How to send a simple string between two programs using pipes? - c

I tried searching on the net, but there are hardly any resources. A small example would suffice.
EDIT
I mean, two different C programs communicating with each other. One program should send "Hi" and the other should receive it. Something like that.

A regular pipe can only connect two related processes. It is created by a process and will vanish when the last process closes it.
A named pipe, also called a FIFO for its behavior, can be used to connect two unrelated processes and exists independently of the processes; meaning it can exist even if no one is using it. A FIFO is created using the mkfifo() library function.
Example
writer.c
#include <fcntl.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <unistd.h>
int main()
{
int fd;
char * myfifo = "/tmp/myfifo";
/* create the FIFO (named pipe) */
mkfifo(myfifo, 0666);
/* write "Hi" to the FIFO */
fd = open(myfifo, O_WRONLY);
write(fd, "Hi", sizeof("Hi"));
close(fd);
/* remove the FIFO */
unlink(myfifo);
return 0;
}
reader.c
#include <fcntl.h>
#include <stdio.h>
#include <sys/stat.h>
#include <unistd.h>
#define MAX_BUF 1024
int main()
{
int fd;
char * myfifo = "/tmp/myfifo";
char buf[MAX_BUF];
/* open, read, and display the message from the FIFO */
fd = open(myfifo, O_RDONLY);
read(fd, buf, MAX_BUF);
printf("Received: %s\n", buf);
close(fd);
return 0;
}
Note: Error checking was omitted from the above code for simplicity.

From Creating Pipes in C, this shows you how to fork a program to use a pipe. If you don't want to fork(), you can use named pipes.
In addition, you can get the effect of prog1 | prog2 by sending output of prog1 to stdout and reading from stdin in prog2. You can also read stdin by opening a file named /dev/stdin (but not sure of the portability of that).
/*****************************************************************************
Excerpt from "Linux Programmer's Guide - Chapter 6"
(C)opyright 1994-1995, Scott Burkett
*****************************************************************************
MODULE: pipe.c
*****************************************************************************/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <sys/types.h>
int main(void)
{
int fd[2], nbytes;
pid_t childpid;
char string[] = "Hello, world!\n";
char readbuffer[80];
pipe(fd);
if((childpid = fork()) == -1)
{
perror("fork");
exit(1);
}
if(childpid == 0)
{
/* Child process closes up input side of pipe */
close(fd[0]);
/* Send "string" through the output side of pipe */
write(fd[1], string, (strlen(string)+1));
exit(0);
}
else
{
/* Parent process closes up output side of pipe */
close(fd[1]);
/* Read in a string from the pipe */
nbytes = read(fd[0], readbuffer, sizeof(readbuffer));
printf("Received string: %s", readbuffer);
}
return(0);
}

dup2( STDIN_FILENO, newfd )
And read:
char reading[ 1025 ];
int fdin = 0, r_control;
if( dup2( STDIN_FILENO, fdin ) < 0 ){
perror( "dup2( )" );
exit( errno );
}
memset( reading, '\0', 1025 );
while( ( r_control = read( fdin, reading, 1024 ) ) > 0 ){
printf( "<%s>", reading );
memset( reading, '\0', 1025 );
}
if( r_control < 0 )
perror( "read( )" );
close( fdin );
But, I think that fcntl can be a better solution
echo "salut" | code

What one program writes to stdout can be read by another via stdin. So simply, using c, write prog1 to print something using printf() and prog2 to read something using scanf(). Then just run
./prog1 | ./prog2

Here's a sample:
int main()
{
char buff[1024] = {0};
FILE* cvt;
int status;
/* Launch converter and open a pipe through which the parent will write to it */
cvt = popen("converter", "w");
if (!cvt)
{
printf("couldn't open a pipe; quitting\n");
exit(1)
}
printf("enter Fahrenheit degrees: " );
fgets(buff, sizeof (buff), stdin); /*read user's input */
/* Send expression to converter for evaluation */
fprintf(cvt, "%s\n", buff);
fflush(cvt);
/* Close pipe to converter and wait for it to exit */
status=pclose(cvt);
/* Check the exit status of pclose() */
if (!WIFEXITED(status))
printf("error on closing the pipe\n");
return 0;
}
The important steps in this program are:
The popen() call which establishes the association between a child process and a pipe in the parent.
The fprintf() call that uses the pipe as an ordinary file to write to the child process's stdin or read from its stdout.
The pclose() call that closes the pipe and causes the child process to terminate.

This answer might be helpful for a future Googler.
#include <stdio.h>
#include <unistd.h>
int main(){
int p, f;
int rw_setup[2];
char message[20];
p = pipe(rw_setup);
if(p < 0){
printf("An error occured. Could not create the pipe.");
_exit(1);
}
f = fork();
if(f > 0){
write(rw_setup[1], "Hi from Parent", 15);
}
else if(f == 0){
read(rw_setup[0],message,15);
printf("%s %d\n", message, r_return);
}
else{
printf("Could not create the child process");
}
return 0;
}
You can find an advanced two-way pipe call example here.

First, have program 1 write the string to stdout (as if you'd like it to appear in screen). Then the second program should read a string from stdin, as if a user was typing from a keyboard. then you run:
$ program_1 | program_2

Related

read() System call and Null-terminated string

If I have the following array :
char message_buffer [100] ="Hello World ";
If I then use an ordinary pipe to send this buffer from the parent process to a child and then at the child , I have used the following code :
#include <unistd.h>
#include <stdio.h>
#include <sys/wait.h>
#include <stdlib.h>
int main()
{
char message_buffer[100] = "Hello World ";
char read_buffer[100];
int return_value;
int fd[2];
return_value = pipe(fd);
if (return_value < 0)
{
printf("Error creating the pipe");
exit(1);
}
int rc = fork();
if (rc < 0)
{
printf("Error forking a child");
exit(1);
}
if (rc > 0)
{
printf("I am the parent , I will write the message now into the pipe. \n");
close(fd[0]);
write(fd[1], message_buffer, 100);
close(fd[1]);
wait(NULL);
}
else
{
printf("I am the child , I will read the message from the pipe. \n");
close(fd[1]);
read(fd[0], read_buffer, 100);
close(fd[0]);
printf("Message recieved: %s", read_buffer);
}
In this situation, the print statement will work without printing any garbage value. However, assume we have a file copying program that copies the content of a file to another file, where the source file will have the content "hello world" and then we read this message into a buffer and send it through a pipe to a child:
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#include <unistd.h>
#include <string.h>
void main()
{
char buffer[100];
char childbuff[100];
int fd[2], des, bytes, target;
pipe(fd);
if (fork())
{
/* parent process closes the downstream */
close(fd[0]);
/* reads the file */
des = open("test.txt", O_RDONLY);
bytes = read(des, buffer, sizeof(buffer));
/* puts data in pipe */
write(fd[1], buffer, bytes);
}
else
{
/* Child process closes the upstream */
close(fd[1]);
/* reads from the pipe */
read(fd[0], childbuff, sizeof(childbuff));
close(fd[0]);
/* output the received string */
printf("\nReceived string is -- %s", childbuff);
target = open("copy.txt", O_CREAT, 00777);
write(target, childbuff, (strlen(childbuff) - 1));
}
}
In this case, I get a garbage value along the message received when I run the print statement. I know that the read() doesn't Null terminate the buffer. But my question is why the print statement has worked fine in the first case (in which we have only transferred an array), while it didn't work fine in the second case (in which we have transferred a content of a file)?

New to IPC, can't get my pipe to work

Sorry for the length of this post... I've encountered about a zillion problems in this. Up front I'll say I'm a student and my professor is a worthless resource. So, all I want to to do is have producer fork, then the parent producer will count some stuff in a file and send two ints to consumer, which was launched by the child process. I've tested everything, the fork and the file stuff works and I have printf statements all over the place so I know what is being done and where the code is at.
When I added the
if (pipe(pipefd) == -1) {
perror("pipe");
}
it caused my parent to just terminate. It reaches "parent pipe open" but then it dies. I checked with $ ps to see if it was just hung, but it's not there; it just dies. If I take that snippet out, it runs to the end but I presume if that code isn't there, then it's not actually aware that pipefd is a pipe... right?
I did search on this site and found another example of this and followed what he did as well as the answer and mine just refuses to work. I'm pretty sure it's a trivially easy thing to fix but I've run out of ideas of what to try :(
I don't really want to post all my code because it'll be a huge wall of text but I don't want to accidentally cut something out that turns out to be important either.
producer.c
#include <stdio.h> /* printf, stderr, fprintf */
#include <sys/types.h> /* pid_t */
#include <unistd.h> /* _exit, fork, execl */
#include <stdlib.h> /* exit */
#include <errno.h> /* errno */
#include <string.h> /* strlen */
#include <sys/wait.h> /* wait */
#define SLEEP_TIME 8
int main (int argc, char *argv[]){
//PID
pid_t local_pid;
local_pid = fork();
//Logic to determine if the process running is the parent or the child
if (local_pid == -1) {
/* Error:
* When fork() returns -1, an error happened
* (for example, number of processes reached the limit).
*/
fprintf(stderr, "can't fork, error %d\n", errno);
exit(EXIT_FAILURE);
} else if (local_pid == 0) {
//Child specific code
int child;
char *temp[] = {NULL};
printf("Child PID found\n");
child = execv("./consumer", temp);
_exit(0);
} else {
//Parent specific code
printf("Parent running\n");
//open file
FILE * randStrings;
randStrings = fopen("randStrings.txt", "r");
int file_length;
int num_of_e = 0;
int c; //using this as a char
//until eof
while (feof(randStrings) == 0) {
c = fgetc(randStrings);
//calculate length of file
file_length++;
//count e chars
if (c == 'e') {
num_of_e++;
}
}
//close file
fclose(randStrings);
//send bundle to child
int a[2];
a[0] = num_of_e;
a[1] = file_length;
printf("num of e = %i\n", a[0]);
printf("len = %i\n", a[1]);
//set up parent pipe
int pipefd[2];
if (pipe(pipefd) == -1) {
perror("pipe");
printf("x\n");
}
printf("parent pipe open\n");
close(pipefd[0]); //close the read end
write(pipefd[1], &a[0], sizeof(int));
write(pipefd[1], &a[1], sizeof(int));
close(pipefd[1]);
printf("parent pipe closed\n");
//wait for child to finish running
wait(NULL);
printf("parent out\n");
//terminate
}
}
and consumer.c
#include <stdio.h> /* printf, stderr, fprintf */
#include <sys/types.h> /* pid_t */
#include <unistd.h> /* _exit, fork, execl */
#include <stdlib.h> /* exit */
#include <errno.h> /* errno */
#define SLEEP_TIME 5
int main (int argc, char *argv[]){
sleep(SLEEP_TIME);
printf("Child program launched\n");
//receive bundle
int pipefd[2];
int buf[2];
if (pipe(pipefd) == -1) {
perror("pipe");
printf("child x\n");
}
close(pipefd[1]); //child closes write end
buf[0] = 0;
buf[1] = 0;
/*int i = 0; // i dont like this
while (read(pipefd[0], &buf[i], sizeof(int)) > 0) {
i++;
}*/
printf("child reading pipe\n");
read(pipefd[0], &buf[0], sizeof(int));
read(pipefd[0], &buf[1], sizeof(int));
close(pipefd[0]);
//buf should have the stuff in it
int num_of_e = buf[0];
int file_length = buf[1];
printf("child num of e = %i\n", num_of_e);
printf("child len = %i\n", file_length);
//open file
FILE * resultStrings;
resultStrings = fopen("resultStrings.txt", "w");
for (int i = 0; i < num_of_e; i++) {
//write num_of_e e chars
fputc('e', resultStrings);
}
//or if no e chars, write - chars
if (num_of_e == 0) {
for (int i = 0; i < file_length; i++) {
//write file_length '-' chars
fputc('-', resultStrings);
}
}
//close file
fclose(resultStrings);
printf("child out\n");
}
if you're still here after all that, you deserve a thank you just due to the length of this.
You're doing it wrong. The whole mechanism works because a child process inherits the parent's open file descriptors.
It should go like this:
Open the pipe with pipe(pipefd)
fork()
Parent (producer):
closes the read side (pipefd[0])
writes to the write side (pipefd[1])
Child (consumer):
closes the write side (pipefd[1])
reads from the read side (pipefd[0]) or calls exec
You are opening distinct pipes in both the parent and child process (after you've forked.) It needs to happen before you fork.
Now since you're execing, the new process needs to be aware of read-only pipe. There are a couple ways you could do this:
Pass it the file descriptor number (pipefd[0]) on the command line
dup2(1, fd) it to be the stdin of the newly exec'd process

Fread blocks eternally on redirected stdout with named pipes

We are trying to communicate between two processes via named pipes that are redirected to stdin and stdout in the child process. The parent process opens the named pipe and calls fdopen on them. The problem we see is that fwrite on this works, however even reading one byte from redirected stdout pipe blocks eternally.
The code works when using the file descriptors instead of FILE *. What is wrong? Code is a little long, sorry.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <fcntl.h>
int create_fifo()
{
int file1;
unlink("fifo-0.0");
file1 = mkfifo("fifo-0.0",0666);
if(file1<0) {
printf("Unable to create a fifo");
return 0;
}
unlink("fifo-0.1");
file1 = mkfifo("fifo-0.1",0666);
if(file1<0) {
printf("Unable to create a fifo");
return 0;
}
return 1;
}
int main()
{
int fd, fd0, fd1;
pid_t pid;
char read_buf_p[50],write_buf_p[50];
char * args[3];
FILE *fd_stdin_p, *fd_stdout_p;
create_fifo();
args[0] = "/bin/cat";
args[1] = "-n";
args[2] = NULL;
pid = fork();
if(pid == 0)
{
fd = open("fifo-0.0", O_RDONLY);
dup2(fd, 0);
close(fd);
fd = open("fifo-0.1", O_WRONLY);
dup2(fd, 1);
close(fd);
execv(args[0],args);
}
else
{
fd0 = open("fifo-0.0", O_WRONLY);
fd_stdin_p = fdopen(fd0,"w");
fd1 = open("fifo-0.1", O_RDONLY);
fd_stdout_p = fdopen(fd1,"r");
int sz = fwrite("Hello World", sizeof(char), strlen("Hello World"), fd_stdin_p);
fread(read_buf_p,1,1,fd_stdout_p);
printf("%s\n", read_buf_p);
}
return 0;
}
I think its because of buffering of Standard output.
Just use '\n' at the end of fflush()
This is the result of FILE-based I/O being "line-buffered", by default. This means that it reads and writes whole lines, and since your data isn't a whole line, it's stuck in the buffer and not passed through to the underlying file descriptor.
Try adding \n at the end of the output data, or call fflush().

How to pipe stdin to a child and execl cat in C

In the code below, I am simply trying to send a file via stdin to a child process which will exec the cat OS command. The code compiles fine. Here is how I call it from the command line:
$ ./uniquify < words.txt
However, when I run it I get a seg fault error. I am really having a hard time understanding how the flow if information is supposed to work through pipes to children. I am trying to make the code as simple as possible, so I can understand it, but it is not yet making sense. Any help would be appreciated.
#include <unistd.h>
#include <errno.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>
#define NUM_CHILDREN 2
int main(int argc, char *argv[])
{
pid_t catPid;
int writeFds[NUM_CHILDREN];
int catFds[2];
int c = 0;
FILE *writeToChildren[NUM_CHILDREN];
//create a pipe
(void) pipe(catFds);
if ((catPid = fork()) < 0) {
perror("cat fork failed");
exit(1);
}
//this is the child case
if (catPid == 0) {
//close the write end of the pipe
close(catFds[1]);
//close stdin?
close(0);
//duplicate the read side of the pipe
dup(catFds[0]);
//exec cat
execl("/bin/cat", "cat", (char *) 0);
perror("***** exec of cat failed");
exit(20);
}
else { //this is the parent case
//close the read end of the pipe
close(catFds[0]);
int p[2];
//create a pipe
pipe(p);
writeToChildren[c] = fdopen(p[1], "w");
} //only the the parent continues from here
//close file descriptor so the cat child can exit
close(catFds[1]);
char words[NUM_CHILDREN][50];
//read through the input file two words at a time
while (fscanf(stdin, "%s %s", words[0], words[1]) != EOF) {
//loop twice passing one of the words to each rev child
for (c = 0; c < NUM_CHILDREN; c++) {
fprintf(writeToChildren[c], "%s\n", words[c]);
}
}
//close all FILEs and fds by sending and EOF
for (c = 0; c < NUM_CHILDREN; c++) {
fclose(writeToChildren[c]);
close(writeFds[c]);
}
int status = 0;
//wait on all children
for (c = 0; c < (NUM_CHILDREN + 1); c++) {
wait(&status);
}
return 0;
}
Since your question seems to be about understanding how pipes and forks work, I hope below programs can help you. Please notice that this is for illustration only. It wouldn't qualify for commercial implementation, but I wanted to keep it short!
You can compile the two programs as follows:
cc pipechild.c -o pipechild
cc pipeparent.c -o pipeparent
Then execute with ./pipeparent
pipeparent.c source
/* pipeparent.c */
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#define MESSAGE "HELLO!\n"
#define INBUFSIZE 80
#define RD 0 // Read end of pipe
#define WR 1 // Write end of pipe
int main(void)
{
int ptocpipe[2]; // Parent-to-child pipe
int ctoppipe[2]; // Chile-to-parent pipe
pid_t childpid; // Process ID of child
char inbuf[80]; // Input from child
int rd; // read() return
int rdup; // dup():ed stdin for child
int wdup; // dup():ed stdout for child
char *eol; // End of line
// Create pipe for writing to child
if (pipe(ptocpipe) < 0) {
fprintf(stderr, "pipe(ptocpipe) failed!\n");
return 2;
}
// Create pipe for writing back to parent
if (pipe(ctoppipe) < 0) {
fprintf(stderr, "pipe(ctoppipe) failed!\n");
return 2;
}
// Verify that one of the pipes are working by filling it first
// in one end and then reading it from the other. The OS will
// buffer the contents for us. Note, this is not at all necessary,
// it's just to illustrate how it works!
write(ptocpipe[WR], MESSAGE, strlen(MESSAGE));
read(ptocpipe[RD], inbuf, INBUFSIZE);
if (strlen(inbuf) != strlen(MESSAGE)) {
fprintf(stderr, "Failed to flush the toilet!\n");
return 6;
} else {
printf("Wrote to myself: %s", inbuf);
}
// Next, we want to launch some interactive program which
// replies with exactly one line to each line we send to it,
// until it gets tired and returns EOF to us.
// First, we must clone ourselves by using fork(). Then the
// child process must be replaced by the interactive program.
// Problem is: How do we cheat the program to read its stdin
// from us, and send its stdout back to us?
switch (childpid = fork()) {
case -1: // Error
fprintf(stderr, "Parent: fork() failed!\n");
return 3;
case 0: // Child process
// Close the ends we don't need. If not, we might
// write back to ourselves!
close(ptocpipe[WR]);
close(ctoppipe[RD]);
// Close stdin
close(0);
// Create a "new stdin", which WILL be 0 (zero)
if ((rdup = dup(ptocpipe[RD])) < 0) {
fprintf(stderr, "Failed dup(stdin)\n");
return 4;
}
// Close stdout
close(1);
// Create a "new stdout", which WILL be 1 (one)
if ((wdup = dup(ctoppipe[WR])) < 0) {
fprintf(stderr, "Failed dup(stdout)\n");
return 5;
}
// For debugging, verify stdin and stdout
fprintf(stderr, "rdup: %d, wdup %d\n", rdup, wdup);
// Overload current process by the interactive
// child process which we want to execute.
execlp("./pipechild", "pipechild", (char *) NULL);
// Getting here means we failed to launch the child
fprintf(stderr, "Parent: execl() failed!\n");
return 4;
}
// This code is executed by the parent only!
// Close the ends we don't need, to avoid writing back to ourself
close(ptocpipe[RD]);
close(ctoppipe[WR]);
// Write one line to the child and expect a reply, or EOF.
do {
write(ptocpipe[WR], MESSAGE, strlen(MESSAGE));
if ((rd = read(ctoppipe[RD], inbuf, INBUFSIZE)) > 0) {
// Chop off ending EOL
if ((eol = rindex(inbuf, '\n')) != NULL)
*eol = '\0';
printf("Parent: Read \"%s\" from child.\n", inbuf);
}
} while (rd > 0);
fprintf(stderr, "Parent: Child done!\n");
return 0;
}
pipechild.c source
/* pipechild.c
* Note - This is only for illustration purpose!
* To be stable, we should catch/ignore signals,
* and use select() to read.
*/
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
#include <strings.h>
#include <string.h>
#define MAXCOUNT 5 // Maximum input lines toread
#define INBUFSIZE 80 // Buffer size
int main(void)
{
char buff[INBUFSIZE];
int remains = MAXCOUNT;
pid_t mypid;
char *eol;
mypid = getpid(); // Process-ID
fprintf(stderr, "Child %d: Started!\n", mypid);
// For each line read, write one tostdout.
while (fgets(buff, INBUFSIZE, stdin) && remains--) {
// Chop off ending EOL
if ((eol = rindex(buff, '\n')) != NULL)
*eol = '\0';
// Debug to console
fprintf(stderr, "Child %d: I got %s. %d remains.\n",
mypid, buff, 1 + remains);
// Reply to parent
sprintf(buff, "Child %d: %d remains\n", mypid, 1 + remains);
write(1, buff, strlen(buff));
}
fprintf(stderr, "Child %d: I'm done!\n", mypid);
return 0;
}

C Named pipe (fifo). Parent process gets stuck

I want to make a simple program, that fork, and the child writes into the named pipe and the parent reads and displays from the named pipe.
The problem is that it enters the parent, does the first printf and then it gets weird, it doesn't do anything else, does not get to the second printf, it just ways for input in the console.
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
void main()
{
char t[100];
mkfifo("myfifo",777);
pid_t pid;
pid = fork();
if (pid==0)
{
//execl("fifo2","fifo2",(char*)0);
char r[100];
printf("scrie2->");
scanf("%s",r);
int fp;
fp = open("myfifo",O_WRONLY);
write(fp,r,99);
close(fp);
printf("exit kid \n");
exit(0);
} else
{
wait(0);
printf("entered parent \n"); // <- this it prints
// whats below this line apparently its not being executed
int fz; printf("1");
fz = open("myfifo",O_RDONLY); printf("2");
printf("fd: %d",fz);
char p[100];
int size;
printf("------");
//struct stat *info;
//stat("myfifo",info); printf("%d",(*info).st_size);
read(fz,p,99);
close(fz);
printf("%s",p);
printf("exit"); exit(0);
}
}
You really should be checking the return value on function calls for errors, especially mkfifo() and open().
Your call to wait() is going to cause problems in its current location. Opening a FIFO for reading normally blocks until some other process opens the same FIFO for writing, and vice versa1. The parent is waiting for the child to terminate and the child is waiting for a reader process, i.e., the parent, to connect to the FIFO.
1 - see note on open() below for using O_NONBLOCK with a FIFO
Moving the wait() call to just before the parent process exits along with changing the mode in the call to mkfifo() to 0666 seems to resolve some of your immediate problems.
It is also good practice to remove the FIFO when you are finished with it.
unlink("myfifo");
From the open() function documentation in IEEE Std 1003.1-2004:
When opening a FIFO with O_RDONLY or O_WRONLY set:
If O_NONBLOCK is set, an open() for reading-only shall return without delay. An open() for writing-only shall return an error if no process currently has the file open for reading.
If O_NONBLOCK is clear, an open() for reading-only shall block the calling thread until a thread opens the file for writing. An open() for writing-only shall block the calling thread until a thread opens the file for reading.
The following example is a combination of the code in your original question and the FIFO page of Beej's Guide to Unix IPC:
#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
#include <string.h>
#include <fcntl.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <sys/wait.h>
#include <unistd.h>
#define FIFO_NAME "myfifo"
int main(void)
{
char buf[256];
int num, fd;
pid_t pid;
if (mkfifo(FIFO_NAME, 0666) < 0)
perror("mkfifo");
pid = fork();
if (pid == 0)
{
printf("child - waiting for readers...\n");
if ((fd = open(FIFO_NAME, O_WRONLY)) < 0)
perror("child - open");
printf("child - got a reader -- type some stuff\n");
while (fgets(buf, sizeof(buf), stdin), !feof(stdin))
{
if ((num = write(fd, buf, strlen(buf))) < 0)
perror("child - write");
else
printf("child - wrote %d bytes\n", num);
}
close(fd);
exit(0);
}
else
{
printf("parent - waiting for writers...\n");
if ((fd = open(FIFO_NAME, O_RDONLY)) < 0)
perror("parent - open");
printf("parent - got a writer\n");
do
{
if ((num = read(fd, buf, sizeof(buf))) < 0)
perror("parent - read");
else
{
buf[num] = '\0';
printf("parent - read %d bytes: \"%s\"\n", num, buf);
}
} while (num > 0);
close(fd);
wait(0);
}
unlink(FIFO_NAME);
return 0;
}
This example was tested in Linux. Press Ctrl-D to terminate the program.
First of all, try fprintf to stderr instead of printf (to stdout)
The stderr is unbuffered.
Then you can tell what actually gets printed and what does not.
or at least add fflush before waiting for anything.

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