How to determine whether a group is security group? - active-directory

I need to check whether a group given by name is a security group in AD using C# code.
I notice there's a property named "groupType" in groups properties, but I don't know what this property is used for. I checked several groups and find its value can be null, 8 or -2147483646. Is it associated with the security group type?
I also find in the distinguishedName of the group, there can be "OU=Security Group" or "OU=Secuity Group with Mail Lists" blabla. Can it be a criteria to determine security group type?
Thanks in advance.

From http://adsearch-winzero.blogspot.com/2006/04/object-group-attribute-grouptype.html
The groupType attribute returns the type of group. However the returned value is in RAW format.
...
-2147483646 ~ Global Security Group
-2147483644 ~ Local Security Group
-2147483643 ~ BuiltIn Group
-2147483640 ~ Universal Security Group
2 ~ Global Distribution Group
4 ~ Local Distribution Group
8 ~ Universal Distribution Group

You can use "Security Group" as a query condition. But it's not so trustful based on how your company set up it. It's better to have a OU entry for all security groups and use that entry directly.

With all due to respect to Matt, the better answer should come from Microsoft:
https://msdn.microsoft.com/en-us/library/ms675935(v=vs.85).aspx
The values are the same, but should still come from the creator. The * security group is derived from adding the security group value of -2147483648 to the * distribution group value.
https://blogs.technet.microsoft.com/heyscriptingguy/2004/12/21/how-can-i-tell-whether-a-group-is-a-security-group-or-a-distribution-group/

Related

LDAP query for Window AD

For authentication in Jitsi Meet, we would like to read out a Windows AD group with an ldap query. Unfortunately our ldap query does not work.
LDAP_URL=ldaps://server.domain.local:636/
LDAP_BASE=DC=domain,DC=local
LDAP_BINDDN=CN=bind_user,OU=Administrative Accounts,OU=Benutzer,DC=domain,DC=local
LDAP_BINDPW=*
LDAP_FILTER= (&(|objectclass=user))(|(memberof=CN=group,OU=Jitsi,OU=Sicherheit,OU=Gruppen,DC=domain,DC=local)
(primaryGroupID=4989))
The error must be due to the filter, it works with the filter LDAP_FILTER = (sAMAccountName =% u).
Can you tell me what is wrong with our query.
A few things stand out to me:
The | in front of objectClass should not be there.
You have two closing parentheses after the objectClass condition, but the second one should be moved to the end of the whole query.
Oddly, objectClass=user will actually end up including other objects than just user accounts (like computer accounts). If you want to filter to only user objects, you have to use both (objectClass=user)(objectCategory=person). But that would only matter if you have other types of objects as members of that group.
Maybe this is just an error with pasting into the question, but there is a line break before (primaryGroupID=
I've never used Jitsi, but it may or may not like the space after LDAP_FILTER=. The other examples I see online don't show a space there.
It should look like this:
LDAP_FILTER=(&(objectclass=user)(objectCategory=person)(|(memberof=CN=group,OU=Jitsi,OU=Sicherheit,OU=Gruppen,DC=domain,DC=local)(primaryGroupID=4989)))
That means: find all user objects that are either members of that group, or have a primary group ID of 4989.

Display all nested groups members of a specific group using LDAP?

I am looking for an LDAP query that would return all groups that are members of a certain LDAP/AD group, including all children.
Imagine this tree: A, A.1, A.2, A.1.1
I want to query A and get: 3 results: A.1, A.2, A.1.1
From my initial research it seems that is related to LDAP_MATCHING_RULE_IN_CHAIN from http://msdn.microsoft.com/en-us/library/aa746475%28VS.85%29.aspx but I wasn't able to figure out the proper syntax for performing the query.
Note: this is a Microsoft Active Directory so the solution doesn't have to be generic.
Not sure from your explanation what you are trying to accomplish, but One of these should work:
Resolves all members (including nested) security groups (requires at least Windows 2003 SP2)#
(memberOf:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=YOURDOMAIN,DC=NET)
Or to retrieve only users:
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=YOURDOMAIN,DC=NET)
-jim

LDAP nested group filter for microsoft AD

I would like to write a search filter which would help me retrieve all groups which a user is part of.
For instance:
Say I am retrieving entries for user A (which is part of group A). And group A may be part of group B and group D which in turn may be part of group E.
Now, my search filter should return me MemberOf attribute as all possible groups which user A is part of (in this specific case it is Group A, B, D, E).
Any pointers on how the search filter can look like?
This should do what you are asking about. It will return the FDN of each group the user is a memberOf, however, this queries the group, not the user.
As an example, to find all the groups that "CN=John Smith,DC=MyDomain,DC=NET" is a member of, set the base to the groups container DN; for example (OU=groupsOU,DC=MyDomain,DC=NET) and the scope to subtree, and use the following filter.
(member:1.2.840.113556.1.4.1941:=(CN=John Smith,DC=MyDomain,DC=NET))
-jim
There is an attribute called tokenGroups in user object. It's a constructed attributes calculated by Active Directory on the runtime. It includes all the groups the user object belong to.
Make sure your domain has a Global Catalog and make sure the account that you are using Pre-Windows 2000 Compatible Access group. Then, make sure tokenGroups is specified as one of the returned property. Do a base scope search on the user object.
You can use adfind.exe (joeware) to sort out this issue and to utilize standard ldap filters that are described here. For example:
http://social.technet.microsoft.com/wiki/contents/articles/5392.active-directory-ldap-syntax-filters.aspx
Group nesting is specified to be like this:
(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)
and if you use adfind, then it would look like this:
adfind -f "(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)" samaccountname -list
If you want to have output other than samaccountname, for example displayname, or mail attribute, just add to the list. Also if you want to search multiple users, then you might want to have inputfile containing all users and some script to extract each lines to adfind for example.

How to get the nested groups in LDAP/AD?

We have an LDAP login problem of a specific user and I'm suspecting that this is due to cyclic groups assignment in LDAP, i.e. the user is assigned to groups A,B,C,D. Group A contains sub-groups E,F,G and group E contains group A again.
If I query for the user I can see that he has been assigned with 50+ groups and each group may contain more groups and each of those may contain more....
My question is if there's a query I can run to get the nested groups inside those main groups all the way down instead of going each group and do it manually?
The server is AD
To find all the groups that "user1" is a member of (adaptation of this answer see AD search filter):
Set the base to the groups container DN; for example root DN (dc=dom,dc=fr)
Set the scope to subtree
Use the following filter : (member:1.2.840.113556.1.4.1941:=cn=user1,cn=users,DC=x)
Example with LDIFDE.EXE (native command line AD search on windows) :
ldifde -f t.txt -d "DC=dom,DC=fr" -r "(member:1.2.840.113556.1.4.1941:=CN=jblanc,OU=MonOu,DC=dom,DC=fr)"
Remark : as far as I remember there is a small syntax difference with in brackets user DN name. '1.2.840.113556.1.4.1941' is not working in W2K3 SP1, it begins to work with SP2. I presume it's the same with W2K3 R2. I test here with W2K8R2.
With Apache Directory Studio :
Result :

Query to list all users of a certain group

How can I use a a search filter to display users of a specific group?
I've tried the following:
(&
(objectCategory=user)
(memberOf=MyCustomGroup)
)
and this:
(&
(objectCategory=user)
(memberOf=cn=SingleSignOn,ou=Groups,dc=tis,dc=eg,dc=ddd,D‌​C=com)
)
but neither display users of a specific group.
memberOf (in AD) is stored as a list of distinguishedNames. Your filter needs to be something like:
(&(objectCategory=user)(memberOf=cn=MyCustomGroup,ou=ouOfGroup,dc=subdomain,dc=domain,dc=com))
If you don't yet have the distinguished name, you can search for it with:
(&(objectCategory=group)(cn=myCustomGroup))
and return the attribute distinguishedName. Case may matter.
For Active Directory users, an alternative way to do this would be -- assuming all your groups are stored in OU=Groups,DC=CorpDir,DC=QA,DC=CorpName -- to use the query (&(objectCategory=group)(CN=GroupCN)). This will work well for all groups with less than 1500 members. If you want to list all members of a large AD group, the same query will work, but you'll have to use ranged retrieval to fetch all the members, 1500 records at a time.
The key to performing ranged retrievals is to specify the range in the attributes using this syntax: attribute;range=low-high. So to fetch all members of an AD Group with 3000 members, first run the above query asking for the member;range=0-1499 attribute to be returned, then for the member;range=1500-2999 attribute.
If the DC is Win2k3 SP2 or above, you can use something like:
(&(objectCategory=user)(memberOf:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=example,DC=com))
to get the nested group membership.
Source: https://ldapwiki.com/wiki/Active%20Directory%20Group%20Related%20Searches
And the more complex query if you need to search in a several groups:
(&(objectCategory=user)(|(memberOf=CN=GroupOne,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf=CN=GroupTwo,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf=CN=GroupThree,OU=Security Groups,OU=Groups,DC=example,DC=com)))
The same example with recursion:
(&(objectCategory=user)(|(memberOf:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf:1.2.840.113556.1.4.1941:=CN=GroupTwo,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf:1.2.840.113556.1.4.1941:=CN=GroupThree,OU=Security Groups,OU=Groups,DC=example,DC=com)))

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