Oracle split text into multiple rows - database

Inside a varchar2 column I have text values like :
aaaaaa. fgdfg.
bbbbbbbbbbbbbb ccccccccc
dddddd ddd dddddddddddd,
asdasdasdll
sssss
if i do select column from table where id=... i get the whole text in a single row, normally.
But i would like to get the result in multiple rows, 5 for the example above.
I have to use just one select statement, and the delimiters will be new line or carriage return (chr(10), chr(13) in oracle)
Thank you!

Like this, maybe (but it all depends on the version of oracle you are using):
WITH yourtable AS (SELECT REPLACE('aaaaaa. fgdfg.' ||chr(10)||
'bbbbbbbbbbbbbb ccccccccc ' ||chr(13)||
'dddddd ddd dddddddddddd,' ||chr(10)||
'asdasdasdll ' ||chr(13)||
'sssss '||chr(10),chr(13),chr(10)) AS astr FROM DUAL)
SELECT REGEXP_SUBSTR ( astr, '[^' ||chr(10)||']+', 1, LEVEL) data FROM yourtable
CONNECT BY LEVEL <= LENGTH(astr) - LENGTH(REPLACE(astr, chr(10))) + 1
see: Comma Separated values in Oracle

The answer by Kevin Burton contains a bug if your data contains empty lines.
The adaptation below, based on the solution invented here, works. Check that post for an explanation on the issue and the solution.
WITH yourtable AS (SELECT REPLACE('aaaaaa. fgdfg.' ||chr(10)||
'bbbbbbbbbbbbbb ccccccccc ' ||chr(13)||
chr(13)||
'dddddd ddd dddddddddddd,' ||chr(10)||
'asdasdasdll ' ||chr(13)||
'sssss '||chr(10),chr(13),chr(10)) AS astr FROM DUAL)
SELECT REGEXP_SUBSTR ( astr, '([^' ||chr(10)||']*)('||chr(10)||'|$)', 1, LEVEL, null, 1) data FROM yourtable
CONNECT BY LEVEL <= LENGTH(astr) - LENGTH(REPLACE(astr, chr(10))) + 1;

Related

Extract string in snowflake

Is there a way in snowflake to do the followin
I want to provide input like below
'ab.cd#test.com,ef.gh#test.com,ij.kl.mn#test.com,op.qr#test.com'
output should be
ab.cd#test.com
That means, output would be starting from beginning before the first occurrence of "comma"
I am not sure if below code will work in all scenarios or there is a better way to do this in Snowflake
SELECT
SUBSTRING ('ab.cd#test.com,ef.gh#test.com,ij.kl.mn#test.com,op.qr#test.com', 1,
CHARINDEX (',', 'ab.cd#test.com,ef.gh#test.com,ij.kl.mn#test.com,op.qr#test.com')-1
)
Using SPLIT_PART function:
SELECT
SPLIT_PART('ab.cd#test.com,ef.gh#test.com,ij.kl.mn#test.com,op.qr#test.com', ',',1)
Output:
ab.cd#test.com
Alternatively SPLIT_TO_TABLE:
SELECT *
FROM TABLE(SPLIT_TO_TABLE('ab.cd#test.com,ef.gh#test.com,ij.kl.mn#test.com,op.qr#test.com', ',')) s
WHERE s.Index = 1;
Hi you can use SPLIT_PART
Reference: SPLIT_PART
https://docs.snowflake.com/en/sql-reference/functions/split_part.html#split-part
select split_part('ab.cd#test.com,ef.gh#test.com,ij.kl.mn#test.com,op.qr#test.com' ,
',',1) from dual;

How to remove space when concatenating data from different rows into one column using xml?

I am trying to combine data from different rows into one column, and this is working with just one minor problem.
declare #RitID int = 16
select ...,
( select distinct
ISNULL(LTRIM(RTRIM(r2.LotNr)), LTRIM(RTRIM(r.LotNr))) + '+' as 'data()'
from tblExtraBestemming eb2
inner join tblRit r2 on eb2.RitID = r2.RitID
where eb2.BestemmingID = eb.BestemmingID
and eb2.BestemmingTypeID = eb.BestemmingTypeID
and ( (eb.CombinedChildExtraBestemmingID is null and eb2.RitID = #RitID)
or
(eb.CombinedChildExtraBestemmingID is not null and eb2.RitID in (select r4.RitID from tblRit r4 where r4.MasterRitID = #RitID) )
)
for XML PATH('')
) as LotNr
from tblExtraBestemming eb
where ...
this returns the correct data for the column LotNr, like this
GTT18196
GTT18197
GTT18198+ GTT18199
Now my only problem is the space after the + sign in the third row from the result, how can I get rid of this ?
I expect this result
GTT18196
GTT18197
GTT18198+GTT18199
PS, actually there is also a + at the end of each row, but that is removed by the client. I thought I better mentions this already.
EDIT
I checked the data, there are no spaces at the end or the beginning of the data
EDIT
Query updated as suggested by #Larnu
EDIT
if I check the data in the table, this is the result
select '/' + r.LotNr + '/' from tblRit r where r.RitID in (50798, 50799)
COLUMN1
-------
/GTT18198/
/GTT18199/
So it appears to me there are no characters before or after the data
Just remove AS 'data()' from your query (it is not required in the above case).
And if trailing + is a problem, move it to the beginning and use STUFF function to chop off the first character from the result.

Using SQL WHERE LIKE to filter when have consecutive numbers

Trying to convert a PostgreSQL view to SQL Server (2016) view.
I have a table with a column named filename, with the following data:
R24bMP1.png
MP3.png
R28.jpg
I002.jpg
App_1472669569054.jpg
Test_1575753047890.png
So, I like to filter all rows the filename must contains 13 consecutives numbers, in the example, only App_1472669569054.jpg and Test_1575753047890.png.
In PostgreSQL, I can use regex to do this:
SELECT * FROM table WHERE filename ~ '\d{13}'.
Tried in SQL Server with:
SELECT * FROM table WHERE filename LIKE '%[0-9]{13}%', but got no results. The only way that worked is:
SELECT * FROM table WHERE filename LIKE '%[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]%'
After that, I need to get only the number part of filename, in the example, the returned value must be:
1472669569054
1575753047890
I know I can use CLR with SQL Server, but I like to known if is possible to filter without CLR in this case.
As Martin Smith pointed out:
'%[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]%'
can be reduced to:
'%' + replicate('[0-9]',13) + '%'
You were most of the way there:
declare #filename varchar(128) = 'Test_1575753047890.png'
select test=substring(#filename
,patindex('%' + replicate('[0-9]',13) + '%',#filename)
,13
)
returns: 1575753047890
So for your table it would look like:
select test=substring([filename]
,patindex('%' + replicate('[0-9]',13) + '%',[filename])
,13
)
from t
where patindex('%' + replicate('[0-9]',13) + '%',[filename]) > 0

Count the 'X' then arrange the value as row in SQL

I have a table in SQL that have many columns which the value of each columns in every row is either ' ' or 'X'. I need to count this 'X' for every columns which can be done by following code;
SELECT COUNT(GVI0) AS GVI0, COUNT(GVI1) AS GVI1, COUNT(GVI2) AS GVI2
FROM dbo.HullInspectionProgram
WHERE (StructureEntry='1' AND Year='2016')
The result of the query is;
GVI0 NDT0 GVI1 NDT1 GVI2 NDT2
11 11 2 4 11 11
However, (in my understanding) in order for this count value to be bind into ASP.net Chart Control with multiple series name 'GVI' and 'NDT', I need to make the column into row for the DataTable.
I try to use UNPIVOT in SQL like this;
SELECT GVI0Count
FROM (
SELECT COUNT(GVI0) AS GVI0, COUNT(GVI1) AS GVI1, COUNT(GVI2) AS GVI2
FROM dbo.HullInspectionProgram
WHERE (StructureEntry='1' AND Year='2016')
)
UNPIVOT (GVI0Count FOR ListOfColumns IN (GVI0)) AS unpivott
but it seem that the code is wrong.
How do I do this?
I think the following might work for you. At least, as a start.
SELECT *
FROM (
SELECT COUNT(GVI0) AS GVI0, COUNT(GVI1) AS GVI1, COUNT(GVI2) AS GVI2
FROM dbo.HullInspectionProgram
WHERE (StructureEntry='1' AND Year='2016')
) P
UNPIVOT (GVI0Count FOR ListOfColumns IN (GVI0, GVI1, GVI2)) AS unpivott

SQL Invalid data is showing

t0212_1 t0212_2
884999999 GCP-9 Company A
8849999 GCP-7 Company B
#val = 884999999
Here's my query :
Select * Company
WHERE t0212_1= (LEFT(CONVERT(BIGINT,#val),convert(int,substring('GCP-9',5,2)))) OR
t0212_1= LEFT(CONVERT(BIGINT,#val),convert(int,substring('GCP-7',5,2)))
When I searched 8849999 , 8849999 shows(this is RIGHT).
When I searched 884999999 , 884999999 shows(this is RIGHT) and 8849999 shows(WRONG).
What to do, please help
Thanks,
If you dont understand my very short explanation you can verify it to me.
Your filteration is either 7 or 9 characters from the input (DECLARE #val INT = 884999999)
should match the column (t0212_1) value.
As per your filter, you would get two records since the two records matched on your filteration.
You can use this SQL
SELECT *
FROM #Company
WHERE t0212_1 = (LEFT(CONVERT(BIGINT, #val), convert(INT, substring(t0212_2, 5, 2))))

Resources