I am using an afterFind function to modify data from a find function. It works fine. If I move the afterFind function into a behavior (in a plugin) it still works, but only when the model of interest is the primary model, i.e. it isn't called when the model belongsTo another model. Is there any way round this? I'm using cake 1.3.4. This is a simplified version of the behavior:
class ChemicalStructureBehavior extends ModelBehavior {
function afterFind(&$model, $results, $primary) {
foreach ($results as &$unit) {
// format chemical formula (with subscripts)
$unit[$model->alias]['chemical_formula_formatted'] = preg_replace('/([0-9]+)/i', '<sub>$1</sub>', $unit[$model->alias]['chemical_formula']);
}
return $results;
}
}
I guess I'd do one of 2 things depending on how generically the code block applies:
Universal version: not use a behavior, but include your method block in AppModel::afterFind
Surgical version: use a behavior and attach it to each model that needs to share the functionality.
A behavior isn't supposed to work on related models, for example, if you have this two models:
app/models/product.php
<?php
class Product extends AppModel{
var $belongsTo = array('Category');
var $actsAs = array('SomeBehavior');
}
?>
app/models/category.php
<?php
class Category extends AppModel {
var $hasMany = array('Product');
}
?>
SomeBehavior will only be executed when calling methods for Product, because the behavior isn't associated with Category
http://github.com/m3nt0r/eventful-cakephp
Set up an event that does the formatting - trigger that event however you need to. Easy as Cake.
Related
Can I use another Model inside one model?
Eg.
<?php
class Form extends AppModel
{
var $name='Form';
var $helpers=array('Html','Ajax','Javascript','Form');
var $components = array( 'RequestHandler','Email');
function saveFormName($data)
{
$this->data['Form']['formname']=$data['Form']['formname'];
$this->saveField('name',$this->data['Form']['formname']);
}
function saveFieldname($data)
{
$this->data['Attribute']['fieldname']=$data['Attribute']['fieldname'];
}
}
?>
Old thread but I'm going to chime in because I believe the answers to be incomplete and lacking in "why". CakePHP has three ways to load models. Though only two methods work outside of a Controller, I'll mention all three. I'm not sure about version availability but this is core stuff so I believe they'll work.
App::import() only finds and require()s the file and you'll need to instantiate the class to use it. You can tell import() the type of class, the name and file path details.
ClassRegistry::init() loads the file, adds the instance to the object map and returns the instance. This is the better way to load something because it sets up "Cake" things as would happen if you loaded the class through normal means. You can also set an alias for the class name which I've found useful.
Controller::loadModel() uses ClassRegistry::init() as well as adds the Model as a property of the controller. It also allows $persistModel for model caching on future requests. This only works in a Controller and, if that's your situation, I'd use this method before the others.
You can create instances of other models from within any model/controller using one of these two methods.
If you're using Cake 1.2:
App::import('model','Attribute');
$attr = new Attribute();
$attr->save($dataYouWantToSavetoAttribute);
If you're using Cake 1.1:
loadModel('Attribute');
$attr = new Attribute();
$attr->save($dataYouWantToSavetoAttribute);
An obvious solution everyone missed is to create an association between two models, if appropriate. You can use it to be able to reference one model from inside another.
class Creation extends AppModel {
public $belongsTo = array(
'Inventor' => array(
'className' => 'Inventor',
'foreignKey' => 'inventor_id',
)
);
public function whoIsMyMaker() {
$this->Inventor->id = $this->field('inventor_id');
return $this->Inventor->field('name');
}
}
In CakePHP 1.2, it's better to use:
ClassRegistry::init('Attribute')->save($data);
This will do simply
<?php
class Form extends AppModel
{
//...
$another_model = ClassRegistry::init('AnotherModel');
//...
}
?>
In CakePHP 3 we may use TableRegistry::get(modelName)
use Cake\ORM\TableRegistry;
$itemsOb = TableRegistry::get('Items');
$items = $itemsOb->find("all");
debug($items);
If you want to use Model_B inside Model_A, add this line at the beginning of Model_A file:
App::uses('Model_B_ClassName', 'Model');
and then you will be able to use it inside Model_A. For example:
$Model_B = new Model_B_ClassName();
$result = $Model_B->findById($some_id);
var $uses = array('ModeloneName','ModeltwoName');
By using $uses property, you can use multiple models in controller instead of using loadModel('Model Name').
App::import('model','Attribute');
is way to use one model into other model. Best way will be to used association.
The question probably sounds quite odd, and indeed it is. Here's the problem: I have a model, FollowingStationLine, and its corresponding table, following_station_lines. In the model, I am trying to save a record with $this->save(array('field' => 'value));. When I hit the corresponding page, the method seems to be calling in an infinite loop (I've put some debug()s before and after the save statement) and it ends only when the memory limit has been reached. I tried even with 2GB of memory, and still the same issue.
This happens also when calling the method from another controller, other than FollowingStationLinesController. All other models/tables work as expected, beside this one. I really can't imagine what is the problem. Here are the codes for the controller, respectively the model:
Controller:
App::uses('AppController', 'Controller');
class FollowingStationLinesController extends AppController {
public function admin_set() {
$this->FollowingStationLine->set(array(1));
}
}
Model:
App::uses('AppModel', 'Model');
class FollowingStationLine extends AppModel {
public function set($lineIds = array()){
if(!is_array($lineIds)){
return false;
}
$save = array();
$save[] = array('station_id' => 45);
debug($save[0]);
$this->save($save[0]);
}
}
Any help would be highly appreciated!
CakePHP's AppModel class has a function called 'set' that is called by the model's 'save' function. By overrriding 'set', you are causing a loop between the 2 methods.
Rename your function to something else and you should be ok.
You can inspect the AppModel source for more info: https://github.com/cakephp/cakephp/blob/master/lib/Cake/Model/Model.php
UPDATE:
#mark made a very good comment that if your PHP configuration included error reporting mode E_STRICT, you would have received an error for overriding with a mismatched signature.
More info to set your configuration: http://php.net/manual/en/migrating5.errorrep.php
I'm using CakePHP 2.0.5 (but this isn't necessarily a cakephp specific question). I have a Coupon and a User model. Each time a user prints a coupon (proccessed by: Coupon Controller):
class CouponsController extends AppController {
public function printcoupon($id = null) {
// code
}
}
I want to save the information to a "coupons_printed" table (id/coupon_id/user_id/created). Should I create a new model for this, or should I just create a function inside of the Coupon model similar to (and call it in the controller each time that page is viewed)?:
class Coupon extends AppModel {
function insertIntoPrinted($id) {
$this->query("UPDATE coupons_printed SET .....");
}
}
Whatever you do, a raw SQL query is not the best way to go. Always use CakePHP methods if at all possible (and almost always it is possible).
You should put the insertIntoPrinted() function in the CouponsPrinted model (although, as a side note, PrintedCoupon would be a more natural way to name the model...) You can then add a HasMany relationship to the Coupon model ($hasMany = array( 'CouponsPrinted' )) and call the function in the CouponsController:
public function printcoupon($id = null) {
$this->Coupon->CouponsPrinted->insertIntoPrinted( $id );
}
CakePHP's model has a thing call association.
In your case, Coupon has a hasMany association with coupons_printed.
You can create a new model, or query using the association in the Coupon model, the generated queries will be the same, I believe.
Your CouponsController already depend on Coupon Model, so not creating another model is a better solution.
I'm new to cakePhp development. I've stuck on following problem:
I've made few models, controllers and views - it works great. The problem is that after production, I have to made new table(Transactionaltemp table and corresponding model and controller ) in the db that logically is "connected" to other tables, but technically does not needs to - for ex. it holds temporary info on user_id, time, ip and similar. So, other tables doesn't need to be directly connected to that.
The problem is when I try (in some other controller than transactionaltemps_controller):
$this->loadModel('Transactionaltemp');
I get error - the model is not found (it is true because the model is missing in the cache). Interesting enough transactionaltempls_controller is in the cache (in the cake_controllers_list file).
I tried following stuff to resolve the problem:
clear cache
disable cache
tried using uses={..} code in the controller that I would like to use mymodels_controller
tried using init('Transactionaltemp')
with no success. Here is corresponding code:
The model:
<?php
class Transactionaltemp extends AppModel
{
var $name = 'Transactionaltemp';
function beforeSave() {
return true;
}
}
?>
The controller:
<?php
class TransactionaltempsController extends AppController
{
var $name = 'Transactionaltemps';
var $scaffold;
}
?>
I'll very grateful to any help!!!
App:Import('Model','Transactionaltemp');
$this->Transactionaltemp= new Transactionaltemp;
I hope this may work
If you are connecting to a table name with different name than your model, you must specify the table name in it:
<?php
class Transactionaltemp extends AppModel
{
var $uses = 'Transactional';
var $name = 'Transactionaltemp';
function beforeSave() {
return true;
}
}
Try
App::Import('Model', 'YourModelName');
in your controller (or where you want).
Can I use another Model inside one model?
Eg.
<?php
class Form extends AppModel
{
var $name='Form';
var $helpers=array('Html','Ajax','Javascript','Form');
var $components = array( 'RequestHandler','Email');
function saveFormName($data)
{
$this->data['Form']['formname']=$data['Form']['formname'];
$this->saveField('name',$this->data['Form']['formname']);
}
function saveFieldname($data)
{
$this->data['Attribute']['fieldname']=$data['Attribute']['fieldname'];
}
}
?>
Old thread but I'm going to chime in because I believe the answers to be incomplete and lacking in "why". CakePHP has three ways to load models. Though only two methods work outside of a Controller, I'll mention all three. I'm not sure about version availability but this is core stuff so I believe they'll work.
App::import() only finds and require()s the file and you'll need to instantiate the class to use it. You can tell import() the type of class, the name and file path details.
ClassRegistry::init() loads the file, adds the instance to the object map and returns the instance. This is the better way to load something because it sets up "Cake" things as would happen if you loaded the class through normal means. You can also set an alias for the class name which I've found useful.
Controller::loadModel() uses ClassRegistry::init() as well as adds the Model as a property of the controller. It also allows $persistModel for model caching on future requests. This only works in a Controller and, if that's your situation, I'd use this method before the others.
You can create instances of other models from within any model/controller using one of these two methods.
If you're using Cake 1.2:
App::import('model','Attribute');
$attr = new Attribute();
$attr->save($dataYouWantToSavetoAttribute);
If you're using Cake 1.1:
loadModel('Attribute');
$attr = new Attribute();
$attr->save($dataYouWantToSavetoAttribute);
An obvious solution everyone missed is to create an association between two models, if appropriate. You can use it to be able to reference one model from inside another.
class Creation extends AppModel {
public $belongsTo = array(
'Inventor' => array(
'className' => 'Inventor',
'foreignKey' => 'inventor_id',
)
);
public function whoIsMyMaker() {
$this->Inventor->id = $this->field('inventor_id');
return $this->Inventor->field('name');
}
}
In CakePHP 1.2, it's better to use:
ClassRegistry::init('Attribute')->save($data);
This will do simply
<?php
class Form extends AppModel
{
//...
$another_model = ClassRegistry::init('AnotherModel');
//...
}
?>
In CakePHP 3 we may use TableRegistry::get(modelName)
use Cake\ORM\TableRegistry;
$itemsOb = TableRegistry::get('Items');
$items = $itemsOb->find("all");
debug($items);
If you want to use Model_B inside Model_A, add this line at the beginning of Model_A file:
App::uses('Model_B_ClassName', 'Model');
and then you will be able to use it inside Model_A. For example:
$Model_B = new Model_B_ClassName();
$result = $Model_B->findById($some_id);
var $uses = array('ModeloneName','ModeltwoName');
By using $uses property, you can use multiple models in controller instead of using loadModel('Model Name').
App::import('model','Attribute');
is way to use one model into other model. Best way will be to used association.