT coming from a model, but from a form subsmission) as follows:
Array
(
[Details] => Array
(
[firstname] => Test
[nationality_id] => 3
)
)
Then I have the following coming from a $this->Detail->Nationality->find('list') which looks like this:
Array
(
[0] => American
[1] => Australian
[2] => British
[3] => Canadian
)
So how can I get $details['Details']['nationality_id']; from the Wizard Component to display 'Canadian' instead of '3' for example? How to I make the relationship when only one of the arrays is coming from a model? I only need this to momentarily confirm all of the data to the user. The id '3' will, of course, be written to the Model once the user presses submit, and this is already working as it should do.
Or is this a completely crazy way of doing things and I should look at a totally different approach such as saving the data first? I don't really want to save it until the user clicks the final submit, though.
I can see what you are getting at here - CakePHP isn't automatically querying these related models for you (as you aren't pulling from the database) but you can't help but think you are missing out on some of the framework's free functionality.
If you were still using FormHelper::input() it would automatically select the correct option (given you perform a Model::find('list') and passed the options list to the view first), but I'm assuming you wish for the review screen to be free of form inputs (disabled or not).
The most straightforward approach would be to simply perform the same Model::find('list') calls you do for each step in the wizard, set the data from each to the view, and print out the appropriate value manually:
// controller
$nationalities = $this->Review->Details->Nationality->find('list');
$this->set(compact(/*..., */ 'nationalities'));
// view
<?php echo $nationalities['Nationality'][$details['Detail']['nationality_id']]; ?>
outputs 'Canadian' (the value for $nationalities['Nationality'][3])
It might be possible to get CakePHP to do it for you by calling DboSource::queryAssociation() just right - if your up for the challenge - but is probably overkill for this particular problem.
// model
$db =& ConnectionManager::getDataSource($this->useDbConfig);
$data = $db->queryAssociation($model, $linkModel, $type, $association, $assocData, $queryData, $external, $resultSet, $recursive, $stack) {
How can I filter Results by County,District,City with dropdown select.
Is there a way to do it in Cake way, because currently I'm doing it classic way, by passing Id to url, like:
/sort/county_id/1/district_id/5
But this is very bad hack, because I have to explode $this->here and not good thing. I don't know if there is uri class like in codeigniter, so I can play with $this->uri->segment().
In fact my problem is that I need to see if isset then pass it.
Have you considered named parameters?
Add/remove Cake named URL parameter for a link