I have a simple application with just a window and a user control. The user control has a list box. The user control is positioned on the Window and I want to bind the user control's listbox to an element on the window's data context.
The examples I've been able to find have CLR properties on the user control which are accessed in code not via XAML.
<Window x:Class="WpfApplication2b.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:WpfApplication2b="clr-namespace:WpfApplication2b" Title="MainWindow" Height="410" Width="520">
<Grid>
<WpfApplication2b:MyUserControl></WpfApplication2b:MyUserControl>
</Grid>
And here is the user control itself.
<UserControl x:Class="WpfApplication2b.MyUserControl"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300">
<Grid Background="#FFD8AA13">
<ListBox Height="276" HorizontalAlignment="Left" Margin="12,12,0,0" Name="listBox1" VerticalAlignment="Top" Width="276" />
</Grid>
As you can see it's just a listbox on a different coloured background. I have no idea where to go next :)
I'm guessing that I need to add a code behind property for the list box as a dependency property?
Edit: I've added a dependencyProperty, but I don't think I've quite got the point.
public partial class MyUserControl : UserControl
{
public static readonly DependencyProperty ListBoxProperty;
static MyUserControl()
{
FrameworkPropertyMetadata md = new FrameworkPropertyMetadata();
MyUserControl.ListBoxProperty = DependencyProperty.Register("MyListBox", typeof (ListBox),
typeof (MyUserControl), md);
}
public ListBox MyListBox
{
get
{
return (ListBox) GetValue(ListBoxProperty);
}
set
{
SetValue(ListBoxProperty, value);
}
}
public MyUserControl()
{
InitializeComponent();
}
}
Your UserControl will inherit the DataContext from the Window so you can bind properties on the ListBox as though it were declared in the Window. To make the control more flexible you can declare Dependency Properties for the data items from the DataContext that you want to use (i.e. an ItemsSource collection) and pass them into the control, rather than passing the ListBox out.
I think this question/answer is almost what you're looking for. Essentially you're going to need to make a dependency property (using the AddOwner registration method) and set up the DataBinding on the ListBox's ItemsSource to hook to the Dependency Property. The example in the answer does the same thing for a ComboBox, and should be almost the same for a ListBox.
Exposing inner Control properties for binding in WPF
Related
In a mvvm application some areas inside a window (in reality it is a UserControl inside MainWindow) are dynamically displayed according to the user selections.
The changing blocks are inside Stackpanels, I have 4 of them and only one at a time is displayed. This is accomplished binding Visibility to a bool property and using the BooleanToVisibilityConverter.
I put all the alternate StackPanel inside parent control. It works correctly, but during design phase in Visual Studio I see all of them, so I have problems in figuring the final layout.
How can I easily create the layout having more controls which share the same window area and are displayed one at a time ?
Setting A Design Time Only Data Context
Developing XAML in the Studio Designer can be greatly simplified by setting the Design-Time Data Context.
One implementation is based on setting a duplicate DataContext which will be ignored during the final compilation.
To implement the switching, add to the ViewModel, a property that will inform the designer whether it can be used in Development Mode or not.
I use an MVVMLight situation for this example, but for this declared instance property IsInDesignMode and static property ViewModelBase.IsInDesignModeStatic.
Example:
using System.ComponentModel;
namespace DataContextDesignTime.Example
{
public class MyViewModel : INotifyPropertyChanged
{
public event PropertyChangedEventHandler PropertyChanged;
private bool _flag;
public bool Flag
{
get => _flag;
set
{
if (!Equals(_flag, value))
{
_flag = value;
PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(nameof(Flag)));
PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(nameof(NotFlag)));
}
}
}
public bool NotFlag => !Flag;
}
}
<Window x:Class="DataContextDesignTime.Example.ExamleWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:DataContextDesignTime.Example"
mc:Ignorable="d"
Title="ExamleWindow" Height="450" Width="800">
<d:Window.DataContext>
<local:MyViewModel Flag="True" NotFlag="True"/>
</d:Window.DataContext>
<Window.Resources>
<BooleanToVisibilityConverter x:Key="BooleanToVisibilityConverter"/>
</Window.Resources>
<StackPanel>
<Border Background="LightBlue" Height="200"
Visibility="{Binding Flag, Converter={StaticResource BooleanToVisibilityConverter}}"/>
<Border Background="LightGreen" Height="400"
Visibility="{Binding NotFlag, Converter={StaticResource BooleanToVisibilityConverter}}"/>
</StackPanel>
</Window>
In this example, you can change property values in XAML or in the Property Browser.
And you will immediately see the work of your bindings, triggers, how the display for certain data changes.
Note
This may fail on more complex VMs/packages, but in general by setting the DataContext at design time is not difficult.
I need to recompile the project to see the changes in the properties.
The XAML Designer panel has an «Enable/Disable Project Code» button.
, but during design phase in Visual Studio I see all of them, so I have problems in figuring the final layout.
This problem is easily resolved by bringing up the Document Outline tab in visual studio. Once open, navigate to the visible tree and toggle the eyeball to visibly hide/unhide the control[s] one is not interested in; during design time only.
I need to set a TextBox being focused when the dialog box was opened. It was working with Prism 6.x; but is no longer working since 7.x and 8.x. The framework difference is that Prism 6.x uses InteractionRequest for dialog box; while Prism 7/8 uses the dialog service. Does Prism 7 and 8 also introduce some new approaches related to dialog box? Following is the code snippet of XAML setting FocusManager:
<UserControl x:Class="FeatureModule.Views.MyDialogView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:prism="http://prismlibrary.com/"
prism:ViewModelLocator.AutoWireViewModel="True"
FocusManager.FocusedElement="{Binding ElementName=edit}"
mc:Ignorable="d" d:DesignHeight="140" d:DesignWidth="400">
It does not function any more. Does it related to the dialog service?
The dialog service starting from Prism 7.2.x is completely different from the legacy interaction requests in prior versions, so it is hard to tell what exactly was the breaking change. Setting the focus manager property on the root element of the UserControl instead of on the UserControl could solve this the issue, but it might not work under other circumstances, read below why.
<UserControl x:Class="FeatureModule.Views.MyDialogView" ...>
<Grid FocusManager.FocusedElement="{Binding ElementName=edit}">
<!-- ...your markup -->
</Grid>
</UserControl>
I think the issue is more general. WPF has two different focus concepts, logical and keyboard focus. What you want to set on the TextBox is keyboard focus, but the FocusManager only sets logical focus.
Logical focus pertains to the FocusManager.FocusedElement within a specific focus scope.
The important part is the relationship between logical and keyboard focus.
An element with logical focus does not necessarily have keyboard focus, but an element with keyboard focus will have logical focus.
This means, even if you set the logical focus on a different element it might not work.
Keyboard focus pertains to the element that is currently receiving keyboard input. There can be only one element with keyboard focus.
Unfortunately, the Keyboard.FocusedElement property has only a getter and is not a dependency property, so you cannot bind to it, but you can call the Keyboard.Focus method instead. In order to avoid code-behind, you can either create a small behavior or simply an attached property like this:
public static class KeyboardFocus
{
public static readonly DependencyProperty ElementProperty = DependencyProperty.RegisterAttached(
"Element", typeof(FrameworkElement), typeof(KeyboardFocus), new PropertyMetadata(null, OnElementChanged));
public static FrameworkElement GetElement(DependencyObject dependencyObject)
{
return (FrameworkElement)dependencyObject.GetValue(ElementProperty);
}
public static void SetElement(DependencyObject dependencyObject, FrameworkElement value)
{
dependencyObject.SetValue(ElementProperty, value);
}
private static void OnElementChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
{
if (e.NewValue is FrameworkElement frameworkElement)
frameworkElement.Loaded += OnLoaded;
}
private static void OnLoaded(object sender, RoutedEventArgs e)
{
var frameworkElement = (FrameworkElement)sender;
frameworkElement.Loaded -= OnLoaded;
Keyboard.Focus(frameworkElement);
}
}
This attached property can be used on any FrameworkElement, not only TextBox. You can customize it to fit your needs. In XAML apply it to the root element of your UserControl, not the UserControl itself, otherwise the binding element might not be found e.g.:
<UserControl x:Class="FeatureModule.Views.MyDialogView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:prism="http://prismlibrary.com/"
xmlns:local="clr-namespace:FeatureModule.Views"
prism:ViewModelLocator.AutoWireViewModel="True"
FocusManager.FocusedElement="{Binding ElementName=edit}"
mc:Ignorable="d" d:DesignHeight="140" d:DesignWidth="400">
<Grid local:KeyboardFocus.Element="{Binding ElementName=edit}">
<!-- ...your markup. -->
</Grid>
</UserControl>
Alternatively, you can set the property on the TextBox itself.
<TextBox local:KeyboardFocus.Element="{Binding RelativeSource={RelativeSource Self}}"/>
I'm building a custom UserControl in WPF, which has a ViewModel associated. I also want do dynamically make controls in the code behind. But now I'm having problems binding the generated controls with the ViewModel properties. My code is:
<UserControl x:Class="SVT.Teste.UserControl1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300"
DataContext="UserControl1ViewModel">
<Grid Name="GridContainer">
</Grid>
</UserControl>
and code behind:
public UserControl1()
{
InitializeComponent();
System.Windows.Controls.Button newBtn = new Button();
newBtn.SetBinding(Button.ContentProperty, new Binding("Test"));
GridContainer.Children.Add(newBtn);
}
public class UserControl1ViewModel
{
private string test = "ola";
public string Test
{
get { return test; }
}
}
When I run this I get:
"System.Windows.Data Error: 40 : BindingExpression path error: 'Test'
property not found on 'object' ''String' (HashCode=-946585093)'.
BindingExpression:Path=Test; DataItem='String' (HashCode=-946585093);
target element is 'Button' (Name=''); target property is 'Content'
(type 'Object')"
Can you help me?
You are setting DataContext property of UserControl1 to a string instead of your view model instance.
You need to do something like this:
<UserControl xmlns:local="clr-namespace:NAMESPACE_WHERE_VIEWMODEL_IS_DEFINED">
<UserControl.DataContext>
<local:UserControl1ViewModel />
</UserControl.DataContext>
<!-- unrelated code omitted -->
</UserControl>
You are setting you DataContext to the type, not an instance that has the properties.
In your method that creates the user control do :
public UserControl1()
{
InitializeComponent();
System.Windows.Controls.Button newBtn = new Button();
newBtn.SetBinding(Button.ContentProperty, new Binding("Test"));
GridContainer.Children.Add(newBtn);
**DataContext = new UserControl1ViewModel();**
}
You still have more work to do. The way you have it no notifications or update will happen. Implement the INotifyPropertyChanged interface (on UserControlViewModel). And remove setting DataContext in the XAML to the type.
try with this binding
Binding MyBinding = new Binding();
MyBinding.Path = new PropertyPath("Test");
newBtn.DataContext = new UserControl1ViewModel(); //or MyBinding.Source = new //UserControl1ViewModel();
newBtn.SetBinding(Button.ContentProperty, MyBinding);
max is right, but i have another question. why do you want create your usercontrol dynamic when you have a viemwodel you wanna bind to? makes no sense to me. let me explain:
if you have a viewmodel - you know in mind how this viewmodel should be rendered and what the bindings are. so you could create a usercontrol/view for this viewmodel
MyUserControl1View.xaml
<UserControl>
<Grid>
<Button Content="{Binding Test}"/>
<!-- more controls and binding if the viewmodel expose more-->
</Grid>
</UserControl>
so what you have now is a representation of your viewmodel. they are not connnected but your viewmodel should look like this and the binding are set. till now no datacontext is set at all.
all you have to do now is to go the viewmodel first approach and the use of datatemplates.
let us assume the following in your mainwindow
<Window>
<Window.Resources>
<DataTemplate Datatype="{x:Type local:Usercontrol1viewmodel}">
<view:MyUserControl1View/>
</DataTemplate>
</Window.Resources>
now wpf knows how to render Usercontrol1viewmodel.
one step more in your mainwindow viewmodel you handle your Usercontrol1viewmodel.
public Usercontrol1viewmodel MyWhatEver {get;set;}
if you bind this property to a contentpresenter, you will see the wpf magic;)
<ContentPresenter Content="{Binding MyWhatEver}"/>
now you see the MyUserControl1View in the contentpresenter, no dynamic view code needed. just go with your viewmodels.
ps: feel free to edit my bad english.
I have a UserControl (called Invoice) with a textbox (txtReferenceCode) hosted in a TabControl (myTabControl) on MainWindow. From the UserControl I call a window (SearchWindow) which contains a list of stock items. The window needs to return a string value to the textbox contained by the UserControl. I cannot access the textbox on the UserControl from the window and thus cannot pass the string value from the window to the text property.
The UserControl is an instance loaded as a new tabItem (there may be many open as content of tabitems.) I need to only affect the current tabitem instance of the UserControl.
Eg: (Button Click Event in SearchWindow)
Invoice.txtReferenceCode.Text = SearchWindow.txtReferenceCode.Text
I need a simple uncomplicated, solution preferably in VB (but I'll take C# gladly).
I got it! I am posting the solution here for any who struggle with this issue.
XAML
WPF UserControl
<UserControl x:Class="Invoice"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300">
<TextBox x:Name="txtReferenceCode" Width=100 />
</UserControl>
WPF Window
<Window x:Class="SearchWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Height="300" Width="300">
<TextBox X:Name="TextToChangeTextBox" Width=100 />
</Window>
Code Behind
Add a Property to your Window
Class SearchWindow
Public ReadOnly Property TextValue
Get
Return TextToChangeTextBox.Text
End Get
End Property
...
End Class
now you can use the property in your window to pass a string to the TextBox on the UserControl.
Public Class Invoice
Private Sub SetValueToTextBox
Dim win As New SearchWindow
win.ShowDialog()
txtReferenceCode.Text = win.TextValue
End Sub
...
End Class
*
And That's it! EASY!
*
There are much better ways to go about doing this (i.e. share a viewmodel between the two windows and let binding update the textbox as needed).
But if you insist on doing it this way, try adding a public modifier to your textbox, that should let you access it like you want to.
<TextBox Name="txtReferenceCode" x:FieldModifier="public"/>
I have one query related to designing WPF using MVVM
Here is the scenario :
1> I have one WPF screen which contains various user controls which are reusable in some other screens too.
2> Can i have separate ViewModel class for each of those user controls , what could be ideal design in this scenario
3> Should i separate my Viewmodel based on individual screen or on UserControls .
4> If i create separate viewmodels based on UserControls how i should integrate it .
Is there any design guidelines around this !!
Urgent Help appreciated ..
This post describes what I do in certain scenario, I don't know if it is a best practice or not but it works for me.
I create ViewModel for my Window that holds all the user controls, so this called ContainerViewModel and I create an instance of that Viewmodel and put it in the DataContext of the Window. From that moment all the UserControls can access that ViewModel with Binding.
The next thing to do is to create a property on my ContainerViewModel for everty UserControl that holds the ViewModel for each UserControl.
Then use binding to attach the usercontrols ViewModel to the DataContext property of the Usercontrol.
example of the viewmodels and a window with 2 listboxes instead of usercontrols:
Viewmodel classes without any implementation but just empty classes to show the concept:
public class ContainerViewModel
{
public ContainerViewModel()
{
ViewModelForControl1 = new Control1ViewModel();
ViewModelForControl2 = new Control2ViewModel();
}
public Control1ViewModel ViewModelForControl1 { get; set; }
public Control2ViewModel ViewModelForControl2 { get; set; }
}
public class Control1ViewModel { }
public class Control2ViewModel { }
Window xaml:
<Window x:Class="ConfigHellp.UI.Windows.ContainerWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:vm="clr-namespace:ConfigHellp.UI.ViewModel"
mc:Ignorable="d"
DataContext="{DynamicResource ContainerViewModel}" >
<Window.Resources>
<vm:ContainerViewModel x:Key="ContainerViewModel" d:IsDataSource="True" />
</Window.Resources>
<StackPanel>
<ListBox DataContext="{Binding ViewModelForControl1}" />
<ListBox DataContext="{Binding ViewModelForControl2}" />
</StackPanel>
</Window>
this depends on how complex the embedding of the UserControl into the environment is. If you think that its to much effort to build the view model logic for your user control again and again (which is also a very nice source for mistakes), you should infact encapsulate the logic in a single viewmodel for your control. If the user control will be an ListItem for example, i generally suggest you to build an own viewmodel for the control.
The infrastructure will be than:
A general viewmodel for your WPF screen, which holds instances of the viewmodels for your usercontrols. That DataContext of the screen will be the general viewmodel. The users controls's DataContext will be a Binding to the PropertyPath of the user control viewmodel in your general viewmodel. e.g:
In WPF Screen:
<ListBox DataContext="{Binding}" ItemsSource="{Binding Path=ItemList}">
<ListBox.ItemTemplate>
<yourControls:YourUserControl />
</ListBox.ItemTemplate>
</ListBox>
In the general viewmodel:
public class ScreenViewModel : INotifyPropertyChanged
{
private ObservableCollection<YourUserControlViewModel> _itemList =
new ObservableCollection<YourUserControlViewModel>();
public ObservableCollection<YourUserControlViewModel> ItemList
{
get { return _itemList; }
set { _itemList = value; }
}
}
This will automatically generate a your user control for each viewmodel in the ItemList of your general view model.