Program to print N first factorial numbers in c - c

Question

Factorial number is a number that is multiplied by it's previous numbers. For example it's 5. 1*2*3*4*5 is it's factorial number.
I already made a program which prints factorial of any number, but i don't know how to make it to print N first factorial number in c.
For example i type 10. It must show first 10 numbers along with their factorials (Making a table)
Here is what i was made to print factorial of any number.Is there any possibility to do with while/ if else statements/ and for loop?
#include <stdio.h>
int main()
{
int i, n, fakt = 1;
printf("Enter a number:\n");
scanf("%d", &n);
for (i = 1; i <= n; i++)
fakt = fakt*i;
printf("Factorial of %d js %d\n", n, fakt);
getch();
}

Answer 1

You probably want this:
Program:
#include <stdio.h>
int main()
{
int i, n, fakt = 1;
printf("Enter a number:\n");
scanf("%d", &n);
for (i=1;i<= n;i++) //use braces to write more than one statement inside the loop
{
fakt=fakt*i;
printf("Factorial of %d is %d\n", i, fakt);
}
getch();
}
Output:
Enter a number:
5
Factorial of 1 is 1
Factorial of 2 is 2
Factorial of 3 is 6
Factorial of 4 is 24
Factorial of 5 is 120

Answer 2

#include <conio.h>
#include <stdio.h>
void main()
{
int f=1,i,v;
clrscr();
printf("Enter the number :");
scanf("%d",&v);
for(i=1;i<=v;i++)
{
f=f*i;
printf("num =%d and fac=%d\n",i,f);
}
getch();
}
this code will work

Answer 3

That code already uses the for loop. The while loop equivalent is:
i = 1;
while (i <= n) {
fakt = fakt*i;
i++;
}

Answer 4

#include <stdio.h>
int factorial(int n)
{
int i,fakt = 1;
printf("Enter a number:\n");
scanf("%d", &n);
for (i = 1; i <= n; i++)
fakt = fakt*i;
return fakt;
}
int main()
{
int n;
printf("Enter a number:\n");
scanf("%d", &n);
int i = 0;
for(i=1;i<=n;i++)
{
printf("Factorial for %d is %d\n",i,factorial(i));
}
return 0;
}
I think this will do the job just fine.

Answer 5

You can do a nested loop.
Run the parent loop from 1 to n,
and the nested loop will be your already working for loop.
You may want this:
#include <stdio.h>
int main()
{
int n, i, num, factorial;
printf("Enter the number of terms: ");
scanf("%d", &n);
for(i = 1; i <= n; i++)
{
num = i;
factorial = 1;
while(num)
factorial *= num--;
printf("%d \t %d\n", i, factorial);
}
return 0;
}
Output:
Enter the number of terms: 10
1 1
2 2
3 6
4 24
5 120
6 720
7 5040
8 40320
9 362880
10 3628800

Answer 6

Use this fastest version of factorial using recursion with if ..else statement
#include<stdio.h>
int fact(int n);
void main()
{
int n;
printf("\nEnter an integer:");
scanf("%d",&n);
fact(n);
}
int fact(int n)
{
int a;
if(n==0)
{
printf("The Factorial of 0 is 1\n");
return 1;
}
else
{
a=n*fact(n-1);
printf("The Factorial of %d is %d\n",n,a);
return a;
}
}

Answer 7

#include<stdio.h>
int main(int n){
int fact;
clrscr();
printf("Enter a number and type exit:\n");
scanf("%d",&n);
if(n!=0){
fact=n*main(n-1);
printf("Factorial of %d is %d\n",n,fact);
getch();
return fact;
}
else{
printf("Factorial of 0 is 1.\n");
getch();
return 1;
}
}