I'm unable to find any for loop syntax that works with ksh for me. I'm wanting to create a program that esentially will add up numbers that are assigned to letters when a user inputs a word into the program. I want the for loop to read the first character, grab the number value of the letter, and then add the value to a variable that starts out equaled to 0. Then the next letter will get added to the variable's value and so on until there are no more letters and there will be a variable from the for loop that equals a value.
I understand I more than likely need an array that specifies what a letter's (a-z) value would be (1-26)...which I am finding difficult to figure that out as well. Or worst case I figure out the for loop and then make about 26 if statements saying something like if the letter equals c, add 3 to the variable.
So far I have this (which is pretty bare bones):
#!/bin/ksh
typeset -A my_array
my_array[a]=1
my_array[b]=2
my_array[c]=3
echo "Enter a word: \c"
read work
for (( i=0; i<${work}; i++ )); do
echo "${work:$i:1}"
done
Pretty sure this for loop is bash and not ksh. And the array returns an error of typeset: bad option(s) (I understand I haven't specified the array in the for loop).
I want the array letters (a, b, c, etc) to correspond to a value such as a = 1, b = 2, c = 3 and so on. For example the word is 'abc' and so it would add 1 + 2 + 3 and the final output will be 6.
You were missing the pound in ${#work}, which expands to 'length of ${work}'.
#!/bin/ksh
typeset -A my_array
my_array[a]=1
my_array[b]=2
my_array[c]=3
read 'work?enter a word: '
for (( i=0; i<${#work}; i++ )); do
c=${work:$i:1} w=${my_array[${work:$i:1}]}
echo "$c: $w"
done
ksh2020 supports read -p PROMPT syntax, which would make this script 100% compatible with bash. ksh93 does not. You could also use printf 'enter a word: ', which works in all three (ksh2020, ksh93, bash) and zsh.
Both ksh2020 and ksh93 understand read var?prompt which I used above.
First check the input work, you only want {a..z}.
charwork=$(tr -cd "[a-z]" <<< "$work")
Next you can fill 2 arrays with corresponding values
a=( {a..z} )
b=( {1..26} )
Using these arrays you can make a file with sed commands
for ((i=0;i<26;i++)); do echo "s/${a[i]}/${b[i]}+/g"; done > replaceletters.sed
# test it
echo "abcz" | sed -f replaceletters.sed
# result: 1+2+3+26+
Before you can pipe this into bc, use sed to remove the last + character.
Append s/+$/\n/ to replaceletters.sed and bc can calculate it.
Now you can use sed for replacing letters by digits and insert + signs.
Combining the steps, you have
a=( {a..z} )
b=( {1..26} )
tr -cd "[a-z]" <<< "$work" |
sed -f <(
for ((i=0;i<26;i++)); do
echo "s/${a[i]}/${b[i]}+/g"
done
echo 's/+$/\n/'
) | bc
In the loop you can use $i and avoid array b, but remember that the array start with 0, so a[5] corresponds with 6.
I am working on the below script.
I don't understand why I am unable to assign the value to the array and when I print the array elements I only get arr[0], the rest of elements are empty
Is there a more efficient way to match l_num between fields rt_h and rt_f extracted from rt_facts file?
$ bash -version
GNU bash, version 4.1.2(1)-release (x86_64-redhat-linux-gnu)
$ cat rt_facts
T5 1 2:8 47:9 44
T14 2 48:8 93:9 44
T15 3 94:8 96:9 1
here is the filtered file:
$cat filtered_file
12 4046580009982686 05072021 24692161126100379438583 44442
54 4046580009982686 05072021 24692161126100379438583 44442
95 4046580009982686 05072021 24692161126100379438583 44442
In this script, I am trying to match a string in the filtered file using line number from the original file.
bash-4.1$ vi comb_rt_ct.ksh
#!/bin/bash
rows=1
cols=$(($(cat rt_facts | wc -l) + 1))
declare -a arr #=( $(for i in {1..$cols}; do echo 0; done) )
echo "cols " $cols
for l_num in $(grep '4046580009982686 05072021 24692161126100379438583 44442' filtered_file | cut -d" " -f 1)
do
arr[0]="4046580009982686 05072021 24692161126100379438583 44442"
echo "l_num " $l_num
cat rt_facts | while IFS=" " read -r lineStr
do
line=( $lineStr )
#echo ${line[*]}
rt_h=$(echo ${line[2]} | cut -d":" -f 1)
rt_f=$(echo ${line[3]} | cut -d":" -f 1)
if (( l_num > $rt_h && l_num < $rt_f )); then
echo "rt_h rt_f " $rt_h " " $rt_f
echo "line[*] " ${line[*]}
i=${line[1]}
echo "i " $i
if [[ -z "${arr[$i]}" ]]; then
echo "empty"
arr[$i]=0
fi
(( arr[$i]++ ))
echo "arr[$i] "${arr[$i]}
#echo ${line[0]}
break
fi
done
echo
done
echo ${arr[#]}
echo ${arr[*]}
echo ${arr[2]}
Here is the output when I run the script:
bash-4.1$ sh comb_rt_ct.ksh
cols 4
l_num 12
rt_h rt_f 2 47
line[*] T5 1 2:8 47:9 44
i 1
empty
arr[1] 1
l_num 54
rt_h rt_f 48 93
line[*] T14 2 48:8 93:9 44
i 2
empty
arr[2] 1
l_num 95
rt_h rt_f 94 96
line[*] T15 3 94:8 96:9 1
i 3
empty
arr[3] 1
4046580009982686 05072021 24692161126100379438583 44442
4046580009982686 05072021 24692161126100379438583 44442
bash-4.1$
As #glennjackman has pointed out, the question needs to be updated to provide a minimal, reproducible example; so I'm skipping trying to reverse engineer the intent of the script (or figure out the content of the file named filtered_file) and instead focus on one item of interest:
cat t_facts | while IFS=" " read
...
<assign_values_to_array>
...
done
The | while ... invokes a subshell; new values are assigned to the arr[] array within this subshell.
In ksh, when exiting the subshell, the newly updated arr[] values are (effectively) passed to the calling/parent process.
In bash, when exiting the subshell, the newly updated arr[] values are discarded when returning to the calling/parent process.
Because OP's code is running under bash (#!/bin/bash), the changes to arr[] are lost upon exiting the subshell; this in turn means the calling/parent process 'still' has the same initial value in arr[], namely:
arr[0]="4046580009982686 05072021 24692161126100379438583 44442"
One method to address this issue, which should work in ksh and bash:
while IFS=" " read
...
<assign_value_to_array>
...
done < t_facts
This eliminates the subshell invocation and therefore allows the new array assignments to be made in the main process.
Again, I haven't attempted to understand the overall logic of the script, but fwiw ... I'd suggest OP make the suggested code change to the while loop (to eliminate the subshell invocation) to see if the arr[] array is populated with the desired results.
It is easy to declare and store a number in array but problem is that the user gives input 1234 and i wanted to store this numbers as $array[0]=1, $array[1]=2, $array[2]=3, $array[3]=4 but instead what actually happens is that $array[0]=1234, $array[1]=null, $array[2]=null, $array[3]=null. I don't know how to store each number separately
#!/bin/bash
declare -a key
read -p "Enter the encryption key: " numbers
key=($numbers)
echo ${key[0]}
echo ${key[1]}
echo ${key[2]}
echo ${key[3]}.
Actual output:
Enter the encryption key: 1234
1234
null
null
null
Desired output:
Enter the encryption key: 1234
1
2
3
4
Thank you, in advance :)
There is also a possibility to use
key=(`grep -o . <<< "$numbers"`)
And you can access different letters in $numbers without creating an array by using a substring notation ${string:initial_index:length_of_substring}:
echo ${numbers:0:1}
echo ${numbers:1:1}
echo ${numbers:2:1}
echo ${numbers:3:1}
Seeing how you're using read so you already assume that there are no spaces in the key, you can do this:
#!/bin/bash
declare str
read -p "Enter the encryption key: " str
# replace each character with that character + space
spaced=$(echo "$str" | sed 's/\(.\)/\1 /g')
# without quotes, array elements will be each of the space-separated strings
numbers=( $spaced )
printf "array element %s\n" "${numbers[#]}"
Output:
Enter the encryption key: hello123
array element h
array element e
array element l
array element l
array element o
array element 1
array element 2
array element 3
You can try.
declare -a key
read -p "Enter the encryption key: " numbers
while read -n1 input; do
key+=("$input")
done < <(printf '%s' "$numbers")
printf '%s\n' "${key[#]}"
I need to remove an element from an array in bash shell.
Generally I'd simply do:
array=("${(#)array:#<element to remove>}")
Unfortunately the element I want to remove is a variable so I can't use the previous command.
Down here an example:
array+=(pluto)
array+=(pippo)
delete=(pluto)
array( ${array[#]/$delete} ) -> but clearly doesn't work because of {}
Any idea?
The following works as you would like in bash and zsh:
$ array=(pluto pippo)
$ delete=pluto
$ echo ${array[#]/$delete}
pippo
$ array=( "${array[#]/$delete}" ) #Quotes when working with strings
If need to delete more than one element:
...
$ delete=(pluto pippo)
for del in ${delete[#]}
do
array=("${array[#]/$del}") #Quotes when working with strings
done
Caveat
This technique actually removes prefixes matching $delete from the elements, not necessarily whole elements.
Update
To really remove an exact item, you need to walk through the array, comparing the target to each element, and using unset to delete an exact match.
array=(pluto pippo bob)
delete=(pippo)
for target in "${delete[#]}"; do
for i in "${!array[#]}"; do
if [[ ${array[i]} = $target ]]; then
unset 'array[i]'
fi
done
done
Note that if you do this, and one or more elements is removed, the indices will no longer be a continuous sequence of integers.
$ declare -p array
declare -a array=([0]="pluto" [2]="bob")
The simple fact is, arrays were not designed for use as mutable data structures. They are primarily used for storing lists of items in a single variable without needing to waste a character as a delimiter (e.g., to store a list of strings which can contain whitespace).
If gaps are a problem, then you need to rebuild the array to fill the gaps:
for i in "${!array[#]}"; do
new_array+=( "${array[i]}" )
done
array=("${new_array[#]}")
unset new_array
You could build up a new array without the undesired element, then assign it back to the old array. This works in bash:
array=(pluto pippo)
new_array=()
for value in "${array[#]}"
do
[[ $value != pluto ]] && new_array+=($value)
done
array=("${new_array[#]}")
unset new_array
This yields:
echo "${array[#]}"
pippo
This is the most direct way to unset a value if you know it's position.
$ array=(one two three)
$ echo ${#array[#]}
3
$ unset 'array[1]'
$ echo ${array[#]}
one three
$ echo ${#array[#]}
2
This answer is specific to the case of deleting multiple values from large arrays, where performance is important.
The most voted solutions are (1) pattern substitution on an array, or (2) iterating over the array elements. The first is fast, but can only deal with elements that have distinct prefix, the second has O(n*k), n=array size, k=elements to remove. Associative array are relative new feature, and might not have been common when the question was originally posted.
For the exact match case, with large n and k, possible to improve performance from O(nk) to O(n+klog(k)). In practice, O(n) assuming k much lower than n. Most of the speed up is based on using associative array to identify items to be removed.
Performance (n-array size, k-values to delete). Performance measure seconds of user time
N K New(seconds) Current(seconds) Speedup
1000 10 0.005 0.033 6X
10000 10 0.070 0.348 5X
10000 20 0.070 0.656 9X
10000 1 0.043 0.050 -7%
As expected, the current solution is linear to N*K, and the fast solution is practically linear to K, with much lower constant. The fast solution is slightly slower vs the current solution when k=1, due to additional setup.
The 'Fast' solution: array=list of input, delete=list of values to remove.
declare -A delk
for del in "${delete[#]}" ; do delk[$del]=1 ; done
# Tag items to remove, based on
for k in "${!array[#]}" ; do
[ "${delk[${array[$k]}]-}" ] && unset 'array[k]'
done
# Compaction
array=("${array[#]}")
Benchmarked against current solution, from the most-voted answer.
for target in "${delete[#]}"; do
for i in "${!array[#]}"; do
if [[ ${array[i]} = $target ]]; then
unset 'array[i]'
fi
done
done
array=("${array[#]}")
Here's a one-line solution with mapfile:
$ mapfile -d $'\0' -t arr < <(printf '%s\0' "${arr[#]}" | grep -Pzv "<regexp>")
Example:
$ arr=("Adam" "Bob" "Claire"$'\n'"Smith" "David" "Eve" "Fred")
$ echo "Size: ${#arr[*]} Contents: ${arr[*]}"
Size: 6 Contents: Adam Bob Claire
Smith David Eve Fred
$ mapfile -d $'\0' -t arr < <(printf '%s\0' "${arr[#]}" | grep -Pzv "^Claire\nSmith$")
$ echo "Size: ${#arr[*]} Contents: ${arr[*]}"
Size: 5 Contents: Adam Bob David Eve Fred
This method allows for great flexibility by modifying/exchanging the grep command and doesn't leave any empty strings in the array.
Partial answer only
To delete the first item in the array
unset 'array[0]'
To delete the last item in the array
unset 'array[-1]'
To expand on the above answers, the following can be used to remove multiple elements from an array, without partial matching:
ARRAY=(one two onetwo three four threefour "one six")
TO_REMOVE=(one four)
TEMP_ARRAY=()
for pkg in "${ARRAY[#]}"; do
for remove in "${TO_REMOVE[#]}"; do
KEEP=true
if [[ ${pkg} == ${remove} ]]; then
KEEP=false
break
fi
done
if ${KEEP}; then
TEMP_ARRAY+=(${pkg})
fi
done
ARRAY=("${TEMP_ARRAY[#]}")
unset TEMP_ARRAY
This will result in an array containing:
(two onetwo three threefour "one six")
Here's a (probably very bash-specific) little function involving bash variable indirection and unset; it's a general solution that does not involve text substitution or discarding empty elements and has no problems with quoting/whitespace etc.
delete_ary_elmt() {
local word=$1 # the element to search for & delete
local aryref="$2[#]" # a necessary step since '${!$2[#]}' is a syntax error
local arycopy=("${!aryref}") # create a copy of the input array
local status=1
for (( i = ${#arycopy[#]} - 1; i >= 0; i-- )); do # iterate over indices backwards
elmt=${arycopy[$i]}
[[ $elmt == $word ]] && unset "$2[$i]" && status=0 # unset matching elmts in orig. ary
done
return $status # return 0 if something was deleted; 1 if not
}
array=(a 0 0 b 0 0 0 c 0 d e 0 0 0)
delete_ary_elmt 0 array
for e in "${array[#]}"; do
echo "$e"
done
# prints "a" "b" "c" "d" in lines
Use it like delete_ary_elmt ELEMENT ARRAYNAME without any $ sigil. Switch the == $word for == $word* for prefix matches; use ${elmt,,} == ${word,,} for case-insensitive matches; etc., whatever bash [[ supports.
It works by determining the indices of the input array and iterating over them backwards (so deleting elements doesn't screw up iteration order). To get the indices you need to access the input array by name, which can be done via bash variable indirection x=1; varname=x; echo ${!varname} # prints "1".
You can't access arrays by name like aryname=a; echo "${$aryname[#]}, this gives you an error. You can't do aryname=a; echo "${!aryname[#]}", this gives you the indices of the variable aryname (although it is not an array). What DOES work is aryref="a[#]"; echo "${!aryref}", which will print the elements of the array a, preserving shell-word quoting and whitespace exactly like echo "${a[#]}". But this only works for printing the elements of an array, not for printing its length or indices (aryref="!a[#]" or aryref="#a[#]" or "${!!aryref}" or "${#!aryref}", they all fail).
So I copy the original array by its name via bash indirection and get the indices from the copy. To iterate over the indices in reverse I use a C-style for loop. I could also do it by accessing the indices via ${!arycopy[#]} and reversing them with tac, which is a cat that turns around the input line order.
A function solution without variable indirection would probably have to involve eval, which may or may not be safe to use in that situation (I can't tell).
Using unset
To remove an element at particular index, we can use unset and then do copy to another array. Only just unset is not required in this case. Because unset does not remove the element it just sets null string to the particular index in array.
declare -a arr=('aa' 'bb' 'cc' 'dd' 'ee')
unset 'arr[1]'
declare -a arr2=()
i=0
for element in "${arr[#]}"
do
arr2[$i]=$element
((++i))
done
echo "${arr[#]}"
echo "1st val is ${arr[1]}, 2nd val is ${arr[2]}"
echo "${arr2[#]}"
echo "1st val is ${arr2[1]}, 2nd val is ${arr2[2]}"
Output is
aa cc dd ee
1st val is , 2nd val is cc
aa cc dd ee
1st val is cc, 2nd val is dd
Using :<idx>
We can remove some set of elements using :<idx> also. For example if we want to remove 1st element we can use :1 as mentioned below.
declare -a arr=('aa' 'bb' 'cc' 'dd' 'ee')
arr2=("${arr[#]:1}")
echo "${arr2[#]}"
echo "1st val is ${arr2[1]}, 2nd val is ${arr2[2]}"
Output is
bb cc dd ee
1st val is cc, 2nd val is dd
http://wiki.bash-hackers.org/syntax/pe#substring_removal
${PARAMETER#PATTERN} # remove from beginning
${PARAMETER##PATTERN} # remove from the beginning, greedy match
${PARAMETER%PATTERN} # remove from the end
${PARAMETER%%PATTERN} # remove from the end, greedy match
In order to do a full remove element, you have to do an unset command with an if statement. If you don't care about removing prefixes from other variables or about supporting whitespace in the array, then you can just drop the quotes and forget about for loops.
See example below for a few different ways to clean up an array.
options=("foo" "bar" "foo" "foobar" "foo bar" "bars" "bar")
# remove bar from the start of each element
options=("${options[#]/#"bar"}")
# options=("foo" "" "foo" "foobar" "foo bar" "s" "")
# remove the complete string "foo" in a for loop
count=${#options[#]}
for ((i = 0; i < count; i++)); do
if [ "${options[i]}" = "foo" ] ; then
unset 'options[i]'
fi
done
# options=( "" "foobar" "foo bar" "s" "")
# remove empty options
# note the count variable can't be recalculated easily on a sparse array
for ((i = 0; i < count; i++)); do
# echo "Element $i: '${options[i]}'"
if [ -z "${options[i]}" ] ; then
unset 'options[i]'
fi
done
# options=("foobar" "foo bar" "s")
# list them with select
echo "Choose an option:"
PS3='Option? '
select i in "${options[#]}" Quit
do
case $i in
Quit) break ;;
*) echo "You selected \"$i\"" ;;
esac
done
Output
Choose an option:
1) foobar
2) foo bar
3) s
4) Quit
Option?
Hope that helps.
There is also this syntax, e.g. if you want to delete the 2nd element :
array=("${array[#]:0:1}" "${array[#]:2}")
which is in fact the concatenation of 2 tabs. The first from the index 0 to the index 1 (exclusive) and the 2nd from the index 2 to the end.
POSIX shell script does not have arrays.
So most probably you are using a specific dialect such as bash, korn shells or zsh.
Therefore, your question as of now cannot be answered.
Maybe this works for you:
unset array[$delete]
What I do is:
array="$(echo $array | tr ' ' '\n' | sed "/itemtodelete/d")"
BAM, that item is removed.
This is a quick-and-dirty solution that will work in simple cases but will break if (a) there are regex special characters in $delete, or (b) there are any spaces at all in any items. Starting with:
array+=(pluto)
array+=(pippo)
delete=(pluto)
Delete all entries exactly matching $delete:
array=(`echo $array | fmt -1 | grep -v "^${delete}$" | fmt -999999`)
resulting in
echo $array -> pippo, and making sure it's an array:
echo $array[1] -> pippo
fmt is a little obscure: fmt -1 wraps at the first column (to put each item on its own line. That's where the problem arises with items in spaces.) fmt -999999 unwraps it back to one line, putting back the spaces between items. There are other ways to do that, such as xargs.
Addendum: If you want to delete just the first match, use sed, as described here:
array=(`echo $array | fmt -1 | sed "0,/^${delete}$/{//d;}" | fmt -999999`)
Actually, I just noticed that the shell syntax somewhat has a behavior built-in that allows for easy reconstruction of the array when, as posed in the question, an item should be removed.
# let's set up an array of items to consume:
x=()
for (( i=0; i<10; i++ )); do
x+=("$i")
done
# here, we consume that array:
while (( ${#x[#]} )); do
i=$(( $RANDOM % ${#x[#]} ))
echo "${x[i]} / ${x[#]}"
x=("${x[#]:0:i}" "${x[#]:i+1}")
done
Notice how we constructed the array using bash's x+=() syntax?
You could actually add more than one item with that, the content of a whole other array at once.
In ZSH this is dead easy (note this uses more bash compatible syntax than necessary where possible for ease of understanding):
# I always include an edge case to make sure each element
# is not being word split.
start=(one two three 'four 4' five)
work=(${(#)start})
idx=2
val=${work[idx]}
# How to remove a single element easily.
# Also works for associative arrays (at least in zsh)
work[$idx]=()
echo "Array size went down by one: "
[[ $#work -eq $(($#start - 1)) ]] && echo "OK"
echo "Array item "$val" is now gone: "
[[ -z ${work[(r)$val]} ]] && echo OK
echo "Array contents are as expected: "
wanted=("${start[#]:0:1}" "${start[#]:2}")
[[ "${(j.:.)wanted[#]}" == "${(j.:.)work[#]}" ]] && echo "OK"
echo "-- array contents: start --"
print -l -r -- "-- $#start elements" ${(#)start}
echo "-- array contents: work --"
print -l -r -- "-- $#work elements" "${work[#]}"
Results:
Array size went down by one:
OK
Array item two is now gone:
OK
Array contents are as expected:
OK
-- array contents: start --
-- 5 elements
one
two
three
four 4
five
-- array contents: work --
-- 4 elements
one
three
four 4
five
To avoid conflicts with array index using unset - see https://stackoverflow.com/a/49626928/3223785 and https://stackoverflow.com/a/47798640/3223785 for more information - reassign the array to itself: ARRAY_VAR=(${ARRAY_VAR[#]}).
#!/bin/bash
ARRAY_VAR=(0 1 2 3 4 5 6 7 8 9)
unset ARRAY_VAR[5]
unset ARRAY_VAR[4]
ARRAY_VAR=(${ARRAY_VAR[#]})
echo ${ARRAY_VAR[#]}
A_LENGTH=${#ARRAY_VAR[*]}
for (( i=0; i<=$(( $A_LENGTH -1 )); i++ )) ; do
echo ""
echo "INDEX - $i"
echo "VALUE - ${ARRAY_VAR[$i]}"
done
exit 0
[Ref.: https://tecadmin.net/working-with-array-bash-script/ ]
How about something like:
array=(one two three)
array_t=" ${array[#]} "
delete=one
array=(${array_t// $delete / })
unset array_t
#/bin/bash
echo "# define array with six elements"
arr=(zero one two three 'four 4' five)
echo "# unset by index: 0"
unset -v 'arr[0]'
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
arr_delete_by_content() { # value to delete
for i in ${!arr[*]}; do
[ "${arr[$i]}" = "$1" ] && unset -v 'arr[$i]'
done
}
echo "# unset in global variable where value: three"
arr_delete_by_content three
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
echo "# rearrange indices"
arr=( "${arr[#]}" )
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
delete_value() { # value arrayelements..., returns array decl.
local e val=$1; new=(); shift
for e in "${#}"; do [ "$val" != "$e" ] && new+=("$e"); done
declare -p new|sed 's,^[^=]*=,,'
}
echo "# new array without value: two"
declare -a arr="$(delete_value two "${arr[#]}")"
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
delete_values() { # arraydecl values..., returns array decl. (keeps indices)
declare -a arr="$1"; local i v; shift
for v in "${#}"; do
for i in ${!arr[*]}; do
[ "$v" = "${arr[$i]}" ] && unset -v 'arr[$i]'
done
done
declare -p arr|sed 's,^[^=]*=,,'
}
echo "# new array without values: one five (keep indices)"
declare -a arr="$(delete_values "$(declare -p arr|sed 's,^[^=]*=,,')" one five)"
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
# new array without multiple values and rearranged indices is left to the reader
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Output of command in Bash script to Drop-down box?
I have an array in a bash script. I have apache2 configured so I can run cgi/bash scripts in my cgi-bin directory, and they will display like a webpage.
Is there any way to take each element of the array and make it one result in a drop down box on the page?
For example, if my array looked like:
a[0] = "255"
a[1] = "254"
a[2] = "253"
a[3] = "252"
a[4] = "251"
I would want the dropbox to look like (lol, ASCII)
_____
|255 |
|254 |
|253 |
|252 |
|251 |
-----
Any suggestions? Thanks for your help.
you can write a bash for loop to do everything. This just prints out the elements:
for i in `seq 1 "${#x[*]}"`; do
echo "|${x[i]} |"
done
To get the alignment correct, you need to figure out the max length (one loop) and then print out the terms:
# w will be the length
w=0
for i in `seq 1 "${#x[*]}"`; do
if [ $w -lt ${#x[$i]} ]; then w=${#x[$i]}; fi
done
for i in `seq 1 $((w+2))`; do printf "%s" "-"; done
printf "\n"
for i in `seq 1 "${#x[*]}"`; do
printf "|%-$ws |\n" ${#x[$i]}
done
for i in `seq 1 $((w+2))`; do printf "%s" "-"; done
printf "\n"
Slightly simpler (but more verbose) solution:
box()
{
local -a a=(1 20 300 4000 50000)
local -i w=0
for i in "${a[#]}"
do
[ $w -lt $i ] && w="${#i}"
done
printf -- '-%.s' $(seq $w)
printf -- '---\n'
for i in "${a[#]}"
do
printf -- '|%-'$w's |\n' $i
done
printf -- '-%.s' $(seq $w)
printf -- '---\n'
}