We have an LDAP login problem of a specific user and I'm suspecting that this is due to cyclic groups assignment in LDAP, i.e. the user is assigned to groups A,B,C,D. Group A contains sub-groups E,F,G and group E contains group A again.
If I query for the user I can see that he has been assigned with 50+ groups and each group may contain more groups and each of those may contain more....
My question is if there's a query I can run to get the nested groups inside those main groups all the way down instead of going each group and do it manually?
The server is AD
To find all the groups that "user1" is a member of (adaptation of this answer see AD search filter):
Set the base to the groups container DN; for example root DN (dc=dom,dc=fr)
Set the scope to subtree
Use the following filter : (member:1.2.840.113556.1.4.1941:=cn=user1,cn=users,DC=x)
Example with LDIFDE.EXE (native command line AD search on windows) :
ldifde -f t.txt -d "DC=dom,DC=fr" -r "(member:1.2.840.113556.1.4.1941:=CN=jblanc,OU=MonOu,DC=dom,DC=fr)"
Remark : as far as I remember there is a small syntax difference with in brackets user DN name. '1.2.840.113556.1.4.1941' is not working in W2K3 SP1, it begins to work with SP2. I presume it's the same with W2K3 R2. I test here with W2K8R2.
With Apache Directory Studio :
Result :
Related
I checked a few posts asked the similar questions before, but none works for my case, not sure if something wrong on my side or it's the AD.
So I have security group at path:
CN=MigratedUsers,OU=Azure Groups,OU=Security Groups,OU=National Organization,DC=abc,DC=firm,AD
And in the MigratedUsers group, there is a member property with a few AD users in the group.
I am trying to get the list of users, so I can iterate through them.
So in my base location I specified:
OU=Azure Groups,OU=Security Groups,OU=National Organization,DC=abc,DC=firm
For the LDAP Filter I have:
(&(objectCategory=user)(memberOf=CN=MigratedUsers,OU=Azure Groups,OU=Security Groups,OU=National Organization,DC=abc,DC=firm))
The result returned 0 records.
I tried other combinations such as (&(objectCategory=group)(CN=MigratedUsers)), it doesn't work either.
So, could anyone point out to me if anything in my query is wrong or I need to start checking something else like AD settings etc.
Thank you.
Your first filter looks fine :
(&(objectCategory=user)(memberOf=CN=MigratedUsers,OU=Azure Groups,OU=Security Groups,OU=National Organization,DC=abc,DC=firm))
But the search base is not, (it's a group search base, while you want to retrieve user entries). The user base should look like this :
OU=Users,OU=National Organization,DC=abc,DC=firm
You're searching for users, but you set the base of the search to:
OU=Azure Groups,OU=Security Groups,OU=National Organization,DC=abc,DC=firm
That tells it to only return users that are in the Azure Groups OU. I'm guessing that there are no users in that OU. Set the base of the search to the root of the domain (e.g. DC=abc,DC=firm), or just don't set it at all, since that will be the default.
Your first filter is the correct one (which has the full DN of the group).
I am looking for an LDAP query that would return all groups that are members of a certain LDAP/AD group, including all children.
Imagine this tree: A, A.1, A.2, A.1.1
I want to query A and get: 3 results: A.1, A.2, A.1.1
From my initial research it seems that is related to LDAP_MATCHING_RULE_IN_CHAIN from http://msdn.microsoft.com/en-us/library/aa746475%28VS.85%29.aspx but I wasn't able to figure out the proper syntax for performing the query.
Note: this is a Microsoft Active Directory so the solution doesn't have to be generic.
Not sure from your explanation what you are trying to accomplish, but One of these should work:
Resolves all members (including nested) security groups (requires at least Windows 2003 SP2)#
(memberOf:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=YOURDOMAIN,DC=NET)
Or to retrieve only users:
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=YOURDOMAIN,DC=NET)
-jim
I would like to write a search filter which would help me retrieve all groups which a user is part of.
For instance:
Say I am retrieving entries for user A (which is part of group A). And group A may be part of group B and group D which in turn may be part of group E.
Now, my search filter should return me MemberOf attribute as all possible groups which user A is part of (in this specific case it is Group A, B, D, E).
Any pointers on how the search filter can look like?
This should do what you are asking about. It will return the FDN of each group the user is a memberOf, however, this queries the group, not the user.
As an example, to find all the groups that "CN=John Smith,DC=MyDomain,DC=NET" is a member of, set the base to the groups container DN; for example (OU=groupsOU,DC=MyDomain,DC=NET) and the scope to subtree, and use the following filter.
(member:1.2.840.113556.1.4.1941:=(CN=John Smith,DC=MyDomain,DC=NET))
-jim
There is an attribute called tokenGroups in user object. It's a constructed attributes calculated by Active Directory on the runtime. It includes all the groups the user object belong to.
Make sure your domain has a Global Catalog and make sure the account that you are using Pre-Windows 2000 Compatible Access group. Then, make sure tokenGroups is specified as one of the returned property. Do a base scope search on the user object.
You can use adfind.exe (joeware) to sort out this issue and to utilize standard ldap filters that are described here. For example:
http://social.technet.microsoft.com/wiki/contents/articles/5392.active-directory-ldap-syntax-filters.aspx
Group nesting is specified to be like this:
(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)
and if you use adfind, then it would look like this:
adfind -f "(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)" samaccountname -list
If you want to have output other than samaccountname, for example displayname, or mail attribute, just add to the list. Also if you want to search multiple users, then you might want to have inputfile containing all users and some script to extract each lines to adfind for example.
I have a scheme that looks like this:
Users exist like UserA, UserB, UserC.
Groups exist like OverGroup, SubGroup.
OverGroup automatically adds new users like UserA, UserB, etc. to its membership.
SubGroup I created myself. I have set OverGroup to be a member of SubGroup.
I want to be able to one-line query SubGroup and retrieve not OverGroup, i.e.:
Values:
CN=OverGroup,OU=Groups,DC=example,DC=com
but the full enumeration of the actual Users (User A, B, C) within OverGroup, i.e.:
Values:
CN=UserA,OU=OtherOU,DC=example,DC=com
CN=UserB,OU=OtherOU,DC=example,DC=com
CN=UserC,OU=OtherOU,DC=example,DC=com
Is there a one-liner LDAP filter that could retrieve this? (It will be put into the ExternalAuth configuration 'ldap' section in a Request Tracker instance. Pretty sure I can only do this with one query the ExternalAuth module can understand.)
Everything I try does not work, and from my reading, it does not seem possible to enumerate a list of users within a group that is a member of another group with any one-line query. Thoughts?
Active Directory has a special search filter option that allows it to filter through chained objects, like nested groups. The capability is described here.
Here is an example of how to retrieve all users in a group, including nested groups:
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:={0}))
where {0} is the DN of the parent group.
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:=CN=MPV_BedPlacement,OU=Security Groups,OU=Groups,OU=CCHCS,DC=CCHCS,DC=LDAP))
You have to add the full DN for the group and no curly braces.
How do I filter an Active Directory LDAP query to groups containing the authenticated/bound user (or any user at all)? This works fine:
(&(objectClass=group)(member=*))
>>> lots of results
But I can't go any more detail:
(&(objectClass=group)(member=*S*))
>>> nothing
The MSDN mentions using a filter like this:
(member:1.2.840.113556.1.4.1941:=(cn=user1,cn=users,DC=x))
But even ignoring the crazy hyper magic number involved in that, I always get 0 results when I try to filter with that (even replacing cn=user1,cn=users,DC=x with my own distinguishedName, even replacing it with *).
You need the full DN of the user i.e
(&(member=CN=Your Name,OU=Your OU,DC=company,DC=com)(objectClass=group))
take note you cannot use * in this one
So the crazy hyper magic number involved in recursive search is explained in Search Filter Syntax.
To find in one search (recursively) all the groups that "user1" is a member of:
Set the base to the groups container DN; for example root DN (dc=dom,dc=fr)
Set the scope to subtree
Use the following filter: (member:1.2.840.113556.1.4.1941:=cn=user1,cn=users,DC=x)
explicited using LDIFDE.EXE the command line tool included in Windows Server it gives:
ldifde -f user1Grps.ldf -d "dc=societe,dc=local" -r "(member:1.2.840.113556.1.4.1941:=cn=user1,ou=Monou,dc=societe,dc=local)"
If you are running that on a W2K8 or W2K8 R2 server be careful to run as administrator.
If you are programming in C# you can use:
/* Retreiving a principal context
*/
Console.WriteLine("Retreiving a principal context");
PrincipalContext domainContext = new PrincipalContext(ContextType.Domain, "WM2008R2ENT:389", "dc=dom,dc=fr", "jpb", "PWD");
/* Look for all the groups a user belongs to
*/
UserPrincipal aUser = UserPrincipal.FindByIdentity(domainContext, "user1");
PrincipalSearchResult<Principal> a = aUser.GetAuthorizationGroups();
foreach (GroupPrincipal gTmp in a)
{
Console.WriteLine(gTmp.Name);
}