Need help to PIVOT/UNPIVOT some data in SQL - sql-server

I am having some difficulty trying to achieve some data in MSSQL. Here what I have:
SO_ID | SO_DATE | WAGE_A | WAGE_B | WAGE_B_DUR |
1 | 12/12/06| 100 | 200 | 15 |
2 | 10/10/06| 150 | 250 | 10 |
What I want :
SO_ID | SO_DATE | WAGE_TYPE | AMOUNT | DURATION |
1 | 12/12/06| WAGE_A | 100 | NULL |
1 | 12/12/06| WAGE_B | 200 | 15 |
2 | 10/10/06| WAGE_B | 250 | 10 |
2 | 10/10/06| WAGE_A | 150 | NULL |
I really appreciate it if you could give me some help or advice (including change the first table).

Try as:
CREATE TABLE try_val(SO_ID int, SO_DATE int, WAGE_A int, WAGE_B int, WAGE_B_DUR int)
insert into try_val values (1 , 12/12/06, 100 , 200 , 15 )
insert into try_val values (2 , 10/10/06, 150 , 250 , 10 )
select SO_ID,SO_DATE,'WAGE_A' AS WAGE_TYPE,WAGE_A AS AMOUNT,NULL AS DURATION from try_val
UNION ALL
select SO_ID,SO_DATE,'WAGE_B' AS WAGE_TYPE,WAGE_A AS AMOUNT,WAGE_B_DUR AS DURATION from try_val
ORDER BY SO_ID

You can use a simple SELECT with UNION ALL as follows
select
SO_ID,
SO_DATE,
WAGE_TYPE = 'WAGE_A',
AMOUNT = WAGE_A,
DURATION = WAGE_B_DUR
from myData
union all
select
SO_ID,
SO_DATE,
WAGE_TYPE = 'WAGE_B',
AMOUNT = WAGE_B,
DURATION = WAGE_B_DUR
from myData
order by SO_ID

Related

T-SQL Limited Cross Join

I want to join 2 tables such that I get the NAR for every combination of Type and BillingID where it exists.
Where a BillingID doesn't have a certain Type, then either NULL or 0 is returned for the NAR along with the Type and BillingID.
Is something like this even possible using SQL?
A simplified version of my data is shown below:
Type list:
+----------+
| Type |
+----------+
| NEW |
| CHNG |
| LAP |
+----------+
Data:
+----------+-----------+-----+
| Type | BillingID | NAR |
+----------+-----------+-----+
| NEW | ABC | 5 |
| CHNG | ABC | 15 |
| LAP | ABC | 10 |
| CHNG | DEF | 20 |
+----------+-----------+-----+
Desired result:
+----------+-----------+-----+
| Type | BillingID | NAR |
+----------+-----------+-----+
| NEW | ABC | 5 |
| CHNG | ABC | 15 |
| LAP | ABC | 10 |
| CHNG | DEF | 20 |
| NEW | DEF | 0 |
| LAP | DEF | 0 |
+----------+-----------+-----+
The last 2 rows are what is causing me problems.
I think you can do it like this:
declare #table table (type1 varchar(5))
insert into #table
values
('new'),
('chng'),
('lap')
declare #table2 table (typeid varchar(5),billingid varchar(5),nar int)
insert into #table2
values
( 'NEW', 'ABC', 5 ),
( 'CHNG' , 'ABC', 15 ),
( 'LAP' , 'ABC', 10 ),
( 'CHNG' , 'DEF', 20 )
select Z.*,case when c.nar IS null then 0 else c.nar end as nar from (
select * from #table a
outer apply (select distinct billingid from #table2 b ) p
)Z
left join #table2 c on Z.type1 = c.typeid and Z.billingid = c.billingid
order by billingid
Result

SQL Server query for next row value where previous row value

This query gives me Event values from 1 to 20 within an hour, how to add to that if a consecutive Event value is >=200 as well?
SELECT ID, count(Event) as numberoftimes
FROM table_name
WHERE Event >=1 and Event <=20
GROUP BY ID, DATEPART(HH, AtHour)
HAVING DATEPART(HH, AtHour) <= 1
ORDER BY ID desc
In this dummy 24h table:
+----+-------+--------+
| ID | Event | AtHour |
+----+-------+--------+
| 1 | 1 | 11:00 |
| 1 | 4 | 11:01 |
| 1 | 1 | 11:02 |
| 1 | 20 | 11:03 |
| 1 | 200 | 11:04 |
| 1 | 1 | 13:00 |
| 1 | 1 | 13:05 |
| 1 | 2 | 13:06 |
| 1 | 500 | 13:07 |
| 1 | 39 | 13:10 |
| 1 | 50 | 13:11 |
| 1 | 2 | 13:12 |
+----+-------+--------+
I would like to select IDs with Event with values with range between 1 and 20 followed immediately by value greater than or equal to 200 within an hour.
Expected result should be something like that:
+----+--------+
| ID | AtHour |
+----+--------+
| 1 | 11 |
| 1 | 13 |
| 2 | 11 |
| 2 | 14 |
| 3 | 09 |
| 3 | 12 |
+----+--------+
or just how many times it has happened for unique ID instead of which hour.
Please excuse me I am still rusty with post formatting!
CREATE TABLE data (Id INT, Event INT, AtHour SMALLDATETIME);
INSERT data (Id, Event, AtHour) VALUES
(1,1,'2017-03-16 11:00:00'),
(1,4,'2017-03-16 11:01:00'),
(1,1,'2017-03-16 11:02:00'),
(1,20,'2017-03-16 11:03:00'),
(1,200,'2017-03-16 11:04:00'),
(1,1,'2017-03-16 13:00:00'),
(1,1,'2017-03-16 13:05:00'),
(1,2,'2017-03-16 13:06:00'),
(1,500,'2017-03-16 13:07:00'),
(1,39,'2017-03-16 13:10:00')
;
; WITH temp as (
SELECT rownum = ROW_NUMBER() OVER (PARTITION BY id ORDER BY AtHour)
, *
FROM data
)
SELECT a.id, DATEPART(HOUR, a.AtHour) as AtHour, COUNT(*) AS NumOfPairs
FROM temp a JOIN temp b ON a.rownum = b.rownum-1
WHERE a.Event BETWEEN 1 and 20 AND b.Event >= 200
AND DATEDIFF(MINUTE, a.AtHour, b.AtHour) <= 60
GROUP BY a.id, DATEPART(HOUR, a.AtHour)
;

Sql query to check if a certain value appears more than once in rows

I have table with 5 columns like this
+----+-------------------------+-----------+--------+-----------+
| Id | CreateDate | CompanyId | UserId | IsEnabled |
+----+-------------------------+-----------+--------+-----------+
| 1 | 2016-01-02 23:40:46.517 | 1 | 1 | 1 |
| 2 | 2016-01-16 00:07:59.857 | 1 | 2 | 1 |
| 3 | 2016-01-25 15:17:54.420 | 3 | 3 | 1 |
| 25 | 2016-03-07 16:48:39.260 | 24 | 10 | 0 |
| 26 | 2016-03-07 16:48:39.263 | 25 | 2 | 0 |
+----+-------------------------+-----------+--------+-----------+
(thanks http://www.sensefulsolutions.com/2010/10/format-text-as-table.html for ASCII table!)
I'm trying to check if a UserId is recorded for more than one CompanyId's.
So far I managed to check if a UserId happens to appear more than one by using this query
WITH T AS
(
SELECT * ,
Count(*) OVER (PARTITION BY UserId) as Cnt
From CompanyUser
)
select Distinct UserId
FROM T
Where Cnt >1
It returns 2 correctly.
Where I'm stuck is, how can I parameterize the UserId and check if an Id is recorded for more than one company.
Declare #UserID as bigint
Set #UserID = 2
select Distinct Count(CompanyID)
FROM ComapynUser
Where UserId = #UserId
I think this gives you what you need.

Group by on columns with repeated data

In the SQL Server I have a table with repeated data in few columns and NULL values in few other columns some thing similar show as below.
DirName | BillingNPI | Average | TotalClaims | MaxString | MinString | CorrectString
------------------------------------------------------------------------------------
AASTA | 158967 | 10 | 20 | NULL | NULL | Value
AASTA | 158967 | 10 | 20 | NULL | ValueSTA | Value
AASTA | 158967 | 10 | 20 | STAValue | NULL | Value
Now using GROUP BY I'm trying the output of my query to be
DirName | BillingNPI | Average | TotalClaims | MaxString | MinString | CorrectString
------------------------------------------------------------------------------------
AASTA | 158967 | 10 | 20 | STAValue | ValueSTA | Value
Do I have to use inner join on the same table to achieve this ?
Does this get what you need?
select
DirName ,
BillingNPI ,
Average ,
TotalClaims ,
max(isnull(MaxString,'') maxstring,
max(isnull(MinString,'') minstring,
CorrectString
group by
DirName ,
BillingNPI ,
Average ,
TotalClaims ,
CorrectString

Finding the max and min date values in SQL Server tables

I have two tables:
A lookup table (tabOne):
KEY | Group | Name | Desc | Val_Key
----------------------------------------
1 | a | NameA | DescA | 10
2 | b | NameB | DescB | 20
3 | c | NameC | DescC | 30
4 | d | NameD | DescD | 40
5 | e | NameE | DescE | 50
6 | f | NameF | DescF | 60
A second table containing readings (tabTwo):
KEY | Date | Reading | Val_Key
----------------------------------------
1 | Date | Read | 10
2 | Date | Read | 20
3 | Date | Read | 40
4 | Date | Read | 40
5 | Date | Read | 30
6 | Date | Read | 20
7 | Date | Read | 40
8 | Date | Read | 20
9 | Date | Read | 10
10 | Date | Read | 20
11 | Date | Read | 50
12 | Date | Read | 60
What I need to do is join tabTwo with TabOne and create a column with the newest Reading and a column with the oldest reading for each item in the group column of TabOne.
At the end of the day I want a table that look as follow:
KEY | Group | Name | Desc | Val_Key | LastReading | FirstReading |
-------------------------------------------------------------------------
1 | a | NameA | DescA | 10 | | |
2 | b | NameB | DescB | 20 | | |
3 | c | NameC | DescC | 30 | | |
4 | d | NameD | DescD | 40 | | |
5 | e | NameE | DescE | 50 | | |
6 | f | NameF | DescF | 60 | | |
Thanks!
Freddie
If this is Sql Server 2005 or newer, outer apply will help:
select TabOne.*,
last.Reading LastReading,
first.Reading FirstReading
from TabOne
outer apply
(
select top 1
Reading
from TabTwo
where TabTwo.Val_Key = TabOne.val_Key
order by TabTwo.Date desc
) last
outer apply
(
select top 1
Reading
from TabTwo
where TabTwo.Val_Key = TabOne.val_Key
order by TabTwo.Date asc
) first
Live test is # Sql Fiddle.
#Nikola Markovinović's solution can be made more universally applicable if the subqueries are moved directly to the main query's SELECT clause, which is possible each of them retrieves only one value and is, therefore, valid as a scalar expression:
SELECT
t1.[KEY],
t1.[Group],
t1.Name,
t1.[Desc],
t1.Val_Key,
(
SELECT TOP 1 Reading
FROM TabTwo
WHERE Val_Key = t1.Val_Key
ORDER BY Date DESC
) AS LastReading,
(
SELECT TOP 1 Reading
FROM TabTwo
WHERE Val_Key = t1.Val_Key
ORDER BY Date ASC
) AS FirstReading
FROM TabOne t1
If you needed e.g. dates along the way, you would probably have to stick to Nikola's solution. There is an alternative to it, but it's more cumbersome (albeit more standard too): it would involve grouping TabTwo's data by Val_Key to get earliest/latest dates per Val_Key, then joining back to TabTwo to access entire rows corresponding to the found dates to finally pull the necessary columns, and ultimately joining both result sets to TabOne to get the final column set.

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