I have a date in table as "26052016" in format DDMMYYYY
I want to convert this date to "YYYYMMDD" format.
Any idea
I have tried this method
select CONVERT(varchar(8),[doc-date],112) FROM C034_PDK_ParallelBillingSourceExtract
But this is gives me the same date as a result.
Please help me
I can find this way, i don't know if any other way exist or not..
declare #date nvarchar(max)='01052016'
select convert(varchar(8),cast(CONCAT(SUBSTRING(#date,3,2),'/',SUBSTRING(#date,1,2),'/',SUBSTRING(#date,5,4)) as date),112)as [YYYYMMDD]
Clear Code:
declare #date nvarchar(max)='01052016'
declare #date1 date
set #date1 =cast(CONCAT(SUBSTRING(#date,3,2),'/',SUBSTRING(#date,1,2),'/',SUBSTRING(#date,5,4)) as date)
select convert(varchar(8),#date1,112)as [YYYYMMDD]
If you are using Sql version< 2012 then you need to skip CONCAT and use + for string concatination.
SELECT CONVERT(VARCHAR(8), doc-date, 112) AS [YYYYMMDD] from
C034_PDK_ParallelBillingSourceExtract
Check ... this should work correctly.
Thanks
SELECT CONVERT(VARCHAR(8), '26052016', 112) AS [YYYYMMDD] from
C034_PDK_ParallelBillingSourceExtract
Try like this,
SELECT substring([doc-date], 5, 4) + substring([doc-date], 3, 2) + substring([doc-date], 1, 2) AS [YYYYMMDD]
FROM C034_PDK_ParallelBillingSourceExtract
There are differet ways to do it.
The best way is to use substring method as you know the character positions are going to remain same.
For Example
Suppose your date is - 31122015
Pick the portions of date using substring method and concatenate them
select SUBSTRING('31122015',5,4) + SUBSTRING('31122015',3,2) + SUBSTRING('31122015',1,2)
The result would be - 20153112
Since SQL Server 2016 we have a couple of handy tools for this:
Use DATEFROMPARTS and SUBSTRING to convert odd date formats from any arrangement within a Varchar to an actual date:
SELECT DATEFROMPARTS(SUBSTRING('31122015',5,4), SUBSTRING('31122015',3,2), SUBSTRING('31122015',1,2))
Use FORMAT to Convert an actual date to YYYYMMDD:
SELECT FORMAT(MyDate, 'yyyyMMdd')
watch out for the yyyyMMdd, that's the only part of MS SQL that is case-sensitive. Lower case mm is "minutes" and upper case MM is "Month", upper case YYYY or DD is nothing, and will just add letters to your output!
Related
I have a datetime2 format in my Database 2015-06-22 06:23:42.790. I need to convert this into the following format 22/06/2015 06:23:42.790.
Is it possible?
Here is one way to do this:
DECLARE #date DATETIME2 = '2015-06-22 06:23:42.790';
SELECT cast(convert(VARCHAR(10), cast(LEFT(#date, 10) AS DATE), 3) AS VARCHAR(10))
+ ' ' + substring(cast(#date AS VARCHAR(50)), 12, 12)
Query breakdown:
First part: take first 10 characters from your datefield and then convert it to date style 3 (dd/mm/yyyy).
Second part: Add a space between date and time.
Third part: cast your datefield as varchar and extract the time which should always start in the 12th position of your string.
Join them all together and there you have it! Hope this helps!
Don't try to convert the database layout. Year Month Day is how SQL server shows the date because it ignores any international date formats.
I notice you want it as 22/06/2015 are you in the UK ? In the USA it would be 06/22/2015 Not such a problem because it's obvious that the 22 is the day. But if the date was 05/06/2015 how would sql or anyone know what day or month you're talking about.
So, get in to the habit of working in the ISO format year month day.
You don't mention what programming language. When reading data out of the database youd read it into a datetime variable. That will convert the date correctly into whatever locale your user is using. Different languages have different ways of getting the date into a datettime variable.
If it's only for display-use you can convert to varchar with FORMAT() function:
DECLARE #tab TABLE
(
datevalue DATETIME2
)
INSERT INTO #tab VALUES(GETDATE())
SELECT datevalue,
FORMAT(datevalue,'dd/MM/yyyy hh:mm:ss.fff') as newformat
FROM #tab
I'm surprised not to be able to find this question here already.
I have a date time var and I want to convert it to a string so that I can append it to another string. I want it in a format that can be converted easily back to a date time.
How can I do this?
(I want the date part and the time part.)
The following query will get the current datetime and convert into string. with the following format yyyy-mm-dd hh:mm:ss(24h)
SELECT convert(varchar(25), getdate(), 120)
SQLFiddle Demo
SQL Server Date Formats
There are many different ways to convert a datetime to a string. Here is one way:
SELECT convert(varchar(25), getdate(), 121) – yyyy-mm-dd hh:mm:ss.mmm
See Demo
Here is a website that has a list of all of the conversions:
How to Format datetime & date in SQL Server
In addition to the CAST and CONVERT functions in the previous answers, if you are using SQL Server 2012 and above you use the FORMAT function to convert a DATETIME based type to a string.
To convert back, use the opposite PARSE or TRYPARSE functions.
The formatting styles are based on .NET (similar to the string formatting options of the ToString() method) and has the advantage of being culture aware. eg.
DECLARE #DateTime DATETIME2 = SYSDATETIME();
DECLARE #StringResult1 NVARCHAR(100) = FORMAT(#DateTime, 'g') --without culture
DECLARE #StringResult2 NVARCHAR(100) = FORMAT(#DateTime, 'g', 'en-gb')
SELECT #DateTime
SELECT #StringResult1, #StringResult2
SELECT PARSE(#StringResult1 AS DATETIME2)
SELECT PARSE(#StringResult2 AS DATETIME2 USING 'en-gb')
Results:
2015-06-17 06:20:09.1320951
6/17/2015 6:20 AM
17/06/2015 06:20
2015-06-17 06:20:00.0000000
2015-06-17 06:20:00.0000000
SELECT CONVERT(varchar, #datetime, 103) --for UK Date format 'DD/MM/YYYY'
101 - US - MM/DD/YYYY
108 - Time - HH:MI:SS
112 - Date - YYYYMMDD
121 - ODBC - YYYY-MM-DD HH:MI:SS.FFF
20 - ODBC - YYYY-MM-DD HH:MI:SS
There are 3 different methods depending on what I is my requirement and which version I am using.
Here are the methods..
1) Using Convert
DECLARE #DateTime DATETIME = GETDATE();
--Using Convert
SELECT
CONVERT(NVARCHAR, #DateTime,120) AS 'myDateTime'
,CONVERT(NVARCHAR(10), #DateTime, 120) AS 'myDate'
,RIGHT(CONVERT(NVARCHAR, #DateTime, 120),8) AS 'myTime'
2) Using Cast (SQL Server 2008 and beyond)
SELECT
CAST(#DateTime AS DATETIME2) AS 'myDateTime'
,CAST(#DateTime AS DATETIME2(3)) AS 'myDateTimeWithPrecision'
,CAST(#DateTime AS DATE) AS 'myDate'
,CAST(#DateTime AS TIME) AS 'myTime'
,CAST(#DateTime AS TIME(3)) AS 'myTimeWithPrecision'
3) Using Fixed-length character data type
DECLARE #myDateTime NVARCHAR(20) = CONVERT(NVARCHAR, #DateTime, 120);
DECLARE #myDate NVARCHAR(10) = CONVERT(NVARCHAR, #DateTime, 120);
SELECT
#myDateTime AS 'myDateTime'
,#myDate AS 'myDate'
You can use the convert statement in Microsoft SQL Server to convert a date to a string. An example of the syntax used would be:
SELECT convert(varchar(20), getdate(), 120)
The above would return the current date and time in a string with the format of YYYY-MM-DD HH:MM:SS in 24 hour clock.
You can change the number at the end of the statement to one of many which will change the returned strings format. A list of these codes can be found on the MSDN in the CAST and CONVERT reference section.
Check CAST and CONVERT syntax of t-sql:
http://msdn.microsoft.com/en-us/library/ms187928.aspx
Try below :
DECLARE #myDateTime DATETIME
SET #myDateTime = '2013-02-02'
-- Convert to string now
SELECT LEFT(CONVERT(VARCHAR, #myDateTime, 120), 10)
This has been answered by a lot of people, but I feel like the simplest solution has been left out.
SQL SERVER (I believe its 2012+) has implicit string equivalents for DATETIME2 as shown here
Look at the section on "Supported string literal formats for datetime2"
To answer the OPs question explicitly:
DECLARE #myVar NCHAR(32)
DECLARE #myDt DATETIME2
SELECT #myVar = #GETDATE()
SELECT #myDt = #myVar
PRINT(#myVar)
PRINT(#myDt)
output:
Jan 23 2019 12:24PM
2019-01-23 12:24:00.0000000
Note:
The first variable (myVar) is actually holding the value '2019-01-23 12:24:00.0000000' as well. It just gets formatted to Jan 23 2019 12:24PM due to default formatting set for SQL SERVER that gets called on when you use PRINT. Don't get tripped up here by that, the actual string in (myVer) = '2019-01-23 12:24:00.0000000'
In the stored procedure for me works something like this.
convert(varchar(10), StartingDate) AS 'StartingDate'
I have a datetime column in SQL Server that gives me data like this 10/27/2010 12:57:49 pm and I want to query this column but just have SQL Server return the day month and year - eg. 2010 10 27 or something like that.
What are the functions I should be researching?
Should I be trying to convert to another date data type? Or simply convert it to a string?
Have a look at CONVERT. The 3rd parameter is the date time style you want to convert to.
e.g.
SELECT CONVERT(VARCHAR(10), GETDATE(), 103) -- dd/MM/yyyy format
Try this:
print cast(getdate() as date )
If you need the result in a date format you can use:
Select Convert(DateTime, Convert(VarChar, GetDate(), 101))
In addition to CAST and CONVERT, if you are using Sql Server 2008, you can convert to a date type (or use that type to start with), and then optionally convert again to a varchar:
declare #myDate date
set #myDate = getdate()
print cast(#myDate as varchar(10))
output:
2012-01-17
If you have a datetime field that gives the results like this 2018-03-30 08:43:28.177
Proposed: and you want to change the datetime to date to appear like 2018-03-30
cast(YourDateField as Date)
With SQL Server 2005, I would use this:
select replace(convert(char(10),getdate(),102),'.',' ')
Results: 2015 03 05
The shortest date format of mm/dd/yy can be obtained with:
Select Convert(varchar(8),getdate(),1)
Just add date keyword.
E.g. select date(orderdate),count(1) from orders where orderdate > '2014-10-01' group by date(orderdate);
orderdate is in date time.
This query will show the orders for that date rather than datetime.
Date keyword applied on a datetime column will change it to short date.
For any versions of SQL Server: dateadd(dd, datediff(dd, 0, getdate()), 0)
The original DateTime field : [_Date_Time]
The converted to Shortdate : 'Short_Date'
CONVERT(date, [_Date_Time]) AS 'Short_Date'
I need date part from datetime. in format of "dd-mm-yyyy"
I have tried follwoing
Query:
select Convert(varchar(11), getdate(),101)
Output:
01/11/2011
Query
SELECT cast(floor(cast(GETDATE() as float)) as datetime)
Output
2011-01-11 00:00:00.000
Query:
SELECT
CONVERT(VARCHAR(MAX),DATENAME(DD,GETDATE())) + '-' +
CONVERT(VARCHAR(MAX),DATEPART(MONTH,GETDATE())) + '-' +
CONVERT(VARCHAR(MAX),DATENAME(YYYY,GETDATE())) `
Output:
11-1-2011 i.e. "d-m-yyyy"
I required output in "dd-mm-yyyy" format.
SELECT CONVERT(VARCHAR(10),GETDATE(),105)
Try:
SELECT convert(varchar, getdate(), 105)
More here.
Here you can find some examples how to do this: http://blog.pengoworks.com/index.cfm/2009/1/9/Useful-tips-and-tricks-for-dealing-with-datetime-in-SQL
Using the CONVERT function "works" but only if you're comparing strings with strings. To compare dates effectively, you really need to keep the SMALLDATETIME data type strongly typed on both side of the equation (ie "="). Therefore 'apros' comment above is really the best answer here because the blog mentioned has the right formulas to use to strip off the time component by "flattening" it to midnight (ie 12:00:00) via rounding and any date column in SQL Server 2005 will always default to 12:00:00 if the date is given without a time.
This worked for me ...
select dateadd(day, datediff(day, '20000101', #date), '20000101')
There is a field which is date type in a table. The format of this field is mm/dd/yy. Is there any way to convert it to dd-Month name-yy?
Best Regards,
Without any hassle, you can use CONVERT to get "dd MONTHNAME yyyy" format:
SELECT CONVERT(VARCHAR, GETDATE(), 106)
e.g. "25 Jan 2010"
If you want your exact format, you may need a bit of manual fiddling around like:
SELECT CAST(DAY(GETDATE()) AS VARCHAR) + '-' + LEFT(DATENAME(mm, GETDATE()), 3) + '-' + RIGHT(CAST(YEAR(GETDATE()) AS VARCHAR), 2)
e.g. "25-Jan-10"
Update:
In fact, a shorter way to achieving this is:
SELECT REPLACE(CONVERT(VARCHAR, GETDATE(), 6), ' ', '-')
e.g. "25-Jan-10"
Take a look at the CAST and CONVERT functions:
http://msdn.microsoft.com/en-us/library/ms187928.aspx
example:
select convert( char(8), getdate(), 5 )
output:
dd-mm-yy
Source: compuspec date format conversion
you can try convert() ?
Maybe you need to differentiate between storing datetime values in SQL Server and displaying them. Here is a great article that explains what's going on behind the scenes: The ultimate guide to the datetime datatypes