I have a user control that I've created, however when I go to add it to the XAML in the window, Intellisense doesn't pick it up, and I can't figure out how to add it to the window.
You need to add a reference inside the window tag. Something like:
xmlns:controls="clr-namespace:YourCustomNamespace.Controls;assembly=YourAssemblyName"
(When you add xmlns:controls=" intellisense should kick in to make this bit easier)
Then you can add the control with:
<controls:CustomControlClassName ..... />
You probably need to add the namespace:
<Window x:Class="UserControlTest.Window1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:UserControlTest"
Title="User Control Test" Height="300" Width="300">
<local:UserControl1 />
</Window>
Make sure there is an namespace definition (xmlns) for the namespace your control belong to.
xmlns:myControls="clr-namespace:YourCustomNamespace.Controls;assembly=YourAssemblyName"
<myControls:thecontrol/>
This is how I got it to work:
User Control WPF
<UserControl x:Class="App.ProcessView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300">
<Grid>
</Grid>
</UserControl>
User Control C#
namespace App {
/// <summary>
/// Interaction logic for ProcessView.xaml
/// </summary>
public partial class ProcessView : UserControl // My custom User Control
{
public ProcessView()
{
InitializeComponent();
}
} }
MainWindow WPF
<Window x:Name="RootWindow" x:Class="App.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:app="clr-namespace:App"
Title="Some Title" Height="350" Width="525" Closing="Window_Closing_1" Icon="bouncer.ico">
<Window.Resources>
<app:DateConverter x:Key="dateConverter"/>
</Window.Resources>
<Grid>
<ListView x:Name="listView" >
<ListView.ItemTemplate>
<DataTemplate>
<app:ProcessView />
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
</Grid>
</Window>
Related
I have a WPF User Control embedded in an application, which is inheriting the style of the application. I designed the User Control with the default WPF style in mind and it doesn't define its own resources/styles. However, as a result of inheriting the style of the host application, it doesn't look correct. I'd prefer if the User Control just used the default WPF style. Is there a simple way I can do this?
The UserControl itself consists of a System.Windows.Controls.Frame, which references a System.Windows.Control.Page:
<UserControl x:Class="OrderParcelAddInPrototype.WpfControls.Controls.OrderParcelControl"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d" d:DesignHeight="300" d:DesignWidth="450">
<Frame Source="/OrderParcelAddInPrototype.WpfControls;component/Pages/MainPage.xaml" />
</UserControl>
Neither the UserControl or the Page define their own styles.
<Page x:Class="OrderParcelAddInPrototype.WpfControls.Pages.StartPage"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d" d:DesignHeight="300" d:DesignWidth="450" Title="Main Page">
<ScrollViewer VerticalScrollBarVisibility="Auto">
<StackPanel VerticalAlignment="Top" MaxWidth="350" CanVerticallyScroll="True"
ScrollViewer.CanContentScroll="True">
<!-- Removed for brevity -->
</StackPanel>
</ScrollViewer>
</Page>
Define your usercontrol style inside usercontrol resources and apply that style in user control
<UserControl x:Class="MyNamespace.MyUserControl"
...
Style="{DynamicResource ResourceKey=MyUserControlStyle}">
<UserControl.Resources>
...
<Style x:Key="MyUserControlStyle" TargetType="{x:Type UserControl}">
</Style>
</UserControl.Resources>
otherwise, you can merge resource dictionary of your usercontrol by using
mergeddictionary in resource dictionary in app.xaml
I have wpf application with the following xaml as the mainwindow
<Window x:Class="Video_Editor.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525">
<Grid>
</Grid>
</Window>
I also have a class that inherits 'Control' called 'MyControl'.
How do I make it possible to put an instance of that MyControl inside the xaml.
Something like this
<Grid>
<MyControl/>
</Grid>
You need to setup the XAML namespace mapping:
<Window x:Class="Video_Editor.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:YourNamespaceContainingMyControl"
Title="MainWindow" Height="350" Width="525">
<Grid>
<local:MyControl />
</Grid>
</Window>
Note that, if the control is in a different assembly (DLL), you'll need to use xmlns:local="clr-namespace:YourNamespaceContainingMyControl;assembly=YourLibrary".
In my project, I have XAML file like this:
<Grid Margin="50,0,0,0">
//Huge amount of code goes here
</Grid>
It is very difficult to go through all the code in Grid while designing. Can I move all the code to a separate XAML file file and in in this Grid content i will call that XAML file??
<Grid Margin="50,0,0,0">
//call xaml file here
</Grid>
You should define a UserControl; assume the "Huge amount of code" is sth like this:
<Border Name="yourBorder">
//Other Xamls
</Border>
Now you create a new UserControl an put this Border in it
<UserControl x:Class="WpfApplication.UserControl1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300">
<Border Name="yourBorder">
//Other Xamls
</Border>
</UserControl>
You can use UserControl1 in other Xamls. You should add xmlns:wp="clr-namespace:WpfApplication" to your Xaml. For example if you want to use it in a Window:
<Window x:Class="WpfApplication.Window2"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:wp="clr-namespace:WpfApplicationUpper" //This is what I mentioned
Title="Window2" Height="300" Width="300">
<StackPanel>
<wp:UserControl1 /> // You call it using this format
</SatckPanel>
I am trying to create a extension from an existing view where I have a list of text controls and in the new project I would like to use this control and change one of these text boxes to a radio button.
Using MVVM makes it easy to use the same code without having duplicated code, but for the XAML view I find no good way to do this change without creating a copy.
Example:
Core project with the main user control
<UserControl x:Class="SilverlightApplication4.MainPage" Name="test"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="400">
<Grid x:Name="LayoutRoot" Background="White">
<StackPanel>
<TextBlock>
asdfasdf
this is a test
</TextBlock>
<Button Height="120" Name="asdf" Content="This is a Button">
</Button>
</StackPanel>
</Grid>
</UserControl>
Now I have a second project where I want to change the TextBlock to something else.
<UserControl x:Class="SilverlightApplication1.MainPage"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" mc:Ignorable="d"
xmlns:core="clr-namespace:SilverlightApplication4;assembly=SilverlightApplication4" d:DesignHeight="300" d:DesignWidth="400">
<core:MainPage>
<!-- how do i change the type of child elements?-->
</core:MainPage>
</UserControl>
Solution will be to use a ContentControl and bind it to a ViewModel through Caliburn.Micro.
I added an example and code to my other question (below the XAML section): Project structure for EF/Silverlight application
I'm trying to build a small MVVM test application, but can't really figure how to display my user control in the MainWindow.
My Solution Explorer:
I got a resource dictionary:
<ResourceDictionary
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:vm="clr-namespace:MVVM.ViewModel"
xmlns:vw="clr-namespace:MVVM.View">
<DataTemplate DataType="{x:Type vm:ViewModel}">
<vw:View />
</DataTemplate>
</ResourceDictionary>
I got my view:
<UserControl x:Class="MVVM.View.View"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="300">
<UserControl.Resources>
<DataTemplate x:Key="PersonTemplate">
<StackPanel>
<TextBlock Text="{Binding FirstName}" />
</StackPanel>
</DataTemplate>
</UserControl.Resources>
<ListBox ItemsSource="{Binding Path=Persons}"
ItemTemplate="{StaticResource PersonTemplate}" />
</UserControl>
and My MainWindow
<Window x:Class="MVVM.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:vm="clr-namespace:MVVM.ViewModel"
Title="MainWindow" Height="350" Width="525">
<Window.Resources>
<ResourceDictionary Source="MainWindowResources.xaml" />
</Window.Resources>
<Grid>
</Grid>
</Window>
The most obvious and easiest way is to add the ContentControl element:
<Grid>
<ContentControl x:Name="mainContentControl" />
</Grid>
And after that set the Content property of this control to your view model, and the corresponding view will be loaded and applied automatically:
this.mainContentControl.Content = new ViewModel.ViewModel();
But I would prefer to use another way without datatemplates:
<Grid>
<vw:View x:Name="mainView"/>
</Grid>
this.mainView.DataContext = new ViewModel.ViewModel();
Build your VS2010 solution, then, go to your MainWindow's XAML.
On the left, there is a toolbar with button "Toolbox"
Open it, it contains all the possible WPF controls you could add to your UI
Your UserControl should appear on top of the list (in a category probably named "MVVM Controls"), just drag&drop it to your UI :)