Why does my c program not free memory as it should? - c

I have made a program in c and wanted to see, how much memory it uses and noticed, that the memory usage grows while normally using it (at launch time it uses about 250k and now it's at 1.5mb). afaik, I freed all the unused memory and after some time hours, the app uses less memory. Could it be possible, that the freed memory just goes from the 'active' memory to the 'wired' or something, so it's released when free space is needed?
btw. my machine runs on mac os x, if this is important.

How do you determine the memory usage? Have you tried using valgrind to locate potential memory leaks? It's really easy. Just start your application with valgrind, run it, and look at the well-structured output.

If you're looking at the memory usage from the OS, you are likely to see this behavior. Freed memory is not automatically returned to the OS, but normally stays with the process, and can be malloced later. What you see is usually the high-water mark of memory use.
As Konrad Rudolph suggested, use something that examines the memory from inside the process to look for memory links.

The C library does not usually return "small" allocations to the OS. Instead it keeps the memory around for the next time you use malloc.
However, many C libraries will release large blocks, so you could try doing a malloc of several megabytes and then freeing it.

On OSX you should be able to use MallocDebug.app if you have installed the Developer Tools from OSX (as you might have trouble finding a port of valgrind for OSX).
/Developer/Applications/PerformanceTools/MallocDebug.app

I agree with what everyone has already said, but I do want to add just a few clarifying remarks specific to os x:
First, the operating system actually allocates memory using vm_allocate which allocates entire pages at a time. Because there is a cost associated with this, like others have stated, the C library does not just deallocate the page when you return memory via free(3). Specifically, if there are other allocations within the memory page, it will not be released. Currently memory pages are 4096 bytes in mac os x. The number of bytes in a page can be determined programatically with sysctl(2) or, more easily, with getpagesize(2). You can use this information to optimize your memory usage.
Secondly, user-space applications do not wire memory. Generally the kernel wires memory for critical data structures. Wired memory is basically memory that can never be swapped out and will never generate a page fault. If, for some reason, a page fault is generated in a wired memory page, the kernel will panic and your computer will crash. If your application is increasing your computer's wired memory by a noticeable amount, it is a very bad sign. It generally means that your application is doing something that significantly grows kernel data structures, like allocating and not reaping hundreds of threads of child processes. (of course, this is a general statement... in some cases, this growth is expected, like when developing a virtual host or something like that).

In addition to what the others have already written:
malloc() allocates bigger chunks from the OS and spits it out in smaller pieces as you malloc() it. When free()ing, the piece first goes into a free-list, for quick reuse by another malloc if the size fits. It may at this time be merged with another free item, to form bigger free blocks, to avoid fragmentation (a whole bunch of different algorithms exist there, from freeLists to binary-sized-fragments to hashing and what not else).
When freed pieces arrive so that multiple fragments can be joined, free() usually does this, but sometimes, fragments remain, depending on size and orderof malloc() and free(). Also, only when a big such free block has been created will it be (sometimes) returned to the OS as a block. But usually, malloc() keeps things in its pocket, dependig on the allocated/free ratio (many heuristics and sometimes compile or flag options are often available).
Notice, that there is not ONE malloc/free algotrithm. There is a whole bunch of different implementations (and literature). Highly system, OS and library dependent.

Related

When do you consider a programme is leaking, and do you have to free before exit? [duplicate]

We are all taught that you MUST free every pointer that is allocated. I'm a bit curious, though, about the real cost of not freeing memory. In some obvious cases, like when malloc() is called inside a loop or part of a thread execution, it's very important to free so there are no memory leaks. But consider the following two examples:
First, if I have code that's something like this:
int main()
{
char *a = malloc(1024);
/* Do some arbitrary stuff with 'a' (no alloc functions) */
return 0;
}
What's the real result here? My thinking is that the process dies and then the heap space is gone anyway so there's no harm in missing the call to free (however, I do recognize the importance of having it anyway for closure, maintainability, and good practice). Am I right in this thinking?
Second, let's say I have a program that acts a bit like a shell. Users can declare variables like aaa = 123 and those are stored in some dynamic data structure for later use. Clearly, it seems obvious that you'd use some solution that will calls some *alloc function (hashmap, linked list, something like that). For this kind of program, it doesn't make sense to ever free after calling malloc because these variables must be present at all times during the program's execution and there's no good way (that I can see) to implement this with statically allocated space. Is it bad design to have a bunch of memory that's allocated but only freed as part of the process ending? If so, what's the alternative?
Just about every modern operating system will recover all the allocated memory space after a program exits. The only exception I can think of might be something like Palm OS where the program's static storage and runtime memory are pretty much the same thing, so not freeing might cause the program to take up more storage. (I'm only speculating here.)
So generally, there's no harm in it, except the runtime cost of having more storage than you need. Certainly in the example you give, you want to keep the memory for a variable that might be used until it's cleared.
However, it's considered good style to free memory as soon as you don't need it any more, and to free anything you still have around on program exit. It's more of an exercise in knowing what memory you're using, and thinking about whether you still need it. If you don't keep track, you might have memory leaks.
On the other hand, the similar admonition to close your files on exit has a much more concrete result - if you don't, the data you wrote to them might not get flushed, or if they're a temp file, they might not get deleted when you're done. Also, database handles should have their transactions committed and then closed when you're done with them. Similarly, if you're using an object oriented language like C++ or Objective C, not freeing an object when you're done with it will mean the destructor will never get called, and any resources the class is responsible might not get cleaned up.
Yes you are right, your example doesn't do any harm (at least not on most modern operating systems). All the memory allocated by your process will be recovered by the operating system once the process exits.
Source: Allocation and GC Myths (PostScript alert!)
Allocation Myth 4: Non-garbage-collected programs
should always deallocate all memory
they allocate.
The Truth: Omitted
deallocations in frequently executed
code cause growing leaks. They are
rarely acceptable. but Programs that
retain most allocated memory until
program exit often perform better
without any intervening deallocation.
Malloc is much easier to implement if
there is no free.
In most cases, deallocating memory
just before program exit is pointless.
The OS will reclaim it anyway. Free
will touch and page in the dead
objects; the OS won't.
Consequence: Be careful with "leak
detectors" that count allocations.
Some "leaks" are good!
That said, you should really try to avoid all memory leaks!
Second question: your design is ok. If you need to store something until your application exits then its ok to do this with dynamic memory allocation. If you don't know the required size upfront, you can't use statically allocated memory.
=== What about future proofing and code reuse? ===
If you don't write the code to free the objects, then you are limiting the code to only being safe to use when you can depend on the memory being free'd by the process being closed ... i.e. small one-time use projects or "throw-away"[1] projects)... where you know when the process will end.
If you do write the code that free()s all your dynamically allocated memory, then you are future proofing the code and letting others use it in a larger project.
[1] regarding "throw-away" projects. Code used in "Throw-away" projects has a way of not being thrown away. Next thing you know ten years have passed and your "throw-away" code is still being used).
I heard a story about some guy who wrote some code just for fun to make his hardware work better. He said "just a hobby, won't be big and professional". Years later lots of people are using his "hobby" code.
You are correct, no harm is done and it's faster to just exit
There are various reasons for this:
All desktop and server environments simply release the entire memory space on exit(). They are unaware of program-internal data structures such as heaps.
Almost all free() implementations do not ever return memory to the operating system anyway.
More importantly, it's a waste of time when done right before exit(). At exit, memory pages and swap space are simply released. By contrast, a series of free() calls will burn CPU time and can result in disk paging operations, cache misses, and cache evictions.
Regarding the possiblility of future code reuse justifing the certainty of pointless ops: that's a consideration but it's arguably not the Agile way. YAGNI!
I completely disagree with everyone who says OP is correct or there is no harm.
Everyone is talking about a modern and/or legacy OS's.
But what if I'm in an environment where I simply have no OS?
Where there isn't anything?
Imagine now you are using thread styled interrupts and allocate memory.
In the C standard ISO/IEC:9899 is the lifetime of memory stated as:
7.20.3 Memory management functions
1 The order and contiguity of storage allocated by successive calls to the calloc,
malloc, and realloc functions is unspecified. The pointer returned if the allocation
succeeds is suitably aligned so that it may be assigned to a pointer to any type of object
and then used to access such an object or an array of such objects in the space allocated
(until the space is explicitly deallocated). The lifetime of an allocated object extends
from the allocation until the deallocation.[...]
So it has not to be given that the environment is doing the freeing job for you.
Otherwise it would be added to the last sentence: "Or until the program terminates."
So in other words:
Not freeing memory is not just bad practice. It produces non portable and not C conform code.
Which can at least be seen as 'correct, if the following: [...], is supported by environment'.
But in cases where you have no OS at all, no one is doing the job for you
(I know generally you don't allocate and reallocate memory on embedded systems,
but there are cases where you may want to.)
So speaking in general plain C (as which the OP is tagged),
this is simply producing erroneous and non portable code.
I typically free every allocated block once I'm sure that I'm done with it. Today, my program's entry point might be main(int argc, char *argv[]) , but tomorrow it might be foo_entry_point(char **args, struct foo *f) and typed as a function pointer.
So, if that happens, I now have a leak.
Regarding your second question, if my program took input like a=5, I would allocate space for a, or re-allocate the same space on a subsequent a="foo". This would remain allocated until:
The user typed 'unset a'
My cleanup function was entered, either servicing a signal or the user typed 'quit'
I can not think of any modern OS that does not reclaim memory after a process exits. Then again, free() is cheap, why not clean up? As others have said, tools like valgrind are great for spotting leaks that you really do need to worry about. Even though the blocks you example would be labeled as 'still reachable' , its just extra noise in the output when you're trying to ensure you have no leaks.
Another myth is "If its in main(), I don't have to free it", this is incorrect. Consider the following:
char *t;
for (i=0; i < 255; i++) {
t = strdup(foo->name);
let_strtok_eat_away_at(t);
}
If that came prior to forking / daemonizing (and in theory running forever), your program has just leaked an undetermined size of t 255 times.
A good, well written program should always clean up after itself. Free all memory, flush all files, close all descriptors, unlink all temporary files, etc. This cleanup function should be reached upon normal termination, or upon receiving various kinds of fatal signals, unless you want to leave some files laying around so you can detect a crash and resume.
Really, be kind to the poor soul who has to maintain your stuff when you move on to other things .. hand it to them 'valgrind clean' :)
It is completely fine to leave memory unfreed when you exit; malloc() allocates the memory from the memory area called "the heap", and the complete heap of a process is freed when the process exits.
That being said, one reason why people still insist that it is good to free everything before exiting is that memory debuggers (e.g. valgrind on Linux) detect the unfreed blocks as memory leaks, and if you have also "real" memory leaks, it becomes more difficult to spot them if you also get "fake" results at the end.
This code will usually work alright, but consider the problem of code reuse.
You may have written some code snippet which doesn't free allocated memory, it is run in such a way that memory is then automatically reclaimed. Seems allright.
Then someone else copies your snippet into his project in such a way that it is executed one thousand times per second. That person now has a huge memory leak in his program. Not very good in general, usually fatal for a server application.
Code reuse is typical in enterprises. Usually the company owns all the code its employees produce and every department may reuse whatever the company owns. So by writing such "innocently-looking" code you cause potential headache to other people. This may get you fired.
What's the real result here?
Your program leaked the memory. Depending on your OS, it may have been recovered.
Most modern desktop operating systems do recover leaked memory at process termination, making it sadly common to ignore the problem (as can be seen by many other answers here.)
But you are relying on a safety feature not being part of the language, one you should not rely upon. Your code might run on a system where this behaviour does result in a "hard" memory leak, next time.
Your code might end up running in kernel mode, or on vintage / embedded operating systems which do not employ memory protection as a tradeoff. (MMUs take up die space, memory protection costs additional CPU cycles, and it is not too much to ask from a programmer to clean up after himself).
You can use and re-use memory (and other resources) any way you like, but make sure you deallocated all resources before exiting.
If you're using the memory you've allocated, then you're not doing anything wrong. It becomes a problem when you write functions (other than main) that allocate memory without freeing it, and without making it available to the rest of your program. Then your program continues running with that memory allocated to it, but no way of using it. Your program and other running programs are deprived of that memory.
Edit: It's not 100% accurate to say that other running programs are deprived of that memory. The operating system can always let them use it at the expense of swapping your program out to virtual memory (</handwaving>). The point is, though, that if your program frees memory that it isn't using then a virtual memory swap is less likely to be necessary.
There's actually a section in the OSTEP online textbook for an undergraduate course in operating systems which discusses exactly your question.
The relevant section is "Forgetting To Free Memory" in the Memory API chapter on page 6 which gives the following explanation:
In some cases, it may seem like not calling free() is reasonable. For
example, your program is short-lived, and will soon exit; in this case,
when the process dies, the OS will clean up all of its allocated pages and
thus no memory leak will take place per se. While this certainly “works”
(see the aside on page 7), it is probably a bad habit to develop, so be wary
of choosing such a strategy
This excerpt is in the context of introducing the concept of virtual memory. Basically at this point in the book, the authors explain that one of the goals of an operating system is to "virtualize memory," that is, to let every program believe that it has access to a very large memory address space.
Behind the scenes, the operating system will translate "virtual addresses" the user sees to actual addresses pointing to physical memory.
However, sharing resources such as physical memory requires the operating system to keep track of what processes are using it. So if a process terminates, then it is within the capabilities and the design goals of the operating system to reclaim the process's memory so that it can redistribute and share the memory with other processes.
EDIT: The aside mentioned in the excerpt is copied below.
ASIDE: WHY NO MEMORY IS LEAKED ONCE YOUR PROCESS EXITS
When you write a short-lived program, you might allocate some space
using malloc(). The program runs and is about to complete: is there
need to call free() a bunch of times just before exiting? While it seems
wrong not to, no memory will be "lost" in any real sense. The reason is
simple: there are really two levels of memory management in the system.
The first level of memory management is performed by the OS, which
hands out memory to processes when they run, and takes it back when
processes exit (or otherwise die). The second level of management
is within each process, for example within the heap when you call
malloc() and free(). Even if you fail to call free() (and thus leak
memory in the heap), the operating system will reclaim all the memory of
the process (including those pages for code, stack, and, as relevant here,
heap) when the program is finished running. No matter what the state
of your heap in your address space, the OS takes back all of those pages
when the process dies, thus ensuring that no memory is lost despite the
fact that you didn’t free it.
Thus, for short-lived programs, leaking memory often does not cause any
operational problems (though it may be considered poor form). When
you write a long-running server (such as a web server or database management
system, which never exit), leaked memory is a much bigger issue,
and will eventually lead to a crash when the application runs out of
memory. And of course, leaking memory is an even larger issue inside
one particular program: the operating system itself. Showing us once
again: those who write the kernel code have the toughest job of all...
from Page 7 of Memory API chapter of
Operating Systems: Three Easy Pieces
Remzi H. Arpaci-Dusseau and Andrea C. Arpaci-Dusseau
Arpaci-Dusseau Books
March, 2015 (Version 0.90)
There's no real danger in not freeing your variables, but if you assign a pointer to a block of memory to a different block of memory without freeing the first block, the first block is no longer accessible but still takes up space. This is what's called a memory leak, and if you do this with regularity then your process will start to consume more and more memory, taking away system resources from other processes.
If the process is short-lived you can often get away with doing this as all allocated memory is reclaimed by the operating system when the process completes, but I would advise getting in the habit of freeing all memory you have no further use for.
You are correct, memory is automatically freed when the process exits. Some people strive not to do extensive cleanup when the process is terminated, since it will all be relinquished to the operating system. However, while your program is running you should free unused memory. If you don't, you may eventually run out or cause excessive paging if your working set gets too big.
You are absolutely correct in that respect. In small trivial programs where a variable must exist until the death of the program, there is no real benefit to deallocating the memory.
In fact, I had once been involved in a project where each execution of the program was very complex but relatively short-lived, and the decision was to just keep memory allocated and not destabilize the project by making mistakes deallocating it.
That being said, in most programs this is not really an option, or it can lead you to run out of memory.
It depends on the scope of the project that you're working on. In the context of your question, and I mean just your question, then it doesn't matter.
For a further explanation (optional), some scenarios I have noticed from this whole discussion is as follow:
(1) - If you're working in an embedded environment where you cannot rely on the main OS' to reclaim the memory for you, then you should free them since memory leaks can really crash the program if done unnoticed.
(2) - If you're working on a personal project where you won't disclose it to anyone else, then you can skip it (assuming you're using it on the main OS') or include it for "best practices" sake.
(3) - If you're working on a project and plan to have it open source, then you need to do more research into your audience and figure out if freeing the memory would be the better choice.
(4) - If you have a large library and your audience consisted of only the main OS', then you don't need to free it as their OS' will help them to do so. In the meantime, by not freeing, your libraries/program may help to make the overall performance snappier since the program does not have to close every data structure, prolonging the shutdown time (imagine a very slow excruciating wait to shut down your computer before leaving the house...)
I can go on and on specifying which course to take, but it ultimately depends on what you want to achieve with your program. Freeing memory is considered good practice in some cases and not so much in some so it ultimately depends on the specific situation you're in and asking the right questions at the right time. Good luck!
If you're developing an application from scratch, you can make some educated choices about when to call free. Your example program is fine: it allocates memory, maybe you have it work for a few seconds, and then closes, freeing all the resources it claimed.
If you're writing anything else, though -- a server/long-running application, or a library to be used by someone else, you should expect to call free on everything you malloc.
Ignoring the pragmatic side for a second, it's much safer to follow the stricter approach, and force yourself to free everything you malloc. If you're not in the habit of watching for memory leaks whenever you code, you could easily spring a few leaks. So in other words, yes -- you can get away without it; please be careful, though.
If a program forgets to free a few Megabytes before it exits the operating system will free them. But if your program runs for weeks at a time and a loop inside the program forgets to free a few bytes in each iteration you will have a mighty memory leak that will eat up all the available memory in your computer unless you reboot it on a regular basis => even small memory leaks might be bad if the program is used for a seriously big task even if it originally wasn't designed for one.
It depends on the OS environment the program is running in, as others have already noted, and for long running processes, freeing memory and avoiding even very slow leaks is important always. But if the operating system deals with stuff, as Unix has done for example since probably forever, then you don't need to free memory, nor close files (the kernel closes all open file descriptors when a process exits.)
If your program allocates a lot of memory, it may even be beneficial to exit without "hesitation". I find that when I quit Firefox, it spends several !minutes ! paging in gigabytes of memory in many processes. I guess this is due to having to call destructors on C++ objects. This is actually terrible. Some might argue, that this is necessary to save state consistently, but in my opinion, long-running interactive programs like browsers, editors and design programs, just to mention a few, should ensure that any state information, preferences, open windows/pages, documents etc is frequently written to permanent storage, to avoid loss of work in case of a crash. Then this state-saving can be performed again quickly when the user elects to quit, and when completed, the processes should just exit immediately.
All memory allocated for this process will be marked unused by OS then reused, because the memory allocation is done by user space functions.
Imagine OS is a god, and the memories is the materials for creating a wolrd of process, god use some of materials creat a world (or to say OS reserved some of memory and create a process in it). No matter what the creatures in this world have done the materials not belong to this world won't be affected. After this world expired, OS the god, can recycle materials allocated for this world.
Modern OS may have different details on releasing user space memory, but that has to be a basic duty of OS.
I think that your two examples are actually only one: the free() should occur only at the end of the process, which as you point out is useless since the process is terminating.
In you second example though, the only difference is that you allow an undefined number of malloc(), which could lead to running out of memory. The only way to handle the situation is to check the return code of malloc() and act accordingly.

Why does C manage the heap, instead of the operating system?

In other words, why doesn't free() just return the memory to the operating system, and malloc simply request memory from the operating system?
This unpacks to three closely related questions:
Why does C need to manage its own heap? (Is it because the OS will only allow you to allocate and free contiguous memory of a minimum size?)
Assuming what I wrote in parentheses is true, why is it?
Can this problem affect the operating system itself, so that it's unable to allocate blocks of memory to any running processes?
Why does C need to manage its own heap?
It's not actually specified that it needs to, but it needs to implement malloc() and friends the way they are described in the standard. So if there was an OS already providing such an interface, a C implementation could just provide a tiny wrapper.
Is it because the OS will only allow you to allocate and free contiguous memory of a minimum size? And if that's true, what's the reason?
Yes. A typical OS will manage paged memory and map or unmap processes whole pages of memory. The unit of memory that can be "paged" depends on the hardware architecture. You might want to read some details on how memory management units (MMU) work. On architectures without MMU, the operating system might not do anything and a C implementation would just fullfill malloc() requests from a fixed location in physical address space.
malloc is a C method itself. You are using a standard library that provides it for you, but in the end, it is C code just like yours is.
In some operating systems, you can only get memory from the OS in the size of pages (using mmap). This is too big for your regular data structure.
Doing a system call every time you need memory is way too expensive.
Actually it is left for the implementation. The question :
why doesn't free() just return the memory to the operating system, and
malloc simply request memory from the operating system?
is wrong as nothing stops the implementation from doing it. So there is no answer for this question - every implementation can be potentially different (it only has to be standard compliant)
Why does C need to manage its own heap? (Is it because the OS will only allow you to allocate and free contiguous memory of a minimum size?)
Operating systems manage memory in pages. Allocating and freeing pages has a high overhead. Most allocations in C tend to be much smaller than a page size.
From the other answers, here's what I gathered the answer to be.
Most operating systems only allocate memory to processes in fixed sizes, called pages. When a process returns memory to the OS, it can only do so in pagefuls. A page is a sequence of memory of a fixed size. The start and end points of a page are fixed, so even if you've got a large enough amount of free memory, you won't be able to return it to the OS unless it's between the start and end points of a page.
On the other hand, you could imagine that there is no operating system (or that the operating system allocates memory to programs from its own heap). This helps me understand things better, because the operating system was getting in the way of my intuition, because it looked as if the freed memory was being dropped into a black hole, and the allocated memory was coming out of a similar black hole. Without any OS, all the memory in a computer could be pictured as belonging to a large sequence of cells. If you allocate all available memory in a computer, and then start freeing some memory, then you might not be able to find a large enough contiguous chunk of memory to fulfill a malloc request.

heap overflow affecting other programs

I was trying to create the condition for malloc to return a NULL pointer. In the below program, though I can see malloc returning NULL, once the program is forcebly terminated, I see that all other programs are becoming slow and finally I had to reboot the system. So my question is whether the memory for heap is shared with other programs? If not, other programs should not have affected. Is OS is not allocating certain amount of memory at the time of execution? I am using windows 10, Mingw.
#include <stdio.h>
#include <malloc.h>
void mallocInFunction(void)
{
int *ptr=malloc(500);
if(ptr==NULL)
{
printf("Memory Could not be allocated\n");
}
else
{
printf("Allocated memory successfully\n");
}
}
int main (void)
{
while(1)
{
mallocInFunction();
}
return(0);
}
So my question is whether the memory for heap is shared with other programs?
Physical memory (RAM) is a resource that is shared by all processes. The operating system makes decisions about how much RAM to allocate to each process and adjusts that over time.
If not, other programs should not have affected. Is OS is not allocating certain amount of memory at the time of execution?
At the time the program starts executing, the operating system has no idea how much memory the program will want or need. Instead, it deals with allocations as they happen. Unless configured otherwise, it will typically do everything it possibly can to allow the program's allocation to succeed because presumably there's a reason the program is doing what it's doing and the operating system won't try to second guess it.
... whether the memory for heap is shared with other programs?
Well, the C standard doesn't exactly require a heap, but in the context of a task-switching, multi-user and multi-threaded OS, of course memory is shared between processes! The C standard doesn't require any of this, but this is all pretty common stuff:
CPU cache memory tends to be preferred for code that's executed often, though this might get swapped around quite a bit; that may or may not be swapped to a heap.
Task switching causes registers to be swapped to other forms of memory; that may or may not be swapped to a heap.
Entire pages are swapped to and from disk, so that other programs can make use of them when your OS switches execution away from your program and to the other programs, and when it's your programs turn to execute again among other reasons. This may or may not involve manipulating the heap.
FWIW, you're referring to memory that has allocated storage duration. It's best to avoid using terms like heap and stack, as they're virtually meaningless. The memory you're referring to is on a silicon chip, regardless of whether it uses a heap or a stack.
... Is OS is not allocating certain amount of memory at the time of execution?
Speaking of silicon chips and execution, your OS likely only has control of one processor (a silicon chip which contains some logic circuits and memory, among other things I'm sure) with which to execute many programs! To summarise this post, yes, your program is most likely sharing those silicon chips with other programs!
On a tangential note, I don't think heap overflow means what you think it means.
Your question cannot be answered in the context of C, the language. For C, there's no such thing as a heap, a process, ...
But it can be answered in the context of operating systems. Even a bit generically because many modern multitasking OSes do similar things.
Given a modern multitasking OS, it will use virtual address spaces for each process. The OS manages a fixed size of physical RAM and divides this into pages, when a process needs memory, such pages are mapped into the process' virtual address space (typically using a different virtual address than the physical one). So when all memory pages are claimed by the OS itself and by the processes running, the OS will typically save some of these pages that are not in active use to disk, in a swap area, in order to serve this page as a fresh page to the next process requesting one. But when the original page is touched (and this is typically the case with free(), see below), it must first be loaded from disk again, but to have a free page for this, another page must be saved to swap space.
This is, like all disk I/O, slow, and it's probably what you see happening here.
Now to fully understand this: what does malloc() do? It typically requests from the operating system to have the memory of the own process increased (and if necessary, the OS does this by mapping another page), and it uses this new memory by writing some information there about the block of memory requested (so free() can work correctly later) and ultimately returns a pointer to a block that's free to use for the program. free() uses the information written by malloc(), modifies it to indicate this block is free again, and it typically can't give any memory back to the OS because there are other malloc()d blocks in the same page. It will give memory back when possible, but that's the exception in a typical scenario where dynamic allocations are heavily used.
So, the answer to your question is: Yes, the RAM is shared because there is only one set of physical RAM. The OS does the best it can to hide that fact and virtualize RAM, but if a process consumes all that is there, this will have visible effects.
malloc() is not system call but libc library function. So when a program ask for allocating memory via malloc(), system call brk()/sbrk() OR mmap() to allocated page(s), more details here.
Please keep in mind that the memory you get is all virtual in nature, that means if you have 3GB of physical RAM you can actually allocate almost infinite memory. So how does this happens? This happens via concept called 'paging', where system stores and retrieves data from secondary memory storage(HDD/SDD) to main memory(RAM), more details here.
So with this theory, out of memory usually quite rare but program like above which is checking system limits, this can happen. This is nicely explained here.
Now, why other programs are sort of hanged OR slow? Because they all share the same operating system and system is starving for resource. In fact at a point the system will crash and reboot again.
Hope this helps?

Can I 'reserve' memory somehow, so as to ensure malloc doesn't fail for this reason

Is it possible to 'reserve' memory before a malloc() call? In other words, can I do something (perhaps OS-specific) which ensures there is a certain amount of free memory available, so that you know that your next malloc() (or realloc() etc.) call won't return NULL due to lack of memory?
The 'reservation' or 'pre-allocation' can fail just like a malloc, but if it succeeds, I want to be sure my next malloc() succeeds.
Notes:
Yes, I know, I want to allocate memory before allocating memory. That's exactly right. The thing is the later allocations are not really under my control and I want to be able to assume they succeed.
Bonus points for an answer regarding multi-threaded code as well.
My motivation: I was considering adopting the use of glib for my C development, but apparently it abort()s when it fails to allocate memory, and that's not acceptable to me.
Perhaps a solution which dynamically replaces the malloc symbol with something else? Or the symbol for the function wrapping the sbrk system call?
With glibc you can hook the allocation functions:
https://www.gnu.org/software/libc/manual/html_node/Hooks-for-Malloc.html
Now that you control memory allocation in your program, you can do what you like, including writing a function to reserve a (possibly thread-local, since you asked about multi-threading) chunk of memory from the system that future calls to your malloc and realloc hooks will use to return memory.
Obviously, you need to somehow know in advance an upper bound how much memory will be required by the series of malloc calls that you need to not fail.
Back in the old Mac Toolbox days it was extremely common to use a chunk of memory called a "rainy-day fund." You'd allocate enough memory such that if you freed it, there'd be enough free memory to throw up a dialog box explaining that the app had run out of memory, save your work, and exit. Then you'd keep that pointer around until malloc() returned null, and at least you'd be guaranteed to be able to deal with it gracefully.
That was on a 100% real-memory system, though, and things these days are very different. Still, if we're talking about those small and simple real-memory systems that still exist, then a similar strategy still makes sense.
I realize the following does not directly answer your question with respect to malloc(). It is instead an attempt to offer up another avenue that might be applicable to your situation.
For a few years I was dealing with certified embedded systems. Two of the constraints were that 1) we were forbidden to free memory and 2) we were forbidden from allocating memory beyond a certain point during the initialization process. This was because fragmentation that could result from dynamic memory allocations and deallocations made it too costly to certify (and guarantee that allocations would succeed).
Our solution was to allocate pools of memory during the early initialization process. The blocks of memory handled by a given pool would all be the same size, thereby avoiding the fragmentation issue. Different pools would handle differently sized memory blocks for a different purpose. This meant that we had to allocate enough memory up front for our worst case memory consumption scenario as well as manage those pools ourselves.
Hope this helps.
Obviously there's no magic way for your program to ensure your system has an arbitrary amount of memory, but you can get the memory as soon as your process starts, so that it won't fail unexpectedly part way through the work/day when it'll be a right pain.
On some OSes, simply doing a big malloc then freeing the memory immediately will still have called sbrk or similar OS function to grow your process memory, but even that's not a great solution because getting virtual address space is still a ways short of getting physical memory to back it when needed, so you'd want to write through that memory with some noise values, then even if it's swapped out to disk while unused you can expect that the virtual memory of the system is committed to your memory needs and will instead deny other programs (or smaller new/malloc requests you make later ;-P) memory should the system be running short.
Another approach is to seek an OS specific function to insist on locking memory pages in physical memory, such as mlock(2) on Linux.
(These kind of "I'm the most important thing on the server" assumptions tend to make for a fragile system once a few running programs have all taken that attitude....)

What REALLY happens when you don't free after malloc before program termination?

We are all taught that you MUST free every pointer that is allocated. I'm a bit curious, though, about the real cost of not freeing memory. In some obvious cases, like when malloc() is called inside a loop or part of a thread execution, it's very important to free so there are no memory leaks. But consider the following two examples:
First, if I have code that's something like this:
int main()
{
char *a = malloc(1024);
/* Do some arbitrary stuff with 'a' (no alloc functions) */
return 0;
}
What's the real result here? My thinking is that the process dies and then the heap space is gone anyway so there's no harm in missing the call to free (however, I do recognize the importance of having it anyway for closure, maintainability, and good practice). Am I right in this thinking?
Second, let's say I have a program that acts a bit like a shell. Users can declare variables like aaa = 123 and those are stored in some dynamic data structure for later use. Clearly, it seems obvious that you'd use some solution that will calls some *alloc function (hashmap, linked list, something like that). For this kind of program, it doesn't make sense to ever free after calling malloc because these variables must be present at all times during the program's execution and there's no good way (that I can see) to implement this with statically allocated space. Is it bad design to have a bunch of memory that's allocated but only freed as part of the process ending? If so, what's the alternative?
Just about every modern operating system will recover all the allocated memory space after a program exits. The only exception I can think of might be something like Palm OS where the program's static storage and runtime memory are pretty much the same thing, so not freeing might cause the program to take up more storage. (I'm only speculating here.)
So generally, there's no harm in it, except the runtime cost of having more storage than you need. Certainly in the example you give, you want to keep the memory for a variable that might be used until it's cleared.
However, it's considered good style to free memory as soon as you don't need it any more, and to free anything you still have around on program exit. It's more of an exercise in knowing what memory you're using, and thinking about whether you still need it. If you don't keep track, you might have memory leaks.
On the other hand, the similar admonition to close your files on exit has a much more concrete result - if you don't, the data you wrote to them might not get flushed, or if they're a temp file, they might not get deleted when you're done. Also, database handles should have their transactions committed and then closed when you're done with them. Similarly, if you're using an object oriented language like C++ or Objective C, not freeing an object when you're done with it will mean the destructor will never get called, and any resources the class is responsible might not get cleaned up.
Yes you are right, your example doesn't do any harm (at least not on most modern operating systems). All the memory allocated by your process will be recovered by the operating system once the process exits.
Source: Allocation and GC Myths (PostScript alert!)
Allocation Myth 4: Non-garbage-collected programs
should always deallocate all memory
they allocate.
The Truth: Omitted
deallocations in frequently executed
code cause growing leaks. They are
rarely acceptable. but Programs that
retain most allocated memory until
program exit often perform better
without any intervening deallocation.
Malloc is much easier to implement if
there is no free.
In most cases, deallocating memory
just before program exit is pointless.
The OS will reclaim it anyway. Free
will touch and page in the dead
objects; the OS won't.
Consequence: Be careful with "leak
detectors" that count allocations.
Some "leaks" are good!
That said, you should really try to avoid all memory leaks!
Second question: your design is ok. If you need to store something until your application exits then its ok to do this with dynamic memory allocation. If you don't know the required size upfront, you can't use statically allocated memory.
=== What about future proofing and code reuse? ===
If you don't write the code to free the objects, then you are limiting the code to only being safe to use when you can depend on the memory being free'd by the process being closed ... i.e. small one-time use projects or "throw-away"[1] projects)... where you know when the process will end.
If you do write the code that free()s all your dynamically allocated memory, then you are future proofing the code and letting others use it in a larger project.
[1] regarding "throw-away" projects. Code used in "Throw-away" projects has a way of not being thrown away. Next thing you know ten years have passed and your "throw-away" code is still being used).
I heard a story about some guy who wrote some code just for fun to make his hardware work better. He said "just a hobby, won't be big and professional". Years later lots of people are using his "hobby" code.
You are correct, no harm is done and it's faster to just exit
There are various reasons for this:
All desktop and server environments simply release the entire memory space on exit(). They are unaware of program-internal data structures such as heaps.
Almost all free() implementations do not ever return memory to the operating system anyway.
More importantly, it's a waste of time when done right before exit(). At exit, memory pages and swap space are simply released. By contrast, a series of free() calls will burn CPU time and can result in disk paging operations, cache misses, and cache evictions.
Regarding the possiblility of future code reuse justifing the certainty of pointless ops: that's a consideration but it's arguably not the Agile way. YAGNI!
I completely disagree with everyone who says OP is correct or there is no harm.
Everyone is talking about a modern and/or legacy OS's.
But what if I'm in an environment where I simply have no OS?
Where there isn't anything?
Imagine now you are using thread styled interrupts and allocate memory.
In the C standard ISO/IEC:9899 is the lifetime of memory stated as:
7.20.3 Memory management functions
1 The order and contiguity of storage allocated by successive calls to the calloc,
malloc, and realloc functions is unspecified. The pointer returned if the allocation
succeeds is suitably aligned so that it may be assigned to a pointer to any type of object
and then used to access such an object or an array of such objects in the space allocated
(until the space is explicitly deallocated). The lifetime of an allocated object extends
from the allocation until the deallocation.[...]
So it has not to be given that the environment is doing the freeing job for you.
Otherwise it would be added to the last sentence: "Or until the program terminates."
So in other words:
Not freeing memory is not just bad practice. It produces non portable and not C conform code.
Which can at least be seen as 'correct, if the following: [...], is supported by environment'.
But in cases where you have no OS at all, no one is doing the job for you
(I know generally you don't allocate and reallocate memory on embedded systems,
but there are cases where you may want to.)
So speaking in general plain C (as which the OP is tagged),
this is simply producing erroneous and non portable code.
I typically free every allocated block once I'm sure that I'm done with it. Today, my program's entry point might be main(int argc, char *argv[]) , but tomorrow it might be foo_entry_point(char **args, struct foo *f) and typed as a function pointer.
So, if that happens, I now have a leak.
Regarding your second question, if my program took input like a=5, I would allocate space for a, or re-allocate the same space on a subsequent a="foo". This would remain allocated until:
The user typed 'unset a'
My cleanup function was entered, either servicing a signal or the user typed 'quit'
I can not think of any modern OS that does not reclaim memory after a process exits. Then again, free() is cheap, why not clean up? As others have said, tools like valgrind are great for spotting leaks that you really do need to worry about. Even though the blocks you example would be labeled as 'still reachable' , its just extra noise in the output when you're trying to ensure you have no leaks.
Another myth is "If its in main(), I don't have to free it", this is incorrect. Consider the following:
char *t;
for (i=0; i < 255; i++) {
t = strdup(foo->name);
let_strtok_eat_away_at(t);
}
If that came prior to forking / daemonizing (and in theory running forever), your program has just leaked an undetermined size of t 255 times.
A good, well written program should always clean up after itself. Free all memory, flush all files, close all descriptors, unlink all temporary files, etc. This cleanup function should be reached upon normal termination, or upon receiving various kinds of fatal signals, unless you want to leave some files laying around so you can detect a crash and resume.
Really, be kind to the poor soul who has to maintain your stuff when you move on to other things .. hand it to them 'valgrind clean' :)
It is completely fine to leave memory unfreed when you exit; malloc() allocates the memory from the memory area called "the heap", and the complete heap of a process is freed when the process exits.
That being said, one reason why people still insist that it is good to free everything before exiting is that memory debuggers (e.g. valgrind on Linux) detect the unfreed blocks as memory leaks, and if you have also "real" memory leaks, it becomes more difficult to spot them if you also get "fake" results at the end.
This code will usually work alright, but consider the problem of code reuse.
You may have written some code snippet which doesn't free allocated memory, it is run in such a way that memory is then automatically reclaimed. Seems allright.
Then someone else copies your snippet into his project in such a way that it is executed one thousand times per second. That person now has a huge memory leak in his program. Not very good in general, usually fatal for a server application.
Code reuse is typical in enterprises. Usually the company owns all the code its employees produce and every department may reuse whatever the company owns. So by writing such "innocently-looking" code you cause potential headache to other people. This may get you fired.
What's the real result here?
Your program leaked the memory. Depending on your OS, it may have been recovered.
Most modern desktop operating systems do recover leaked memory at process termination, making it sadly common to ignore the problem (as can be seen by many other answers here.)
But you are relying on a safety feature not being part of the language, one you should not rely upon. Your code might run on a system where this behaviour does result in a "hard" memory leak, next time.
Your code might end up running in kernel mode, or on vintage / embedded operating systems which do not employ memory protection as a tradeoff. (MMUs take up die space, memory protection costs additional CPU cycles, and it is not too much to ask from a programmer to clean up after himself).
You can use and re-use memory (and other resources) any way you like, but make sure you deallocated all resources before exiting.
If you're using the memory you've allocated, then you're not doing anything wrong. It becomes a problem when you write functions (other than main) that allocate memory without freeing it, and without making it available to the rest of your program. Then your program continues running with that memory allocated to it, but no way of using it. Your program and other running programs are deprived of that memory.
Edit: It's not 100% accurate to say that other running programs are deprived of that memory. The operating system can always let them use it at the expense of swapping your program out to virtual memory (</handwaving>). The point is, though, that if your program frees memory that it isn't using then a virtual memory swap is less likely to be necessary.
There's actually a section in the OSTEP online textbook for an undergraduate course in operating systems which discusses exactly your question.
The relevant section is "Forgetting To Free Memory" in the Memory API chapter on page 6 which gives the following explanation:
In some cases, it may seem like not calling free() is reasonable. For
example, your program is short-lived, and will soon exit; in this case,
when the process dies, the OS will clean up all of its allocated pages and
thus no memory leak will take place per se. While this certainly “works”
(see the aside on page 7), it is probably a bad habit to develop, so be wary
of choosing such a strategy
This excerpt is in the context of introducing the concept of virtual memory. Basically at this point in the book, the authors explain that one of the goals of an operating system is to "virtualize memory," that is, to let every program believe that it has access to a very large memory address space.
Behind the scenes, the operating system will translate "virtual addresses" the user sees to actual addresses pointing to physical memory.
However, sharing resources such as physical memory requires the operating system to keep track of what processes are using it. So if a process terminates, then it is within the capabilities and the design goals of the operating system to reclaim the process's memory so that it can redistribute and share the memory with other processes.
EDIT: The aside mentioned in the excerpt is copied below.
ASIDE: WHY NO MEMORY IS LEAKED ONCE YOUR PROCESS EXITS
When you write a short-lived program, you might allocate some space
using malloc(). The program runs and is about to complete: is there
need to call free() a bunch of times just before exiting? While it seems
wrong not to, no memory will be "lost" in any real sense. The reason is
simple: there are really two levels of memory management in the system.
The first level of memory management is performed by the OS, which
hands out memory to processes when they run, and takes it back when
processes exit (or otherwise die). The second level of management
is within each process, for example within the heap when you call
malloc() and free(). Even if you fail to call free() (and thus leak
memory in the heap), the operating system will reclaim all the memory of
the process (including those pages for code, stack, and, as relevant here,
heap) when the program is finished running. No matter what the state
of your heap in your address space, the OS takes back all of those pages
when the process dies, thus ensuring that no memory is lost despite the
fact that you didn’t free it.
Thus, for short-lived programs, leaking memory often does not cause any
operational problems (though it may be considered poor form). When
you write a long-running server (such as a web server or database management
system, which never exit), leaked memory is a much bigger issue,
and will eventually lead to a crash when the application runs out of
memory. And of course, leaking memory is an even larger issue inside
one particular program: the operating system itself. Showing us once
again: those who write the kernel code have the toughest job of all...
from Page 7 of Memory API chapter of
Operating Systems: Three Easy Pieces
Remzi H. Arpaci-Dusseau and Andrea C. Arpaci-Dusseau
Arpaci-Dusseau Books
March, 2015 (Version 0.90)
There's no real danger in not freeing your variables, but if you assign a pointer to a block of memory to a different block of memory without freeing the first block, the first block is no longer accessible but still takes up space. This is what's called a memory leak, and if you do this with regularity then your process will start to consume more and more memory, taking away system resources from other processes.
If the process is short-lived you can often get away with doing this as all allocated memory is reclaimed by the operating system when the process completes, but I would advise getting in the habit of freeing all memory you have no further use for.
You are correct, memory is automatically freed when the process exits. Some people strive not to do extensive cleanup when the process is terminated, since it will all be relinquished to the operating system. However, while your program is running you should free unused memory. If you don't, you may eventually run out or cause excessive paging if your working set gets too big.
You are absolutely correct in that respect. In small trivial programs where a variable must exist until the death of the program, there is no real benefit to deallocating the memory.
In fact, I had once been involved in a project where each execution of the program was very complex but relatively short-lived, and the decision was to just keep memory allocated and not destabilize the project by making mistakes deallocating it.
That being said, in most programs this is not really an option, or it can lead you to run out of memory.
It depends on the scope of the project that you're working on. In the context of your question, and I mean just your question, then it doesn't matter.
For a further explanation (optional), some scenarios I have noticed from this whole discussion is as follow:
(1) - If you're working in an embedded environment where you cannot rely on the main OS' to reclaim the memory for you, then you should free them since memory leaks can really crash the program if done unnoticed.
(2) - If you're working on a personal project where you won't disclose it to anyone else, then you can skip it (assuming you're using it on the main OS') or include it for "best practices" sake.
(3) - If you're working on a project and plan to have it open source, then you need to do more research into your audience and figure out if freeing the memory would be the better choice.
(4) - If you have a large library and your audience consisted of only the main OS', then you don't need to free it as their OS' will help them to do so. In the meantime, by not freeing, your libraries/program may help to make the overall performance snappier since the program does not have to close every data structure, prolonging the shutdown time (imagine a very slow excruciating wait to shut down your computer before leaving the house...)
I can go on and on specifying which course to take, but it ultimately depends on what you want to achieve with your program. Freeing memory is considered good practice in some cases and not so much in some so it ultimately depends on the specific situation you're in and asking the right questions at the right time. Good luck!
If you're developing an application from scratch, you can make some educated choices about when to call free. Your example program is fine: it allocates memory, maybe you have it work for a few seconds, and then closes, freeing all the resources it claimed.
If you're writing anything else, though -- a server/long-running application, or a library to be used by someone else, you should expect to call free on everything you malloc.
Ignoring the pragmatic side for a second, it's much safer to follow the stricter approach, and force yourself to free everything you malloc. If you're not in the habit of watching for memory leaks whenever you code, you could easily spring a few leaks. So in other words, yes -- you can get away without it; please be careful, though.
If a program forgets to free a few Megabytes before it exits the operating system will free them. But if your program runs for weeks at a time and a loop inside the program forgets to free a few bytes in each iteration you will have a mighty memory leak that will eat up all the available memory in your computer unless you reboot it on a regular basis => even small memory leaks might be bad if the program is used for a seriously big task even if it originally wasn't designed for one.
It depends on the OS environment the program is running in, as others have already noted, and for long running processes, freeing memory and avoiding even very slow leaks is important always. But if the operating system deals with stuff, as Unix has done for example since probably forever, then you don't need to free memory, nor close files (the kernel closes all open file descriptors when a process exits.)
If your program allocates a lot of memory, it may even be beneficial to exit without "hesitation". I find that when I quit Firefox, it spends several !minutes ! paging in gigabytes of memory in many processes. I guess this is due to having to call destructors on C++ objects. This is actually terrible. Some might argue, that this is necessary to save state consistently, but in my opinion, long-running interactive programs like browsers, editors and design programs, just to mention a few, should ensure that any state information, preferences, open windows/pages, documents etc is frequently written to permanent storage, to avoid loss of work in case of a crash. Then this state-saving can be performed again quickly when the user elects to quit, and when completed, the processes should just exit immediately.
All memory allocated for this process will be marked unused by OS then reused, because the memory allocation is done by user space functions.
Imagine OS is a god, and the memories is the materials for creating a wolrd of process, god use some of materials creat a world (or to say OS reserved some of memory and create a process in it). No matter what the creatures in this world have done the materials not belong to this world won't be affected. After this world expired, OS the god, can recycle materials allocated for this world.
Modern OS may have different details on releasing user space memory, but that has to be a basic duty of OS.
I think that your two examples are actually only one: the free() should occur only at the end of the process, which as you point out is useless since the process is terminating.
In you second example though, the only difference is that you allow an undefined number of malloc(), which could lead to running out of memory. The only way to handle the situation is to check the return code of malloc() and act accordingly.

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