Best method to check between 2 dates to see if they are within exactly 3 months of each other using T-SQL.
For example if I had these 2 dates below I want to check if #Date1 is within 3 months of #Date2 and vice versa.
DECLARE #Date1 DATETIME = '2019-01-15 00:00:00.000'
DECLARE #Date2 DATETIME = '2018-10-23 00:00:00.000'
Here is the simple statement:
SELECT abs(DATEDIFF(month, #date1, #date2)) <= 3
You may try this.
DECLARE #Date1 DATETIME = '2019-01-15 00:00:00.000'
DECLARE #Date2 DATETIME = '2018-10-23 00:00:00.000'
SELECT dateadd(MONTH, 3,#Date1 ) >= #Date2
You may try
DECLARE #Date1 DATETIME = '2019-01-15 00:00:00.000'
DECLARE #Date2 DATETIME = '2018-10-23 00:00:00.000'
SELECT CASE WHEN ABS(DATEDIFF(DAY, #date1, #date2)) <= 90 THEN 'Inside 3 Months'
ELSE 'Outside 3 months' END
Related
In SQL Server, I want to get days from date to date. Example: from 2015/12/28 to 2016/01/02, the result as
2015/12/28
2015/12/29
2015/12/30
2015/12/31
2016/01/01
2016/01/02
DECLARE #STARTDATE DATETIME = '2015-12-28'
DECLARE #ENDDATE DATETIME = '2016-01-02'
SELECT BETWEEN #STARTDATE AND #ENDDATE AS DAYS
Use CTE
DECLARE #STARTDATE DATE = '2015-12-28'
DECLARE #ENDDATE DATE = '2016-01-02'
;WITH CTE AS
(
SELECT #STARTDATE As dt
UNION ALL
SELECT DATEADD(D,1,dt) AS dt
FROM CTE
WHERE dt < #ENDDATE
)
SELECT * FROM CTE
You could build a calendar table, which would probably come in handy down the road. Or you could use a loop.
DECLARE #ENDDATE DATETIME = '2016-01-02'
DECLARE #DAY DATETIME = '2015-12-28'
WHILE #Day <= #ENDDATE
BEGIN
SELECT #DAY
SET #DAY = DATEADD(DD,1,#DAY)
END
Or for all of the days in one result set:
DECLARE #ENDDATE DATETIME = '2016-01-02'
DECLARE #DAY DATETIME = '2015-12-28'
DECLARE #TABLE TABLE (DATE DATETIME)
WHILE #Day <= #ENDDATE
BEGIN
INSERT #TABLE
VALUES (#DAY)
SET #DAY = DATEADD(DD,1,#DAY)
END
SELECT *
FROM #TABLE
You can specify the dates in your WHERE clause. For example, WHERE date >=#STARTDATE AND date <=#ENDDATE. That should return the full date in your results.
using Numbers table
select dateadd(day,n,startdate)
from numbers
where dateadd(day,n,startdate)<=enddate
order by n
How can I list all dates between two date parameters in SQL Server, without creating a stored procedure, calendar table or recursive function?
There's always the recursive CTE option:
DECLARE #STARTDATE DATETIME
DECLARE #ENDDATE DATETIME
SET #STARTDATE = '2015-01-01'
SET #ENDDATE = '2015-12-31'
;WITH DATE_RANGE (DATES) AS (
SELECT DATEADD(DAY, DATEDIFF(DAY, 0, #STARTDATE), 0)
UNION ALL SELECT DATEADD(DAY, 1, DATES)
FROM DATE_RANGE
WHERE DATEADD(DAY, 1, DATES) <= #ENDDATE)
SELECT DATES
FROM DATE_RANGE
OPTION (MAXRECURSION 0)
Be sure to use the MAXRECURSION option, or your results will be limited to 100 as default.
This uses Row_Number on the spt_values table in Master database to create a list of years, months and dates within the date range.
This is then built into a datetime field, and filtered to only return dates within the date parameters entered.
Very quick to execute and returns 500 years worth of dates (182987 days) in less than 1 second.
Declare #DateFrom datetime = '2000-01-01'
declare #DateTo datetime = '2500-12-31'
Select
*
From
(Select
CAST(CAST(years.Year AS varchar) + '-' + CAST(Months.Month AS varchar) + '-' + CAST(Days.Day AS varchar) AS DATETIME) as Date
From
(select row_number() over(order by number) as Year from master.dbo.spt_values) as Years
join (select row_number() over(order by number) as Month from master.dbo.spt_values) as Months on 1 = 1
join (select row_number() over(order by number) as Day from master.dbo.spt_values) as Days on 1 = 1
Where
Years.Year between datepart(year,#DateFrom) and datepart(year,#DateTo)
and Months.Month between 1 and 12
and
Days.Day between 1 and datepart(day,dateadd(day,-1,dateadd(month,1,(CAST(CAST(Years.Year AS varchar)+'-' + CAST(Months.Month AS varchar) + '-01' AS DATETIME)))))
) as Dates
Where Dates.Date between #DateFrom and #DateTo
order by 1
Following will be a solution for YOU
DECLARE #DATE1 DATE
DECLARE #DATE2 DATE
SET #DATE1 ='20020101'
SET #DATE2 = '20020311'
SELECT #DATE1 as t
into #FromDate
DECLARE cur CURSOR FOR
SELECT t FROM #FromDate
OPEN cur
FETCH NEXT FROM cur INTO #DATE1
WHILE(##FETCH_STATUS=0)
BEGIN
IF(#DATE1<=#DATE2)
INSERT INTO #FromDate
VALUES(DATEADD(DAY,1,#DATE1))
FETCH NEXT FROM cur INTO #DATE1
END
CLOSE cur
DEALLOCATE cur;
SELECT t FROM #FromDate;
DROP TABLE #FromDate;
Simple result.
DECLARE #DATE1 DATE
DECLARE #DATE2 DATE
SET #DATE1 ='20020101'
SET #DATE2 = '20020311'
WHILE(#DATE1<=#DATE2)
Begin
PRINT #DATE1
set #DATE1 = DATEADD(dd,1,#DATE1)
END
I need to display dates of all Mondays in the given date range.
For example, if my start date is 01/05/2015 and end date is 31/05/2015, I need to show
04/05/2015
11/05/2015
18/05/2015
25/05/2015
How is it possible?
This procedure is independent from regions and languages.
Please note the first line with SET DATEFIRST 1.
SET DATEFIRST 1; -- First day of the week is set to monday
DECLARE #DateFrom DateTime ='20150601', #DateTo DateTime = '20150630' ;
WITH CTE(dt)
AS
(
SELECT #DateFrom
UNION ALL
SELECT DATEADD(d, 1, dt) FROM CTE
WHERE dt < #DateTo
)
SELECT dt FROM CTE where datepart ("dw", dt) = 1;
Using a CTE it is possible this way..
DECLARE #DateFrom DateTime ='2015-05-01',
#DateTo DateTime = '2015-05-31'
;WITH CTE(dt)
AS
(
SELECT #DateFrom
UNION ALL
SELECT DATEADD(d, 1, dt) FROM CTE
WHERE dt < #DateTo
)
SELECT 'Monday', dt FROM CTE
WHERE DATENAME(dw, dt) In ('Monday')
Refer: Select dates of a day between two dates.
SELECT [Day],[Dt] FROM dbo.fnGetDatesforAday('7/1/2008','8/31/2008','Sunday')
CREATE FUNCTION fnGetDatesforAday
(
-- Add the parameters for the function here
#DtFrom DATETIME,
#DtTo DATETIME,
#DayName VARCHAR(12)
)
RETURNS #DateList TABLE ([Day] varchar(20),Dt datetime)
AS
BEGIN
IF NOT (#DayName = 'Monday' OR #DayName = 'Sunday' OR #DayName = 'Tuesday' OR #DayName = 'Wednesday' OR #DayName = 'Thursday' OR #DayName = 'Friday' OR #DayName = 'Saturday')
BEGIN
--Error Insert the error message and return
INSERT INTO #DateList
SELECT 'Invalid Day',NULL AS DAT
RETURN
END
DECLARE #TotDays INT
DECLARE #CNT INT
SET #TotDays = DATEDIFF(DD,#DTFROM,#DTTO)-- [NO OF DAYS between two dates]
SET #CNT = 0
WHILE #TotDays >= #CNT -- repeat for all days
BEGIN
-- Pick each single day and check for the day needed
IF DATENAME(DW, (#DTTO - #CNT)) = #DAYNAME
BEGIN
INSERT INTO #DateList
SELECT #DAYNAME,(#DTTO - #CNT) AS DAT
END
SET #CNT = #CNT + 1
END
RETURN
END
SET DATEFIRST 7; -- Set's sunday as first day of week, won't work otherwise
DECLARE #StartDate DATE = '06/01/2015'
DECLARE #EndDate DATETIME = '06/30/2015'
DECLARE #TableOfDates TABLE(DateValue DATETIME)
DECLARE #CurrentDate DATETIME
SET #CurrentDate = #startDate
WHILE #CurrentDate <= #endDate
BEGIN
INSERT INTO #TableOfDates(DateValue) VALUES (#CurrentDate)
SET #CurrentDate = DATEADD(DAY, 1, #CurrentDate)
END
SELECT * FROM #TableOfDates WHERE DATEPART(weekday,Datevalue) = 2
Is it possible to add all the dates between 1st Jan-31-Dec in MS Sql server using query?
If someone has done it before please guide me to right track.
Thanks
DECLARE #dt Date
SET #dt = '2015-01-01'
WHILE #dt < '2016-01-01'
BEGIN
SELECT #dt
--INSERT .....
SET #dt = DATEADD(DAY, 1, #dt)
END
Of course it depends on your table structure
using loop we can achieve this
Declare #date table(d datetime)
Declare #d datetime, #d1 datetime, #d2 datetime
Declare #inc INT
set #d1='20150101'
set #d2='20151231'
Set #inc = DATEDIFF(D, #d1, #d2)
Set #d = #d1
While #d<=#d2
Begin
Insert into #date values (#d)
set #d=#d+1
End
Select d as DateCol from #date
This should do the trick:
DECLARE #year int = 2015
;WITH N(N)AS
(SELECT 1 FROM(VALUES(1),(1),(1),(1),(1),(1),(1),(1),(1),(1))M(N)),
tally(N)AS(SELECT ROW_NUMBER()OVER(ORDER BY N.N)-1 FROM N,N a,N b,N c,N d,N e,N f)
SELECT top (datediff(d, cast(#year as char(4)), cast(#year + 1 as char(4))))
CAST(DATEADD(d, N, cast(#year as char(4))) as date)
FROM tally
Result:
2015-01-01
2015-01-02
..
..
2015-12-31
I am trying to get the date difference in a given date excluding the week days.
Here is what I have:
SELECT DATEADD (w, -4, GETDATE())
This returns 2013-05-04 19:01:53.170, which means that it also counts weekends.
Same for
SELECT DATEADD (dw, -4, GETDATE())
Any help will be appreciated.
Thanks in advance.
I'm using these functions that return the non-weekend seconds between two dates:
CREATE FUNCTION [dbo].[DateDiff_NoWeekends](
#date1 DATETIME,
#date2 DATETIME
)
RETURNS INT AS BEGIN
DECLARE #retValue INT
SET #date1 = dbo.__CorrectDate(#date1, 1)
SET #date2 = dbo.__CorrectDate(#date2, 0)
IF (#date1 >= #date2)
SET #retValue = 0
ELSE BEGIN
DECLARE #days INT, #weekday INT
SET #days = DATEDIFF(d, #date1, #date2)
SET #weekday = DATEPART(dw, #date1) - 1
SET #retValue = DATEDIFF(s, #date1, #date2) - 2 * 24 * 3600 * ((#days + #weekday) / 7)
END
RETURN #retValue
END
GO
CREATE FUNCTION [dbo].[__CorrectDate](
#date DATETIME,
#forward INT
)
RETURNS DATETIME AS BEGIN
IF (DATEPART(dw, #date) > 5) BEGIN
IF (#forward = 1) BEGIN
SET #date = #date + (8 - DATEPART(dw, #date))
SET #date = DateAdd(Hour, (8 - DatePart(Hour, #date)), #date)
END ELSE BEGIN
SET #date = #date - (DATEPART(dw, #date)- 5)
SET #date = DateAdd(Hour, (18 - DatePart(Hour, #date)), #date)
END
SET #date = DateAdd(Minute, -DatePart(Minute, #date), #date)
SET #date = DateAdd(Second, -DatePart(Second, #date), #date)
END
RETURN #date
END
Here's a sql-fiddle demo for all non-weekend days in april (22).
SELECT [no weekend days in april] =
(dbo.DateDiff_NoWeekends('2013-04-01','2013-05-01')
/ 3600 / 24)
The query below gives the difference for week days alone , Ie counts the no od days between two days and subtracts the no of weekend days ,
DECLARE #StartDate DATETIME,
#EndDate DATETIME
SELECT #StartDate = '01-July-2008',
#EndDate = '30-July-2008'
;WITH DATE (Date1)
AS (
SELECT DATEADD(DAY, DATEDIFF(DAY, '19000101', #StartDate), '19000101')
UNION ALL
SELECT DATEADD(DAY, 1, Date1)
FROM DATE
WHERE Date1 < #EndDate
)
SELECT count(*) -
(
SELECT count(*)
--CONVERT(VARCHAR(15),d1.DATE1 ,110) as [Working Date],
--DATENAME(weekday, d1.Date1) [Working Day]
from DATE d1 where (DATENAME(weekday, d1.Date1)) in ('Saturday','Sunday')
)
--CONVERT(VARCHAR(15),d1.DATE1 ,110) as [Working Date],
--DATENAME(weekday, d1.Date1) [Working Day]
from DATE d1 where (DATENAME(weekday, d1.Date1)) not in ('Saturday','Sunday')
please let me know for any clarifications
Maybe I am still missing some full testing, but this works for me too: take the difference in days and then subtract 2 days for each weekend
DateDiff(d, d1, d2) - 2*DateDiff(wk, d1, d2)
Could be put in a function as well