PDOException: SQLSTATE[HY000]: General error: 1406 Data too long for column
'delta' at row 1:
INSERT INTO {block}
(module, delta, theme, status, weight, region, pages, cache)
VALUES
(:db_insert_placeholder_0, :db_insert_placeholder_1, :db_insert_placeholder_2,
:db_insert_placeholder_3, :db_insert_placeholder_4, :db_insert_placeholder_5,
:db_insert_placeholder_6, :db_insert_placeholder_7);
Array (
[:db_insert_placeholder_0] => panels_mini
[:db_insert_placeholder_1] => mini_panel_titulo_de_adminisracion
[:db_insert_placeholder_2] => bartik
[:db_insert_placeholder_3] => 0
[:db_insert_placeholder_4] => 0
[:db_insert_placeholder_5] => -1
[:db_insert_placeholder_6] =>
[:db_insert_placeholder_7] => -1 )
in drupal_write_record()
(line 7013 of C:\xampp\htdocs\drupal-7.14\includes\common.inc).
someone can help me with this error.....
The delta column in the block table is a varchar with a maximum length of 32 characters.
That query is trying to insert the delta value mini_panel_titulo_de_adminisracion which is 34 characters long.
I don't use panels so I can't really advise, except to say if you can change the name of the administration title field to something at least 2 characters shorter the error will probably go away.
If not you could try filing a bug report on the panels issue queue
Related
I made two requests. The first one gives me 2419 results and I store the result in $requestFirst. The second, 1 result and I store the result in $requestTwo.
I make a union :
$requestTot = $requestFirst->union($requestTwo);
The total of the $requestTot is 2420 results so all is well so far.
Then :
$request = $this->paginate($requestTot);
$this->set(compact('request'));
And here I don't understand, on each page of the pagination I find the result of $requestTwo. Moreover the pagination displays me :
Page 121 of 121, showing 20 record(s) out of 2,420 total
This is the right number of results except that when I multiply the number of results per page by the number of pages I get 2540. This is the total number of results plus one per page.
Can anyone explain?
Check the generated SQL in Debug Kit's SQL panel, you should see that the LIMIT AND OFFSET clauses are being set on the first query, not appended as global clauses so that they would affect the unionized query.
It will look something like this:
(SELECT id, title FROM a LIMIT 20 OFFSET 0)
UNION
(SELECT id, title FROM b)
So what happens then is that pagination will only be applied to the $requestFirst query, and the $requestTwo query will be unionized on top of it each and every time, hence you'll see its result on every single page.
A workaround for this current limitation would be to use the union query as a subquery or a common table expression from which to fetch the results. In order for this to work you need to make sure that the fields of your queries for the union are being selected without aliasing! This can be achieved by either using Table::subquery():
$requestFirst = $this->TableA
->subquery()
->select(['a', 'b'])
// ...
$requestTwo = $this->TableB
->subquery()
->select(['c', 'd'])
// ...
or by explicitly selecting the fields with aliases equal to the column names:
$requestFirst = $this->TableA
->find()
->select(['a' => 'a', 'b' => 'b'])
// ...
$requestTwo = $this->TableB
->find()
->select(['c' => 'c', 'd' => 'd'])
// ...
Then you can safely use those queries for a union as a subquery:
$union = $requestFirst->union($requestTwo);
$wrapper = $this->TableA
->find()
->from([$this->TableA->getAlias() => $union]);
$request = $this->paginate($wrapper);
or as a common table expression (in case your DBMS supports them):
$union = $requestFirst->union($requestTwo);
$wrapper = $this->TableA
->find()
->with(function (\Cake\Database\Expression\CommonTableExpression $cte) use ($union) {
return $cte
->name('union_source')
->field(['a', 'b'])
->query($union)
})
->select(['a', 'b'])
->from([$this->TableA->getAlias() => 'union_source']);
$request = $this->paginate($wrapper);
I am trying get month wise sum of amount from transactions table. I have written below cakephp function to get my desire output.
public function getLastSixMOnthsExpenses($since_date, $t_type)
{
$query = $this->find()->select([
'month' => $this->find()->func()->monthname([
'created' => 'identifier'
]),
'amount' => $this->find()->func()->sum('Transactions.amount')
])
->where([
'Transactions.created >='=> $since_date->modify('6 months ago')->startOfMonth(),
'Transactions.created <='=> $since_date->endOfMonth(),
'Transactions.transaction_type '=>$t_type
])
->group(['month'])
->order(['Transactions.created'=>'ASC'])
;
return $query;
}
I am getting below error
Syntax error or access violation: 1055 Expression #1 of ORDER BY clause is not in GROUP BY clause and contains nonaggregated column 'kjoumaa_kamaljoumaa.Transactions.created' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
Without change sql mode , How can I run group by here ?
Order on an aggregate instead.
Since you group by the month, all created fields in those groups will be of one and the same month, eg all created fields in one group will point to either an earlier or a later date than the fields of another group, so you could simply pick either the min or the max value out of a group:
->orderAsc(function (
\Cake\Database\Expression\QueryExpression $exp,
\Cake\ORM\Query $query
) {
return $query->func()->min(
$query->identifier('Transactions.created')
);
})
ORDER BY MIN(Transactions.created) ASC
Also if you would select the month as a number instead of as a name, you could order on that field.
I'm using CakePHP 3.x+
I have to show a graph on the page and thus want to build script for that.
I have to select count of records group by month for current year.
This is what I have tried.
$graph = $this->GenerateVideos->find()
->select('COUNT(id)', 'MONTH(created)')
->where(['YEAR(created)' => date('Y')])
->group(['MONTH(created)']);
which generates sql like
'sql' => 'SELECT GenerateVideos.COUNT(id) AS GenerateVideos__COUNT(`id`) FROM generate_videos GenerateVideos WHERE YEAR(created) = :c0 GROUP BY MONTH(created) ',
'params' => [
':c0' => [
'value' => '2018',
'type' => null,
'placeholder' => 'c0'
]
],
But this is giving error as
Error: SQLSTATE[42000]: Syntax error or access violation:
1064 You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near '(`id`)
FROM generate_videos GenerateVideos WHERE YEAR(created) = '2018' GROUP BY' at line 1
Try using an array in your ->select() value:
->select(['COUNT(id)', 'MONTH(created)'])
In the book, it always shows an array, and it doesn't appear to be utilizing your second select value.
Or, per the book here, you could try this:
$query = $this->GenerateVideos->find();
$query->select(['count' => $query->func()->count('id'), 'month' => 'MONTH(created)']);
$query->where(['YEAR(created)' => date('Y')])
$query->group(['month' => 'MONTH(created)']);
I am running the following query on my database:-
SELECT COUNT(*) AS COUNT, `Doctor`.`device_type` FROM `doctors` AS `Doctor` WHERE 1 = 1 GROUP BY `Doctor`.`device_type`
and it gives the result:-
count device_type
47 Android
23 iPhone
Whereas when running this query as a CakePHP query it gives the result as '2':-
$this->Doctor->find('count',array('group'=>'Doctor.device_type'));
Can anyone please suggest why this is happening?
The CakePHP result is correct as it is returning a count of the number of results returned by your query. In your case you have 2 rows: 'Android' and 'iPhone'.
find('count') always returns an integer, not an array. What Cake is doing is basically this:-
$data = $this->Doctor->find('all', array('group' => 'Doctor.device_type'));
$count = count($data); // This is what find('count') will return.
You need to do something like the following instead:-
$data = $this->Doctor->find('all', array(
'fields' => array(
'Doctor.device_type',
'COUNT(Doctor.*) AS count'
)
'group' => 'Doctor.device_type'
));
Noob here.
I have a super column family sorted by timeuuidtype which has a number of entries. I'm trying to perform a simple get function with phpcassa that wont work. I'm trying to return a specific value from a UTF8 sorted column within a TimeUUID sorted SC. The exact code works with a similar SC Family sorted by BytesType.
Here is the info on the scf I'm trying to get from which i previously entered via -cli.
ColumnFamily: testSCF (Super)
Columns sorted by: org.apache.cassandra.db.marshal.TimeUUIDType/org.apache.cassandra.db.marshal.UTF8Type
RowKey: TestKey
=> (super_column=48dd0330-5bd6-11e0-adc5-343960c1b6b8,
(column=test, value=74657374, timestamp=1301603831288000))
=> (super_column=141a69b0-5c6e-11e0-bcce-343960c1b6b8,
(column=new test, value=6e657774657374, timestamp=1301669004440000))
And here is the phpcassa script I'm using to retrieve the data.
<?php
require_once('.../connection.php');
require_once('.../columnfamily.php');
$conn = new Connection('siteRoot');
$scf = 'testSCF';
$key = 'testKey';
$super = '141a69b0-5c6e-11e0-bcce-343960c1b6b8';
$col = 'new test';
$entry = new ColumnFamily($conn, $scf);
$q = ($entry->get($key, $columns=array($super)));
echo $q[$super][$col];
?>
Also if I don't specify the SC like so.
$q = ($entry->get($key));
print_r($q);
It returns:
Array ( [HÝ0[ÖàÅ49`Á¶¸] => Array ( [test] => test ) [i°\nà¼Î49`Á¶¸] => Array ( [new test] => newtest ) )
I know part of the issue might have been brought up in How do I insert a row with a TimeUUIDType column in Cassandra?
But it didn't really help me as I presumably have accepted timeuuidtypes.
Thanks for any help guys.
Suppose I didn't try hard enough to begin with. The answer in fact was everything to do with the link.
Appears that the -cli accepted what jbellis in the link describes as 32 byte representation of the timeUUID (141a69b0-5c6e-11e0-bcce-343960c1b6b8) when I inserted it. This confused me.
It works fine when you 'get()' with the "raw" 16 byte form (HÝ0[ÖàÅ49`Á¶¸).
Cheers.