Show window after double click in notify icon (after minimize to tray) - wpf

Question

I want to use in my wpf aplication notify icon (with .dll library in project http://www.codeproject.com/Articles/36468/WPF-NotifyIcon).
But I don't know, how to show my window (after minimize to tray) by double click in tray icon.
I declared new command
namespace MyBasicFlyffKeystroke
{
class ShowWindowCommand : ICommand
{
public void Execute(object parameter)
{
Window1 window = new Window1();
window.Show();
}
public bool CanExecute(object parameter)
{
return true;
}
public event EventHandler CanExecuteChanged;
}
}
And I used it in my window1.xaml file:
<tb:TaskbarIcon x:Name="notifyIcon" IconSource="icon.ico" ToolTipText="MyBasicFlyffKeystroke"
DoubleClickCommand="{StaticResource ShowWindow}">
</tb:TaskbarIcon>
and
<Grid.Resources>
<my:ShowWindowCommand x:Key="ShowWindow" />
</Grid.Resources>
But after double clicking open new instance with Window1... Is any metod here?
Best regards,
Dagna

Answer 1

Try add an event handler for window messages
Command
namespace MyBasicFlyffKeystroke
{
class ShowWindowCommand : ICommand
{
public void Execute(object parameter)
{
// Broadcast isn't a good idea but work...
NativeMethods.PostMessage((IntPtr)NativeMethods.HWND_BROADCAST, NativeMethods.WM_SHOWME, IntPtr.Zero, IntPtr.Zero);
}
public bool CanExecute(object parameter)
{
return true;
}
public event EventHandler CanExecuteChanged;
}
}
In Window1
protected override void OnSourceInitialized(EventArgs e) {
base.OnSourceInitialized(e);
HwndSource source = PresentationSource.FromVisual(this) as HwndSource;
source.AddHook(WndProc);
}
private IntPtr WndProc(IntPtr hwnd, int msg, IntPtr wParam, IntPtr lParam, ref bool handled) {
if (msg == NativeMethods.WM_SHOWME) {
WindowState = WindowState.Normal;
}
return IntPtr.Zero;
}
And in NativeMethods (UPDATED)
public static readonly int HWND_BROADCAST = 0xffff;
public static readonly int WM_SHOWME = RegisterWindowMessage("WM_SHOWME");
[DllImport("user32.dll")]
public static extern int RegisterWindowMessage(string message);
[DllImport("user32.dll")]
public static extern bool PostMessage(IntPtr hwnd, int msg, IntPtr wparam, IntPtr lparam);

Answer 2

Application.Current.Window1.Show();
this worked for me