I'm trying to render a png file in a controller in Rails3. I'm using:
render :file=>'public/images/filename.png'
However, the output seems not to be a PNG file (its contents start with "PNG" -checked it with curl- but it's not a valid file). I cannot find documentation on render :file in Rails3. Has the syntax changed for this? Even if it's a MIME type issue, I think I should be able to obtain the file with curl.
I'm using this technique to show a default image when using Fleximage's images if available. Fleximage's images work correctly, but this simple operation does not.
use:
send_file path_to_file
Related
I'm finishing a script that playblasts several pieces of animation into different movie files. It works fine but I'd like it to NOT open all the video files once it is done playblasting them.
Can't find that option even inside maya playblast options itself... Any light on that?
You need to pass the viewer flag to false, are you doing playblast via code ? if so check this doc
I am not getting any warning or error message while executing the program.
wd.findElement(By.xpath("XPATH")).sendKeys("ABC.jpg","XYZ.jpg");
But no file is uploading.
wd.findElement(By.xpath("XPATH")).sendKeys("can we make CTRL+A operation" );
Thanks in advance.
I think you may be going about this while "file upload in Selenium" thing wrong, so that's what I'm going to address.
This article by SauceLabs covers the basic steps to handle a file upload through Selenium in both Java and Ruby. Assuming you're using Java, there are a few steps you'd need:
Set the FileDetector method for your WebDriver
Get a WebElement pointing to a valid HTML input tag of type file
Have Selenium type in the file's path (Not sure if this requires absolute paths, but it's probably a good idea)
Submit the form
The following code listing demonstrates how to perform each of these steps:
wd.setFileDetector(new LocalFileDetector());
// point your webdriver to the page containing the upload form.
WebElement upload = wd.findElement(By.xpath("XPATH")); // TODO replace xpath!
upload.sendKeys("/path/to/ABC.jpg");
upload.submit(); // NOTE: Submits the form *containing* the upload field!
Because you've set the file detection method to LocalFileDetection, Selenium will be able to find the appropriate file. If this is not set, then Selenium defaults to the UselessFileDetection implementation, which fails every time to avoid accidental file uploads.
Caveat: If you're using a Javascript or Flash-based multiple file upload system, then this probably won't work, since those typically bypass the original input field or handle upload independently from the form's submission.
You are not getting an error because sendKeys() accepts an array of CharSequence objects. and you are conforming to that method contract
But no file is uploading
That is because the way your code is written now, will actually send the text: ABC.jpgXYZ.jpg.
What function in Drupal gets file attachment path?
Edit: the attachments provided by Upload module in system section. But since you mentioned there may be another way around it. Maybe I could achieve may goals using FileField module so if you could tell me how to get a direct link of a file uploaded by FileField module that may also be very helpful.
Edit 2:
Ok I will start from my main and final objective:
It is to get an image linking to a file which visibility I could be managed using CCK module.
I am doing this step by step. So now I have written a code which generates the needed image and I have added that image to one of content types teaser. I found a way to warp my image in a tag and I had dug up simple attachments url. So my next step is to advance from simple upload attachment to the one added by FileFields and from odd looking HTML pace in all PHP document into beautifully managed CCK field.
How to fetch file path of a file uploaded FileFields?
Some plain and at the same time rich tutorials for making custom fields for CCK module.
Assuming you know how to get the $node object for a node containing a file attachment, this is super easy:
Upload (core)
$file = upload_load($node);
echo $file[1]->filepath;
Where 1 is the index of the file. Upload can let you upload more than one file, so file 2 would have an index of 2 and so on. If there's only one file, it'll always be 1.
More info: upload_load() API reference.
FileField
echo $node->field_fieldname[0]['filepath'];
Where field_filename is the short name you've used for the field, and 0 is the index of the field. CCK fields let you have multiple values in one field, so 0 would be the first, 1 would be the second, etc. If you only have one value, it'll always be 0.
Note: if you want to get the rendered output of the FileField using its formatters, you can just use $field_fieldname in your node template, or if you want to store the rendered output, you can use:
echo content_format('field_fieldname', $node->field_fieldname[0]);
More info: content_format() API reference.
Upload is a sad little module, and has been completely replaced with a core implementation of FileField in Drupal 7. If you have the option to use FileField, you should.
Don't direct links of file attachments appear below the uploaded file for the core Upload module?
Since you are trying to use images, you should use http://drupal.org/project/imagefield CCK module in order to add images to specified content type. After that using the Display fields tab in Content type configuration you can specify how image would be presented (as a link, image, image with link to node...) both in teaser and body view.
I want to receive multi file post from image uploader.(i use this)
Most examples show how to receive one image from post.
I tried many ways but never got the results.
For example
self.request.POST['Filename']
gives only first filename.
What to do when there are multiple files/images in post?
The reason for this is to resize before upload images, that are too big for google app engine
to upload.
EDIT:
self.request.POST.multi.__dict__
shows
{'_items':
[('Filename', 'camila1.jpg'),
('Filedata[]', FieldStorage('Filedata[]', 'camila1.jpg')),
('Upload', 'Submit Query\r\n--negpwjpcenudkacqrxpleuuubfqqftwm----negpwjpcenudkacqrxpleuuubfqqftwm\r\nContent-Disposition: form-data; name="Filename"\r\n\r\nbornToBeWild1.jpg'),
('Filedata[]', FieldStorage('Filedata[]', 'bornToBeWild1.jpg')),
('Upload', 'Submit Query')]}
Your flash uploader is designed to work with PHP and sends multiple Filedata[] fields (php interprets this as an array for easy access)
So you need to iterate and get them all:
def post(self):
for file_data in self.request.POST.getall('Filedata[]'):
logging.info(file_data.filename)
data should be file_data.value
Are you using the Django libraries available to you? If so, check this out.
Call self.request.POST.getall('Filename') to get a list of FieldStorage objects; each one contains one file. You can access the file data with .value, the name with .name, and the mimetype with .type.
I have no idea how that multi uploader works, I have made one in the past however and I just added a number on the end of input field name, then hide it. Then add a new file input field to add another file. The reason for this is that they don't let you play around with input file fields to much because you could make it upload files they didn't want you uploading.
Using my conventions, in your example the 2 files in your example would be "Filename0" and "Filename1". You could also use firebug to see what it renaming the input file fields to.
Edit: I had a look, and it's using flash. So i have no idea how it works.
I have a PDF file where every page is a (LZW) TIFF file. I know this because I created it. I want to be able to load it and save it as a bunch of TIFF files.
I can open the PDF file with CGPDFDocumentCreateWithURL, and get a page. I can even draw the page onto the screen.
What I WANT to do is draw the page into a bitmapContext, so that I can use CGBitmapContextCreateImage to get the image into a CGImageRef. However, in order to create a bitmap context, I need to know the size and resolution of the image. I can't seem to find out how to get either a CGPDFDocument or a CGPDFPage to tell me the resolution of the image object on that page.
Is there an easier way to do this that I'm not realizing?
thanks.
Ghostscript will work for you here :
gs -sDEVICE=tiff32nc -sOutputFile=foo-Page%d.tif foo.pdf
For 2 page document foo.pdf you should get :
foo-Page1.tif
foo-Page2.tif
From memory I think the output resolution from GS is that of the containing Page, not necessarily the resolution of the embedded file (unless these are the same to begin with).
If this is the case and you want to recover the image as it was originally res-wise, you can use iText (java) or iTextSharp(.net) to get to the image content stream (ie. Bytes) and write them out to disk in the format of your choice, after converting the content stream into a PdfImage iirc.
Hope the ghostscript option is applicable to save writing yet another utility...