What function in Drupal gets file attachment path?
Edit: the attachments provided by Upload module in system section. But since you mentioned there may be another way around it. Maybe I could achieve may goals using FileField module so if you could tell me how to get a direct link of a file uploaded by FileField module that may also be very helpful.
Edit 2:
Ok I will start from my main and final objective:
It is to get an image linking to a file which visibility I could be managed using CCK module.
I am doing this step by step. So now I have written a code which generates the needed image and I have added that image to one of content types teaser. I found a way to warp my image in a tag and I had dug up simple attachments url. So my next step is to advance from simple upload attachment to the one added by FileFields and from odd looking HTML pace in all PHP document into beautifully managed CCK field.
How to fetch file path of a file uploaded FileFields?
Some plain and at the same time rich tutorials for making custom fields for CCK module.
Assuming you know how to get the $node object for a node containing a file attachment, this is super easy:
Upload (core)
$file = upload_load($node);
echo $file[1]->filepath;
Where 1 is the index of the file. Upload can let you upload more than one file, so file 2 would have an index of 2 and so on. If there's only one file, it'll always be 1.
More info: upload_load() API reference.
FileField
echo $node->field_fieldname[0]['filepath'];
Where field_filename is the short name you've used for the field, and 0 is the index of the field. CCK fields let you have multiple values in one field, so 0 would be the first, 1 would be the second, etc. If you only have one value, it'll always be 0.
Note: if you want to get the rendered output of the FileField using its formatters, you can just use $field_fieldname in your node template, or if you want to store the rendered output, you can use:
echo content_format('field_fieldname', $node->field_fieldname[0]);
More info: content_format() API reference.
Upload is a sad little module, and has been completely replaced with a core implementation of FileField in Drupal 7. If you have the option to use FileField, you should.
Don't direct links of file attachments appear below the uploaded file for the core Upload module?
Since you are trying to use images, you should use http://drupal.org/project/imagefield CCK module in order to add images to specified content type. After that using the Display fields tab in Content type configuration you can specify how image would be presented (as a link, image, image with link to node...) both in teaser and body view.
Related
I am doing object detection for a specific class, say, chairs .
I want to download images of chairs from imageNet. I also want to download the annotation xml files (bounding boxes) from imageNet.
Both these things are provided on imageNet and I have successfully been able to download them using a tool called ImageNet_Utils
https://github.com/tzutalin/ImageNet_Utils
But the downloaded images and bounding boxes don't have matching names. So it is impossible to tell which xml file is for which image.
How do I download images and bounding boxes from imageNet such that corresponding image and annotation xml files have matching names?
The download image URLs page says
The URLs are listed in a single txt file, where each line contains an
image ID and the original URL
Unfortunately, as of 2020-03-06, all the URL mapping files link to a Oops! The URL is not valid page. However, can however get mappings for each node individually. They are available by wnid: http://www.image-net.org/api/text/imagenet.synset.geturls.getmapping?wnid=n03273913
A bounding box annotation file will contain this element.
<filename>n03273913_16800</filename>
The n03273913 is the synset id and the 16800 is the image id. In the synset mapping file you'll find the line
n03273913_16800 http://farm1.static.flickr.com/186/425238103_8fe80b37de.jpg
You can download the image from that location.
There's a c++ library known as dlib. You can pass your downloaded images from dlib, it has GUI support for drawing blocks in images and save them in vector formats in an XML file. You can refer here for the documentation
Lets say I have Project A with an attached imageFile.
Then I created 10 different Projects which are underprojects of Project A.
I want to link the ImageFile of Project A to the Wiki of every underproject , so that I can see the ImageFile in the Wiki-Area of each underproject.
What im doing so far is to copy full path of the attached file of Project A in the Wiki of every underproject, like for example:
!>/attachments/download/157/schnittprofil.png!
Is there a better way to achieve that, because every time I update the imagefile, I have to renew the id-numbers of all imagefile-links in the underprojects.
Since an attachment is only actually identified by its ID and all attachments are immutable (i.e. can be changed after upload), new uploads will result in a new ID. Since multiple attachments with different IDs can have the same name, you can also not reliably find an attachment just by using its name in broad contexts.
That said, to solve your issue, you could use the include macro to include a common Wiki page in your sub-project's wiki pages which then displays the image attachment.
For that, you can create a Wiki page named e.g. Schnittprofil in your parent project where you directly upload your file. In the wiki page, just reference the image with
!schnittprofil.png!
Assuming the parent project has an identifier of project-a, you can then include the page in other wiki pages with
{{include(project-a:Schnittprofil)}}
Each time you change the page on the parent project, it will automatically also show the updated content on the child wikis. The only requirement is that the users need to be able to read the wiki of your parent project (e.g. are members of the project with the "Read wiki" permission).
I have one drupal content type. there is one image field, the configuration is:
content type field setting
It works fine. I can upload multi image to that content type. The only problem is that, the uploaded image is themed in table format.
uploaded results
How can i change the output format other than table? I have searched for the whole day, still can not find the answer :(
What I have seen from your given images, you have an image field in your content type. Also I am not sure that in which way you are showing all the images on the front end. This could be done in several ways. One of them is using 'Views'.
Views
So if you are collecting all the images into a view creating a page or block, then you can easily change the showing format. Like you can use the table format and also list format. And on the front end you could be able have a non-tabular format.
Tpl files
On the other hand, if you are using special node tpl then you have to format the html properly so that they won't come in a tabular format.
I will personally suggest you to use the views to avoid unnecessary problems and also you can also specify the view specific tpl file.
Cheers :) keep Drupalizing :)
I'm making a website in drupal 7 and need some help.
I created a content type called Itenary where user will upload information and five images.
The images I have taken as Image1, Image2.... Image5 as fields of type image pf the itenary content type.
Now I wish to show these images as something like this
So I go to the views module -> add new view
Now when I had tried this before, I had selected
Show content of type itenary
And it didn't work as I hoped.
So this time, I chose
Show File of type Image
I hope this is the right option for my need.
Then I went to create a block, gave it a name.
Now my dilema is how do I bring those fields of Image1 Image2 .. Image5 into this block ?
The fields it shows by default are related to files and not the field of my content type.
Make sure you have the following steps checked.
1- Try to download jQuery cycle plugin.
2- Create a folder a new folder sites/all/libraries/jquery.cycle and place jquery.cycle.all.js file inside it.
3- Go and test the results :).
Hope this works... Muhammad.
I want to receive multi file post from image uploader.(i use this)
Most examples show how to receive one image from post.
I tried many ways but never got the results.
For example
self.request.POST['Filename']
gives only first filename.
What to do when there are multiple files/images in post?
The reason for this is to resize before upload images, that are too big for google app engine
to upload.
EDIT:
self.request.POST.multi.__dict__
shows
{'_items':
[('Filename', 'camila1.jpg'),
('Filedata[]', FieldStorage('Filedata[]', 'camila1.jpg')),
('Upload', 'Submit Query\r\n--negpwjpcenudkacqrxpleuuubfqqftwm----negpwjpcenudkacqrxpleuuubfqqftwm\r\nContent-Disposition: form-data; name="Filename"\r\n\r\nbornToBeWild1.jpg'),
('Filedata[]', FieldStorage('Filedata[]', 'bornToBeWild1.jpg')),
('Upload', 'Submit Query')]}
Your flash uploader is designed to work with PHP and sends multiple Filedata[] fields (php interprets this as an array for easy access)
So you need to iterate and get them all:
def post(self):
for file_data in self.request.POST.getall('Filedata[]'):
logging.info(file_data.filename)
data should be file_data.value
Are you using the Django libraries available to you? If so, check this out.
Call self.request.POST.getall('Filename') to get a list of FieldStorage objects; each one contains one file. You can access the file data with .value, the name with .name, and the mimetype with .type.
I have no idea how that multi uploader works, I have made one in the past however and I just added a number on the end of input field name, then hide it. Then add a new file input field to add another file. The reason for this is that they don't let you play around with input file fields to much because you could make it upload files they didn't want you uploading.
Using my conventions, in your example the 2 files in your example would be "Filename0" and "Filename1". You could also use firebug to see what it renaming the input file fields to.
Edit: I had a look, and it's using flash. So i have no idea how it works.