Please suggest me a query, which retrieves only those record which has the single row in table. For example:
**table1.**
name age
aaa 20
bbb 10
ccc 20
ddd 30
If I run "select distinct age from table1. result will be:
age
20
10
30
But I need a query, which give the result like
name age
bbb 10
ddd 30
I am using DB2 as database.
Thanks....
To get just the unique ages:
SELECT age
FROM table1
GROUP BY age
HAVING COUNT(*) = 1
To also get the name column, in MySQL you would just add the column:
SELECT name, age
FROM table1
GROUP BY age
HAVING COUNT(*) = 1
This trick won't work in most other databases though, and I'm guessing that it won't work in DB2. Instead you can use an aggregate function like MIN or an inner select with an EXISTS, IN or JOIN:
SELECT MIN(name), age
FROM table1
GROUP BY age
HAVING COUNT(age) = 1
or:
SELECT name, age
FROM table1
WHERE age IN (
SELECT age
FROM table1
GROUP BY age
HAVING COUNT(age) = 1
)
SELECT name, age
FROM table1
GROUP BY age
HAVING COUNT(age)=1
Related
Problem
Using SQL Server, I'm trying to pivot data based on values in a column. I want to move Bob and John's value column over if Salary is in the metric column.
Sample data:
Person table
Person ID
-------------
Bob 1
Bob 1
John 2
John 2
Value table
Metric Value ID
---------------------
Age 52 1
Salary 60000 1
Age 45 2
Salary 55000 2
Expected output
My goal is to pivot the table if salary is present in the Metric column.
Person Metric Value Salary ID
---------------------------------------
Bob Age 52 60000 1
John Age 45 55000 2
Current code:
SELECT *
FROM person_table pt, value_table vb
WHERE pt.id = vb.id
AND vb.metric IN ('Age', 'Salary')
Use the following pivot query:
SELECT
pt.Person,
'Age' AS Metric,
MAX(CASE WHEN vb.Metric = 'Age' THEN vb.Value END) AS Value,
MAX(CASE WHEN vb.Metric = 'Salary' THEN vb.Value END) AS Salary,
pt.ID
FROM person_table pt
INNER JOIN value_table vb
ON pt.id = vb.id
GROUP BY
pt.Person,
pt.ID
ORDER BY
pt.ID;
I have 2 tables
OrderDetails:
Id Name type Quantity
------------------------------------------
2009 john a 10
2009 john a 20
2010 sam b 25
2011 sam c 50
2012 sam d 30
ValueDetails:
Id Value
-------------------
2009 300
2010 500
2011 200
2012 100
I need to get an output which displays the data as such :
Id Name type Quantity Price
-------------------------------------------------
2009 john a 10
2009 john a 20 9000
2010 sam b 25
2011 sam c 50
2012 sam d 30 25500
The price is calculated by Value x Quantity and the sum of the values is displayed in the last repeating row of the given Name.
I tired to use sum and group by but I get only two rows. I need to display all 5 rows. How can I write this query?
You can use Row_Number with max of Row_Number to get this formatted sum
;with cte as (
select od.*, sm= sum( od.Quantity*vd.value ) over (partition by Name),
RowN = row_number() over(partition by Name order by od.id)
from #yourOrderDetails od
inner join #yourValueDetails vd
on od.Id = vd.Id
)
select Id, Name, Type, Quantity,
case when max(RowN) over(partition by Name) = row_number() over(partition by Name order by Id)
then sm else null end as ActualSum
from cte
Your input tables:
create table #yourOrderDetails (Id int, Name varchar(20), type varchar(2), Quantity int)
insert into #yourOrderDetails (Id, Name, type, Quantity) values
(2009 ,'john','a', 10 )
,(2009 ,'john','a', 20 ) ,(2010 ,'sam ','b', 25 )
,(2011 ,'sam ','c', 50 ) ,(2012 ,'sam ','d', 30 )
create table #yourValueDetails(Id int, Value Int)
insert into #yourValueDetails(Id, value) values
( 2009 , 300 ) ,( 2010 , 500 )
,( 2011 , 200 ) ,( 2012 , 100 )
SELECT a.ID,
a.Name,
a.Type,
a.quantity,
price = (a.quantity * b.price)
FROM OrderDetails a LEFT JOIN
ValueDetails b on a.id = b.id
This will put the price on every row. If you want to do a SUM by Id,Name and Type it's not going to show the individual records like you show them above. If you want to put a SUM on one of the lines that share the same Id, Name and Type then you'd need a rule to figure out which one and then you could probably use a CASE statement to decide on which line you want to show the SUM total.
I have a select * query which gives lots of row and lots of columns of results. I have an issue with duplicates of one column A when given the same value of another column B that I would like to only include one of.
Basically I have a column that tells me the "name" of object and another that tells me the "number". Sometimes I have an object "name" with more than one entry for a given object "number". I only want distinct "numbers" within a "name" but I want the query to give the entire table when this is true and not just these two columns.
Name Number ColumnC ColumnD
Bob 1 93 12
Bob 2 432 546
Bob 3 443 76
This example above is fine
Name Number ColumnC ColumnD
Bob 1 93 12
Bob 2 432 546
Bill 1 443 76
Bill 2 54 1856
This example above is fine
Name Number ColumnC ColumnD
Bob 1 93 12
Bob 2 432 546
Bob 2 209 17
This example above is not fine, I only want one of the Bob 2's.
Try it if you are using SQL 2005 or above:
With ranked_records AS
(
select *,
ROW_NUMBER() OVER(Partition By name, number Order By name) [ranked]
from MyTable
)
select * from ranked_records
where ranked = 1
If you just want the Name and number, then
SELECT DISTINCT Name, Number FROM Table1
If you want to know how many of each there are, then
SELECT Name, Number, COUNT(*) FROM Table1 GROUP BY Name, Number
By using a Common Table Expression (CTE) and the ROW_NUMBER OVER PARTION syntax as follows:
WITH
CTE AS
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY Name, Number ORDER BY Name, Number) AS R
FROM
dbo.ATable
)
SELECT
*
FROM
CTE
WHERE
R = 1
WITH
CTE AS
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY Plant, BatchNumber ORDER BY Plant, BatchNumber) AS R
FROM dbo.StatisticalReports WHERE dbo.StatisticalReports. \!"FermBatchStartTime\!" >= DATEADD(d,-90, getdate())
)
SELECT
*
FROM
CTE
WHERE
R = 1
ORDER BY dbo.StatisticalReports.Plant, dbo.StatisticalReports.FermBatchStartTime
EmpID Name Date Earn
1 A 7/1/2014 2
1 A 7/1/2014 4
1 A 7/2/2014 1
1 A 7/2/2014 2
2 B 7/1/2014 5
2 B 7/2/2014 5
I would like combine two results in one row as below.here is my statement but i want to find the solution to get the Total_Earn?. Thank
"SELECT EmpID, Name, Date, Sum(earn) FROM employee WHERE Date between DateFrom and DateTo
GROUP BY EmpID, Name, Date"
EmpID Name Date Earn Total_Earn
1 A 7/2/2014 3 9
2 B 7/2/2014 5 10
It looks like you want the Max date and the Sum of Earn for each employee. Assuming you want one record for each ID/Name, you would do this:
select EmpID, Name, Max(Date), Sum(Earn)
from YourTableName
group by EmpID, Name
Try this. Substitute the date for whatever value you want.
SELECT table1.EmpID, table1.Name, table1.Date, table1.Earn, table2.Total_Earn
FROM
(SELECT EmpID, Name, Date, Earn
FROM yourtablename
WHERE Date = "2014-07-02"
GROUP BY EmpID) table1
LEFT JOIN
(SELECT EmpID, SUM(Earn)
FROM yourtablename
WHERE Date <= "2014-07-02"
GROUP BY EmpID) table2
ON table1.EmpID = table2.EmpID
This will perform two SELECTs and join their results. The first select (defined as table1) well select the employee ID and earnings for the specified date.
The second statement (defined as table2) will select the total earnings for an employee up to and including that date.
The two statements are then joined together according to the employee ID.
i have a table named customer_age that loks like this:
ID 1 2 3 4 5 6 7 8 9
NAME JIM JIM JIM NICK NICK NICK Paul Paul Paul
VALUE 20 13 12 10 20 8 4 24 14
and i want to display only the first record from each name. Something like this
ID 1 4 7
NAME JIM NICK Paul
VALUE 20 10 4
So far i have not been able to work it out.
i use sql server 2005
Any help would be appreciated...
Try using a subselect to find the lowest ID for each name, and use that set of IDs to pull the records from the main table:
SELECT ID, Name, Value
FROM customer_age
WHERE ID IN
(
SELECT MIN(ID) AS ID
FROM customer_age
GROUP BY Name
)
Just select the first record for each name using cross apply:
SELECT
ca.ID, ca.NAME, ca.VALUE
FROM customer_age c
CROSS APPLY (SELECT TOP 1 ID, NAME, VALUE
FROM customer_age ca
WHERE ca.NAME = c.NAME ORDER BY ID) ca
ORDER BY ca.ID
How about using window functions??
SELECT Id, Name, Value
FROM (
SELECT Id, Name, Value, ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Id ASC) AS rowNum
FROM customer_age
) AS sub
WHERE rowNum = 1
Assuming first record means highest ID, you may try your query with descending orderby ID and TOP n.