I need an SSIS expression to get the left part of a string before the separator, and then put the new string in a new column. I checked in derived column, it seems no such expressions. Substring could only return string part with fixed length.
For example, with separator string - :
Art-Reading Should return Art
Art-Writing Should return Art
Science-chemistry Should return Science
P.S.
I knew this could be done in MySQL with SUBSTRING_INDEX(), but I'm looking for an equivalent in SSIS, or at least in SQL Server
Better late than never, but I wanted to do this too and found this.
TOKEN(character_expression, delimiter_string, occurrence)
TOKEN("a little white dog"," ",2)
returns little the source is below
http://technet.microsoft.com/en-us/library/hh213216.aspx
of course you can:
just configure your derived columns like this:
Here is the expression to make your life easier:
SUBSTRING(name,1,FINDSTRING(name,"-",1) - 1)
FYI, the second "1" means to get the first occurrence of the string "-"
EDIT:
expression to deal with string without "-"
FINDSTRING(name,"-",1) != 0 ? (SUBSTRING(name,1,FINDSTRING(name,"-",1) - 1)) : name
You can specify the length to copy in the SUBSTRING function and check for the location of the dash using CHARINDEX
SELECT SUBSTRING(#sString, 1, CHARINDEX('-',#sString) - 1)
For the SSIS expression it is pretty much the same code:
SUBSTRING(#[User::String], 1, FINDSTRING(#[User::String], "-", 1)-1)
if SUBSTRING length param returns -1 then it results in error,
"The length -1 is not valid for function "SUBSTRING". The length parameter cannot be negative. Change the length parameter to zero or a positive value."
Related
I'm looking to extract all the text up until a '\' (backslash).
The substring is required to remove all proceeding characters (17 in total) and so I would like to return all after the 17th until it comes across a backslash.
I've tried using charindex but it doesn't seem to stop at the \ it returns characters afterward. My code is as follows
SELECT path, substring(path,17, CHARINDEX('\',Path)+ LEN(Path)) As Data
FROM [Table].[dbo].[Projects]
WHERE Path like '\ENQ%\' AND
Deleted = '0'
Example
The below screen shot shows the basic query and result i.e the whole string
I then use substring to remove the first X characters as there will always be the same amount of proceeding characters
But what Im actually after is (based on the above result) the "Testing 1" "Testing 2" and "Testing ABC" section
The substring is required to remove all proceeding characters (17 in total) and so I would like to return all after the 17th until it comes across a backslash.
select
substring(path,17,CHARINDEX('\',Path)-17)
from
table
To overcome Invalid length parameter passed to the LEFT or SUBSTRING function error, you can use CASE
select
substring(path,17,
CASE when CHARINDEX('\',Path,17)>0
Then CHARINDEX('\',Path)-17)
else VA end
)
from
table
I am comparing two string.I am reading String 1 i.e expectedResult from excelsheet and String 2 i.e actualResult i am getting from web page by using " getElementByXPath("errorMsg_userPass").getText();
but when i equate two string even though they are same result of comparison are coming false i.e they are not same.
enter image description here
I don't know why it is happening like this .Please Help
use trim() to remove leading and trailing spaces!!
I recommend you looking at the exact bytes of the actual and expected strings. There might be for instance an unbreakable space instead of a regular space and then they will look the same but won't be the same for equals.
You can see the difference by running the following snippet:
String a = new String("a\u00A0b");
String b = new String ("a b");
System.out.println(a + "|" + Arrays.toString(a.getBytes()));
System.out.println(b + "|" + Arrays.toString(b.getBytes()));
Which will output:
a b|[97, -62, -96, 98]
a b|[97, 32, 98]
I need to validate in my query if the value of a string (the first part) is equal to a definited value, for instance:
String
----------
F11-EDEDED
F1-SAFSDA
F455-ADADD
F11-ASDA-FAFA
And validate when the string is F11, i was searching something like split on vba, but i can't find it.
Im working with :
Case when ("splitted string") =F11 then X)
Use a Left() and Charindex() to grab the beginning of your strings.
Declare #str varchar(100)='F11-ASDA-FAFA'
Select #str,Case When left(#str,charindex('-',#str)-1)='F11' Then 1 Else 0 End
I have some sql function that returns character varying type. The output is something like this:
'TTFFFFNN'. I need to get this characters by index. How to convert character varying to array?
Use string_to_array() with NULL as delimiter (pg 9.1+):
SELECT string_to_array('TTFFFFNN'::text, NULL) AS arr;
Per documentation:
In string_to_array, if the delimiter parameter is NULL, each character
in the input string will become a separate element in the resulting array.
In older versions (pg 9.0-), the call with NULL returned NULL. (Fiddle.)
To get the 2nd position (example):
SELECT (string_to_array('TTFFFFNN'::text, NULL))[2] AS item2;
Alternatives
For single characters I would use substring() directly, like #a_horse commented:
SELECT substring('TTFFFFNN'::text, 2, 1) AS item2;
SQL Fiddle showing both.
For strings with actual delimiters, I suggest split_part():
Split comma separated column data into additional columns
Only use regexp_split_to_array() if you must. Regular expression processing is more expensive.
In addition to the solutions outlined by Erwin and a horse, you can use regexp_split_to_array() with an empty regexp instead:
select regexp_split_to_array('TTFFFFNN'::text, '');
With an index, that becomes:
select (regexp_split_to_array('TTFFFFNN'::text, ''))[2];
I parsed a string which I use substring to get the last 11 i think numbers of characters. I accomplished that one but when I use cast and round it gives a different result from the manual computation I did.
Here's my query
SELECT round(cast(SUBSTRING('351856040520298,241111;1R,141117003059,A,1420.4629N,12058.7028E,0.0,77,0.9,20000006;2R,141117003059,11,98.3,12.58,04.10,282098820.9', 123,11)as float)/3600, 0, 1)
This gives me a result of 583. But when I try to manually compute using the computation below
282098820.9 / 3600
The result is
78360.7835
Is there something wrong with my query?
Thanks for the help.
The problem is with your SUBSTRING. It only returns 2098820.9 instead of 282098820.9. Try using RIGHT to extract the last 11 characters.
SELECT round(cast(right('351856040520298,241111;1R,141117003059,A,1420.4629N,12058.7028E,0.0,77,0.9,20000006;2R,141117003059,11,98.3,12.58,04.10,282098820.9', 11)as float)/3600, 0, 1)