Finding min and max between several integers - c

Question

Seeing the solution to this online on Stackoverflow https://stackoverflow.com/a/19200031/3185410 I tried to come up with another solution by setting max to -infinity and min to +infinity.
The code here by #haccks works pretty fine.
#include <stdio.h>
int main()
{
int num, max, min;
printf ("Enter four numbers: ");
scanf ("%d", &num);
max = min = num;
for (int i = 0; i < 3; i++)
{
scanf ("%d", &num);
if (max < num)
max = num;
else if (min > num)
min = num;
}
printf ("\n%d %d", max, min);
return 0;
}
Here's the one I came up with:
#include <stdio.h>
#include <limits.h>
void main()
{
int max,min,num,i;
min=INT_MAX;
max=INT_MIN;
for (i=0;i<=3;)
{
i++;
printf("Enter number %d : ",i);
scanf("%d",&num);
if (num>max) max=num;
else if (num<min) min=num;
}
printf("max is %d and min is %d",max,min);
}
What am I doing wrong with that?

Answer 1

If the users input 5 then 6 you have :
for 5 :
5>-inf => max = 5
for 6 :
6>5 => max = 6
but then min has become 5 and yet it is still INT_MAX.
If you put if instead of else if, you loose in performance but have the right output I think (I cannot test right now).

Answer 2

Set first input as min and max value. And then add logic you wrote. Here you had 2 lines of extra code but you don't have to sacrifice performance.
#include <stdio.h>
#include <limits.h>
void main()
{
int max,min,num,i=0;
min=INT_MAX;
max=INT_MIN;
printf("Enter number %d : ",i+1);
scanf("%d",&num);
min=num;
max=num;
for (i=1;i<=3;)
{
i++;
printf("Enter number %d : ",i);
scanf("%d",&num);
if (num>max) max=num;
else if (num<min) min=num;
}
printf("max is %d and min is %d",max,min);
}