Using the following code:
#include<stdio.h>
#include<time.h>
int main()
{
clock_t start, stop;
int i;
start = clock();
for(i=0; i<2000;i++)
{
printf("%d", (i*1)+(1^4));
}
printf("\n\n");
stop = clock();
//(double)(stop - start) / CLOCKS_PER_SEC
printf("%6.3f", start);
printf("\n\n%6.3f", stop);
return 0;
}
I get the following output:
56789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297298299300301302303304305306307308309310311312313314315316317318319320321322323324325326327328329330331332333334335336337338339340341342343344345346347348349350351352353354355356357358359360361362363364365366367368369370371372373374375376377378379380381382383384385386387388389390391392393394395396397398399400401402403404405406407408409410411412413414415416417418419420421422423424425426427428429430431432433434435436437438439440441442443444445446447448449450451452453454455456457458459460461462463464465466467468469470471472473474475476477478479480481482483484485486487488489490491492493494495496497498499500501502503504505506507508509510511512513514515516517518519520521522523524525526527528529530531532533534535536537538539540541542543544545546547548549550551552553554555556557558559560561562563564565566567568569570571572573574575576577578579580581582583584585586587588589590591592593594595596597598599600601602603604605606607608609610611612613614615616617618619620621622623624625626627628629630631632633634635636637638639640641642643644645646647648649650651652653654655656657658659660661662663664665666667668669670671672673674675676677678679680681682683684685686687688689690691692693694695696697698699700701702703704705706707708709710711712713714715716717718719720721722723724725726727728729730731732733734735736737738739740741742743744745746747748749750751752753754755756757758759760761762763764765766767768769770771772773774775776777778779780781782783784785786787788789790791792793794795796797798799800801802803804805806807808809810811812813814815816817818819820821822823824825826827828829830831832833834835836837838839840841842843844845846847848849850851852853854855856857858859860861862863864865866867868869870871872873874875876877878879880881882883884885886887888889890891892893894895896897898899900901902903904905906907908909910911912913914915916917918919920921922923924925926927928929930931932933934935936937938939940941942943944945946947948949950951952953954955956957958959960961962963964965966967968969970971972973974975976977978979980981982983984985986987988989990991992993994995996997998999100010011002100310041005100610071008100910101011101210131014101510161017101810191020102110221023102410251026102710281029103010311032103310341035103610371038103910401041104210431044104510461047104810491050105110521053105410551056105710581059106010611062106310641065106610671068106910701071107210731074107510761077107810791080108110821083108410851086108710881089109010911092109310941095109610971098109911001101110211031104110511061107110811091110111111121113111411151116111711181119112011211122112311241125112611271128112911301131113211331134113511361137113811391140114111421143114411451146114711481149115011511152115311541155115611571158115911601161116211631164116511661167116811691170117111721173117411751176117711781179118011811182118311841185118611871188118911901191119211931194119511961197119811991200120112021203120412051206120712081209121012111212121312141215121612171218121912201221122212231224122512261227122812291230123112321233123412351236123712381239124012411242124312441245124612471248124912501251125212531254125512561257125812591260126112621263126412651266126712681269127012711272127312741275127612771278127912801281128212831284128512861287128812891290129112921293129412951296129712981299130013011302130313041305130613071308130913101311131213131314131513161317131813191320132113221323132413251326132713281329133013311332133313341335133613371338133913401341134213431344134513461347134813491350135113521353135413551356135713581359136013611362136313641365136613671368136913701371137213731374137513761377137813791380138113821383138413851386138713881389139013911392139313941395139613971398139914001401140214031404140514061407140814091410141114121413141414151416141714181419142014211422142314241425142614271428142914301431143214331434143514361437143814391440144114421443144414451446144714481449145014511452145314541455145614571458145914601461146214631464146514661467146814691470147114721473147414751476147714781479148014811482148314841485148614871488148914901491149214931494149514961497149814991500150115021503150415051506150715081509151015111512151315141515151615171518151915201521152215231524152515261527152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2.169
2.169
Start and stop times are the same. Does it mean that the program hardly takes time to complete execution?
If 1. is false, then atleast the no.of digits beyond the (.) should differ, which does not happen here. Is my logic correct?
Note: I need to calculate the time taken for execution, and hence the above code.
Yes, this program has likely used less than a millsecond. Try using microsecond resolution with timeval.
e.g:
#include <sys/time.h>
struct timeval stop, start;
gettimeofday(&start, NULL);
//do stuff
gettimeofday(&stop, NULL);
printf("took %lu us\n", (stop.tv_sec - start.tv_sec) * 1000000 + stop.tv_usec - start.tv_usec);
You can then query the difference (in microseconds) between stop.tv_usec - start.tv_usec. Note that this will only work for subsecond times (as tv_usec will loop). For the general case use a combination of tv_sec and tv_usec.
Edit 2016-08-19
A more appropriate approach on system with clock_gettime support would be:
struct timespec start, end;
clock_gettime(CLOCK_MONOTONIC_RAW, &start);
//do stuff
clock_gettime(CLOCK_MONOTONIC_RAW, &end);
uint64_t delta_us = (end.tv_sec - start.tv_sec) * 1000000 + (end.tv_nsec - start.tv_nsec) / 1000;
Here is what I write to get the timestamp in millionseconds.
#include<sys/time.h>
long long timeInMilliseconds(void) {
struct timeval tv;
gettimeofday(&tv,NULL);
return (((long long)tv.tv_sec)*1000)+(tv.tv_usec/1000);
}
A couple of things might affect the results you're seeing:
You're treating clock_t as a floating-point type, I don't think it is.
You might be expecting (1^4) to do something else than compute the bitwise XOR of 1 and 4., i.e. it's 5.
Since the XOR is of constants, it's probably folded by the compiler, meaning it doesn't add a lot of work at runtime.
Since the output is buffered (it's just formatting the string and writing it to memory), it completes very quickly indeed.
You're not specifying how fast your machine is, but it's not unreasonable for this to run very quickly on modern hardware, no.
If you have it, try adding a call to sleep() between the start/stop snapshots. Note that sleep() is POSIX though, not standard C.
This code snippet can be used for displaying time in seconds,milliseconds and microseconds:
#include <sys/time.h>
struct timeval start, stop;
double secs = 0;
gettimeofday(&start, NULL);
// Do stuff here
gettimeofday(&stop, NULL);
secs = (double)(stop.tv_usec - start.tv_usec) / 1000000 + (double)(stop.tv_sec - start.tv_sec);
printf("time taken %f\n",secs);
You can use gettimeofday() together with the timedifference_msec() function below to calculate the number of milliseconds elapsed between two samples:
#include <sys/time.h>
#include <stdio.h>
float timedifference_msec(struct timeval t0, struct timeval t1)
{
return (t1.tv_sec - t0.tv_sec) * 1000.0f + (t1.tv_usec - t0.tv_usec) / 1000.0f;
}
int main(void)
{
struct timeval t0;
struct timeval t1;
float elapsed;
gettimeofday(&t0, 0);
/* ... YOUR CODE HERE ... */
gettimeofday(&t1, 0);
elapsed = timedifference_msec(t0, t1);
printf("Code executed in %f milliseconds.\n", elapsed);
return 0;
}
Note that, when using gettimeofday(), you need to take seconds into account even if you only care about microsecond differences because tv_usec will wrap back to zero every second and you have no way of knowing beforehand at which point within a second each sample is obtained.
From man clock:
The clock() function returns an approximation of processor time used by the program.
So there is no indication you should treat it as milliseconds. Some standards require precise value of CLOCKS_PER_SEC, so you could rely on it, but I don't think it is advisable.
Second thing is that, as #unwind stated, it is not float/double. Man times suggests that will be an int.
Also note that:
this function will return the same value approximately every 72 minutes
And if you are unlucky you might hit the moment it is just about to start counting from zero, thus getting negative or huge value (depending on whether you store the result as signed or unsigned value).
This:
printf("\n\n%6.3f", stop);
Will most probably print garbage as treating any int as float is really not defined behaviour (and I think this is where most of your problem comes). If you want to make sure you can always do:
printf("\n\n%6.3f", (double) stop);
Though I would rather go for printing it as long long int at first:
printf("\n\n%lldf", (long long int) stop);
The standard C library provides timespec_get. It can tell time up to nanosecond precision, if the system supports. Calling it, however, takes a bit more effort because it involves a struct. Here's a function that just converts the struct to a simple 64-bit integer so you can get time in milliseconds.
#include <stdio.h>
#include <inttypes.h>
#include <time.h>
int64_t millis()
{
struct timespec now;
timespec_get(&now, TIME_UTC);
return ((int64_t) now.tv_sec) * 1000 + ((int64_t) now.tv_nsec) / 1000000;
}
int main(void)
{
printf("Unix timestamp with millisecond precision: %" PRId64 "\n", millis());
}
Unlike clock, this function returns a Unix timestamp so it will correctly account for the time spent in blocking functions, such as sleep.
Modern processors are too fast to register the running time. Hence it may return zero. In this case, the time you started and ended is too small and therefore both the times are the same after round of.
Related
I'm using the following function to estimate the execution time (performance) of a function:
double print_time(struct timeval *start, struct timeval *end)
{
double usec;
usec = (end->tv_sec * 1000000 + end->tv_usec) - (start->tv_sec * 1000000 + start->tv_usec);
return usec / 1000.0;
}
Simple Code:
struct timeval start, end;
double t = 0.0;
gettimeofday(&start, NULL);
... //code
gettimeofday(&end, NULL);
t = print_time(&start, &end);
printf("%.2f", t);
Why when I print the variable I see the time formatted in this manner: 3.613.97? The problem is related for the two points. What means the first point and the second point? Normally I always saw just one decimal point to separate the digits.
Include the right headers:
#include <time.h>
#include <stdio.h>
At the beginning of the program:
clock_t starttime = clock();
At the end of the program:
printf("elapsed time: %.3f s\n", (float)(clock() - starttime) / CLOCKS_PER_SEC);
This works on several platforms (including Windows with MinGW-w64), but the resolution of the timer (CLOCKS_PER_SEC) may vary per platform.
Note that this measures the clock cycles used by your application, instead of the time passed between start and end.
So while it is not an exact chronometer, it gives a better idea of how much time your program actually took to run.
I want to measure the time between the start to the end of the function in a loop. This difference will be used to set the amount of loops of the inner while-loops which does some here not important stuff.
I want to time the function like this :
#include <wiringPi.h>
#include <time.h>
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <unistd.h>
#define BILLION 1E9
float hz = 1000;
long int nsPerTick = BILLION/hz;
double unprocessed = 1;
struct timespec now;
struct timespec last;
clock_gettime(CLOCK_REALTIME, &last);
[ ... ]
while (1)
{
clock_gettime(CLOCK_REALTIME, &now);
double diff = (last.tv_nsec - now.tv_nsec );
unprocessed = unprocessed + (diff/ nsPerTick);
clock_gettime(CLOCK_REALTIME, &last);
while (unprocessed >= 1) {
unprocessed --;
DO SOME RANDOM MAGIC;
}
}
The difference between the timer is always negative. I was told this was where the error was:
if ( (last.tv_nsec - now.tv_nsec)<0) {
double diff = 1000000000+ last.tv_nsec - now.tv_nsec;
}
else {
double diff = (last.tv_nsec - now.tv_nsec );
}
But still, my variable difference and is always negative like "-1095043244" (but the time spent during the function is a positive of course).
What's wrong?
Your first issue is that you have `last.tv_nsec - now.tv_nsec, which is the wrong way round.
last.tv_nsec is in the past (let's say it's set to 1), and now.tv_nsec will always be later (for example, 8ns later, so it's 9). In that case, last.tv_nsec - now.tv_nsec == 1 - 9 == -8.
The other issue is that tv_nsec isn't the time in nanoseconds: for that, you'd need to multiply the time in seconds by a billion and add that. So to get the difference in ns between now and last, you want:
((now.tv_sec - last.tv_sec) * ONE_BILLION) + (now.tv_nsec - last.tv_nsec)
(N.B. I'm still a little surprised that although now.tv_nsec and last.tv_nsec are both less than a billion, subtracting one from the other gives a value less than -1000000000, so there may yet be something I'm missing here.)
I was just investigating timing on Pi, with similar approach and similar problems. My thoughts are:
You don't have to use double. In fact you also don't need nano-seconds, as the clock on Pi has 1 microsecond accuracy anyway (it's the way the Broadcom did it). I suggest you to use gettimeofday() to get microsecs instead of nanosecs. Then computation is easy, it's just:
number of seconds + (1000 * 1000 * number of micros)
which you can simply calculate as unsigned int.
I've implemented the convenient API for this:
typedef struct
{
struct timeval startTimeVal;
} TIMER_usecCtx_t;
void TIMER_usecStart(TIMER_usecCtx_t* ctx)
{
gettimeofday(&ctx->startTimeVal, NULL);
}
unsigned int TIMER_usecElapsedUs(TIMER_usecCtx_t* ctx)
{
unsigned int rv;
/* get current time */
struct timeval nowTimeVal;
gettimeofday(&nowTimeVal, NULL);
/* compute diff */
rv = 1000000 * (nowTimeVal.tv_sec - ctx->startTimeVal.tv_sec) + nowTimeVal.tv_usec - ctx->startTimeVal.tv_usec;
return rv;
}
And the usage is:
TIMER_usecCtx_t timer;
TIMER_usecStart(&timer);
while (1)
{
if (TIMER_usecElapsedUs(timer) > yourDelayInMicroseconds)
{
doSomethingHere();
TIMER_usecStart(&timer);
}
}
Also notice the gettime() calls on Pi take almost 1 [us] to complete. So, if you need to call gettime() a lot and need more accuracy, go for some more advanced methods of getting time... I've explained more about it in this short article about Pi get-time calls
Well, I don't know C, but if it's a timing issue on a Raspberry Pi it might have something to do with the lack of an RTC (real time clock) on the chip.
You should not be storing last.tv_nsec - now.tv_nsec in a double.
If you look at the documentation of time.h, you can see that tv_nsec is stored as a long. So you will need something along the lines of:
long diff = end.tv_nsec - begin.tv_nsec
With that being said, only comparing the nanoseconds can go wrong. You also need to look at the number of seconds also. So to convert everything to seconds, you can use this:
long nanosec_diff = end.tv_nsec - begin.tv_nsec;
time_t sec_diff = end.tv_sec - begin.tv_sec; // need <sys/types.h> for time_t
double diff_in_seconds = sec_diff + nanosec_diff / 1000000000.0
Also, make sure you are always subtracting the end time from the start time (or else your time will still be negative).
And there you go!
I have a C program that aims to be run in parallel on several processors. I need to be able to record the execution time (which could be anywhere from 1 second to several minutes). I have searched for answers, but they all seem to suggest using the clock() function, which then involves calculating the number of clocks the program took divided by the Clocks_per_second value.
I'm not sure how the Clocks_per_second value is calculated?
In Java, I just take the current time in milliseconds before and after execution.
Is there a similar thing in C? I've had a look, but I can't seem to find a way of getting anything better than a second resolution.
I'm also aware a profiler would be an option, but am looking to implement a timer myself.
Thanks
CLOCKS_PER_SEC is a constant which is declared in <time.h>. To get the CPU time used by a task within a C application, use:
clock_t begin = clock();
/* here, do your time-consuming job */
clock_t end = clock();
double time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
Note that this returns the time as a floating point type. This can be more precise than a second (e.g. you measure 4.52 seconds). Precision depends on the architecture; on modern systems you easily get 10ms or lower, but on older Windows machines (from the Win98 era) it was closer to 60ms.
clock() is standard C; it works "everywhere". There are system-specific functions, such as getrusage() on Unix-like systems.
Java's System.currentTimeMillis() does not measure the same thing. It is a "wall clock": it can help you measure how much time it took for the program to execute, but it does not tell you how much CPU time was used. On a multitasking systems (i.e. all of them), these can be widely different.
If you are using the Unix shell for running, you can use the time command.
doing
$ time ./a.out
assuming a.out as the executable will give u the time taken to run this
In plain vanilla C:
#include <time.h>
#include <stdio.h>
int main()
{
clock_t tic = clock();
my_expensive_function_which_can_spawn_threads();
clock_t toc = clock();
printf("Elapsed: %f seconds\n", (double)(toc - tic) / CLOCKS_PER_SEC);
return 0;
}
You functionally want this:
#include <sys/time.h>
struct timeval tv1, tv2;
gettimeofday(&tv1, NULL);
/* stuff to do! */
gettimeofday(&tv2, NULL);
printf ("Total time = %f seconds\n",
(double) (tv2.tv_usec - tv1.tv_usec) / 1000000 +
(double) (tv2.tv_sec - tv1.tv_sec));
Note that this measures in microseconds, not just seconds.
Most of the simple programs have computation time in milli-seconds. So, i suppose, you will find this useful.
#include <time.h>
#include <stdio.h>
int main(){
clock_t start = clock();
// Execuatable code
clock_t stop = clock();
double elapsed = (double)(stop - start) * 1000.0 / CLOCKS_PER_SEC;
printf("Time elapsed in ms: %f", elapsed);
}
If you want to compute the runtime of the entire program and you are on a Unix system, run your program using the time command like this time ./a.out
(All answers here are lacking, if your sysadmin changes the systemtime, or your timezone has differing winter- and sommer-times. Therefore...)
On linux use: clock_gettime(CLOCK_MONOTONIC_RAW, &time_variable);
It's not affected if the system-admin changes the time, or you live in a country with winter-time different from summer-time, etc.
#include <stdio.h>
#include <time.h>
#include <unistd.h> /* for sleep() */
int main() {
struct timespec begin, end;
clock_gettime(CLOCK_MONOTONIC_RAW, &begin);
sleep(1); // waste some time
clock_gettime(CLOCK_MONOTONIC_RAW, &end);
printf ("Total time = %f seconds\n",
(end.tv_nsec - begin.tv_nsec) / 1000000000.0 +
(end.tv_sec - begin.tv_sec));
}
man clock_gettime states:
CLOCK_MONOTONIC
Clock that cannot be set and represents monotonic time since some unspecified starting point. This clock is not affected by discontinuous jumps in the system time
(e.g., if the system administrator manually changes the clock), but is affected by the incremental adjustments performed by adjtime(3) and NTP.
Thomas Pornin's answer as macros:
#define TICK(X) clock_t X = clock()
#define TOCK(X) printf("time %s: %g sec.\n", (#X), (double)(clock() - (X)) / CLOCKS_PER_SEC)
Use it like this:
TICK(TIME_A);
functionA();
TOCK(TIME_A);
TICK(TIME_B);
functionB();
TOCK(TIME_B);
Output:
time TIME_A: 0.001652 sec.
time TIME_B: 0.004028 sec.
A lot of answers have been suggesting clock() and then CLOCKS_PER_SEC from time.h. This is probably a bad idea, because this is what my /bits/time.h file says:
/* ISO/IEC 9899:1990 7.12.1: <time.h>
The macro `CLOCKS_PER_SEC' is the number per second of the value
returned by the `clock' function. */
/* CAE XSH, Issue 4, Version 2: <time.h>
The value of CLOCKS_PER_SEC is required to be 1 million on all
XSI-conformant systems. */
# define CLOCKS_PER_SEC 1000000l
# if !defined __STRICT_ANSI__ && !defined __USE_XOPEN2K
/* Even though CLOCKS_PER_SEC has such a strange value CLK_TCK
presents the real value for clock ticks per second for the system. */
# include <bits/types.h>
extern long int __sysconf (int);
# define CLK_TCK ((__clock_t) __sysconf (2)) /* 2 is _SC_CLK_TCK */
# endif
So CLOCKS_PER_SEC might be defined as 1000000, depending on what options you use to compile, and thus it does not seem like a good solution.
#include<time.h>
#include<stdio.h>
int main(){
clock_t begin=clock();
int i;
for(i=0;i<100000;i++){
printf("%d",i);
}
clock_t end=clock();
printf("Time taken:%lf",(double)(end-begin)/CLOCKS_PER_SEC);
}
This program will work like charm.
You have to take into account that measuring the time that took a program to execute depends a lot on the load that the machine has in that specific moment.
Knowing that, the way of obtain the current time in C can be achieved in different ways, an easier one is:
#include <time.h>
#define CPU_TIME (getrusage(RUSAGE_SELF,&ruse), ruse.ru_utime.tv_sec + \
ruse.ru_stime.tv_sec + 1e-6 * \
(ruse.ru_utime.tv_usec + ruse.ru_stime.tv_usec))
int main(void) {
time_t start, end;
double first, second;
// Save user and CPU start time
time(&start);
first = CPU_TIME;
// Perform operations
...
// Save end time
time(&end);
second = CPU_TIME;
printf("cpu : %.2f secs\n", second - first);
printf("user : %d secs\n", (int)(end - start));
}
Hope it helps.
Regards!
ANSI C only specifies second precision time functions. However, if you are running in a POSIX environment you can use the gettimeofday() function that provides microseconds resolution of time passed since the UNIX Epoch.
As a side note, I wouldn't recommend using clock() since it is badly implemented on many(if not all?) systems and not accurate, besides the fact that it only refers to how long your program has spent on the CPU and not the total lifetime of the program, which according to your question is what I assume you would like to measure.
I've found that the usual clock(), everyone recommends here, for some reason deviates wildly from run to run, even for static code without any side effects, like drawing to screen or reading files. It could be because CPU changes power consumption modes, OS giving different priorities, etc...
So the only way to reliably get the same result every time with clock() is to run the measured code in a loop multiple times (for several minutes), taking precautions to prevent the compiler from optimizing it out: modern compilers can precompute the code without side effects running in a loop, and move it out of the loop., like i.e. using random input for each iteration.
After enough samples are collected into an array, one sorts that array, and takes the middle element, called median. Median is better than average, because it throws away extreme deviations, like say antivirus taking up all CPU up or OS doing some update.
Here is a simple utility to measure execution performance of C/C++ code, averaging the values near median: https://github.com/saniv/gauge
I'm myself still looking for a more robust and faster way to measure code. One could probably try running the code in controlled conditions on bare metal without any OS, but that will give unrealistic result, because in reality OS does get involved.
x86 has these hardware performance counters, which including the actual number of instructions executed, but they are tricky to access without OS help, hard to interpret and have their own issues ( http://archive.gamedev.net/archive/reference/articles/article213.html ). Still they could be helpful investigating the nature of the bottle neck (data access or actual computations on that data).
Every solution's are not working in my system.
I can get using
#include <time.h>
double difftime(time_t time1, time_t time0);
Some might find a different kind of input useful: I was given this method of measuring time as part of a university course on GPGPU-programming with NVidia CUDA (course description). It combines methods seen in earlier posts, and I simply post it because the requirements give it credibility:
unsigned long int elapsed;
struct timeval t_start, t_end, t_diff;
gettimeofday(&t_start, NULL);
// perform computations ...
gettimeofday(&t_end, NULL);
timeval_subtract(&t_diff, &t_end, &t_start);
elapsed = (t_diff.tv_sec*1e6 + t_diff.tv_usec);
printf("GPU version runs in: %lu microsecs\n", elapsed);
I suppose you could multiply with e.g. 1.0 / 1000.0 to get the unit of measurement that suits your needs.
If you program uses GPU or if it uses sleep() then clock() diff gives you smaller than actual duration. It is because clock() returns the number of CPU clock ticks. It only can be used to calculate CPU usage time (CPU load), but not the execution duration. We should not use clock() to calculate duration. We still should use gettimeofday() or clock_gettime() for duration in C.
perf tool is more accurate to be used in order to collect and profile the running program. Use perf stat to show all information related to the program being executed.
As simple as possible by using function-like macro
#include <stdio.h>
#include <time.h>
#define printExecTime(t) printf("Elapsed: %f seconds\n", (double)(clock()-(t)) / CLOCKS_PER_SEC)
int factorialRecursion(int n) {
return n == 1 ? 1 : n * factorialRecursion(n-1);
}
int main()
{
clock_t t = clock();
int j=1;
for(int i=1; i <10; i++ , j*=i);
printExecTime(t);
// compare with recursion factorial
t = clock();
j = factorialRecursion(10);
printExecTime(t);
return 0;
}
Comparison of execution time of bubble sort and selection sort
I have a program which compares the execution time of bubble sort and selection sort.
To find out the time of execution of a block of code compute the time before and after the block by
clock_t start=clock();
…
clock_t end=clock();
CLOCKS_PER_SEC is constant in time.h library
Example code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main()
{
int a[10000],i,j,min,temp;
for(i=0;i<10000;i++)
{
a[i]=rand()%10000;
}
//The bubble Sort
clock_t start,end;
start=clock();
for(i=0;i<10000;i++)
{
for(j=i+1;j<10000;j++)
{
if(a[i]>a[j])
{
int temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
end=clock();
double extime=(double) (end-start)/CLOCKS_PER_SEC;
printf("\n\tExecution time for the bubble sort is %f seconds\n ",extime);
for(i=0;i<10000;i++)
{
a[i]=rand()%10000;
}
clock_t start1,end1;
start1=clock();
// The Selection Sort
for(i=0;i<10000;i++)
{
min=i;
for(j=i+1;j<10000;j++)
{
if(a[min]>a[j])
{
min=j;
}
}
temp=a[min];
a[min]=a[i];
a[i]=temp;
}
end1=clock();
double extime1=(double) (end1-start1)/CLOCKS_PER_SEC;
printf("\n");
printf("\tExecution time for the selection sort is %f seconds\n\n", extime1);
if(extime1<extime)
printf("\tSelection sort is faster than Bubble sort by %f seconds\n\n", extime - extime1);
else if(extime1>extime)
printf("\tBubble sort is faster than Selection sort by %f seconds\n\n", extime1 - extime);
else
printf("\tBoth algorithms have the same execution time\n\n");
}
I want to find out for how long (approximately) some block of code executes. Something like this:
startStopwatch();
// do some calculations
stopStopwatch();
printf("%lf", timeMesuredInSeconds);
How?
You can use the clock method in time.h
Example:
clock_t start = clock();
/*Do something*/
clock_t end = clock();
float seconds = (float)(end - start) / CLOCKS_PER_SEC;
You can use the time.h library, specifically the time and difftime functions:
/* difftime example */
#include <stdio.h>
#include <time.h>
int main ()
{
time_t start,end;
double dif;
time (&start);
// Do some calculation.
time (&end);
dif = difftime (end,start);
printf ("Your calculations took %.2lf seconds to run.\n", dif );
return 0;
}
(Example adapted from the difftime webpage linked above.)
Please note that this method can only give seconds worth of accuracy - time_t records the seconds since the UNIX epoch (Jan 1st, 1970).
Sometime it's needed to measure astronomical time rather than CPU time (especially this applicable on Linux):
#include <time.h>
double what_time_is_it()
{
struct timespec now;
clock_gettime(CLOCK_REALTIME, &now);
return now.tv_sec + now.tv_nsec*1e-9;
}
int main() {
double time = what_time_is_it();
printf("time taken %.6lf\n", what_time_is_it() - time);
return 0;
}
The standard C library provides the time function and it is useful if you only need to compare seconds. If you need millisecond precision, though, the most portable way is to call timespec_get. It can tell time up to nanosecond precision, if the system supports. Calling it, however, takes a bit more effort because it involves a struct. Here's a function that just converts the struct to a simple 64-bit integer.
#include <stdio.h>
#include <inttypes.h>
#include <time.h>
int64_t millis()
{
struct timespec now;
timespec_get(&now, TIME_UTC);
return ((int64_t) now.tv_sec) * 1000 + ((int64_t) now.tv_nsec) / 1000000;
}
int main(void)
{
printf("Unix timestamp with millisecond precision: %" PRId64 "\n", millis());
}
Unlike clock, this function returns a Unix timestamp so it will correctly account for the time spent in blocking functions, such as sleep. This is a useful property for benchmarking and implementing delays that take running time into account.
GetTickCount().
#include <windows.h>
void MeasureIt()
{
DWORD dwStartTime = GetTickCount();
DWORD dwElapsed;
DoSomethingThatYouWantToTime();
dwElapsed = GetTickCount() - dwStartTime;
printf("It took %d.%3d seconds to complete\n", dwElapsed/1000, dwElapsed - dwElapsed/1000);
}
I would use the QueryPerformanceCounter and QueryPerformanceFrequency functions of the Windows API. Call the former before and after the block and subtract (current − old) to get the number of "ticks" between the instances. Divide this by the value obtained by the latter function to get the duration in seconds.
For sake of completeness, there is more precise clock counter than GetTickCount() or clock() which gives you only 32-bit result that can overflow relatively quickly. It's QueryPerformanceCounter(). QueryPerformanceFrequency() gets clock frequency which is a divisor for two counters difference. Something like CLOCKS_PER_SEC in <time.h>.
#include <stdio.h>
#include <windows.h>
int main()
{
LARGE_INTEGER tu_freq, tu_start, tu_end;
__int64 t_ns;
QueryPerformanceFrequency(&tu_freq);
QueryPerformanceCounter(&tu_start);
/* do your stuff */
QueryPerformanceCounter(&tu_end);
t_ns = 1000000000ULL * (tu_end.QuadPart - tu_start.QuadPart) / tu_freq.QuadPart;
printf("dt = %g[s]; (%llu)[ns]\n", t_ns/(double)1e+9, t_ns);
return 0;
}
If you don't need fantastic resolution, you could use GetTickCount(): http://msdn.microsoft.com/en-us/library/ms724408(VS.85).aspx
(If it's for something other than your own simple diagnostics, then note that this number can wrap around, so you'll need to handle that with a little arithmetic).
QueryPerformanceCounter is another reasonable option. (It's also described on MSDN)
How do I stamp two times t1 and t2 and get the difference in milliseconds in C?
This will give you the time in seconds + microseconds
#include <sys/time.h>
struct timeval tv;
gettimeofday(&tv,NULL);
tv.tv_sec // seconds
tv.tv_usec // microseconds
Standard C99:
#include <time.h>
time_t t0 = time(0);
// ...
time_t t1 = time(0);
double datetime_diff_ms = difftime(t1, t0) * 1000.;
clock_t c0 = clock();
// ...
clock_t c1 = clock();
double runtime_diff_ms = (c1 - c0) * 1000. / CLOCKS_PER_SEC;
The precision of the types is implementation-defined, ie the datetime difference might only return full seconds.
If you want to find elapsed time, this method will work as long as you don't reboot the computer between the start and end.
In Windows, use GetTickCount(). Here's how:
DWORD dwStart = GetTickCount();
...
... process you want to measure elapsed time for
...
DWORD dwElapsed = GetTickCount() - dwStart;
dwElapsed is now the number of elapsed milliseconds.
In Linux, use clock() and CLOCKS_PER_SEC to do about the same thing.
If you need timestamps that last through reboots or across PCs (which would need quite good syncronization indeed), then use the other methods (gettimeofday()).
Also, in Windows at least you can get much better than standard time resolution. Usually, if you called GetTickCount() in a tight loop, you'd see it jumping by 10-50 each time it changed. That's because of the time quantum used by the Windows thread scheduler. This is more or less the amount of time it gives each thread to run before switching to something else. If you do a:
timeBeginPeriod(1);
at the beginning of your program or process and a:
timeEndPeriod(1);
at the end, then the quantum will change to 1 ms, and you will get much better time resolution on the GetTickCount() call. However, this does make a subtle change to how your entire computer runs processes, so keep that in mind. However, Windows Media Player and many other things do this routinely anyway, so I don't worry too much about it.
I'm sure there's probably some way to do the same in Linux (probably with much better control, or maybe with sub-millisecond quantums) but I haven't needed to do that yet in Linux.
/*
Returns the current time.
*/
char *time_stamp(){
char *timestamp = (char *)malloc(sizeof(char) * 16);
time_t ltime;
ltime=time(NULL);
struct tm *tm;
tm=localtime(<ime);
sprintf(timestamp,"%04d%02d%02d%02d%02d%02d", tm->tm_year+1900, tm->tm_mon,
tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
return timestamp;
}
int main(){
printf(" Timestamp: %s\n",time_stamp());
return 0;
}
Output: Timestamp: 20110912130940 // 2011 Sep 12 13:09:40
Use #Arkaitz Jimenez's code to get two timevals:
#include <sys/time.h>
//...
struct timeval tv1, tv2, diff;
// get the first time:
gettimeofday(&tv1, NULL);
// do whatever it is you want to time
// ...
// get the second time:
gettimeofday(&tv2, NULL);
// get the difference:
int result = timeval_subtract(&diff, &tv1, &tv2);
// the difference is storid in diff now.
Sample code for timeval_subtract can be found at this web site:
/* Subtract the `struct timeval' values X and Y,
storing the result in RESULT.
Return 1 if the difference is negative, otherwise 0. */
int
timeval_subtract (result, x, y)
struct timeval *result, *x, *y;
{
/* Perform the carry for the later subtraction by updating y. */
if (x->tv_usec < y->tv_usec) {
int nsec = (y->tv_usec - x->tv_usec) / 1000000 + 1;
y->tv_usec -= 1000000 * nsec;
y->tv_sec += nsec;
}
if (x->tv_usec - y->tv_usec > 1000000) {
int nsec = (x->tv_usec - y->tv_usec) / 1000000;
y->tv_usec += 1000000 * nsec;
y->tv_sec -= nsec;
}
/* Compute the time remaining to wait.
tv_usec is certainly positive. */
result->tv_sec = x->tv_sec - y->tv_sec;
result->tv_usec = x->tv_usec - y->tv_usec;
/* Return 1 if result is negative. */
return x->tv_sec < y->tv_sec;
}
how about this solution? I didn't see anything like this in my search. I am trying to avoid division and make solution simpler.
struct timeval cur_time1, cur_time2, tdiff;
gettimeofday(&cur_time1,NULL);
sleep(1);
gettimeofday(&cur_time2,NULL);
tdiff.tv_sec = cur_time2.tv_sec - cur_time1.tv_sec;
tdiff.tv_usec = cur_time2.tv_usec + (1000000 - cur_time1.tv_usec);
while(tdiff.tv_usec > 1000000)
{
tdiff.tv_sec++;
tdiff.tv_usec -= 1000000;
printf("updated tdiff tv_sec:%ld tv_usec:%ld\n",tdiff.tv_sec, tdiff.tv_usec);
}
printf("end tdiff tv_sec:%ld tv_usec:%ld\n",tdiff.tv_sec, tdiff.tv_usec);
Also making aware of interactions between clock() and usleep(). usleep() suspends the program, and clock() only measures the time the program is running.
If might be better off to use gettimeofday() as mentioned here
Use gettimeofday() or better clock_gettime()
U can try routines in c time library (time.h). Plus take a look at the clock() in the same lib. It gives the clock ticks since the prog has started. But you can save its value before the operation you want to concentrate on, and then after that operation capture the cliock ticks again and find the difference between then to get the time difference.
#include <sys/time.h>
time_t tm = time(NULL);
char stime[4096];
ctime_r(&tm, stime);
stime[strlen(stime) - 1] = '\0';
printf("%s",stime);
This program clearly shows how to do it. Takes time 1 pauses for 1 second and then takes time 2, the difference between the 2 times should be 1000 milliseconds. So your answer is correct
#include <stdio.h>
#include <time.h>
#include <unistd.h>
// Name: miliseconds.c
// gcc /tmp/miliseconds.c -o miliseconds
struct timespec ts1, ts2; // time1 and time2
int main (void) {
// get time1
clock_gettime(CLOCK_REALTIME, &ts1);
sleep(1); // 1 second pause
// get time2
clock_gettime(CLOCK_REALTIME, &ts2);
// nanoseconds difference in mili
long miliseconds1= (ts2.tv_nsec - ts1.tv_nsec) / 10000000 ;
// seconds difference in mili
long miliseconds2 = (ts2.tv_sec - ts1.tv_sec)*1000;
long miliseconds = miliseconds1 + miliseconds2;
printf("%ld\n", miliseconds);
return 0;
}