I need date part from datetime. in format of "dd-mm-yyyy"
I have tried follwoing
Query:
select Convert(varchar(11), getdate(),101)
Output:
01/11/2011
Query
SELECT cast(floor(cast(GETDATE() as float)) as datetime)
Output
2011-01-11 00:00:00.000
Query:
SELECT
CONVERT(VARCHAR(MAX),DATENAME(DD,GETDATE())) + '-' +
CONVERT(VARCHAR(MAX),DATEPART(MONTH,GETDATE())) + '-' +
CONVERT(VARCHAR(MAX),DATENAME(YYYY,GETDATE())) `
Output:
11-1-2011 i.e. "d-m-yyyy"
I required output in "dd-mm-yyyy" format.
SELECT CONVERT(VARCHAR(10),GETDATE(),105)
Try:
SELECT convert(varchar, getdate(), 105)
More here.
Here you can find some examples how to do this: http://blog.pengoworks.com/index.cfm/2009/1/9/Useful-tips-and-tricks-for-dealing-with-datetime-in-SQL
Using the CONVERT function "works" but only if you're comparing strings with strings. To compare dates effectively, you really need to keep the SMALLDATETIME data type strongly typed on both side of the equation (ie "="). Therefore 'apros' comment above is really the best answer here because the blog mentioned has the right formulas to use to strip off the time component by "flattening" it to midnight (ie 12:00:00) via rounding and any date column in SQL Server 2005 will always default to 12:00:00 if the date is given without a time.
This worked for me ...
select dateadd(day, datediff(day, '20000101', #date), '20000101')
Related
I have a date in table as "26052016" in format DDMMYYYY
I want to convert this date to "YYYYMMDD" format.
Any idea
I have tried this method
select CONVERT(varchar(8),[doc-date],112) FROM C034_PDK_ParallelBillingSourceExtract
But this is gives me the same date as a result.
Please help me
I can find this way, i don't know if any other way exist or not..
declare #date nvarchar(max)='01052016'
select convert(varchar(8),cast(CONCAT(SUBSTRING(#date,3,2),'/',SUBSTRING(#date,1,2),'/',SUBSTRING(#date,5,4)) as date),112)as [YYYYMMDD]
Clear Code:
declare #date nvarchar(max)='01052016'
declare #date1 date
set #date1 =cast(CONCAT(SUBSTRING(#date,3,2),'/',SUBSTRING(#date,1,2),'/',SUBSTRING(#date,5,4)) as date)
select convert(varchar(8),#date1,112)as [YYYYMMDD]
If you are using Sql version< 2012 then you need to skip CONCAT and use + for string concatination.
SELECT CONVERT(VARCHAR(8), doc-date, 112) AS [YYYYMMDD] from
C034_PDK_ParallelBillingSourceExtract
Check ... this should work correctly.
Thanks
SELECT CONVERT(VARCHAR(8), '26052016', 112) AS [YYYYMMDD] from
C034_PDK_ParallelBillingSourceExtract
Try like this,
SELECT substring([doc-date], 5, 4) + substring([doc-date], 3, 2) + substring([doc-date], 1, 2) AS [YYYYMMDD]
FROM C034_PDK_ParallelBillingSourceExtract
There are differet ways to do it.
The best way is to use substring method as you know the character positions are going to remain same.
For Example
Suppose your date is - 31122015
Pick the portions of date using substring method and concatenate them
select SUBSTRING('31122015',5,4) + SUBSTRING('31122015',3,2) + SUBSTRING('31122015',1,2)
The result would be - 20153112
Since SQL Server 2016 we have a couple of handy tools for this:
Use DATEFROMPARTS and SUBSTRING to convert odd date formats from any arrangement within a Varchar to an actual date:
SELECT DATEFROMPARTS(SUBSTRING('31122015',5,4), SUBSTRING('31122015',3,2), SUBSTRING('31122015',1,2))
Use FORMAT to Convert an actual date to YYYYMMDD:
SELECT FORMAT(MyDate, 'yyyyMMdd')
watch out for the yyyyMMdd, that's the only part of MS SQL that is case-sensitive. Lower case mm is "minutes" and upper case MM is "Month", upper case YYYY or DD is nothing, and will just add letters to your output!
I've a SQl Query. I'm using dropdownlist to display the dates. I'd like to display the month in MMMM format.
SELECT DISTINCT[drdates] (CONVERT(CHAR(4), [drdates], 100) + CONVERT(CHAR(4), [drdates], 120)) FROM [DRReceive_20141229]
SELECT DISTINCT UPPER(LEFT(DATENAME(MONTH,MONTH([drdates])),4))
+ CONVERT(CHAR(4), [drdates], 120)
FROM [DRReceive_20141229]
On a side note I have never seen date values being formatted as MMMMyyyy, a rather strange format to show date values.
But if you wanted something rather simple or usual format like MMMyyyy and if you are using sql server 2012 or later version you can do the following ...
SELECT DISTINCT UPPER(FORMAT ( [drdates], 'MMMyyyy' ))
FROM [DRReceive_20141229]
This will help you to retrieve months first four characters :
select CONVERT(CHAR(4),DATENAME(MONTH, [drdates])) + CONVERT(CHAR(4),[drdates], 120)) [DRReceive_20141229];
Does anyone know how can I default the time for the date with SQL Server?
Example:
When I use getdate() and it will return me the current date and time. How can I get the current date but default the time portion to '10:00:00.000' ?
This works for SQL Server (SQLFiddle):
SELECT DATEADD(hour, 10, CAST(CAST(GETDATE() AS DATE) AS DATETIME))
Explanation: GETDATE() gives current date and time. Casting to DATE makes it date only (midnight time). Casting it again to DATETIME makes it compatible with DATEADD, which finally adds 10 hours to it.
Use the below if you are using sql server.
select cast(cast(getdate()AS INT)+0.41667 as datetime)
Note time is scaled on a 0.0 to 0.9999, and the no. of hours are equally distributed. e.g. 0.5 will give 12a.m.
This is from DB2. But same concept should work very DB. Just convert that date in to Timestamp
SELECT TIMESTAMP(CURRENT_DATE, TIME('10:00:00')) AS MY_DATE FROM SYSIBM.SYSDUMMY1
in sql server 2008 and above:
select convert(datetime,convert(varchar(10),convert(date,(GETDATE())))+' 00:00:00')
select convert(datetime,convert(varchar,convert(date,getdate())) + ' 10:00:00.000')
SQL FIDDLE
Again, in Ms SQL Server, You can also use
Select DateAdd(day, datediff(day, getdate()), 0) + 10/24.0
I am facing problem in DateTime converstion.
My input is 09/22/2011, I need to convert into 20110922.
I tried the below one, but failed.
Select CONVERT(VARCHAR(8),'09/22/2011' , 112) as DateConv
Here you go:
SET DATEFORMAT mdy
SELECT CONVERT(VARCHAR(8), CAST('09/22/2011' as DATETIME) , 112) AS DateConv
If your input is actually a dateTime variable like you said (but didn't show in your code example), you can simplify this down to:
SELECT CONVERT(VARCHAR(8), #myDate , 112) AS DateConv
This will do the trick:
select year('09/22/2011') * 10000 + month('09/22/2011') * 100 + day('09/22/2011')
Without any other information, SQL is interpreting the '09/22/2011' as a varchar already, and just passes the data through (ignoring CONVERT's style argument). If you use the following line:
SELECT CONVERT (VARCHAR (8), CAST ('09/22/2011' as DATETIME), 112) as DateConv
it should work as expected since it will then view the '09/22/2011' as a date value. If you were getting the date from a column in a table, it would already know the type and you will not need to worry about the CAST portion of the expression, just use the column name.
I have a variable of DateTime type in SQL.
Just need to have Date part of it.
please Help?
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
The result is: “2009-07-14 00:00:00.000”
Edit: guess the next variant is more common:
SELECT DATEADD(dd, DATEDIFF(dd, 0, GETDATE()), 0)
because of the day pattern can be easily changed to week or month pattern. It is very useful when the GROUP BY clause should group by week of month (reports).
This has been asked and answered before on Stack Overflow. In fact, it's been asked over and over:
Most efficient way in MS SQL to get date from date+time?
Best way to check for current date in where clause of sql query.
SQL Drop Time in DateTime
MS SQL Date Only Without Time
How to return the date part only from a SQL Server datetime datatype
Found this using Google
SELECT CONVERT(DATETIME, FLOOR(CONVERT(FLOAT, GETDATE())))
If you just need a varchar representation of the date, you can use the convert function, e.g.
select convert(varchar, getDate(), 102) /* 2009.07.14 */
If you need a datetime (midnight on the given date), you can just convert it back.
select convert(datetime, convert(varchar, getDate(), 102), 102)
-- Sneaky CAST/DATEDIFF trick strips off the time to get just the day (midnight)!
CAST(DATEDIFF(d,0,DateField) AS DATETIME) AS DayField
SQL Server 2008 has a date datatype that stores just the date, if you are inthis version, perhaps this would be a better datat type for you to use. Be warned though, Date doesn't work exactly like datetime for data manipulation.
SELECT DATEADD(day, DATEDIFF(day, '19900101', CURRENT_TIMESTAMP), '19900101')
A very useful article:
"The purpose of this article is to explain how the datetime types work in SQL Server, including common pitfalls and general recommendations."The ultimate guide to the datetime datatypes
Note that converting to varchar and back (convert(datetime, convert(varchar, getDate(), 102), 102)) is much slower.
If you want the format 'MM/DD/YY', use "CONVERT(varchar, #datetimevalue, 1) to display just the date. If you need it in datetime format, use "CONVERT(datetime, CONVERT(varchar, #datetimevalue, 1))".
I created an entry in my SQL blog about how to retrieve and display all possible formats of the CONVERT(varchar, ..) function:
http://jessesql.blogspot.com/2009/04/converting-datetime-values-to-varchar.html
A tip:
If you find yourself doing this often, you can create a scalar User Defined Function containing the time-stripping logic of your choice.
Be warned: SQL Server 2000 has some painful bugs involving UDF's in ON clauses.
datepart(day, datetimevalue)